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Regex: Replace last segment of url

I try to figure out the correct regex to replace the last segment of an url with a modified version of that very last segment. (I know that there are similar threads out there, but none seemed to help...)
Example:
https://www.test.com/one/two/three/mypost/
--->
one/two/three?id=mypost
https://www.test.com/one/mypost/
--->
one?id=mypost
Now I am stuck here:
https://regex101.com/r/9GqYaU/1
I can get the last segment in capturing group 2 but how would I replace it?
I think I will have to something like this:
const url = 'https://www.test.com/one/two/three/mypost/'
const regex = /(http[s]?:\/\/)([^\/]+\/)*(?=\/$|$)/
const path = url.replace(regex, `${myUrlWithoutTheLastSegmentAnd WithoutHTTPS}?id=$2`)
return path
But I have no idea how to get the url without the last segment. I have currently only access to the whole string or group 1 (which is useless in this case) and then group 2, but not the string without group 2.
I would be very glad for any help here. Sometimes I just lack the knowledge of what is possible with regex and how to achieve it.
Thank you in advance.
Cheers

You could use the URL class to extract the pathname and substring to remove the first '/'.
Then, you could put the last part of the pathname in a group and use it as a reference $1 for the replacement.
const url = new URL('https://www.test.com/one/two/three/mypost/').pathname.substring(1)
console.log(url.replace(/\/([^/]*)\/$/, '?id=$1'))

I came across your question yesterday and agree with going down the route of parsing the URL. Once you get there you could even use JavaScript array methods which I prefer to string methods like:
pathname.split("/").filter(p => p.length).pop()
This would separate each folder, ignore any with no length (i.e. handle a trailing slash) and return the last one (mypost).
Anyway, I am also learning regex so sometimes when I find a question like this I just try to find the answer anyway as the best way of learning is doing. It took 24 hours 😂 I came up with this:
/(https?:\/\/).+?([a-z-]*)\/?$/gm
(https?:\/\/) you know what this does. Small correction, you don't need the square brackets. Question mark matches 0 or 1 of the preceding character. As we're only matching s this just works. If you wanted to match s or z you would use [sz]?. I think.
.+? this is the cool one I think I will use in future now I found it. The question mark here has a different meaning - it makes .+ (which means one or more of any character) non-greedy. That means it stops applying once it reaches the next rule. Which is...
([a-z-]*) any number of letters or a hyphen. You should maybe change this to include numbers and upper case.
\/? Optional slash
$ all this must apply at the end of the string.
Here is a demo
https://regex101.com/r/mQNkIS/1

How do I let user input curly quotes rather than straight ones by JavaScript in a textarea/input[type=text]? [duplicate]

I have an application which uses a Javascript-based rules engine. I need a way to convert regular straight quotes into curly (or smart) quotes. It’d be easy to just do a string.replace for ["], only this will only insert one case of the curly quote.
The best way I could think of was to replace the first occurrence of a quote with a left curly quote and every other one following with a left, and the rest right curly.
Is there a way to accomplish this using Javascript?

You could replace all that preceed a word character with the left quote, and all that follow a word character with a right quote.
str = str.replace(/"(?=\w|$)/g, "“");
str = str.replace(/(?<=\w|^)"/g, "”"); // IF the language supports look-
// behind. Otherwise, see below.
As pointed out in the comments below, this doesn't take punctuation into account, but easily can:
/(?<=[\w,.?!\)]|^)"/g
[Edit:] For languages that don't support look-behind, like Javascript, as long as you replace all the front-facing ones first, you have two options:
str = str.replace(/"/g, "”"); // Replace the rest with right curly quotes
// or...
str = str.replace(/\b"/g, "”"); // Replace any quotes after a word
// boundary with right curly quotes
(I've left the original solution above in case this is helpful to someone using a language that does support look-behind)

You might want to look at what Pandoc does—apparently with the --smart option, it handles quotes properly in all cases (including e.g. ’tis and ’twere).
I recently wrote a Javascript typography prettification engine that does, among other things, quote replacement; I wound up using basically the algorithm suggested by Renesis, but there’s currently a failing test up waiting for a smarter solution.
If you’re interested in cribbing my code (and/or submitting a patch based on work you’ve done), check it out: jsPrettify. jsprettify.prettifyStr does what you’re looking for. If you don’t want to deal with the Closure dependency, there’s an older version that runs on its own—it even works in Rhino.

'foo "foo bar" "bar"'.replace(/"([-a-zA-Z0-9 ]+)"/g, function(wholeMatch, m1){
return "“" + m1 + "”";
});

The following just changes every quote by alternating (this specific example however would leave out the orphaned quotes).
str.replace(/\"([^\"]*)\"/gi,"“$1”");
Works perfectly, as long as the text you're texturizing isn't already screwed up with improper use of the double quote. In English, quotes are never nested.

I don't think something like that in general is easy at all, because you'd have to interpret exactly what each double-quote character in your content means. That said, what I'd do is collect all the text nodes I was interested in, and then go through and keep track of the "on/off" (or "odd/even"; whatever) nature of each double quote instance. Then you can know which replacement entity to use.

I didn't find the logic I wanted here, so here's what I ended up going with.
value = value.replace(/(^|\s)(")/g, "$1“"); // replace quotes that start a line or follow spaces
value = value.replace(/"/g, "”"); // replace rest of quotes with the back smart quote
I have a small textarea that I need to replace straight quotes with curly (smart) quotes. I'm just executing this logic on keyup. I tried to make it behave like Microsoft Word.

Posting for posterity.
As suggested by #Steven Dee, I went to Pandoc.
I try to use a mature and tested tool whenever I can versus baking my own regex. Hand built regex's can be overly greedy, or not greedy enough, and they may not be sensitive to word boundaries and commas etc. Pandoc accounts for most this and more.
From the command line (the --smart parameter turns on smart quotes):
pandoc --smart --standalone -o output.html input.html
..and I know a command line script may or may not fit OP's requirement of using Javascript. (related: How to execute shell command in Javascript)

How to append string after matching field with regex

I want to append a word after <body> tag, it should not modify/replace anything other than just append a word. I have done something like this, is it valid do empty parenthesis fir second capture group will match everything?
/(<body[^>]*>)()/, `$1${my_variable}$2`)

The second capture group, designed to capture nothing, will match "nothing" - it will form a match immediately after your closed body tag. There's nothing wrong with doing this for the regex, though you might want to be wary of using [^>]* - this negated character class will gladly match across lines and grab as much input as it can. Handy for matching multi-line tags, but often very dangerous.
Also, if you're on linux and for some reason have > symbols in filenames (which is valid!) your regex will break horribly, as shown here.
That being said, valid regex or not, it's usually a bad idea to use regex with html, since HTML isn't a regular language. Also, you could accidentally summon Cthulhu.

let page = "<html><body>Some info</body></html>";
page.replace("<body>", `<body>${my_variable}`);
or
page.replace(/<body>|<BODY>/, `<body>${my_variable}`);
If in the broweser you can also use document.querySelector("body").innerHTML
Also depending on which framework you're using there are better ways to accomplish this.

Capturing optional part of URL with RegExp

While writing an API service for my site, I realized that String.split() won't do it much longer, and decided to try my luck with regular expressions. I have almost done it but I can't find the last bit. Here is what I want to do:
The URL represents a function call:
/api/SECTION/FUNCTION/[PARAMS]
This last part, including the slash, is optional. Some functions display a JSON reply without having to receive any arguments. Example: /api/sounds/getAllSoundpacks prints a list of available sound packs. Though, /api/sounds/getPack/8Bit prints the detailed information.
Here is the expression I have tried:
req.url.match(/\/(.*)\/(.*)\/?(.*)/);
What am I missing to make the last part optional - or capture it in whole?

This will capture everything after FUNCTION/ in your URL, independent of the appearance of any further / after FUNCTION/:
FUNCTION\/(.+)$
The RegExp will not match if there is no part after FUNCTION.

This regex should work by making last slash and part after optional:
/^\/[^/]*\/[^/]*(?:\/.*)?$/
This matches all of these strings:
/api/SECTION/FUNCTION/abc
/api/SECTION
/api/SECTION/
/api/SECTION/FUNCTION

Your pattern /(.*)/(.*)/?(.*) was almost correct, it's just a bit too short - it allows 2 or 3 slashes, but you want to accept anything with 3 or 4 slashes. And if you want to capture the last (optional) slash AND any text behind it as a whole, you simply need to create a group around that section and make it optional:
/.*/.*/.*(?:/.+)?
should do the trick.
Demo. (The pattern looks different because multiline mode is enabled, but it still works. It's also a little "better" because it won't match garbage like "///".)

Can someone tell me the purpose of the second capture group in the jQuery rts regular expression?

In Jeff Roberson's jQuery Regular Expressions Review he proposes changing the rts regular expression in jQuery's ajax.js from /(\?|&)_=.*?(&|$)/ to /([?&])_=[^&\r\n]*(&?)/. In both versions, what is the purpose of the second capture group? The code does a replacement of the current random timestamp with a new random timestamp:
var ts = jQuery.now();
// try replacing _= if it is there
var ret = s.url.replace(rts, "$1_=" + ts + "$2");
Doesn't it only replace what it matches? I am thinking this does the same:
var ret = s.url.replace(/([?&])_=[^&\r\n]*/, "$1_=" + ts);
Can someone explain the purpose of the second capture group?

It's to pick up the next delimiter in the query string on the URL, so that it still works properly as a query string. Thus if the url is
http://foo.bar/what/ever?blah=blah&_=12345&zebra=banana
then the second group picks up the "&" before "zebra".
That's an awesome blog post by the way and everybody should read it.
edit — now that I think about it, I'm not sure why it's necessary to bother with replacing that second delimiter. In the "fixed" expression, that greedy * will pick up the whole parameter value and stop at the delimiter (or the end of the string) anyway.

I think you're right. It was needed in the original because matching the ampersand or end-of-string was how the .*? knew when to stop. In Jeff's version that's no longer necessary.

As the author of the article I can't tell you the reason for the second capture group. My intent with the article was to take existing regexes and simply make them more efficient - i.e. they should all match the same text - just do it faster. Unfortunately I did not have time to delve deeply into the code to see exactly how each and every one of them was being used. I assumed that the capture group for this one was there for a reason so I did not mess with it.