I have a button click function like this :
$("#submitButton").click(function (e) {
e.preventDefault();
console.log("let's show my div");
$('#mydiv').show();
//and then doing a lot of front end operations and some ajax calls
})
When I click the submit button, I get the console.log message immediately. But .show() method works like 7-8 seconds after that. Can you tell me how I can make .show() work immediately? Thanks.
EDIT :
My HTML code looks like this :
<div class="main">
<form id="myform" enctype="multipart/form-data" class="contact-forms">
<div class="first-line">
<div class="span3 main-row">
<div class="input">
<input type="text" id="id" name="id" placeholder="insert your ID" maxlength="7" oninput="this.value = this.value.replace(/[^0-9.]/g, '').replace(/(\..*)\./g, '$1');" />
</div>
</div>
</div>
<div class="first-line">
<div class="span8 main-row">
<div class="input">
<input type="text" id="name" name="name" placeholder="Your name" />
</div>
</div>
</div>
<div id="mydiv" style="display:none">
<label>
Processing, please wait.
</label>
</div>
</form>
</div>
This is example of showing the div , you should hide your div with display none not hidden class , if you use hidden class just remove class to show your div
function ShowDiv(){
$("#mydiv").show();
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="mydiv" style='display:none;'>Hello</div>
<button onclick="ShowDiv()"> ShowMe</button>
Related
I'm doing a project and I don't understand the front end well.
I have this html page:
<form class="form-group" action="/create" method="post" enctype="multipart/form-data">
<div class="title">
<h1>Cadastre seu produto</h1>
</div>
<div class="single-input">
<input class="form-control" placeholder="nome do produto" type="text" id="nome_produto" name="nome_produto">
</div>
<div class="single-input">
<input class="form-control" placeholder="quantidade em estoque" type="number" id="quantidade" name="quantidade">
</div>
<div class="single-input">
<input class="form-control" placeholder="preco do produto" type="number" id="preco_produto" name="preco_produto">
</div>
<button onclick="loadPage()" id="button" type="submit" class="btn btn btn-danger">ENVIAR</button>
</form>
I want that when I click on the SUBMIT button, I am redirected to another page, I want to do this using Javascript.
I tried to do this:
<script type="text/javascript">
function loadPage(){
window.location("http://localhost:8080/list")
}
but it's not working, every time I click on the button I'm redirected to a blank page
Any solution ?
Window.location is a property not a function. So it should be
window.location = "http://localhost:8080/list";
More details here: https://developer.mozilla.org/en-US/docs/Web/API/Window/location
I have built a form where you can add a person by clicking a button. Now, I want to add a new button to delete the latest added person. My current code only deletes one person, and after that, I can't add another person again. Do someone know what's wrong?
$(document).ready(function(){
$("#button1").click(function(){
$(".flex-container-name-adult").append($(".test1").html());
});
});
$(document).ready(function(){
$("#button3").click(function(){
$(".test1").remove();
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="flex-container-name-adult">
<button id="button1">Add person</button>
<button id="button3">Delete person</button>
<div class="test1">
<div class="flex-wrapper-name-adult">
<span class="adult">Person</span><br>
<input type="text" class="input" placeholder="Name" name="name" required>
<input type="text" class="input" placeholder="Nachname" name="nachname" required>
<input type="date" class="input" placeholder="Geburtsdatum" name="geburtstag" required onfocus="(this.type='date')" onblur="(this.type='Geburtsdatum')">
</div>
</div>
</div>
When you click the add person button you are appending the html of test1 to the element with class flex-container-name-adult. That html don't include the div with test1 class itself. Now, when you click the delete person button you are deleting all the elements with the class test1. So, after that action, there will be no more elements with class test1 on the document that you can later use on the add person button.
I suggest to use .clone() for what you want to do, and to always delete the last added person. Something like this:
$(document).ready(function()
{
$("#button1").click(function()
{
// Clone the first ".test1" element and append it to the wrapper.
$(".flex-container-name-adult").append($(".test1").first().clone());
});
$("#button3").click(function()
{
// Delete last ".test1" element, if exists more than one.
let tests = $(".test1");
if (tests.length > 1)
tests.last().remove();
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="flex-container-name-adult">
<button id="button1">Add person</button>
<button id="button3">Delete person</button>
<div class="test1">
<div class="flex-wrapper-name-adult">
<span class="adult">Person</span><br>
<input type="text" class="input" placeholder="Name" name="name" required>
<input type="text" class="input" placeholder="Nachname" name="nachname" required>
<input type="date" class="input" placeholder="Geburtsdatum" name="geburtstag" required onfocus="(this.type='date')" onblur="(this.type='Geburtsdatum')">
</div>
</div>
</div>
I'm facing a problem with my project. My user can create a new div by clicking a button, but he can remove whatever div he wants, expect the first one. So if he create 2 new divs here is what the code will look like:
<div id="container1">
<input type="text" id="title1"><br />
<input type="text" id="description1">
</div>
<div id="container2">
<input type="text" id="title2"><br />
<input type="text" id="description2">
</div>
<div id="container3">
<input type="text" id="title3"><br />
<input type="text" id="description3">
</div>
If the user remove the second div my code will look like this.
<div id="container1">
<input type="text" id="title1"><br />
<input type="text" id="description1">
</div>
<div id="container3">
<input type="text" id="title3"><br />
<input type="text" id="description3">
</div>
Pretty simple. Now I want to use the information entered by the user in the text inputs, but I don't know how to select the active divs. Is there a way to select the container1 and container3 in the example above?
Keep in mind that the user can use up to 99 new div.
Your help is appreciated. Thank you,
Just apply a CSS selector:
<div id="parent">
<div id="container1">
<input type="text" id="title"><br />
<input type="text" id="description">
</div>
<div id="container3">
<input type="text" id="title1"><br />
<input type="text" id="description1">
</div>
</div>
$('#parent > div')
See here for more information: https://api.jquery.com/category/selectors/
You can add a class to each item. You would need to amend your code that is called when the button is clicked to handle this.
Let's say you gave all titles a class of "myTitle" and you gave all descriptions a class of "myDescription". Your div created would look something like this:
<div id="container1">
<input type="text" id="title" class="myTitle">
<br />
<input type="text" id="description" class="myDescription">
</div>
Now, in order to get all titles and descriptions you'd use jQuery and say:
$('.myTitle').each(function () {
console.log($(this).val());
});
$('.myDescription').each(function () {
console.log($(this).val());
});
First of all, you have multiple divs with the id "title" and "description", so change those to class. You can select the nth div with jquery: $("#container" + n)
you can select the title of the nth div: `$("#container" + n).children(".title");
you can select all of the divs by adding a class to them, such as .container
Ok, I've been having a really weird problem using a checkbox which collapses a hidden div using bootstrap.
if I have data-toggle="collapse" in the checkbox input attribute section, the Div Collapses but requires that every single one of the inputs inside it be filled out.
If data-toggle="collapse" is not there, the hidden div doesn't collapse, and if the checkbox is checked it requires the inputs to be entered and if it's left unchecked I can submit the form without the inputs being entered. (desired action, but the div doesn't hide or show when the checkbox is checked)
How do I hide/show the div when the checkbox is unchecked/checked AND only require the inputs if the box is checked?
I'm using this as the HTML:
<div class="col-md-1">
<input type="checkbox" onclick="ChangeShip()" href="#moreabout" data-toggle="collapse" aria-expanded="false" aria-controls="moreabout" class="form-control" id="chShipAdd" name="chShipAdd" value="no">
</div>
<label for="chShipAdd" class="col-md-3 control-label">Shipping Information?</label>
<div id="shipadddiv" style="visibility: hidden;">
<div class="collapse" id="moreabout" >
<div class="form-group">
<div class="col-md-12">
<br>
<input id="sStreet" name="sStreet" type="text" placeholder="Street Name (required)" class="form-control shipClass" required>
</div>
</div>
<div class="form-group">
<div class="col-md-4">
<input id="sCity" name="sCity" type="text" placeholder="City (required)" required class="form-control shipClass">
</div>
<div class="col-md-4">
<input id="sState" name="sState" type="text" placeholder="State (required)" required class="form-control shipClass">
</div>
<div class="hidden-lg hidden-md"> </div>
<div class="col-md-4">
<input id="sZipcode" name="sZipcode" type="text" placeholder="Zip (required)" required class="form-control shipClass">
</div>
</div>
</div>
</div>
and the javascript:
function ChangeShip() {
if (!(document.getElementById('chShipAdd').checked)) {
document.getElementById('shipadddiv').style.visibility="hidden";
$(".shipClass").prop("disabled",true);
}
else {
document.getElementById('shipadddiv').style.visibility="visible";
$(".shipClass").prop("disabled",false);
}
}
Any solution that WORKS will be acceptable. I've bashed my brain all day trying to do this simple action. I've tried .prop .attribute .setAttribute .removeAttribute, and much much more.
Any Advice?
You can use jquery to solve this quickly. You can wrap your inputs for change ship and give it and id. And let jquery do the rest.
var form = $('#myForm'),
checkbox = $('#changeShip'),
chShipBlock = $('#changeShipInputs');
chShipBlock.hide();
checkbox.on('click', function() {
if($(this).is(':checked')) {
chShipBlock.show();
chShipBlock.find('input').attr('required', true);
} else {
chShipBlock.hide();
chShipBlock.find('input').attr('required', false);
}
});
See this jsfiddle for your problem. This should help you.
your click event will toggle the display and the disabled, but when the form is loaded you will have hidden content that is not disabled.
simply call the function on document.ready
function ChangeShip() {
var show = $('#chShipAdd').prop('checked');
$('#shipadddiv').toggle(show);
$("#shipadddiv .shipClass").prop("disabled", !show);
}
$(ChangeShip); // call on document.ready
or simply add the disabled attribute to those elements so that the initial form state is valid
If the [required] attribute is still triggered on a [disabled] element you could juggle the attribute value
function ChangeShip() {
var show = $('#chShipAdd').prop('checked');
$('#shipadddiv').toggle(show);
$("#shipadddiv .shipClass").each(function(){
if (!('_required' in this))
this._required = this.required;
this.disabled = !show;
this.required = (show) ? this._required : false;
});
}
Try to do this :
HTML :
<div class="col-md-1">
<input type="checkbox" onclick="ChangeShip()" href="#moreabout" data-toggle="collapse" aria-expanded="false" aria-controls="moreabout" class="form-control" id="chShipAdd" name="chShipAdd" value="no">
</div>
<label for="chShipAdd" class="col-md-3 control-label">Shipping Information?</label>
<div id="shipadddiv" style="visibility: hidden;">
<div class="collapse" id="moreabout" >
<div class="form-group">
<div class="col-md-12">
<br>
<input id="sStreet" name="sStreet" type="text" placeholder="Street Name (required)" class="form-control shipClass" required>
</div>
</div>
<div class="form-group">
<div class="col-md-4">
<input id="sCity" name="sCity" type="text" placeholder="City (required)" required class="form-control shipClass">
</div>
<div class="col-md-4">
<input id="sState" name="sState" type="text" placeholder="State (required)" required class="form-control shipClass">
</div>
<div class="hidden-lg hidden-md"> </div>
<div class="col-md-4">
<input id="sZipcode" name="sZipcode" type="text" placeholder="Zip (required)" required class="form-control shipClass">
</div>
</div>
</div>
</div>
JQUERY :
$('#chShipAdd').change(function() {
if ($('#chShipAdd').prop('checked')) {
$('#shipadddiv').show();
} else {
$('#shipadddiv').hide();
}
});
i would like to click in plus ,then show the next field in every step but my code does not work in third step .is there any method to do these steps for unlimited time?tnx
<html>
<head>
<script>
function showfield(){
document.getElementById("hiddenfield").style.display="block";
}
</script>
</head>
<body>
<div class="form-group" >
<div class="rightbox"> <label for='phone'>Phone1</label></div>
<input type="tel" value="" />
<div class="plus" onClick="showfield()">+</div>
</div>
<div class="form-group" style="display:none;" id="hiddenfield">
<div class="rightbox"><label for='phone'>Phone2</label></div>
<input type="tel" value="" />
<div class="plus" onClick="showfield()">+</div></div>
</div>
<div class="form-group" style="display:none;" id="hiddenfield">
<div class="rightbox"><label for='phone'>Phone3</label></div>
<input type="tel" value="" />
<div class="plus" onClick="showfield()">+</div></div>
</div>
</body>
</html>
You can use unique id for each hidden field, then send current id to your function as parameter.
function showfield(id) {
document.getElementById(id).style.display="block";
}
Another option is jquery:
$('.plus').on('click', function() {
$(this).parent().next().show();
});
Check out jsfiddle.
As others noted, ID of an element must be unique, you can use class to group similar elements.
What you need to do is to show the first hidden field group,
function showfield() {
var el = document.querySelector(".hiddenfield");
if (el) {
el.classList.remove('hiddenfield')
}
}
.hiddenfield {
display: none;
}
<div class="form-group">
<div class="rightbox">
<label for='phone1'>Phone1</label>
</div>
<input type="tel" value="" />
<div class="plus" onClick="showfield()">+</div>
</div>
<div class="form-group hiddenfield">
<div class="rightbox">
<label for='phone2'>Phone2</label>
</div>
<input type="tel" value="" />
<div class="plus" onClick="showfield()">+</div>
</div>
<div class="form-group hiddenfield">
<div class="rightbox">
<label for='phone3'>Phone3</label>
</div>
<input type="tel" value="" />
<div class="plus" onClick="showfield()">+</div>
</div>
Supported in IE10+
Since you've tagged jquery, you could do away with all those (duplicate ids) and showField() and within doc load add this:
$('.plus').on('click', function() {
$(this).parent().next().show();
});
[Edit: Oh, here's the fiddle]
However, I'm not sure what you want to happen when the third + is clicked as there are no more divs to show.
Change id="hiddenfield" to class="hiddenfield" in all divs and change showfield as below :-
function showfield() {
document.getElementsByClassName("hiddenfield").style.display="block";
}
Note:- Supported Browsers IE9+, Chrome 4+, FF3+.
http://www.w3schools.com/jsref/met_document_getelementsbyclassname.asp