I'm trying to run multiple .js files from a directory:
exampleDir/test.js
console.log('hi');
run.js
const fs = require('fs');
const {execFileSync} = require('child_process');
const testsFolder = './exampleDir/';
const files = fs.readdirSync(testsFolder);
const funcs = files.map(function(file) {
const out = execFileSync(`node ${testsFolder}${file}`);
console.log(out.toString());
});
however I get:
> example#1.0.0 test /home/perdugames/example
> node ./run.js
child_process.js:624
throw err;
^
Error: spawnSync node ./exampleDir/test.js ENOENT
...
File paths should be specified unambiguously, preferably independent of current working directory and relative to current module. To create a new Node process, there are spawn and spawnSync in child_process:
...
const path = require('path');
const testsFolder = path.join(__dirname, './exampleDir/');
const files = fs.readdirSync(testsFolder);
const funcs = files.map(function(file) {
const filePath = path.join(testsFolder, file);
const out = spawnSync(filePath);
console.log(out.stdout.toString());
});
Related
I can cmd in node.js using child-process and spawn, I want the ouput of this command to be written into file instead of stdout.
test.js
const expect = require('chai').expect;
const { spawn } = require('child_process')
let path = require('path');
let fs = require('fs');
//tried but didn't work
1) const cmd = spawn(ansysfnonetclient, options, {
stdio: [
0, // Use parent's stdin for child.
'pipe', // Pipe child's stdout to parent.
fs.openSync('err.out', 'w') // Direct child's stderr to a file.
]
});
2) const cmd = spawn(ansysfnonetclient, options, {shell: true, stdio: 'inherit'});
it('run the cmd and write o/p to file', function (done) {
this.timeout(30000);
let options = ['-h','-o','temp.log'];
let ansysfnonetclient = path.resolve(__dirname,'../../../../../../../../saoptest/annetclient.exe');
const cmd = spawn(ansysfnonetclient, options, {shell: true, stdio: 'inherit'});
console.log(cmd);
done();
});
stdio option passes 3 "files":
input
output
error output
If you want to pipe regular output to a file, you have to pass the file as second item in stdio:
const { spawn } = require('child_process');
const fs = require('fs');
const stdio = [
0,
fs.openSync('std.out', 'w'),
fs.openSync('err.out', 'w')
];
const child = spawn('echo', ['hello world!'], {stdio});
Read more about it at https://nodejs.org/api/child_process.html#child_process_options_stdio.
const expect = require('chai').expect;
const { spawn } = require('child_process')
let path = require('path');
let fs = require('fs');
```
const cmd = spawn(ansysfnonetclient, options, {shell: true, stdio: 'inherit'});
cmd.stdout.on('data',function(chunk) {
fs.writeFile(path.resolve(__dirname,'../../../../../../../../output.log'), chunk.toString(), function(err) {
if(err)
{
return console.log(err);
}
console.log("The file was saved!");
});
```
Inspired from this post Node.js: Capture STDOUT of `child_process.spawn`
I need to zip and unzip file with Node.js but I have a problem.
const fs = require("fs");
const zlib = require('zlib');
function UnZip(zip, paths) {
var inp = fs.createReadStream("f:/test.zip");
var Exzip = zlib.createUnzip();
inp.pipe(Exzip).pipe("f:/");
}
Error:
TypeError: dest.on is not a function
Here is how you can do it with zlib module.
const fs = require('fs');
const zlib = require('zlib');
const fileContents = fs.createReadStream('file1.txt.gz');
const writeStream = fs.createWriteStream('file1.txt');
const unzip = zlib.createGunzip();
fileContents.pipe(unzip).pipe(writeStream);
Zipping the file
const archiver = require('archiver'),
archive = archiver('zip'),
fs = require('fs'),
output = fs.createWriteStream( 'mocks.zip');
archive.pipe(output);
// temp.txt file must be available in your folder where you
// are writting the code or you can give the whole path
const file_buffer = fs.readFileSync('temp.txt')
archive.append(file_buffer, { name: 'tttt.txt'});
archive.finalize().then((err, bytes) => {
if (err) {
throw err;
}
console.log(err + bytes + ' total bytes');
});
unzipping a file
const unzip = require('unzip'),
fs = require('fs');
fs.createReadStream('temp1.zip').pipe(unzip.Extract({ path: 'path' }))
I would like to compile multiple contracts in one compile.js file but I'm not sure how to do it.
My compile.js file with a single contract looks like this:
const path = require('path');
const fs = require('fs');
const solc = require('solc');
const lotteryPath = path.resolve(__dirname, 'contracts', 'Lottery.sol');
const source = fs.readFileSync(lotteryPath, 'utf8');
module.exports = solc.compile(source, 1);
How can I add more contracts to the compile.js file? I understand that the 1 must be changed to the number of contracts, but not sure what else is required?
Here is an example I did. You can find it in my public repo. Briefly, I have a "build" folder where I write the output of each compiled contract to Json files.
const path = require("path"); //nodejs ’path’ module
const solc = require("solc"); //solidity compiler module
const fs = require("fs-extra"); //file system module
// Feth path of build
const buildPath = path.resolve(__dirname, "build");
const contractspath = path.resolve(__dirname, "contracts");
// Removes folder build and every file in it
fs.removeSync(buildPath);
// Fetch all Contract files in Contracts folder
const fileNames = fs.readdirSync(contractspath);
// Gets ABI of all contracts into variable input
const input = fileNames.reduce(
(input, fileName) => {
const filePath = path.resolve(__dirname, "contracts", fileName);
const source = fs.readFileSync(filePath, "utf8");
return { sources: { ...input.sources, [fileName]: source } };
},
{ sources: {} }
);
// Compile all contracts
const output = solc.compile(input, 1).contracts;
// Re-Create build folder for output files from each contract
fs.ensureDirSync(buildPath);
// Output contains all objects from all contracts
// Write the contents of each to different files
for (let contract in output) {
fs.outputJsonSync(
path.resolve(buildPath, contract.split(":")[1] + ".json"),
output[contract]
);
}
Basically, if you do not change your path struct to mine, you have to change you this part of the above code:
// Feth path of build
const buildPath = path.resolve(__dirname, "build");
const contractspath = path.resolve(__dirname, "contracts");
The approved solution does not work for solidity >0.6.0 and <=0.8.1.
For the mentioned versions, I solved it as follows:
const path = require("path");
const fs = require("fs-extra");
const solc = require("solc");
const buildPath = path.resolve(__dirname, "build");
fs.removeSync(buildPath);
const contractPath = path.resolve(__dirname, "contracts");
const fileNames = fs.readdirSync(contractPath);
const compilerInput = {
language: "Solidity",
sources: fileNames.reduce((input, fileName) => {
const filePath = path.resolve(contractPath, fileName);
const source = fs.readFileSync(filePath, "utf8");
return { ...input, [fileName]: { content: source } };
}, {}),
settings: {
outputSelection: {
"*": {
"*": ["abi", "evm.bytecode.object"],
},
},
},
};
// Compile All contracts
const compiled = JSON.parse(solc.compile(JSON.stringify(compilerInput)));
fs.ensureDirSync(buildPath);
fileNames.map((fileName) => {
const contracts = Object.keys(compiled.contracts[fileName]);
contracts.map((contract) => {
fs.outputJsonSync(
path.resolve(buildPath, contract + ".json"),
compiled.contracts[fileName][contract]
);
});
});
be sure to check that your pragma solidity x.x.x matches with the version specified in your package.json. For example, if I'm using solidity 0.6.12 my solidity compiles would be:
"dependencies": {
...
"solc": "^0.6.12",
...
}
compile.js:
const path= require('path');
const solc = require('solc');
const fs = require('fs-extra');
const builtPath = path.resolve(__dirname, 'build');
//remove file in build module
fs.removeSync(builtPath);
const healthPath = path.resolve(__dirname, 'contract','health.sol');
//read content present in file
console.log(healthPath);
const source = fs.readFileSync(healthPath,'utf8');
//compile contract
const output = solc.compile(source,1).contracts;
//create build folder
fs.ensureDirSync(builtPath);
console.log(output);
for(let contract in output)
{
fs.outputJsonSync(
path.resolve(buildPath, contract.replace(':','')+ '.json'),
output[contract]
);
}
I am trying to write a file to a directory templates then stream a zip with the content that was written. However, the when the zip file is returned it says Failed - Network Error which is due to the fs.writeFile in the controller. If i remove the WriteFile stream then the zipping works fine. My question is how do i first write the file then run the zip. There seems to be something synchronous happening with the archiving and file writing of typeArrayString.
Controller:
exports.download_one_feed = function(req, res, next) {
Feed.findOne({'name': req.params.id})
.exec(function(err, dbfeeds){
if(err){
res.send('get error has occured in routes/feeds.js');
} else {
const feedArray = dbfeeds.feed.data;
// write file
// get from db collection & write file to download
const typeArrayString = JSON.stringify(feedArray);
let type = 'b'; // test only
fs.writeFile(path.join(appDir, 'templates/' + type + '/template.json'), typeArrayString, (err) => {
if (err) throw err;
console.log('Saved!');
})
archiverService.FileArchiver(feedArray, res);
}
})
};
Archive Service
const archiver = require('archiver')
const zip = archiver('zip')
const path = require('path')
const fs = require('fs')
const appDir = path.dirname(require.main.filename)
exports.FileArchiver = function (feedArray, res) {
// const app = this.app;
const uploadsDir = path.join(appDir, '/uploads/');
const templatesDir = path.join(appDir, '/templates/');
const extensions = [".jpg", ".png", ".svg"];
let imageArray = [];
const feedArrayObject = JSON.parse(feedArrayString);
feedArrayObject.forEach(function(x){iterate(x)}); // grab image names from object
imageArray = uniq_fast(imageArray); // remove duplicates
// zip images
for (let i = 0; i < imageArray.length; i++) {
console.log(imageArray[i])
const filePath = path.join(uploadsDir, imageArray[i]);
zip.append(fs.createReadStream(filePath), { name: 'images/'+imageArray[i] });
}
res.attachment('download.zip');
zip.pipe(res);
// zip template directory
console.log(templatesDir)
zip.directory(templatesDir, false);
zip.on('error', (err) => { throw err; });
zip.finalize();
return this;
}
Instead of writing the file then zipping the directory, i used zip.append to override the old file in the directory.
I want to load test.txt with nodejs.
var fs = require('fs');
fs.readFile('./test.txt', function (err, data) {
if (err) {
throw err;
}
console.log(data);
});
The path of the server is C:\server\test\server.js. The test.txt is located in the same directory, but I get this error: Error: ENOENT, no such file or directory 'C:\Users\User\test.txt'
Paths in Node are resolved relatively to the current working directory. Prefix your path with __dirname to resolve the path to the location of your Node script.
var fs = require('fs');
fs.readFile( __dirname + '/test.txt', function (err, data) {
if (err) {
throw err;
}
console.log(data.toString());
});
With Node 0.12, it's possible to do this synchronously now:
var fs = require('fs');
var path = require('path');
// Buffer mydata
var BUFFER = bufferFile('../test.txt');
function bufferFile(relPath) {
return fs.readFileSync(path.join(__dirname, relPath)); // zzzz....
}
fs is the file system. readFileSync() returns a Buffer, or string if you ask.
fs correctly assumes relative paths are a security issue. path is a work-around.
To load as a string, specify the encoding:
return fs.readFileSync(path,{ encoding: 'utf8' });
You should use __dirname to get the directory name the file is located instead of the current working directory:
fs.readFile(__dirname + "/test.txt", ...);
Use path and fs:
const fs = require("fs");
const pth = require("path");
Sync:
let data = fs.readFileSync(pth.join(__dirname,"file.txt"));
console.log(data + "");
A-Sync:
fs.readFile(pth.join(__dirname,"file.txt"), (err, data) => {
console.log(data + "");
});
And that; If you need to read the file continuously and send it to the client and the file size is not large, you may be able to keep a copy of it:
const exp = require("express");
const app = exp();
const fs = require("fs");
const pth = require("path");
let file = "";
app.get("/file", (q, r) => {
if (file === "")
file = fs.readFileSync(pth.join(__dirname,"file.txt")) + "";
r.writeHead(200, { "Content-Type": "text/plain" });
r.write(file);
r.end();
});
so if it is in the same directory just do this
fs.readFile(__dirname+'/foo.txt',function(e,d){console.log(d)})
If it's in same directory it should work. I have tested with the same code, with a file name.txt and it's working fine:
var fs = require('fs');
fs.readFile('./test.txt', function (err, data) {
if (err) {
throw err;
}
console.log(data.toString());
});