Related
I'm looking for a generalized solution for this.
Consider 2 radio type inputs with the same name. When submitted, the one that is checked determines the value that gets sent with the form:
<input type="radio" name="myRadios" onchange="handleChange1();" value="1" />
<input type="radio" name="myRadios" onchange="handleChange2();" value="2" />
The change event does not fire when a radio button is de-selected. So if the radio with value="1" is already selected and the user selects the second, handleChange1() does not run. This presents a problem (for me anyway) in that there is no event where I can catch this de-selection.
What I would like is a workaround for the onChange event for the checkbox group value or alternatively, an onCheck event that detects not only when a radio button is checked but also when it is unchecked.
I'm sure some of you have run into this problem before. What are some workarounds (or ideally what is the right way to handle this)? I just want to catch the change event, access the previously checked radio as well as the newly checked radio.
P.S.
onClick seems like a better (cross-browser) event to indicate when a radio button is checked but it still does not solve the unchecked problem.
I suppose it makes sense why onChange for a checkbox type does work in a case like this since it changes the value that it submits when you check or un-check it. I wish the radio buttons behaved more like a SELECT element's onChange but what can you do...
var rad = document.myForm.myRadios;
var prev = null;
for (var i = 0; i < rad.length; i++) {
rad[i].addEventListener('change', function() {
(prev) ? console.log(prev.value): null;
if (this !== prev) {
prev = this;
}
console.log(this.value)
});
}
<form name="myForm">
<input type="radio" name="myRadios" value="1" />
<input type="radio" name="myRadios" value="2" />
</form>
Here's a JSFiddle demo: https://jsfiddle.net/crp6em1z/
I would make two changes:
<input type="radio" name="myRadios" onclick="handleClick(this);" value="1" />
<input type="radio" name="myRadios" onclick="handleClick(this);" value="2" />
Use the onclick handler instead of onchange - you're changing the "checked state" of the radio input, not the value, so there's not a change event happening.
Use a single function, and pass this as a parameter, that will make it easy to check which value is currently selected.
ETA: Along with your handleClick() function, you can track the original / old value of the radio in a page-scoped variable. That is:
var currentValue = 0;
function handleClick(myRadio) {
alert('Old value: ' + currentValue);
alert('New value: ' + myRadio.value);
currentValue = myRadio.value;
}
var currentValue = 0;
function handleClick(myRadio) {
alert('Old value: ' + currentValue);
alert('New value: ' + myRadio.value);
currentValue = myRadio.value;
}
<input type="radio" name="myRadios" onclick="handleClick(this);" value="1" />
<input type="radio" name="myRadios" onclick="handleClick(this);" value="2" />
As you can see from this example: http://jsfiddle.net/UTwGS/
HTML:
<label><input type="radio" value="1" name="my-radio">Radio One</label>
<label><input type="radio" value="2" name="my-radio">Radio One</label>
jQuery:
$('input[type="radio"]').on('click change', function(e) {
console.log(e.type);
});
both the click and change events are fired when selecting a radio button option (at least in some browsers).
I should also point out that in my example the click event is still fired when you use tab and the keyboard to select an option.
So, my point is that even though the change event is fired is some browsers, the click event should supply the coverage you need.
You can add the following JS script
<script>
function myfunction(event) {
alert('Checked radio with ID = ' + event.target.id);
}
document.querySelectorAll("input[name='myRadios']").forEach((input) => {
input.addEventListener('change', myfunction);
});
</script>
What about using the change event of Jquery?
$(function() {
$('input:radio[name="myRadios"]').change(function() {
if ($(this).val() == '1') {
alert("You selected the first option and deselected the second one");
} else {
alert("You selected the second option and deselected the first one");
}
});
});
jsfiddle: http://jsfiddle.net/f8233x20/
Easiest and power full way
read only radio inputs using getAttribute
document.addEventListener('input',(e)=>{
if(e.target.getAttribute('name')=="myRadios")
console.log(e.target.value)
})
<input type="radio" name="myRadios" value="1" /> 1
<input type="radio" name="myRadios" value="2" /> 2
Store the previous checked radio in a variable:
http://jsfiddle.net/dsbonev/C5S4B/
HTML
<input type="radio" name="myRadios" value="1" /> 1
<input type="radio" name="myRadios" value="2" /> 2
<input type="radio" name="myRadios" value="3" /> 3
<input type="radio" name="myRadios" value="4" /> 4
<input type="radio" name="myRadios" value="5" /> 5
JS
var changeHandler = (function initChangeHandler() {
var previousCheckedRadio = null;
var result = function (event) {
var currentCheckedRadio = event.target;
var name = currentCheckedRadio.name;
if (name !== 'myRadios') return;
//using radio elements previousCheckedRadio and currentCheckedRadio
//storing radio element for using in future 'change' event handler
previousCheckedRadio = currentCheckedRadio;
};
return result;
})();
document.addEventListener('change', changeHandler, false);
JS EXAMPLE CODE
var changeHandler = (function initChangeHandler() {
var previousCheckedRadio = null;
function logInfo(info) {
if (!console || !console.log) return;
console.log(info);
}
function logPrevious(element) {
if (!element) return;
var message = element.value + ' was unchecked';
logInfo(message);
}
function logCurrent(element) {
if (!element) return;
var message = element.value + ' is checked';
logInfo(message);
}
var result = function (event) {
var currentCheckedRadio = event.target;
var name = currentCheckedRadio.name;
if (name !== 'myRadios') return;
logPrevious(previousCheckedRadio);
logCurrent(currentCheckedRadio);
previousCheckedRadio = currentCheckedRadio;
};
return result;
})();
document.addEventListener('change', changeHandler, false);
I don't think there is any way other then storing the previous state.
Here is the solution with jQuery
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
var lastSelected;
$(function () {
//if you have any radio selected by default
lastSelected = $('[name="myRadios"]:checked').val();
});
$(document).on('click', '[name="myRadios"]', function () {
if (lastSelected != $(this).val() && typeof lastSelected != "undefined") {
alert("radio box with value " + $('[name="myRadios"][value="' + lastSelected + '"]').val() + " was deselected");
}
lastSelected = $(this).val();
});
</script>
<input type="radio" name="myRadios" value="1" />
<input type="radio" name="myRadios" value="2" />
<input type="radio" name="myRadios" value="3" />
<input type="radio" name="myRadios" value="4" />
<input type="radio" name="myRadios" value="5" />
After thinking about it a bit more, I decided to get rid of the variable and add/remove class. Here is what I got: http://jsfiddle.net/BeQh3/2/
I realize this is an old issue, but this snippet of code works for me. Perhaps someone in the future will find it useful:
<h2>Testing radio functionality</h2>
<script type="text/javascript">var radioArray=[null];</script>
<input name="juju" value="button1" type="radio" onclick="radioChange('juju','button1',radioArray);" />Button 1
<input name="juju" value="button2" type="radio" onclick="radioChange('juju','button2',radioArray);" />Button 2
<input name="juju" value="button3" type="radio" onclick="radioChange('juju','button3',radioArray);" />Button 3
<br />
<script type="text/javascript">
function radioChange(radioSet,radioButton,radioArray)
{
//if(radioArray instanceof Array) {alert('Array Passed');}
var oldButton=radioArray[0];
if(radioArray[0] == null)
{
alert('Old button was not defined');
radioArray[0]=radioButton;
}
else
{
alert('Old button was set to ' + oldButton);
radioArray[0]=radioButton;
}
alert('New button is set to ' + radioArray[0]);
}
</script>
As you can see here:
http://www.w3schools.com/jsref/event_onchange.asp
The onchange attribute is not supported for radio buttons.
The first SO question linked by you gives you the answer: Use the onclick event instead and check the radio button state inside of the function it triggers.
Yes there is no change event for currently selected radio button. But problem is when each radio button is taken as a separate element. Instead a radio group should be considered a single element like select. So change event is triggered for that group. If it is a select element we never worry about each option in it, but take only the selected option. We store the current value in a variable which will become the previous value, when a new option is selected. Similarly you have to use a separate variable for storing value of checked radio button.
If you want to identify the previous radio button, you have to loop on mousedown event.
var radios = document.getElementsByName("myRadios");
var val;
for(var i = 0; i < radios.length; i++){
if(radios[i].checked){
val = radios[i].value;
}
}
see this : http://jsfiddle.net/diode/tywx6/2/
This is just off the top of my head, but you could do an onClick event for each radio button, give them all different IDs, and then make a for loop in the event to go through each radio button in the group and find which is was checked by looking at the 'checked' attribute. The id of the checked one would be stored as a variable, but you might want to use a temp variable first to make sure that the value of that variable changed, since the click event would fire whether or not a new radio button was checked.
<input type="radio" name="brd" onclick="javascript:brd();" value="IN">
<input type="radio" name="brd" onclick="javascript:brd();" value="EX">`
<script type="text/javascript">
function brd() {alert($('[name="brd"]:checked').val());}
</script>
If you want to avoid inline script, you can simply listen for a click event on the radio. This can be achieved with plain Javascript by listening to a click event on
for (var radioCounter = 0 ; radioCounter < document.getElementsByName('myRadios').length; radioCounter++) {
document.getElementsByName('myRadios')[radioCounter].onclick = function() {
//VALUE OF THE CLICKED RADIO ELEMENT
console.log('this : ',this.value);
}
}
this works for me
<input ID="TIPO_INST-0" Name="TIPO_INST" Type="Radio" value="UNAM" onchange="convenio_unam();">UNAM
<script type="text/javascript">
function convenio_unam(){
if(this.document.getElementById('TIPO_INST-0').checked){
$("#convenio_unam").hide();
}else{
$("#convenio_unam").show();
}
}
</script>
This is the easiest and most efficient function to use just add as many buttons as you want to the checked = false and make the onclick event of each radio buttoncall this function. Designate a unique number to each radio
button
function AdjustRadios(which)
{
if(which==1)
document.getElementById("rdpPrivate").checked=false;
else if(which==2)
document.getElementById("rdbPublic").checked=false;
}
For some reason, the best answer does not works for me.
I improved best answer by use
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
Original best answer use:
var rad = document.myForm.myRadios;
The others keep the same, finally it works for me.
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
console.log('overlayType_radio', overlayType_radio)
var prev = null;
for (var i = 0; i < overlayType_radio.length; i++) {
overlayType_radio[i].addEventListener('change', function() {
(prev) ? console.log('radio prev value',prev.value): null;
if (this !== prev) {
prev = this;
}
console.log('radio now value ', this.value)
});
}
html is:
<div id='overlay-div'>
<fieldset>
<legend> Overlay Type </legend>
<p>
<label>
<input class='with-gap' id='overlayType_image' value='overlayType_image' name='radio_overlaytype' type='radio' checked/>
<span>Image</span>
</label>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_tiled_image' value='overlayType_tiled_image' name='radio_overlaytype' type='radio' disabled/>
<span> Tiled Image</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_coordinated_tile' value='overlayType_coordinated_tile' name='radio_overlaytype' type='radio' disabled/>
<span> Coordinated Tile</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_none' value='overlayType_none' name='radio_overlaytype' type='radio'/>
<span> None </span>
</p>
</fieldset>
</div>
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
console.log('overlayType_radio', overlayType_radio)
var prev = null;
for (var i = 0; i < overlayType_radio.length; i++) {
overlayType_radio[i].addEventListener('change', function() {
(prev) ? console.log('radio prev value',prev.value): null;
if (this !== prev) {
prev = this;
}
console.log('radio now value ', this.value)
});
}
<div id='overlay-div'>
<fieldset>
<legend> Overlay Type </legend>
<p>
<label>
<input class='with-gap' id='overlayType_image' value='overlayType_image' name='radio_overlaytype' type='radio' checked/>
<span>Image</span>
</label>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_tiled_image' value='overlayType_tiled_image' name='radio_overlaytype' type='radio' />
<span> Tiled Image</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_coordinated_tile' value='overlayType_coordinated_tile' name='radio_overlaytype' type='radio' />
<span> Coordinated Tile</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_none' value='overlayType_none' name='radio_overlaytype' type='radio'/>
<span> None </span>
</p>
</fieldset>
</div>
jsfiddle click here
https://jsfiddle.net/hoogw/jetmkn02/1/
Tl;dr
'focusout' is dispatched before the 'change' event - example:
const radioName = 'radio';
// Add radios
document.body.innerHTML = `
<style>
input + label {
margin-left: 1rem;
}
</style>
<form action="#" name="example-form">
<fieldset>
${Array(5).fill(null, 0, 5).map((_, i) => {
const offsetId = i + 1;
const id = `radio-${offsetId}`;
return `<label for="${id}">Radio ${offsetId}</label>
<input type="radio" name="${radioName}" id="${id}" value="${offsetId}" />`;
}).join('\n')}
</fieldset>
</form>
`;
const {log} = console,
form = document.forms['example-form'];
form.addEventListener('submit', e => e.preventDefault());
form.addEventListener('change', e => {
const {target} = e;
if (target.matches(`[type="radio"][name="${radioName}"]`)) {
log(`[${e.type}]: "${target.id}" selected; Value: ${target.value}`);
}
});
form.addEventListener('focusout', e => {
const {target} = e,
soonToBePrevValue = target && target.form ?
target.form.elements[radioName].value : null;
if (!target.matches(`[type="radio"][name="${radioName}"]`) || !soonToBePrevValue) {
return;
}
// value, for '[name="radio"]', contained in form, will change after 'focusout' event
// has completed it's bubbling stage.
log(`[${e.type}]: previously selected radio value: ` +
`${soonToBePrevValue}`);
// log("Soon to be \"previous\" radio: ", target);
});
jsfiddle
<script>
function radioClick(radio){
alert()
}
</script>
<label>Cash on delivery</label>
<input type="radio" onclick="radioClick('A')" name="payment_method" class="form-group">
<br>
<label>Debit/Credit card, GPay, Paytm etc..</label>
<input type="radio" onclick="radioClick('B')" name="payment_method" class="form-group">
I'm looking for a generalized solution for this.
Consider 2 radio type inputs with the same name. When submitted, the one that is checked determines the value that gets sent with the form:
<input type="radio" name="myRadios" onchange="handleChange1();" value="1" />
<input type="radio" name="myRadios" onchange="handleChange2();" value="2" />
The change event does not fire when a radio button is de-selected. So if the radio with value="1" is already selected and the user selects the second, handleChange1() does not run. This presents a problem (for me anyway) in that there is no event where I can catch this de-selection.
What I would like is a workaround for the onChange event for the checkbox group value or alternatively, an onCheck event that detects not only when a radio button is checked but also when it is unchecked.
I'm sure some of you have run into this problem before. What are some workarounds (or ideally what is the right way to handle this)? I just want to catch the change event, access the previously checked radio as well as the newly checked radio.
P.S.
onClick seems like a better (cross-browser) event to indicate when a radio button is checked but it still does not solve the unchecked problem.
I suppose it makes sense why onChange for a checkbox type does work in a case like this since it changes the value that it submits when you check or un-check it. I wish the radio buttons behaved more like a SELECT element's onChange but what can you do...
var rad = document.myForm.myRadios;
var prev = null;
for (var i = 0; i < rad.length; i++) {
rad[i].addEventListener('change', function() {
(prev) ? console.log(prev.value): null;
if (this !== prev) {
prev = this;
}
console.log(this.value)
});
}
<form name="myForm">
<input type="radio" name="myRadios" value="1" />
<input type="radio" name="myRadios" value="2" />
</form>
Here's a JSFiddle demo: https://jsfiddle.net/crp6em1z/
I would make two changes:
<input type="radio" name="myRadios" onclick="handleClick(this);" value="1" />
<input type="radio" name="myRadios" onclick="handleClick(this);" value="2" />
Use the onclick handler instead of onchange - you're changing the "checked state" of the radio input, not the value, so there's not a change event happening.
Use a single function, and pass this as a parameter, that will make it easy to check which value is currently selected.
ETA: Along with your handleClick() function, you can track the original / old value of the radio in a page-scoped variable. That is:
var currentValue = 0;
function handleClick(myRadio) {
alert('Old value: ' + currentValue);
alert('New value: ' + myRadio.value);
currentValue = myRadio.value;
}
var currentValue = 0;
function handleClick(myRadio) {
alert('Old value: ' + currentValue);
alert('New value: ' + myRadio.value);
currentValue = myRadio.value;
}
<input type="radio" name="myRadios" onclick="handleClick(this);" value="1" />
<input type="radio" name="myRadios" onclick="handleClick(this);" value="2" />
As you can see from this example: http://jsfiddle.net/UTwGS/
HTML:
<label><input type="radio" value="1" name="my-radio">Radio One</label>
<label><input type="radio" value="2" name="my-radio">Radio One</label>
jQuery:
$('input[type="radio"]').on('click change', function(e) {
console.log(e.type);
});
both the click and change events are fired when selecting a radio button option (at least in some browsers).
I should also point out that in my example the click event is still fired when you use tab and the keyboard to select an option.
So, my point is that even though the change event is fired is some browsers, the click event should supply the coverage you need.
You can add the following JS script
<script>
function myfunction(event) {
alert('Checked radio with ID = ' + event.target.id);
}
document.querySelectorAll("input[name='myRadios']").forEach((input) => {
input.addEventListener('change', myfunction);
});
</script>
What about using the change event of Jquery?
$(function() {
$('input:radio[name="myRadios"]').change(function() {
if ($(this).val() == '1') {
alert("You selected the first option and deselected the second one");
} else {
alert("You selected the second option and deselected the first one");
}
});
});
jsfiddle: http://jsfiddle.net/f8233x20/
Easiest and power full way
read only radio inputs using getAttribute
document.addEventListener('input',(e)=>{
if(e.target.getAttribute('name')=="myRadios")
console.log(e.target.value)
})
<input type="radio" name="myRadios" value="1" /> 1
<input type="radio" name="myRadios" value="2" /> 2
Store the previous checked radio in a variable:
http://jsfiddle.net/dsbonev/C5S4B/
HTML
<input type="radio" name="myRadios" value="1" /> 1
<input type="radio" name="myRadios" value="2" /> 2
<input type="radio" name="myRadios" value="3" /> 3
<input type="radio" name="myRadios" value="4" /> 4
<input type="radio" name="myRadios" value="5" /> 5
JS
var changeHandler = (function initChangeHandler() {
var previousCheckedRadio = null;
var result = function (event) {
var currentCheckedRadio = event.target;
var name = currentCheckedRadio.name;
if (name !== 'myRadios') return;
//using radio elements previousCheckedRadio and currentCheckedRadio
//storing radio element for using in future 'change' event handler
previousCheckedRadio = currentCheckedRadio;
};
return result;
})();
document.addEventListener('change', changeHandler, false);
JS EXAMPLE CODE
var changeHandler = (function initChangeHandler() {
var previousCheckedRadio = null;
function logInfo(info) {
if (!console || !console.log) return;
console.log(info);
}
function logPrevious(element) {
if (!element) return;
var message = element.value + ' was unchecked';
logInfo(message);
}
function logCurrent(element) {
if (!element) return;
var message = element.value + ' is checked';
logInfo(message);
}
var result = function (event) {
var currentCheckedRadio = event.target;
var name = currentCheckedRadio.name;
if (name !== 'myRadios') return;
logPrevious(previousCheckedRadio);
logCurrent(currentCheckedRadio);
previousCheckedRadio = currentCheckedRadio;
};
return result;
})();
document.addEventListener('change', changeHandler, false);
I don't think there is any way other then storing the previous state.
Here is the solution with jQuery
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
var lastSelected;
$(function () {
//if you have any radio selected by default
lastSelected = $('[name="myRadios"]:checked').val();
});
$(document).on('click', '[name="myRadios"]', function () {
if (lastSelected != $(this).val() && typeof lastSelected != "undefined") {
alert("radio box with value " + $('[name="myRadios"][value="' + lastSelected + '"]').val() + " was deselected");
}
lastSelected = $(this).val();
});
</script>
<input type="radio" name="myRadios" value="1" />
<input type="radio" name="myRadios" value="2" />
<input type="radio" name="myRadios" value="3" />
<input type="radio" name="myRadios" value="4" />
<input type="radio" name="myRadios" value="5" />
After thinking about it a bit more, I decided to get rid of the variable and add/remove class. Here is what I got: http://jsfiddle.net/BeQh3/2/
I realize this is an old issue, but this snippet of code works for me. Perhaps someone in the future will find it useful:
<h2>Testing radio functionality</h2>
<script type="text/javascript">var radioArray=[null];</script>
<input name="juju" value="button1" type="radio" onclick="radioChange('juju','button1',radioArray);" />Button 1
<input name="juju" value="button2" type="radio" onclick="radioChange('juju','button2',radioArray);" />Button 2
<input name="juju" value="button3" type="radio" onclick="radioChange('juju','button3',radioArray);" />Button 3
<br />
<script type="text/javascript">
function radioChange(radioSet,radioButton,radioArray)
{
//if(radioArray instanceof Array) {alert('Array Passed');}
var oldButton=radioArray[0];
if(radioArray[0] == null)
{
alert('Old button was not defined');
radioArray[0]=radioButton;
}
else
{
alert('Old button was set to ' + oldButton);
radioArray[0]=radioButton;
}
alert('New button is set to ' + radioArray[0]);
}
</script>
As you can see here:
http://www.w3schools.com/jsref/event_onchange.asp
The onchange attribute is not supported for radio buttons.
The first SO question linked by you gives you the answer: Use the onclick event instead and check the radio button state inside of the function it triggers.
Yes there is no change event for currently selected radio button. But problem is when each radio button is taken as a separate element. Instead a radio group should be considered a single element like select. So change event is triggered for that group. If it is a select element we never worry about each option in it, but take only the selected option. We store the current value in a variable which will become the previous value, when a new option is selected. Similarly you have to use a separate variable for storing value of checked radio button.
If you want to identify the previous radio button, you have to loop on mousedown event.
var radios = document.getElementsByName("myRadios");
var val;
for(var i = 0; i < radios.length; i++){
if(radios[i].checked){
val = radios[i].value;
}
}
see this : http://jsfiddle.net/diode/tywx6/2/
This is just off the top of my head, but you could do an onClick event for each radio button, give them all different IDs, and then make a for loop in the event to go through each radio button in the group and find which is was checked by looking at the 'checked' attribute. The id of the checked one would be stored as a variable, but you might want to use a temp variable first to make sure that the value of that variable changed, since the click event would fire whether or not a new radio button was checked.
<input type="radio" name="brd" onclick="javascript:brd();" value="IN">
<input type="radio" name="brd" onclick="javascript:brd();" value="EX">`
<script type="text/javascript">
function brd() {alert($('[name="brd"]:checked').val());}
</script>
If you want to avoid inline script, you can simply listen for a click event on the radio. This can be achieved with plain Javascript by listening to a click event on
for (var radioCounter = 0 ; radioCounter < document.getElementsByName('myRadios').length; radioCounter++) {
document.getElementsByName('myRadios')[radioCounter].onclick = function() {
//VALUE OF THE CLICKED RADIO ELEMENT
console.log('this : ',this.value);
}
}
this works for me
<input ID="TIPO_INST-0" Name="TIPO_INST" Type="Radio" value="UNAM" onchange="convenio_unam();">UNAM
<script type="text/javascript">
function convenio_unam(){
if(this.document.getElementById('TIPO_INST-0').checked){
$("#convenio_unam").hide();
}else{
$("#convenio_unam").show();
}
}
</script>
This is the easiest and most efficient function to use just add as many buttons as you want to the checked = false and make the onclick event of each radio buttoncall this function. Designate a unique number to each radio
button
function AdjustRadios(which)
{
if(which==1)
document.getElementById("rdpPrivate").checked=false;
else if(which==2)
document.getElementById("rdbPublic").checked=false;
}
For some reason, the best answer does not works for me.
I improved best answer by use
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
Original best answer use:
var rad = document.myForm.myRadios;
The others keep the same, finally it works for me.
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
console.log('overlayType_radio', overlayType_radio)
var prev = null;
for (var i = 0; i < overlayType_radio.length; i++) {
overlayType_radio[i].addEventListener('change', function() {
(prev) ? console.log('radio prev value',prev.value): null;
if (this !== prev) {
prev = this;
}
console.log('radio now value ', this.value)
});
}
html is:
<div id='overlay-div'>
<fieldset>
<legend> Overlay Type </legend>
<p>
<label>
<input class='with-gap' id='overlayType_image' value='overlayType_image' name='radio_overlaytype' type='radio' checked/>
<span>Image</span>
</label>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_tiled_image' value='overlayType_tiled_image' name='radio_overlaytype' type='radio' disabled/>
<span> Tiled Image</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_coordinated_tile' value='overlayType_coordinated_tile' name='radio_overlaytype' type='radio' disabled/>
<span> Coordinated Tile</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_none' value='overlayType_none' name='radio_overlaytype' type='radio'/>
<span> None </span>
</p>
</fieldset>
</div>
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
console.log('overlayType_radio', overlayType_radio)
var prev = null;
for (var i = 0; i < overlayType_radio.length; i++) {
overlayType_radio[i].addEventListener('change', function() {
(prev) ? console.log('radio prev value',prev.value): null;
if (this !== prev) {
prev = this;
}
console.log('radio now value ', this.value)
});
}
<div id='overlay-div'>
<fieldset>
<legend> Overlay Type </legend>
<p>
<label>
<input class='with-gap' id='overlayType_image' value='overlayType_image' name='radio_overlaytype' type='radio' checked/>
<span>Image</span>
</label>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_tiled_image' value='overlayType_tiled_image' name='radio_overlaytype' type='radio' />
<span> Tiled Image</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_coordinated_tile' value='overlayType_coordinated_tile' name='radio_overlaytype' type='radio' />
<span> Coordinated Tile</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_none' value='overlayType_none' name='radio_overlaytype' type='radio'/>
<span> None </span>
</p>
</fieldset>
</div>
jsfiddle click here
https://jsfiddle.net/hoogw/jetmkn02/1/
Tl;dr
'focusout' is dispatched before the 'change' event - example:
const radioName = 'radio';
// Add radios
document.body.innerHTML = `
<style>
input + label {
margin-left: 1rem;
}
</style>
<form action="#" name="example-form">
<fieldset>
${Array(5).fill(null, 0, 5).map((_, i) => {
const offsetId = i + 1;
const id = `radio-${offsetId}`;
return `<label for="${id}">Radio ${offsetId}</label>
<input type="radio" name="${radioName}" id="${id}" value="${offsetId}" />`;
}).join('\n')}
</fieldset>
</form>
`;
const {log} = console,
form = document.forms['example-form'];
form.addEventListener('submit', e => e.preventDefault());
form.addEventListener('change', e => {
const {target} = e;
if (target.matches(`[type="radio"][name="${radioName}"]`)) {
log(`[${e.type}]: "${target.id}" selected; Value: ${target.value}`);
}
});
form.addEventListener('focusout', e => {
const {target} = e,
soonToBePrevValue = target && target.form ?
target.form.elements[radioName].value : null;
if (!target.matches(`[type="radio"][name="${radioName}"]`) || !soonToBePrevValue) {
return;
}
// value, for '[name="radio"]', contained in form, will change after 'focusout' event
// has completed it's bubbling stage.
log(`[${e.type}]: previously selected radio value: ` +
`${soonToBePrevValue}`);
// log("Soon to be \"previous\" radio: ", target);
});
jsfiddle
<script>
function radioClick(radio){
alert()
}
</script>
<label>Cash on delivery</label>
<input type="radio" onclick="radioClick('A')" name="payment_method" class="form-group">
<br>
<label>Debit/Credit card, GPay, Paytm etc..</label>
<input type="radio" onclick="radioClick('B')" name="payment_method" class="form-group">
Is there an easy way to attach a "deselect" event on a radio button? It seems that the change event only fires when the button is selected.
HTML
<input type="radio" id="one" name="a" />
<input type="radio" id="two" name="a" />
JavaScript
$('#one').change(function() {
if(this.checked) {
// do something when selected
} else { // THIS WILL NEVER HAPPEN
// do something when deselected
}
});
jsFiddle
Why don't you simply create a custom event like, lets say, deselect and let it trigger on all the members of the clicked radio group except the element itself that was clicked? Its way easier to make use of the event handling API that jQuery provides that way.
HTML
<!-- First group of radio buttons -->
<label for="btn_red">Red:</label><input id="btn_red" type="radio" name="radio_btn" />
<label for="btn_blue">Blue:</label><input id="btn_blue" type="radio" name="radio_btn" />
<label for="btn_yellow">Yellow:</label><input id="btn_yellow" type="radio" name="radio_btn" />
<label for="btn_pink">Pink:</label><input id="btn_pink" type="radio" name="radio_btn" />
<hr />
<!-- Second group of radio buttons -->
<label for="btn_red_group2">Red 2:</label><input id="btn_red_group2" type="radio" name="radio_btn_group2" />
<label for="btn_blue_group2">Blue 2:</label><input id="btn_blue_group2" type="radio" name="radio_btn_group2" />
<label for="btn_yellow_group2">Yellow 2:</label><input id="btn_yellow_group2" type="radio" name="radio_btn_group2" />
<label for="btn_pink_group2">Pink 2:</label><input id="btn_pink_group2" type="radio" name="radio_btn_group2" />
jQuery
// Attaching click event handlers to all radio buttons...
$('input[type="radio"]').bind('click', function(){
// Processing only those that match the name attribute of the currently clicked button...
$('input[name="' + $(this).attr('name') + '"]').not($(this)).trigger('deselect'); // Every member of the current radio group except the clicked one...
});
$('input[type="radio"]').bind('deselect', function(){
console.log($(this));
})
Deselection events will trigger only among members of the same radio group (elements that have the same name attribute).
jsFiddle solution
EDIT: In order to account for all possible placements of the attached label tag (wrapping the radio element or being attached through an id selector) it is perhaps better to use onchange event to trigger the handlers. Thanks to Faust for pointing that out.
$('input[type="radio"]').on('change', function(){
// ...
}
You can create a custom "deselect" event relatively painlessly, but as you've already discovered the standard change event is only triggered on the newly checked radio button, not on the previously checked one that has just been unchecked.
If you'd like to be able to say something like:
$("#one").on("deselect", function() {
alert("Radio button one was just deselected");
});
Then run something like the following function from your document ready handler (or put the code directly in your document ready handler):
function setupDeselectEvent() {
var selected = {};
$('input[type="radio"]').on('click', function() {
if (this.name in selected && this != selected[this.name])
$(selected[this.name]).trigger("deselect");
selected[this.name] = this;
}).filter(':checked').each(function() {
selected[this.name] = this;
});
}
Working demo: http://jsfiddle.net/s7f9s/2
What this does is puts a click handler on all the radios on the page (this doesn't stop you adding your own click event handlers to the same radios) that will check if there was a previously selected radio in the same group (i.e., with the same name) and if so trigger a "deselect" event on that radio. Then it saves the just-clicked one as the current one. The "deselect" event is not triggered if you click the already checked radio or if there was no previously checked one. The .filter().each() bit at the end is to make note of which radios are already selected. (If you need to cater for more than one form on the same page having independent radio groups of the same name then update the function above accordingly.)
I found that the simplest way to do this without putting in a new framework to create a deselected event, is to make changing any radio button trigger an update event on all of the radio buttons in its group and then define the behavior you want in the update event.
The downside is that the code in the deselection branch will run even if the radio button was not previously selected. If all you're doing is simple showing, hiding, or disabling UI elements, that shouldn't matter much.
To use your example:
buttons = $('input[name="a"]');
buttons.change(function() {
buttons.trigger('update:groupA');
}).bind('update:groupA', function(){
if(this.checked) {
//Do your checked things
} else {
//Do your unchecked things. Gets called whenever any other button is selected, so don't toggle or do heavy computation in here.
}
});
I think you need to add the change function on the input level, rather than on each radio button.
Try this:
$("input[name='a']").change(function() {
$("input[name='a']").each(function(){
if(this.checked) {
// do something when selected
} else {
// do something when deselected
}
});
});
I think this could be happening because the focus event triggers before the change event so the next radio you click will be focused before the previous checked radio triggers a change event. Don't quote me on this though...
You could do it like this:
var isChecked = function(id) { alert(id + ': ' + $('#' + id).is(':checked')) }
$('input[name="a"]').change(function(){ isChecked('one') })
Demo: http://jsfiddle.net/elclanrs/cD5ww/
You can trigger the 'change' event yourself. It's a bit tricky to avoid radio buttons infinitely triggering 'change' event on each other, but it can be done like this:
$('input[type="radio"]').each(function() {
var name = $(this).attr('name');
var that = this;
$('input[name="'+name+'"][type="radio"]').not(that)
.on('change', function(e, alreadyTriggered) {
if(!alreadyTriggered || alreadyTriggered.indexOf(this) == -1) {
if(!alreadyTriggered) {
alreadyTriggered = [that];
}
alreadyTriggered.push(this);
$(that).trigger('change', [alreadyTriggered]);
}
});
});
Here's the demo of the above code at work.
I found a workaround for my specific case that might help. This works when the "deselect" event can be applied to all radio buttons that aren't selected.
I wanted to:
add a class to the element when the radiobutton was selected, and
remove that class when the button was "deselected".
I happened to find this question, because I had the same problem:
$('input:radio').on('change', function() {
if( $(this).is(':checked') ) {
$(this).addClass('my-class-for-selected-buttons')
} else { // THIS WILL NEVER HAPPEN
$(this).removeClass('my-class-for-selected-buttons')
}
});
But, in my case, the solution was pretty much easier, because I can try to remove the class from all the radio-buttons pretty simply with jQuery, and then add the class to the selected one:
$('input:radio').on('change', function() {
$('input:radio').removeClass('my-class-for-selected-buttons') // Here!
if( $(this).is(':checked') ) {
$(this).addClass('my-class-for-selected-buttons')
}
});
With this simple tweak, I didn't need to find a way to trigger the "deselect" event.
So, if in your case you can apply the event to all the radio buttons that aren't selected, and not only to the one that's just been "deselected", you can use this measure!
Note: I'm using the most recent version of jquery: version 3.4.1. But this should work for older versions as well.
The major challenge here is that the change event is only triggered for the radio button that was checked. The code below confirms this.
$("input[name^='account']").change(function() {
console.log($(this).prop('id') + " was checked");
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<form action='#'>
<input id='john' type='radio' name='account[]' value=''><label for='john'>John</label><br>
<input id='jane' type='radio' name='account[]' value=''><label for='jane'>Jane</label><br>
<input id='jeff' type='radio' name='account[]' value=''><label for='jeff'>Jeff</label><br>
<input id='jude' type='radio' name='account[]' value=''><label for='jude'>Jude</label><br>
<input type='text' name='amount' value=''><br>
<input type='submit' value='submit'>
</form>
My Solution: Handle everything inside the change event handler in 3 simple steps:
handle the changes for the currently checked radio button.
attach custom event and handler to all other radio buttons in the same group.
immediately trigger this custom event.
No need to play around with click events here. simple!
var radioBtns = $("input[name^='account']");
radioBtns.change(function() {
// 1. handle changes for the currently checked radio button.
console.log($(this).prop('id') + " was checked");
// 2. attach custom event and handler to all other radio buttons in the same group.
radioBtns.not(':checked').off('deselect').on('deselect', function() {
$(this).each(function(i, e) {
console.log($(e).prop('id') + " was not checked");
});
}).trigger('deselect'); // 3. immediately trigger this custom event.
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<form action='#'>
<input id='john' type='radio' name='account[]' value=''><label for='john'>John</label><br>
<input id='jane' type='radio' name='account[]' value=''><label for='jane'>Jane</label><br>
<input id='jeff' type='radio' name='account[]' value=''><label for='jeff'>Jeff</label><br>
<input id='jude' type='radio' name='account[]' value=''><label for='jude'>Jude</label><br>
<input type='text' name='amount' value=''><br>
<input type='submit' value='submit'>
</form>
I played a bit with the ids.
That is probably an inefficient solution to be fair.
<input type="radio" id="radio-1" name="a" value="initial 1"/>
<input type="radio" id="radio-2" name="a" value="initial 2"/>
let id;
$('input[id*="radio-"]').on('click', (function() {
if (this.id != id && this.checked) {
id = this.id;
this.checked = true;
console.log('selected');
} else if (this.id == id && this.checked) {
id = undefined;
this.checked = false;
console.log('deselected');
}
}));
JSFiddle
hows this for ya?
http://jsfiddle.net/WZND9/6/
$('input').change(function() {
if ($('#one').is(':checked')) {
alert('checked');
} else {
alert('not checked');
}
});
Is there an easy way to attach a "deselect" event on a radio button? It seems that the change event only fires when the button is selected.
HTML
<input type="radio" id="one" name="a" />
<input type="radio" id="two" name="a" />
JavaScript
$('#one').change(function() {
if(this.checked) {
// do something when selected
} else { // THIS WILL NEVER HAPPEN
// do something when deselected
}
});
jsFiddle
Why don't you simply create a custom event like, lets say, deselect and let it trigger on all the members of the clicked radio group except the element itself that was clicked? Its way easier to make use of the event handling API that jQuery provides that way.
HTML
<!-- First group of radio buttons -->
<label for="btn_red">Red:</label><input id="btn_red" type="radio" name="radio_btn" />
<label for="btn_blue">Blue:</label><input id="btn_blue" type="radio" name="radio_btn" />
<label for="btn_yellow">Yellow:</label><input id="btn_yellow" type="radio" name="radio_btn" />
<label for="btn_pink">Pink:</label><input id="btn_pink" type="radio" name="radio_btn" />
<hr />
<!-- Second group of radio buttons -->
<label for="btn_red_group2">Red 2:</label><input id="btn_red_group2" type="radio" name="radio_btn_group2" />
<label for="btn_blue_group2">Blue 2:</label><input id="btn_blue_group2" type="radio" name="radio_btn_group2" />
<label for="btn_yellow_group2">Yellow 2:</label><input id="btn_yellow_group2" type="radio" name="radio_btn_group2" />
<label for="btn_pink_group2">Pink 2:</label><input id="btn_pink_group2" type="radio" name="radio_btn_group2" />
jQuery
// Attaching click event handlers to all radio buttons...
$('input[type="radio"]').bind('click', function(){
// Processing only those that match the name attribute of the currently clicked button...
$('input[name="' + $(this).attr('name') + '"]').not($(this)).trigger('deselect'); // Every member of the current radio group except the clicked one...
});
$('input[type="radio"]').bind('deselect', function(){
console.log($(this));
})
Deselection events will trigger only among members of the same radio group (elements that have the same name attribute).
jsFiddle solution
EDIT: In order to account for all possible placements of the attached label tag (wrapping the radio element or being attached through an id selector) it is perhaps better to use onchange event to trigger the handlers. Thanks to Faust for pointing that out.
$('input[type="radio"]').on('change', function(){
// ...
}
You can create a custom "deselect" event relatively painlessly, but as you've already discovered the standard change event is only triggered on the newly checked radio button, not on the previously checked one that has just been unchecked.
If you'd like to be able to say something like:
$("#one").on("deselect", function() {
alert("Radio button one was just deselected");
});
Then run something like the following function from your document ready handler (or put the code directly in your document ready handler):
function setupDeselectEvent() {
var selected = {};
$('input[type="radio"]').on('click', function() {
if (this.name in selected && this != selected[this.name])
$(selected[this.name]).trigger("deselect");
selected[this.name] = this;
}).filter(':checked').each(function() {
selected[this.name] = this;
});
}
Working demo: http://jsfiddle.net/s7f9s/2
What this does is puts a click handler on all the radios on the page (this doesn't stop you adding your own click event handlers to the same radios) that will check if there was a previously selected radio in the same group (i.e., with the same name) and if so trigger a "deselect" event on that radio. Then it saves the just-clicked one as the current one. The "deselect" event is not triggered if you click the already checked radio or if there was no previously checked one. The .filter().each() bit at the end is to make note of which radios are already selected. (If you need to cater for more than one form on the same page having independent radio groups of the same name then update the function above accordingly.)
I found that the simplest way to do this without putting in a new framework to create a deselected event, is to make changing any radio button trigger an update event on all of the radio buttons in its group and then define the behavior you want in the update event.
The downside is that the code in the deselection branch will run even if the radio button was not previously selected. If all you're doing is simple showing, hiding, or disabling UI elements, that shouldn't matter much.
To use your example:
buttons = $('input[name="a"]');
buttons.change(function() {
buttons.trigger('update:groupA');
}).bind('update:groupA', function(){
if(this.checked) {
//Do your checked things
} else {
//Do your unchecked things. Gets called whenever any other button is selected, so don't toggle or do heavy computation in here.
}
});
I think you need to add the change function on the input level, rather than on each radio button.
Try this:
$("input[name='a']").change(function() {
$("input[name='a']").each(function(){
if(this.checked) {
// do something when selected
} else {
// do something when deselected
}
});
});
I think this could be happening because the focus event triggers before the change event so the next radio you click will be focused before the previous checked radio triggers a change event. Don't quote me on this though...
You could do it like this:
var isChecked = function(id) { alert(id + ': ' + $('#' + id).is(':checked')) }
$('input[name="a"]').change(function(){ isChecked('one') })
Demo: http://jsfiddle.net/elclanrs/cD5ww/
You can trigger the 'change' event yourself. It's a bit tricky to avoid radio buttons infinitely triggering 'change' event on each other, but it can be done like this:
$('input[type="radio"]').each(function() {
var name = $(this).attr('name');
var that = this;
$('input[name="'+name+'"][type="radio"]').not(that)
.on('change', function(e, alreadyTriggered) {
if(!alreadyTriggered || alreadyTriggered.indexOf(this) == -1) {
if(!alreadyTriggered) {
alreadyTriggered = [that];
}
alreadyTriggered.push(this);
$(that).trigger('change', [alreadyTriggered]);
}
});
});
Here's the demo of the above code at work.
I found a workaround for my specific case that might help. This works when the "deselect" event can be applied to all radio buttons that aren't selected.
I wanted to:
add a class to the element when the radiobutton was selected, and
remove that class when the button was "deselected".
I happened to find this question, because I had the same problem:
$('input:radio').on('change', function() {
if( $(this).is(':checked') ) {
$(this).addClass('my-class-for-selected-buttons')
} else { // THIS WILL NEVER HAPPEN
$(this).removeClass('my-class-for-selected-buttons')
}
});
But, in my case, the solution was pretty much easier, because I can try to remove the class from all the radio-buttons pretty simply with jQuery, and then add the class to the selected one:
$('input:radio').on('change', function() {
$('input:radio').removeClass('my-class-for-selected-buttons') // Here!
if( $(this).is(':checked') ) {
$(this).addClass('my-class-for-selected-buttons')
}
});
With this simple tweak, I didn't need to find a way to trigger the "deselect" event.
So, if in your case you can apply the event to all the radio buttons that aren't selected, and not only to the one that's just been "deselected", you can use this measure!
Note: I'm using the most recent version of jquery: version 3.4.1. But this should work for older versions as well.
The major challenge here is that the change event is only triggered for the radio button that was checked. The code below confirms this.
$("input[name^='account']").change(function() {
console.log($(this).prop('id') + " was checked");
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<form action='#'>
<input id='john' type='radio' name='account[]' value=''><label for='john'>John</label><br>
<input id='jane' type='radio' name='account[]' value=''><label for='jane'>Jane</label><br>
<input id='jeff' type='radio' name='account[]' value=''><label for='jeff'>Jeff</label><br>
<input id='jude' type='radio' name='account[]' value=''><label for='jude'>Jude</label><br>
<input type='text' name='amount' value=''><br>
<input type='submit' value='submit'>
</form>
My Solution: Handle everything inside the change event handler in 3 simple steps:
handle the changes for the currently checked radio button.
attach custom event and handler to all other radio buttons in the same group.
immediately trigger this custom event.
No need to play around with click events here. simple!
var radioBtns = $("input[name^='account']");
radioBtns.change(function() {
// 1. handle changes for the currently checked radio button.
console.log($(this).prop('id') + " was checked");
// 2. attach custom event and handler to all other radio buttons in the same group.
radioBtns.not(':checked').off('deselect').on('deselect', function() {
$(this).each(function(i, e) {
console.log($(e).prop('id') + " was not checked");
});
}).trigger('deselect'); // 3. immediately trigger this custom event.
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<form action='#'>
<input id='john' type='radio' name='account[]' value=''><label for='john'>John</label><br>
<input id='jane' type='radio' name='account[]' value=''><label for='jane'>Jane</label><br>
<input id='jeff' type='radio' name='account[]' value=''><label for='jeff'>Jeff</label><br>
<input id='jude' type='radio' name='account[]' value=''><label for='jude'>Jude</label><br>
<input type='text' name='amount' value=''><br>
<input type='submit' value='submit'>
</form>
I played a bit with the ids.
That is probably an inefficient solution to be fair.
<input type="radio" id="radio-1" name="a" value="initial 1"/>
<input type="radio" id="radio-2" name="a" value="initial 2"/>
let id;
$('input[id*="radio-"]').on('click', (function() {
if (this.id != id && this.checked) {
id = this.id;
this.checked = true;
console.log('selected');
} else if (this.id == id && this.checked) {
id = undefined;
this.checked = false;
console.log('deselected');
}
}));
JSFiddle
hows this for ya?
http://jsfiddle.net/WZND9/6/
$('input').change(function() {
if ($('#one').is(':checked')) {
alert('checked');
} else {
alert('not checked');
}
});
What method would be best to use to selectively set a single or multiple radio button(s) to a desired setting with JavaScript?
Very simple
radiobtn = document.getElementById("theid");
radiobtn.checked = true;
the form
<form name="teenageMutant">
<input value="aa" type="radio" name="ninjaTurtles"/>
<input value="bb" type="radio" name="ninjaTurtles"/>
<input value="cc" type="radio" name="ninjaTurtles" checked/>
</form>
value="cc" will be checked by default, if you remove the "checked" non of the boxes will be checked when the form is first loaded.
document.teenageMutant.ninjaTurtles[0].checked=true;
now value="aa" is checked. The other radio check boxes are unchecked.
see it in action: http://jsfiddle.net/yaArr/
You may do the same using the form id and the radio button id. Here is a form with id's.
<form id="lizardPeople" name="teenageMutant">
<input id="dinosaurs" value="aa" type="radio" name="ninjaTurtles"/>
<input id="elephant" value="bb" type="radio" name="ninjaTurtles"/>
<input id="dodoBird" value="cc" type="radio" name="ninjaTurtles" checked/>
</form>
value="cc" is checked by default.
document.forms["lizardPeople"]["dinosaurs"].checked=true;
now value="aa" with id="dinosaurs" is checked, just like before.
See it in action: http://jsfiddle.net/jPfXS/
Vanilla Javascript:
yourRadioButton.checked = true;
jQuery:
$('input[name=foo]').prop('checked', true);
or
$("input:checkbox").val() == "true"
You can also explicitly set value of radio button:
<form name="gendersForm">
<input type="radio" name="gender" value="M" /> Man
<input type="radio" name="gender" value="F" /> Woman
</form>
with the following script:
document.gendersForm.gender.value="F";
and corresponding radio button will be checked automatically.
Look at the example on JSFiddle.
/**
* setCheckedValueOfRadioButtonGroup
* #param {html input type=radio} vRadioObj
* #param {the radiobutton with this value will be checked} vValue
*/
function setCheckedValueOfRadioButtonGroup(vRadioObj, vValue) {
var radios = document.getElementsByName(vRadioObj.name);
for (var j = 0; j < radios.length; j++) {
if (radios[j].value == vValue) {
radios[j].checked = true;
break;
}
}
}
Try
myRadio.checked=true
<input type="radio" id="myRadio">My radio<br>
$("#id_of_radiobutton").prop("checked", true);
I am configuring a radio button within a document fragment and tried using radiobtn.checked = true;.
That didn't work so I instead went with this solution:
radiobtn.setAttribute("checked", "checked");
This sets checked using name to cycle through the elements and a value check to set the desired element to true. I kept it as simple as possible, its pretty easy to put it into a function or a loop, etc.
variable 'nameValue' is the radio elements name value
variable 'value' when matched sets the radio button
Array.from( document.querySelectorAll('[name="' + nameValue + '"]') ).forEach((element,index) =>
{
if (value === element.value) {
element.checked = true;
} else {
element.checked = false;
}
});