Validator.js - How to validate Alphanumeric password, in NodeJS? [duplicate] - javascript

This question already has answers here:
What do the brackets around the arguments mean when reading documentation for a method? [duplicate]
(3 answers)
Closed 4 years ago.
I am using criso validator.js, of user Input,
but it Eslint is showing error in syntax on this lines
if (!Validator.isAlphanumeric([(data.password,'en-US')])) {
console.log(" Not an alphanumeric");
}
how to properly check user's entered password is Alphanumeric,
I know we can do it using regex but I wanted to do it by using their provided syntax as isAlphanumeric(str [, locale]).
here is their documentation screenshot of code.

The square brackets in the isAlphanumeric(str [, locale]) notation are not related to JavaScript Array literals. Instead, they denote that when calling isAlphanumeric, the first argument str (in your case, data.password) is required, and the second argument locale is optional.
In your case, you do want to pass in a locale. Here is how that would look:
if (!Validator.isAlphanumeric(data.password, 'en-US')) {
console.log("Not an alphanumeric");
}
In technical documentation, square brackets ([]) generally denote that an argument is optional. Tecnhnically this is just a convention (and probably comes from Unix CLI Usage Messages), but in my experience is so widely used that always interpreting square brackets as denoting an optional argument is usually a safe assumption to make.

Related

Am confused about the functions of caret(^) in Regular expresssions. What does it mean here [^'] and what does it mean here [^01] [duplicate]

This question already has answers here:
Negating specific characters in regex
(4 answers)
Reference - What does this regex mean?
(1 answer)
Closed 20 days ago.
I have a regular expression:
/'([^']*)'/
Am finding it hard to understand how it works. The function of the caret here confuses me.
Unlike this regex:
/[^01]/ : i understand the caret here is an inverter which means the search should return true for any input input value that is different from 01.
let quotedText = /'([^']*)'/;
console.log(quotedText.exec("She said 'hello'"));
The console: ["'hello'", "hello"]
I do understand how the regexpression(quotedText) finds hello. What if the statement was longer with more words in quote. Like:
("She said 'hello' and he responded 'Hi', 'do you need my help'").
Would the exec method find all the words or sentences in quotes?.
I am also very confused about the function of caret^ here. Is it inverting?? Or is it showing where the exec methods starts looking from. Whats the difference between [^']* and [^01]. Does the function of caret change based on the method. Does caret(^) you see work differently when used with test method or exec method?. does Caret behave differently when in square brackets?

how to access json field with "-" e.g. 'data-id': 'smth' [duplicate]

This question already has answers here:
How can I access object properties containing special characters?
(2 answers)
How do I reference a JavaScript object property with a hyphen in it?
(11 answers)
Closed 3 months ago.
I am unable to retrieve a value from a json object when the string has a dash character:
{
"profile-id":1234, "user_id":6789
}
If I try to reference the parsed jsonObj.profile-id it returns ReferenceError: "id" is not defined but jsonObj.user_id will return 6789
I don't have a way to modify the values being returned by the external api call and trying to parse the returned string in order to remove dashes will ruin urls, etc., that are passed as well. Help?
jsonObj.profile-id is a subtraction expression (i.e. jsonObj.profile - id).
To access a key that contains characters that cannot appear in an identifier, use brackets:
jsonObj["profile-id"]
In addition to this answer, note that in Node.js if you access JSON with the array syntax [] all nested JSON keys should follow that syntax
This is the wrong way
json.first.second.third['comment']
and will will give you the 'undefined' error.
This is the correct way
json['first']['second']['third']['comment']
For ansible, and using hyphen, this worked for me:
- name: free-ud-ssd-space-in-percent
debug:
var: clusterInfo.json.content["free-ud-ssd-space-in-percent"]
For anyone trying to apply the accepted solution to HomeAssistant value templates, you must use single quotes if you are nesting in doubles:
value_template: "{{ value_json['internet-computer'].usd }}"
If you are in Linux, try using the following template to print JSON value which contains dashes '-'
jq '.["value-with-dash"]'
It worked for me.

How to get "#" from JSON [duplicate]

This question already has answers here:
How can I access object properties containing special characters?
(2 answers)
How do I reference a JavaScript object property with a hyphen in it?
(11 answers)
Closed 3 months ago.
I am unable to retrieve a value from a json object when the string has a dash character:
{
"profile-id":1234, "user_id":6789
}
If I try to reference the parsed jsonObj.profile-id it returns ReferenceError: "id" is not defined but jsonObj.user_id will return 6789
I don't have a way to modify the values being returned by the external api call and trying to parse the returned string in order to remove dashes will ruin urls, etc., that are passed as well. Help?
jsonObj.profile-id is a subtraction expression (i.e. jsonObj.profile - id).
To access a key that contains characters that cannot appear in an identifier, use brackets:
jsonObj["profile-id"]
In addition to this answer, note that in Node.js if you access JSON with the array syntax [] all nested JSON keys should follow that syntax
This is the wrong way
json.first.second.third['comment']
and will will give you the 'undefined' error.
This is the correct way
json['first']['second']['third']['comment']
For ansible, and using hyphen, this worked for me:
- name: free-ud-ssd-space-in-percent
debug:
var: clusterInfo.json.content["free-ud-ssd-space-in-percent"]
For anyone trying to apply the accepted solution to HomeAssistant value templates, you must use single quotes if you are nesting in doubles:
value_template: "{{ value_json['internet-computer'].usd }}"
If you are in Linux, try using the following template to print JSON value which contains dashes '-'
jq '.["value-with-dash"]'
It worked for me.

What is this kind of variable $variable [duplicate]

This question already has answers here:
Why would a JavaScript variable start with a dollar sign? [duplicate]
(16 answers)
Closed 9 years ago.
I found an JavaScript file in a website using a variable like this:
var $variable
What kind is it?
Thanks, DGM
$ is a regular symbol like any other legal one in JS and can be used as or part of a variable as well:
var $ = {};
It's also the identifier for the jQuery object. So that's why you'll normally see variables named that way that represent jQuery objects:
var $variable = $('#element');
There's also Underscore.js that uses the underscore symbol _ as its root object.
It is a completely normal variable, starting with the dollar sign - which has no special meaning in JavaScript. It is a valid identifier just as like the underscore.
Sometimes, variable names prefixed with $ indicate that they contain an object wrapper created by one of the libraries that use $ as a constructor (for example jQuery); in contrast to a "plain value".
Javascript identifiers must start with a letter, an underscore or a dollar sign. So it is just a variable.
The intended use of the $ sign was for code generators, but some libraries use it for their own purposes.
It is perfectly valid to use $ in javascript variable names. Personally, I try to avoid this as it can be confused with jquery objects or php variables which may have crept into the javascript by mistake.

javascript replace query string value [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
add or update query string parameter
I am trying to replace the page number in the query string no matter what digit is to 1.
query string
index.php?list&page=2&sort=epub
javascript
window.location.href.replace(new RegExp("/page=.*?&/"), "page=1&")
Your code looks almost right; however:
you need to use either new RegExp or the special // regex syntax, but not both.
the replace method doesn't modify the string in-place, it merely returns a modified copy.
rather than .*?, I think it makes more sense to write \d+; more-precise regexes are generally less likely to go awry in cases you haven't thought of.
So, putting it together:
window.location.href = window.location.href.replace(/page=\d+/, "page=1");

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