I have a form calling submitting as follow
<form action="" method="post" id="member_form" onsubmit="return json_add('member','<?php echo ($admin->getnew_id()); ?>','0','slider_form');">
The problem I have is to get the $new_id before submitting the form from another function class.
this is not working
It keep running the funtion getnew_id() and generate the ID before it is saved
I need the process as follow.
Form Open
User complete form
onsubmit it need to do follow.
a. get new id = $new_d
b. then do
return json_add('member','','0','slider_form');">
I tried the following but dont work
$("form").submit(function(){
$.ajax({
url:"lastid.php",
type:'POST',
success:function(response) {
var $new_id = $.trim(response);
return json_add('member-add',$new_id,'0','slider_form');
alert("Submitted");
}
});
The problem seems to be in the third step.
What you should do is prevent the form from submitting and handle it in ajax.
you need onsubmit="return false" to prevent the form from submitting
Next, handle the submission in ajax
$("form#member_form").submit(function(){
$.ajax({
url: "lastid.php",
type: "POST",
data: { // this is where your form's datas are
"json": json_add('member-add',$new_id,'0','slider_form'),
"key": $("form#member_form").serialize()
},
success: function(response) {
var $new_id = $.trim(response);
alert("Submitted");
// alerting here makes more sense
}
// return json_add('member-add',$new_id,'0','slider_form');
// returning here do nothing!
});
You can read more about using ajax in jQuery here
Related
I have ajax request:
<script>
$("#abc_form_submit").click(function(e) {
e.preventDefault();
//........
$.ajax({
type: "POST",
url: url,
dataType: 'json',
data: $("#abc_form").serialize(), // serializes the form's elements.
success: function(data)
{
if(data.success == 'false') {
// show errors
} else {
// SUBMIT NORMAL WAY. $("#abc_from").submit() doesnt work.
}
}
});
return false; // avoid to execute the actual submit of the form.
});
</script>
And php
.....
return $this->paypalController(params, etc...) // which should redirect to other page
.....
How should i make that ajax request if success, submit form normal way, because now if I redirect (at PHP) its only return response, but i need that this ajax request would handle php code as normal form submit (if success)
Dont suggest "window.location" please.
I would add a class to the form to test if your ajax has already occured. if it has just use the normal click funciton.
Something like:
$('form .submit').click(function(e) {
if (!$('form').hasClass('validated'))
{
e.preventDefault();
//Your code here
$.post(url, values, function(data) {
if (success)
{
$('form').addClass('validated');
$('form .submit').click();
}
});
}
}
Why don't you use a result variable that you update after a succesful AJAX request?
<script>
$("#abc_form_submit").click(function(e) {
e.preventDefault();
// avoid to execute the actual submit of the form if not succeded
var result = false;
//........
$.ajax({
type: "POST",
url: url,
dataType: 'json',
async: false,
data: $("#abc_form").serialize(), // serializes the form's elements.
success: function(data)
{
if(data.success == 'false') {
// show errors
} else {
// SUBMIT NORMAL WAY. $("#abc_from").submit() doesnt work.
result = true;
}
}
});
return result;
});
</script>
I've had this issue before where I needed the form to submit to two places, one for tracking and another to the actual form action.
It only worked by submitting it programatically when you put the form.submit() behind a setTimeout. 500ms seems to have done the trick for me. I'm not sure why browsers have trouble submitting the form programatically when they are attempting to submit them traditionally, but this seems to sort it out.
setTimeout(function(){ $("#abc_from").submit(); }, 500);
One thing to keep in mind though once it submits, that's it for the page, it's gone. If you still want whatever processes are running on the page to run, you will need to set the target of the form to _blank so that it will submit in a new tab.
WHAT IM DOING
I'm using jquery to validate form before it is send to server.
I'm validating every input, and if any of them return false i call event.preventDefault() and show the errors.(if it returns true I do nothing...)
THE PROBLEM
It was working fine, the script always run before the form send itself, but now I'm validating email, using ajax - checking if email isnt already in db or if the domain exists... but when the ajax starts, the the form wont wait until its finished and sends itself before the ajax finish and the input validates.
SOME SOLUTIONS MAYBE
I could call event.preventDefault() and after the validation is completed and it returns true I could try to undo the preventDefault perhabs by unbind and then submit through jquery submit the form again.
Or perhabs I could do onsubmit="checkInputs();" and it should wait until it returns true or false...
Solution - Adapted from the accepted answer by user Mirage
function validate(){
$.ajax({
url: 'http://google.nl',
async: false,
type: "POST",
data: {test:'request'},
success: function(data){
console.log(data);
}
});
return data; // important
}
try to add
async: false
example:
$.ajax({
url: 'http://google.nl',
async: false,
type: "POST",
data: {test:'request'},
success: function(data){
console.log(data);
}
});
you want:
onsubmit="checkInputs(); return false;"
Then you would grab the form e.g:
var frm = document.getElementById("myfrm");
frm.submit();
You would place the above in the else condition of your validation logic. Hope this helps.
Your script flow should be something like this:
Bind onsubmit handler
Send vars to server with ajax
Check results
When validates: remove handler and post form
When false: show error messages and start over again.
And in code:
var handleValidationResponse = function(data) {
if(data.errors != 0) {
alert('Sorry my dear user, but you made a mistake');
return false;
}
// aight, so it's all fine
$('#myForm').off('submit').trigger('submit'); // unbind custom submit handler and post the form
};
$('#myForm').on('submit', function(e) {
e.preventDefault();
var $this = $(this);
var serializedFormData = $this.serializeArray();
$.post($this.attr('action'), serializedFormData, function(data) {
handleValidationResponse(data);
});
});
That should be it!
I have two files. One file is named index.php and another file is named process.php.
I have a form that submits to process.php in index.php:
<form class="form" action="process.php" method="POST" name="checkaddress" id="checkaddress">
<table>
<tr class="element">
<td><label>Address</label></td>
<td class="input"><input type="text" name="address" /></td>
</tr>
</table>
<input type="submit" id="submit" value="Submit"/>
</form>
<div class="done"></div>
I also have a process in process.php to echo some data based off of the input. How would I be able to use AJAX to submit the form without leaving the page?
Is it something like:
$.ajax({
url: "process.php",
type: "GET",
data: data,
cache: false,
success: function (html) {
$('.done').fadeIn('slow');
}
});
What page would I put the above code on if it was right?
Also, how do I change the above code to say what the process.php outputted? For example, if I echo "Hello" on process.php, how do I make it say it in the done div?
I have seen many responses regarding AJAX, but they all rely on data that is pre-made like APIs. I need to do a database query and fetch the data dependent on the address entered and print the data out.
You need to collect the data in the form so that you can submit them to the process page, and you need to run your code when submitting the form (and cancel the default form submission)
$('#checkaddress').on('submit', function(e){
// get formdata in a variable that is passed to the ajax request
var dataToPassToAjax = $(this).serialize();
$.ajax({
url: "process.php",
type: "GET",
data: dataToPassToAjax,
cache: false,
success: function (resultHtml) {
// add the returned data to the .done element
$('.done').html( resultHtml ).fadeIn('slow');
}
});
// cancel the default form submit
return false;
});
[update]
If you want to modify the data before submitting them, you will have to manually create the parameters to pass to the ajax
$('#checkaddress').on('submit', function(e){
// get formdata in a variable that is passed to the ajax request
var dataToPassToAjax = {};
var address = $('input[name="address"]', this).val();
// alter address here
address = 'something else';
dataToPassToAjax.address = address;
$.ajax({
url: "process.php",
type: "GET",
data: dataToPassToAjax,
cache: false,
success: function (resultHtml ) {
// add the returned data to the .done element
$('.done').html(resultHtml ).fadeIn('slow');
}
});
// cancel the default form submit
return false;
});
You could use the jQuery form plugin: http://jquery.malsup.com/form/
Let me know if you want example code.
i need help..why does my code not working?what is the proper way to get the data from a form.serialize? mines not working.. also am doing it right when passing it to php? also my php code looks awful and does not look like a good oop
html
<form action="" name="frm" id="frm" method="post">
<input type="text" name="title_val" value="" id="title_val"/>
post topic
</form>
<div id="test">
</div>
Javascript
$( document ).ready(function() {
$('#save').click(function() {
var form = $('#frm');
$.ajax({
url: 'topic.php',
type:'get',
data: form.serializeArray(),
success: function(response) {
$('#test').html(response);
}
});
});
});
Php
<?php
class test{
public function test2($val){
return $val;
}
}
$test = new test();
echo $test->test2($_POST['title_val']);
?>
OUTPUT
You're telling your ajax call to send the variables as GET variables, then trying to access them with the $_POST hyperglobal. Change GET to POST:
type:'post',
Also, it should be noted that you are binding your ajax call to the click on your submit button, so your form will still be posting. You should bind on the form's submit function instead and use preventDefault to prevent the form posting.
$('#frm').submit(function(e) {
e.preventDefault(); // stop form processing normally
$.ajax({
url: 'topic.php',
type: 'post',
data: $(this).serializeArray(),
success: function(response) {
$('#test').html(response);
}
});
});
I have a form that, when submitted, goes through the usual e.preventDefault() and sends an ajax request instead. However, if this ajax request returns a certain condition, I want the form to be submitted normally. How do I achieve this?
// Submit handler
$(".reserveer_form").submit(function(event){
event.preventDefault();
$.ajax({
url: $(this).attr("action"),
data: $(this).serialize(),
success: function(data) {
if($(".messagered",data).length > 0){
var errors = $(".messagered",data);
$(".gegevens").before(errors);
} else {
// SUBMIT THE FORM!
}
}
});
})
Invoke the native submit method on the form, so that it doesn't trigger the jQuery handler.
$.ajax({
context: this, // <-- set the context.
url: $(this).attr("action"),
data: $(this).serialize(),
success: function (data) {
if ($(".messagered", data).length > 0) {
var errors = $(".messagered", data);
$(".gegevens").before(errors);
} else {
this.submit(); // <-- submit the form
}
}
});
Since your comment says you change a form variable, you could start your submit handler by checking that same form variable. If it is changed, just return true. If not, continue with the current handler.
You can use the submit() method or forms:
$(".reserveer_form").submit(function(event){
event.preventDefault();
var form = this,
$form = $(form);
$.ajax({
url: $form.attr("action"),
data: $form.serialize(),
success: function(data) {
var errors = $(".messagered", data);
if (errors.length > 0){
$(".gegevens").before(errors);
} else {
form.submit();
}
}
});
})
However, this seems to be a strange ajax request. First, you send the form (serialized, via ajax) to the server, and when the response contains no errors you send it again? The server would process it twice (and act twice, depending on your form). Also, the user does not get a message that his input is already processed - he clicks "submit", and it always takes a time until it is visibly submitted (where he even could change some input).