I want to do something like this:
(1) click 'create' to invoke function 'createGroupForm', and then some html will be prepend to '#user-group-list'
(2) then I type the group name and click the 'ok' button, and the console will print the group name I typed before.
Now I have achieved step 1, but in step 2 function 'createGroup' can't be invoked. So how can I fix this problem?
html:
<body class="skin-blue sidebar-mini" ng-app="myApp">
<div class="wrapper" ng-controller="authorityController">
<div class="content-wrapper">
<section class="content-header">
<span class="breadcrumb">
<a ng-click="createGroupForm($event)"><i class="fa fa-upload"></i>create</a>
</span>
</section>
<section class="content" id="user-group-list">
</section>
</div>
</div>
</body>
js:
angular.module('myApp').controller("authorityController",['$compile','$scope','$http','$log','$cookies',function ($compile,$scope,$http,$log,$cookies) {
$scope.groupName = "";
$scope.createGroupForm = function($event){
var html = '<div class="box box-solid" ng-repeat="groupInfo in groupInfoList">' +
'<div class="box-body">' +
'<input ng-model="groupName" class="pull-left" placeholder="please type in the group name"/>' +
'<span class="pull-right">' +
"<button ng-click='createGroup()' class='btn btn-danger pull-right btn-block btn-sm'>Ok</button>" +
'</span>' +
'</div>' +
'</div>';
var $html = $compile(html)($scope);
$("#user-group-list").prepend(html);
};
$scope.createGroup = function(){
$log.log($scope.groupName);
};
}]);
You pass the wrong reference, instead of $html you pass html to prepend
var $html = $compile(html)($scope);
$("#user-group-list").prepend(html);
should be
var $html = $compile(html)($scope);
$("#user-group-list").prepend($html);
Related
i have a problem to reference an identifier of a DIV. I allow to add a div with a text field and a button to delete the text field, and i set a id to the DIV like an array with this code:
$('#aggiungi').on('click',function () {
$count ++;
$('#corsi').append(
'<div class="form-group row" id="corso['+$count+']>' +
'<label class="col-sm-2 col-form-label" for="corsi">Corso ' + $count +'</label>' +
'<div class="col-sm-10 form-inline">' +
'<input type="text" class="form-control" id="corso" name="corso['+ $count + ']"/>' +
'<a class="btn btn-default" id="eliminacorso['+$count+']" aria-label="Elimina">' +
'<i class="fa fa-times" aria-hidden="true"></i>' +
'</a>' +
'</div>' +
'</div>' +
'');
});
So.. if i press on the botton at the at the side of the text area, i'll call a function that will remove it.
The skeleton of the function is the follow:
$('#eliminacorso[]').on('click', function() {
$count --;
$('#corso[]').remove();
});
So my ask is: How can i insert between the square brackets the right identifier of the div?
A better choice is:-
1.Instead of using id use button class
2.And then use event delegation concept like below:-
$(document).on('click','.btn-default',function(){
$(this).closest('.form-group').remove();
});
Reference:- https://api.jquery.com/closest/
Use as below the script that add DIV. Remove '[' from id attribute from div tag and anchor tag as below
$('#aggiungi').on('click',function () {
$count ++;
$('#corsi').append(
'<div class="form-group row" id="corso'+$count+'>' +
'<label class="col-sm-2 col-form-label" for="corsi">Corso ' + $count +'</label>' +
'<div class="col-sm-10 form-inline">' +
'<input type="text" class="form-control" id="corso" name="corso['+ $count + ']"/>' +
'<a class="btn btn-default" id="corso'+$count+'" aria-label="Elimina">' +
'<i class="fa fa-times" aria-hidden="true"></i>' +
'</a>' +
'</div>' +
'</div>' +
'');
});
And then script to get the clicked id and remove the matched div on click of button as below
$('.btn').on('click', function() {
var selectedId = $(this).attr('id');
$('#'+selectedId).remove();
});
Try below code.It may help you
var $count =0
$('#aggiungi').on('click',function () {
$count ++;
$('#corsi').append(
'<div class="form-group row" id="corso_'+$count+'">' +
'<label class="col-sm-2 col-form-label" for="corsi">Corso ' + $count +'</label>' +
'<div class="col-sm-10 form-inline">' +
'<input type="text" class="form-control" id="corso" name="corso_'+ $count + '"/>' +
'<a class="btn btn-default" id="eliminacorso_'+$count+'" aria-label="Elimina" onclick="remove(this);">' +
'Test' +
'</a>' +
'</div>' +
'</div>' +
'');
});
function remove(aRemove){
console.log(aRemove);
var divid = aRemove.id.replace("eliminacorso_","corso_");
$("#" + divid).remove();
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button id="aggiungi"> Click ME </button>
<div id="corsi">
</div>
https://codepen.io/vino4all/pen/vZrQEX
Try this code.
<button id="aggiungi">Click</button>
<div id="corsi"></div>
Add a class attribute to the <a> tag.
var $count = 0;
$('#aggiungi').on('click',function () {
$count ++;
$('#corsi').append(
'<div class="form-group row" id="corso['+$count+']>' +
'<label class="col-sm-2 col-form-label" for="corsi">Corso ' + $count +'</label>' +
'<div class="col-sm-10 form-inline">' +
'<input type="text" class="form-control" id="corso" name="corso['+ $count + ']"/>' +
'<a class="btn btn-default delBtn" id="eliminacorso['+$count+']" aria-label="Elimina"><span>X</span>' +
'<i class="fa fa-times" aria-hidden="false"></i>' +
'</a>' +
'</div>' +
'</div>' +
'');
});
$('#corsi').on('click', '.delBtn', function() {
console.log('this :'+$(this));
$count --;
$(this).parent().parent().remove();
});
Notice the usage of on function.
It should be like below
$('#corsi').on('click', '.delBtn', fun);
You can use something like this
var count = 3;
$('button').click(function(){
count--;
$($('.corso')[count]).remove();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="corso">1. <input type="text" /></div><br />
<div class="corso">2. <input type="text" /></div><br />
<div class="corso">3. <input type="text" /></div><br />
<br />
<button>Remove</button>
Try this:
var $count = 0
$('#aggiungi').on('click', function () {
$count++;
let divId = `input_div_${$count}`;
let html = `<div class="form-group row" id="${divId}">
<label class="col-sm-2 col-form-label" for="corsi">Input ${$count}</label>
<div class="col-sm-10 form-inline">
<input type="text" class="form-control" id="input" name="${divId}"/>
<button type="button" id="remove_btn_${$count}" aria-label="Elimina" onclick="remove('${divId}');">
remove
</a>
</div>
</div>`;
$('#main-div').append(html);
});
function remove(removeDivId) {
console.log(removeDivId);
$("#" + removeDivId).remove();
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button type="button" id="aggiungi"> Click ME </button>
<div id="main-div">
</div>
I want a full admin panel Ajax write And a page that details of the bank called with Ajax... I poured this information on a div that performs the button off and on
my cod is :
HTML
<html>
<head>
<script src="file/js/Connection.js"></script>
</head>
<body>
<div class="row" id="box"></div>
</body>
</html>
Connection File js cod :
$(document).ready(function() {
show_all();
});
function show_all() {
work = "select";
$.ajax({
type: "POST",
url: "server.php",
data: "work="+work,
success: function(data) {
$("#box").html(data);
}
});
}
and file server.php :
<?php
$pdo = new PDO('mysql:host=localhost;dbname=Contact', 'root', '');
if (isset($_POST['work'])) {
$work = $_POST['work'];
if ($work == 'select') {
$qcomment = $pdo->query("SELECT * FROM myfeilds");
while ($XXX = $qcomment->fetch()) {
$Z1 = $XXX['id'];
$Z2 = $XXX['name'];
$Z3 = $XXX['active'];
echo '
<div class="col-lg-3">
<div class="row" id="back">
<div class="col-lg-8" id="Fname">
<span class="glyphicon glyphicon-check"></span>
<label>' . $Z2 . '</label>
</div>
<div class="col-lg-4" id="Fbtn"> ';
if ($Z3 == 1) { echo '
<div class="btn btn-on" id="' . $Z1 . '">
<div> <span class="glyphicon glyphicon-remove"></span></div>
<div><span class="glyphicon glyphicon-ok"></span></div>
</div>';
} else { echo '
<div class="btn btn-off" id="' . $Z1 . '">
<div> <span class="glyphicon glyphicon-remove"></span></div>
<div><span class="glyphicon glyphicon-ok"></span></div>
</div>';
} echo '
</div>
</div>
</div>
';
}
}
}
?>
And in the end I tried to write that off and turn on the javascript code
$(".btn").on('click',function(e){
if($(this).hasClass("btn-on")){
$(this).removeClass("btn-on");
$(this).addClass("btn-off");
}
else {
$(this).removeClass("btn-off");
$(this).addClass("btn-on");
}
});
And they told me because the select performed in an external file Then you must use this code to work correctly
$(document).on("click",".btn",function(event) {
if($(this).hasClass("btn-on")){
$(this).removeClass("btn-on");
$(this).addClass("btn-off");
}
else {
$(this).removeClass("btn-off");
$(this).addClass("btn-on");
}
});
This code works, but only the first time that I entered the Fever this page
And if I get another tab and go back again, does not work...
what do I do :)
You can try using Comet in Jquery http://www.screenr.com/SNH
Hope this helps.
Regards,
How can i disable a link after clicking on it once with jquery . on clicking the link its adding an input field inside a div with unique id. I am getting the values in a dropdown from a variable.
$(document).ready(function() {
var count = 1;
$(".block").on('click', function(){
$("#textInput").append(
'<div class="cgparent" id="input'+count+'">' +
'<div class="col-md-8">' +
'<input class="form-control" type="text">' +
'</div>' +
'<div class="col-md-4">' +
'<button style="margin-right: 5px" class="btn btn-info" id="edittext"><i class="fa fa-pencil" aria-hidden="true"></i></button>' +
'<button class="btn btn-danger" type="button" id="removebtn"><i class="fa fa-trash-o" aria-hidden="true"></i></button>' +
'</div>' + '<br><br>' +
'</div>'
).show();
count++;
});
});
<?php if ($table_name == "questions") {?>
<div class="dropdown" >
<button class="btn btn-primary dropdown-toggle" type="button" data-toggle="dropdown">Add Block
<span class="caret"></span>
</button>
<ul class="dropdown-menu">
<?php
$question_fields = $this->db->list_fields('questions');
for ($i=0; $i<count($question_fields); $i++){?>
<li><a class="block" ><?php echo $question_fields[$i]?></li>
<?php } ?>
</ul>
</div>
<?php } ?>
If adding some CSS is ok for you this is the simplest I had found:
Javascript:
$(document).on('click', '#buttonSelector', function () {
$(this).addClass('disabled');
});
CSS:
.disabled {
/* if you also want it to fade a bit:
opacity: 0.5
*/
pointer-events: none;
cursor: default;
}
Using the following code will set a variable true once the link is clicked. After the link is clicked again it will ignore the click.
$(document).ready(function() {
var count = 1;
var clicked = false;
$(".block").on('click', function(e){
if(clicked) {
e.preventDefault();
}
clicked = true;
$("#textInput").append(
'<div class="cgparent" id="input'+count+'">' +
'<div class="col-md-8">' +
'<input class="form-control" type="text">' +
'</div>' +
'<div class="col-md-4">' +
'<button style="margin-right: 5px" class="btn btn-info" id="edittext"><i class="fa fa-pencil" aria-hidden="true"></i></button>' +
'<button class="btn btn-danger" type="button" id="removebtn"><i class="fa fa-trash-o" aria-hidden="true"></i></button>' +
'</div>' + '<br><br>' +
'</div>'
).show();
count++;
});
});
I would do it by setting a counter. If the counter is higher than zero, that means the link has been clicked.
<a class="once-only" href="/do-stuff">Click me</a>
<script type="text/javascript">
$(document).ready(function ($) {
var clicked = 0;
$(document).on('click', '.once-only', function () {
if (clicked != 0) {
return false;
}
var clicked = clicked + 1;
});
});
</script>
Update
The comments brought this solution:
<script type="text/javascript">
$(document).ready(function ($) {
$(document).on('click', '.once-only', function () {
$(this).contents().unwrap();
});
});
</script>
The above will simply remove the anchor.
I have a problem.
here is my php & HTML:
<?php
if ($_POST['btn_tambah'] == 'tambah') {
$sub_lapangan = $_POST['sub_lapangan'];
$SQL = "SELECT AUTO_INCREMENT as IDLapangan FROM information_schema.tables WHERE TABLE_SCHEMA = 'ta' AND TABLE_NAME = 'lapangan';";
$res = mysql_query($SQL, $link);
$row = mysql_fetch_object($res);
$tambah1 = mysql_query("INSERT INTO sub_lapangan(nama,status,id_lapangan) VALUES('".$sub_lapangan."',1,$row->IDLapangan);");
}
?>
<HTML><BODY>
<div class="row">
<div class="form-group" id="sub_lapangan">
<div class="col-lg-3"><label>Nama Sub-Lapangan :</label></div>
<div class="col-lg-2">
<input type="text" name="sub_lapangan" class="form-control" required>
</div>
<div class="col-lg-1">
<a onclick="tambahSubBaru()" class ="btn btn-info"> <i class="fa fa-plus"></i></a>
</div>
</div>
</div>
<div id="sembunyisub">
</div>
</BODY></HTML>
Here is my script:
var count = 0;
function tambahSubBaru() {
count += 1;
if (count > 15) {
alert("Maksimal Untuk Tambah Sub Lapangan adalah 15 Sub Lapangan");
}
else {
$('#sembunyisub').append(
'<div class="row" id="barisbarusub' + count + '">'
+ '<div class="form-group">'
+ '<div class="col-lg-3">'
+ '</div>'
+ '<div class="col-lg-2">'
+ '<input id="subku' + count + '" type="text" class="form-control" name="sub_lapangan" required>'
+ '</div>'
+ '<div class="col-lg-1">'
+ '<a class ="btn btn-warning" onclick="hapusSub(' + count + ')"> <i class="fa fa-trash"></i></a>'
+ '</div>'
+ '</div>'
+ '</div>'
);
}
}
function hapusSub(row) {
$('#barisbarusub' + row).remove();
}
Here is the pic:
So the scenario is, when i click the "plus" button, it will show up the second textbox. I want to insert them into database. but when i try to insert, the SECOND textbox is succedded to insert in database. but the FIRST textbox doesn't insert to database.
How can i insert the FIRST textbox?
to show up the second textbox, i use .append in javascript.
help me please. I aprreciated the answer. many thank you. :)
You have to loop through your fields in PHP. Therefore you have to create an Array-input-element with [] after the name.
HTML:
<input type="text" name="sub_lapangan[]" class="form-control" required> <!-- Add [] to your field name for creating an Array-->
JS:
+ '<input id="subku' + count + '" type="text" class="form-control" name="sub_lapangan[]" required>' //The same in you dynamic input field
PHP: Loop through you fields (Array)
if ($_POST['btn_tambah'] == 'tambah') {
$sub_lapangan = $_POST['sub_lapangan'];
$SQL = "SELECT AUTO_INCREMENT as IDLapangan FROM information_schema.tables WHERE TABLE_SCHEMA = 'ta' AND TABLE_NAME = 'lapangan';";
$res = mysql_query($SQL, $link);
$row = mysql_fetch_object($res);
$fields = $_POST['sub_lapangan']; //Your Array
foreach($fields as $field => $value) {
$tambah1 = mysql_query("INSERT INTO sub_lapangan(nama,status,id_lapangan) VALUES('".$value."',1,$row->IDLapangan);");
}
}
Try this:
'INSERT INTO sub_lapangan(nama,status,id_lapangan) VALUES("'.$sub_lapangan.'","1","'.$row->IDLapangan.'")'
I have a submit form for writing a caption in an image. I'm using plupload for this. When file is uploaded it will append a div and inside it is a textarea where you can write your caption of that image. But I always getting an error of Undefined Index when submitting a form.
This is my code when file was uploaded:
uploader.bind('FileUploaded', function(up, file) {
var filename = file.id + '.' + file.name.split(".").pop()
var uploaded_files = $('#uploaded_files').attr('value');
var appended_files = uploaded_files + file.id + ',';
$('#uploaded_files').attr('value', appended_files);
var prev = '<div class="col-sm-12" style="margin-bottom:5px;" id="upload-' + file.id + '">' +
'<div class="col-sm-3">' +
'<img class="img-thumbnail" width="100%" height="auto" src="./assets/images/gallery/resorts_gallery/' + filename + '">' +
'</div>' +
'<div class="col-sm-6">' +
'<textarea name="' + file.id + '_Caption" class="form-control" style="font-size:12px;height:70px" placeholder="Put a caption"></textarea>' +
'</div>' +
'<div class="col-sm-3"><span class="btn btn-danger btn-xs"><span class="fa fa-times"></span></span></div>' +
'</div>';
$("#prevCap").append(prev);
});
In my html:
<form role="form" method="POST" id="submit-review" enctype="multipart/form-data">
<div class="form-group">
<label for="uploadphoto">Share your Experiences by uploading Photos</label> <span class="small-text">(optional)</span><br/>
<div class="well" id="caption-thumb"> <!-- preview and caption -->
<div id="prevCap" class="col-sm-12" style="margin-bottom:10px"></div>
<input type="hidden" name="uploaded_files" id="uploaded_files" value="" />
<hr>
<button class="btn btn-default navbar-btn" type="button" data-toggle="modal" data-target="#upload-modal">Add Photos</button>
<hr id="hr-line" style="display:none">
</div>
</div>
<input type="submit" class="btn btn-embossed btn-default" id="btnsubmit" name="submit" disabled value="SUBMIT"/>
</form>
in my php i do something like this:
$last_id = insert_getID("reviews", $fields, $val);
$uploaded_files = $_POST['uploaded_files'];
$uploaded_files = explode(',', $uploaded_files);
$uploaded_files = array_filter($uploaded_files);
foreach ($uploaded_files as $file) {
$wherefields = array('img_name', 'users_id');
$upload_value = $file;
$wherevalues = array($upload_value, $_SESSION['uid']);
$where_file = where($wherefields, $wherevalues, "", "");
$caption = $file . "_Caption";
$file_caption = $_POST['\'' . $caption . '\''];
$file_field = array('review_id', 'caption');
$file_value = array($last_id, $file_caption);
update('gallery', $file_field, $file_value, $where_file);
echo "<pre>" + $file_caption + "</pre>";
}
WHen the files where successfully uploaded, textarea will append inside the div #prevCap and that div was also inside the form. I'm getting an error because the form can't get the value of textarea. How can i fix this problem, how can i get textarea value that was appended?