This question already has answers here:
Regex created via new RegExp(myString) not working (backslashes)
(1 answer)
What is the difference between using "new RegExp" and using forward slash notation to create a regular expression?
(4 answers)
Why do regex constructors need to be double escaped?
(5 answers)
Closed 4 years ago.
I am trying to match all UK phone numbers in a string.
The pattern for this is:
^\(?(?:(?:0(?:0|11)\)?[\s-]?\(?|\+)44\)?[\s-]?\(?(?:0\)?[\s-]?\(?)?|0)(?:\d{2}\)?[\s-]?\d{4}[\s-]?\d{4}|\d{3}\)?[\s-]?\d{3}[\s-]?\d{3,4}|\d{4}\)?[\s-]?(?:\d{5}|\d{3}[\s-]?\d{3})|\d{5}\)?[\s-]?\d{4,5}|8(?:00[\s-]?11[\s-]?11|45[\s-]?46[\s-]?4\d))(?:(?:[\s-]?(?:x|ext\.?\s?|\#)\d+)?)$
But when I try to initiate a new RegExp like:
const myRegex = RegExp('^\(?(?:(?:0(?:0|11)\)?[\s-]?\(?|\+)44\)?[\s-]?\(?(?:0\)?[\s-]?\(?)?|0)(?:\d{2}\)?[\s-]?\d{4}[\s-]?\d{4}|\d{3}\)?[\s-]?\d{3}[\s-]?\d{3,4}|\d{4}\)?[\s-]?(?:\d{5}|\d{3}[\s-]?\d{3})|\d{5}\)?[\s-]?\d{4,5}|8(?:00[\s-]?11[\s-]?11|45[\s-]?46[\s-]?4\d))(?:(?:[\s-]?(?:x|ext\.?\s?|\#)\d+)?)$','g');
I get this error:
Uncaught SyntaxError: Invalid regular expression: /^(?(?:(?:0(?:0|11))?[s-]?(?|+)44)?[s-]?(?(?:0)?[s-]?(?)?|0)(?:d{2})?[s-]?d{4}[s-]?d{4}|d{3})?[s-]?d{3}[s-]?d{3,4}|d{4})?[s-]?(?:d{5}|d{3}[s-]?d{3})|d{5})?[s-]?d{4,5}|8(?:00[s-]?11[s-]?11|45[s-]?46[s-]?4d))(?:(?:[s-]?(?:x|ext.?s?|#)d+)?)$/: Invalid group
The error already shows you what the problem is. \ inside a string literal is the escape character. But escaping a character that doesn't need to be escaped simply "drops" the \:
console.log('\(');
So the value you are passing to the regular expression engine (and what the error shows you) is:
^(?(?...
(note: no backslash)
and (?( is not a valid character sequence in a regular expression.
You either have to
escape the escape characters ("\\(")
Use a regular expression literal instead of RegExp("string") (/^.../).
Related
This question already has answers here:
Why do regex constructors need to be double escaped?
(5 answers)
Closed 1 year ago.
I need to define below regex in Javascript:
(\bin region\b)(?!.*\1).+?(?=<)
I tried like below but it looks like not working:
var reg = new RegExp ('(\bin region\b)(?!.*\1).+?(?=<)');
Although the Atom tool matches the regex in the target string, JavaScript code is returning blank.
I am using this in Azure logic app (inline code executor connector)
Anyone can help me with this?
You can see it matches the text in Atom:
Inside a string you need to escape the backslashes.
Otherwise the backslash will escape the next character. So, writing \b will escape the character b instead use \\b which will escape the \
var reg = new RegExp ('(\\bin region\\b)(?!.*\\1).+?(?=<)');
This question already has an answer here:
Javascript RegEx Not Working [duplicate]
(1 answer)
Closed 5 years ago.
I expected new RegExp('\b\w{1,7}\b', "i").test('bc4rg6') to return true since I want to test of the string "bc4rg6" is alphanumeric and has from 1 to 7 characters. But the browser is giving false. How do I fix it so that I can test for the condition stated? Thanks
You need to escape the backslashes in the string, because \b is an escape sequence that turns into the backspace character.
console.log(new RegExp('\\b\\w{1,7}\\b', "i").test('bc4rg6'));
But if the regexp is a constant, you don't need to use new RegExp, just use a RegExp literal.
console.log(/\b\w{1,7}\b/i.test('bc4rg6'))
The RegExp function doesn't accept a string as an argument.
Instead pass a Regular Expression pattern with the escape slashes to indicate the start and end of the pattern.
new RegExp(/\b\w{1,7}\b/, "i").test('bc4rg6');
You can read more about the RegExp function at Mozilla.
This question already has answers here:
How can I match a whole word in JavaScript?
(4 answers)
Closed 5 years ago.
I am trying to match the word ethane (preceded with nothing) while avoiding methane. I've tried this in an online regex tester: /(?<!m)ethane/i (which works), but I get an invalid regex expression error in JavaScript. What am I doing wrong?
You can use RegExp /\bethane\b/ to match "ethane" and not "methane"
var thanes = ["ethane", "methane"];
var re = /\bethane\b/;
thanes.forEach(word => console.log(re.test(word)));
See
Difference between \b and \B in regex
How does \b work when using regular expressions?
This question already has answers here:
JavaScript search() fails to find "()"
(2 answers)
Closed 6 years ago.
Use this string as example
s = "a(b"
These two work as expected
s.search("\\(")
1
s.replace("\(", "")
"ab"
But these don't
s.search("\(")
Uncaught SyntaxError: Invalid regular expression: /(/: Unterminated group
s.replace("\\(", "")
"a(b"
Huh? Why does search require one more escape than replace?
Also, shouldn't string input give a literal search, instead of being interpreted as a regexp? In theory, I shouldn't have to use escape characters at all.
The string literal '\(' is equivalent to '(', so you’re not really escaping anything at all with it.
String#search always interprets its argument as a regular expression; if you want to find an exact match, use String#indexOf.
> s.indexOf('(')
1
s.replace accepts either a string or a regular expression. You’re giving it the string ( in the first case (so it replaces the first opening parenthesis it sees) and \( in the second (not in the string, so it replaces nothing).
This question already has answers here:
Regular expression to match a line that doesn't contain a word
(34 answers)
Closed 8 years ago.
I have a regular expression that matches strings that start with either the word "db" or the word "admin":
/^\/(db|admin)\//
I'm refactoring my code and my requirements have changed: Now I need the opposite, i.e. a regular expression that matches strings that don't start with one of those two words. Is this possible with regular expressions?
Note: I cannot use JS API - the regular expression is inserted in Express.js's app.all(path, callback) method directly (as the path).
Thanks to Nico for pointing out that JavaScript RegExp has (?!) functionality. The solution seems to be:
/^\/(?!admin|db)/