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Need to convert the array of filepaths into treeview json object

Need to convert the array of file paths into Treeview JSON object
Array Data:
[path1/subpath1/file1.doc",
"path1/subpath1/file2.doc",
"path1/subpath2/file1.doc",
"path1/subpath2/file2.doc",
"path2/subpath1/file1.doc",
"path2/subpath1/file2.doc",
"path2/subpath2/file1.doc",
"path2/subpath2/file2.doc",
"path2/subpath2/additionalpath1/file1.doc"]
I want below object Result:
{
"title": "path1",
"childNodes" : [
{ "title":"subpath1", "childNodes":[{ "title":"file1.doc", "childNodes":[] }] },
{ "title":"subpath2", "childNodes":[{ "title":"file1.doc", "childNodes":[] }] }
]
}
I was able to convert it into an object using the below code snippet but not able to transform the way I want it
let treePath = {};
let formattedData = {};
data.forEach(path => {
let levels = path.split("/");
let file = levels.pop();
let prevLevel = treePath;
let prevProp = levels.shift();
levels.forEach(prop => {
prevLevel[prevProp] = prevLevel[prevProp] || {};
prevLevel = prevLevel[prevProp];
prevProp = prop;
});
prevLevel[prevProp] = (prevLevel[prevProp] || []).concat([file]);
});
How can i do this????

You could reduce the parts of pathes and search for same title.
const
pathes = ["path1/subpath1/file1.doc", "path1/subpath1/file2.doc", "path1/subpath2/file1.doc", "path1/subpath2/file2.doc", "path2/subpath1/file1.doc", "path2/subpath1/file2.doc", "path2/subpath2/file1.doc", "path2/subpath2/file2.doc", "path2/subpath2/additionalpath1/file1.doc"],
result = pathes.reduce((r, path) => {
path.split('/').reduce((childNodes, title) => {
let child = childNodes.find(n => n.title === title);
if (!child) childNodes.push(child = { title, childNodes: [] });
return child.childNodes;
}, r);
return r;
}, []);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Show only the information of this date

I have 4 dates of 4 people,I want to bring the name of the person who added that date but when I select the day the array is traversed 4 times and in one of them it brings the name.. that is to say the array travels all the people but not only the one I want.
for example on day 17 when I select it 2 alerts come out with error the third with the name of the person and the fourth alert error.. the others are similar
View picture
The code is this,the function of interest is infoDay
constructor(props) {
super(props);
this.state = {
selected: "",
usuarios: [],
};
}
componentDidMount() {
firebase
.database()
.ref("DatosCli/")
.on("child_added", (data) => {
var datos = data.val();
/* alert(JSON.stringify(datos)); */
var usuariosTemp = this.state.usuarios;
datos.key = data.key;
//Alert.alert("prueba",""+datos.longitud)
usuariosTemp.push(datos);
this.setState({ usuarios: usuariosTemp });
});
}
cargarDatos = async () => {
var userTemp = new Array();
var data = await firebase.database().ref("/DatosCli").once("value");
data.forEach((child) => {
var user = child.val();
user.key = child.key;
userTemp.push(user);
});
this.setState({ usuarios: userTemp });
};
render() {
const markedDates = {};
this.state.usuarios.forEach((usuarioTemp) => {
markedDates[usuarioTemp.date] = {
selected: true,
disableTouchEvent: false,
selectedColor: "orange",
selectedTextColor: "red",
};
});
const infoDay = (day) => {
this.state.usuarios.forEach((usuarioTemp) => {
if (day.dateString == usuarioTemp.date) {
alert(usuarioTemp.nombre);
} else {
alert("fail");
}
});
};
return (
<View style={styles.container}>
<CalendarList markedDates={markedDates} onDayPress={infoDay} />
</View>
);
}

If you remove the else statement you'll only see the correct alerts.
const infoDay = (day) => {
this.state.usuarios.forEach((usuarioTemp) => {
if (day.dateString == usuarioTemp.date) {
alert(usuarioTemp.nombre);
}
});
};
If you want to travel trough a specific user, you must have to make a dict with the user names
For example:
let usuarioTemp = {
firstUser:{day: 17},
secondUser:{day: 19}
}
And your function could it be:
const infoDay = (day, userName) => {
if(usuarioTemp[userName].date === day){
alert(userName);
}
};
And finally, I suppose you are getting the data like this:
[{nombre:"Name", date:17}, {nombre:"Name2", date:19}]
You can use this function:
function groupBy(array, key) {
let arrayReduced = array.reduce(
(result, { [key]: k, ...rest }) => {
(result[k] = rest);
return result;
},
{}
);
return arrayReduced;
}
and you'll see the data like this:
{
"Name": {date: 17},
"Name2": {date: 19}
}
Test:
//Data example
let data = [{nombre:"Name", date:17}, {nombre:"Name2", date:19}]
//Function groupBy
function groupBy(array, key) {
let arrayReduced = array.reduce(
(result, { [key]: k, ...rest }) => {
(result[k] = rest);
return result;
},
{}
);
return arrayReduced;
}
//Usage
console.log(groupBy(data, "nombre"))
I hope it helps!

How to create single array for same key but different values

How to create single array for same key but different values in nodeJs with unique productId
but having different productImage with same productId i want productImage should be an array
and with same productId, productImages are in this productImage array.
var data = [
{
"productID":18,
"productTitle":"Watch",
"productImage":"1588148225540.jpg"
},
{
"productID":18,
"productTitle":"Watch",
"productImage":"15881482433232.jpg"
},
{
"productID":19,
"productTitle":"Shirt",
"productImage":"1588148214343.jpg"
}
]
My expected output should be:
[
{
"productID":18,
"productTitle":"Watch",
"productImage":[
"1588148225540.jpg",
"15881482433232.jpg"
]
},
{
"productID":19,
"productTitle":"Shirt",
"productImage":[
"1588148214343.jpg"
]
}
]

You can use uniqBy function from lodash library
const result = _.uniqBy(products, 'productID');

Here is an answer
var data = [
{
"productID":18,
"productTitle":"Watch",
"productImage":"1588148225540.jpg"
},
{
"productID":18,
"productTitle":"Watch",
"productImage":"15881482433232.jpg"
},
{
"productID":19,
"productTitle":"Shirt",
"productImage":"1588148214343.jpg"
}
]
let output =[];
data.forEach(function(item) {
var existing = output.filter(function(v, i) {
return v.productID == item.productID;
});
if (existing.length) {
var existingIndex = output.indexOf(existing[0]);
output[existingIndex].productImage =
output[existingIndex].productImage.concat(item.productImage);
} else {
if (typeof item.productImage == 'string')
item.productImage = item.productImage;
item.productThumbImage = [item.productThumbImage];
output.push(item);
}
});

How to pick data from array and create a single Object from it?

I want to create a single object from an array of objects. Please refer the code provided.
Here's the input array
let queryArr = [
{
query: {
filter: {
term: {
search: 'complete',
}
}
}
},
{
query: {
notFilter: {
term: {
search: 'failed',
}
}
}
},
{
query: {
bool: {
term: {
search: 'complete',
}
}
}
}
]
The expected output
let oneQuery = {query: {
bool: { ... },
filter: { ... },
notFilter: { ... } // data from respective array object key
}};
The function I wrote
function createQuery(arr){
for(let i = 0; i < arr.length; i++){
if(Object.keys(arr[i].query === 'bool')){
oneQuery.query.bool = arr[i].query.bool;
}
if(Object.keys(arr[i].query === 'filter')){
oneQuery.query.filter = arr[i].query.filter;
}
if(Object.keys(arr[i].query === 'notFilter')){
oneQuery.query.notFilter = arr[i].query.notFilter;
}
}
return oneQuery;
}
createQuery(queryArr);
The output I'm getting:
query: {
bool: { ... },
filter: undefined,
notFilter: undefined
}
I don't get what I'm doing wrong here. A solution using reduce or map will be preferred.

Use Array.map() to get an array with the contents of each query property, then spread into Object.assign() to combine to a single object:
const queryArr = [{"query":{"filter":{"term":{"search":"complete"}}}},{"query":{"notFilter":{"term":{"search":"failed"}}}},{"query":{"bool":{"term":{"search":"complete"}}}}];
const createQuery = (arr) => ({
query: Object.assign({}, ...queryArr.map(({ query }) => query))
});
console.log(createQuery(queryArr));
To fix your code, initialize the query item, and get the 1st key from each item in the array - arr[i].query)[0]:
const queryArr = [{"query":{"filter":{"term":{"search":"complete"}}}},{"query":{"notFilter":{"term":{"search":"failed"}}}},{"query":{"bool":{"term":{"search":"complete"}}}}]
function createQuery(arr){
const oneQuery = { query: {} };
for(let i = 0; i < arr.length; i++){
if(Object.keys(arr[i].query)[0] === 'bool'){
oneQuery.query.bool = arr[i].query.bool;
}
if(Object.keys(arr[i].query)[0] === 'filter'){
oneQuery.query.filter = arr[i].query.filter;
}
if(Object.keys(arr[i].query)[0] === 'notFilter'){
oneQuery.query.notFilter = arr[i].query.notFilter;
}
}
return oneQuery;
}
console.log(createQuery(queryArr));

You problem seems to be this line
Object.keys(arr[i].query === 'filter')
This evaluates to Object.keys(true) or Object.keys(false)
Use reduce
queryArr.reduce( (acc, c) => (
acc[ Object.keys(c.query)[0] ] = Object.values(c.query)[0], //set the first key and value to accumulator
acc ), //return the accumulator
{}); //initialize accumulator to {}

JS - mapping string into array of objects ¿How to change key name?

$(document).ready(function() {
printData("customerNumber>103#customerName>Atelier graphique#contactLastName>Schmitt#contactFirstName>Carine #phone>40.32.2555#addressLine1>54, rueRoyale#addressLine2>#city>Nantes#state>#postalCode>44000#country>France#salesRepEmployeeNumber>1370#creditLimit>21000#~customerNumber>112#customerName>Signal Gift Stores#contactLastName>King#contactFirstName>Jean#phone>7025551838#addressLine1>8489 Strong St.#addressLine2>#city>LasVegas#state>NV#postalCode>83030#country>USA#salesRepEmployeeNumber>1166#creditLimit>71800#~customerNumber>114#customerName>Australian Collectors, Co.#contactLastName>Ferguson#contactFirstName>Peter#phone>03 9520 4555#addressLine1>636 St KildaRoad#addressLine2>Level3#city>Melbourne#state>Victoria#postalCode>3004#country>Australia#salesRepEmployeeNumber>1611#creditLimit>117300#~customerNumber>119#customerName>La Rochelle Gifts#contactLastName>Labrune#contactFirstName>Janine #phone>40.67.8555#addressLine1>67, rue des CinquanteOtages#addressLine2>#city>Nantes#state>#postalCode>44000#country>France#salesRepEmployeeNumber>1370#creditLimit>118200#~")
})
function printData(data){
var customers = data
.split('~')
.map((i, e) => {
return i
.split('#')
.map((i, el) => {
return [i.split('>')[0],i.split('>')[1]];
})
});
// $.each(customers, (i, el) => {
// customers[i] = el.split('#');
// $.each(customers[i], (name, valor) => {
// })
// })
console.log(customers);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
I get data from a source in a string like this:
prop1>value1#prop2>value2~
prop1>value1#prop2>value2~
prop1>value1#prop2>value2
where:
"~" splits rows
"#" splits columns
">" splits propertie:value
this is the function i use to map it actually (where data is the string):
function printData(data){
var customers = data
.split('~')
.map((i, e) => {
return i
.split('#')
.map((i, el) => {
return [i.split('>')[0],i.split('>')[1]];
})
});
console.log(customers);
}
I almost got it, but i need a final help, this is what i get print at console:
And what i would like to get is something like
Array {
customerNumber:103,
customerName:Atelier
}
instead of:
Array{
Array{
0:customerNumber,
1:103
}
Array{
0:customerName,
1:Atelier
}
}
I explained it the best i can, hope it's enough!

to go from:
[
["customerNumber",103 ],
["customerName","Atelier" ]
]
to:
{ customerNumber:103, customerName:"Atelier" }
if that's you want to do ,
you can just remap the array:
var arr = [
[
["customerNumber", 103],
["customerName", "Atelier"]
],
[
["customerNumber", 105],
["customerName", "Atr"]
]
];
var r = arr.map(x => {
return {
[x[0][0]]: x[0][1],
[x[1][0]]: x[1][1]
}
});
console.log(r)
$(document).ready(function() {
printData("customerNumber>103#customerName>Atelier graphique#contactLastName>Schmitt#contactFirstName>Carine #phone>40.32.2555#addressLine1>54, rueRoyale#addressLine2>#city>Nantes#state>#postalCode>44000#country>France#salesRepEmployeeNumber>1370#creditLimit>21000#~customerNumber>112#customerName>Signal Gift Stores#contactLastName>King#contactFirstName>Jean#phone>7025551838#addressLine1>8489 Strong St.#addressLine2>#city>LasVegas#state>NV#postalCode>83030#country>USA#salesRepEmployeeNumber>1166#creditLimit>71800#~customerNumber>114#customerName>Australian Collectors, Co.#contactLastName>Ferguson#contactFirstName>Peter#phone>03 9520 4555#addressLine1>636 St KildaRoad#addressLine2>Level3#city>Melbourne#state>Victoria#postalCode>3004#country>Australia#salesRepEmployeeNumber>1611#creditLimit>117300#~customerNumber>119#customerName>La Rochelle Gifts#contactLastName>Labrune#contactFirstName>Janine #phone>40.67.8555#addressLine1>67, rue des CinquanteOtages#addressLine2>#city>Nantes#state>#postalCode>44000#country>France#salesRepEmployeeNumber>1370#creditLimit>118200#~")
})
function printData(data) {
var customers = data
.split('~')
.map((i, e) => {
return i
.split('#')
.map((i, el) => {
var r = i.split('>');
return {
[r[0]]: r[1]
};
})
});
// $.each(customers, (i, el) => {
// customers[i] = el.split('#');
// $.each(customers[i], (name, valor) => {
// })
// })
console.log(customers);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>