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Changing Dates so They Are Within Business Hours

In a JavaScript step in Pentaho Data Integration, I want calculate the time in hours which passes between one date and another.
After following along with this this blog post, I realize that I need to adjust the startDate and endDate values in the function below which fall outside business hours so that they're within business hours so the function doesn't return zero. The dates are in the format 09/27/2018 18:54:55.
Here's my attempt so far:
var Approve_Gap;
var created_at_copy;
var approved_at_copy1;
// Function that accepts two parameters and calculates
// the number of hours worked within that range
function workingHoursBetweenDates(startDate, endDate) {
// Store minutes worked
var minutesWorked = 0;
// Validate input
if (endDate < startDate) { return 0; }
// Loop from your Start to End dates (by hour)
var current = startDate;
// Define work range
var workHoursStart = 8;
var workHoursEnd = 17;
var includeWeekends = true;
// bring dates into business hours
if(current.getHours() > workHoursEnd) {
current = current - (current.getHours() - workHoursEnd);
}
else if(current.getHours() < workHoursStart) {
current = current + (workHoursStart - current.getHours())
}
if(endDate.getHours() > workHoursEnd) {
endDate = endDate - (endDate.getHours() - workHoursEnd);
}
else if(endDate.getHours() < workHoursStart) {
endDate = endDate + (workHoursStart - endDate.getHours())
}
// Loop while currentDate is less than end Date (by minutes)
while(current <= endDate){
// Is the current time within a work day (and if it
// occurs on a weekend or not)
if(current.getHours() >= workHoursStart && current.getHours() < workHoursEnd && (includeWeekends ? current.getDay() !== 0 && current.getDay() !== 6 : true)){
minutesWorked++;
}
// Increment current time
current.setTime(current.getTime() + 1000 * 60);
}
// Return the number of hours
return minutesWorked / 60;
}
Approve_Gap = workingHoursBetweenDates(created_at_copy, approved_at_copy1);

I got the dates into business hours by adjusting copies of the dates as shown below:
if(created_at_copy.getHours() >= workHoursEnd) {
created_at_copy.setDate(created_at_copy.getDate() + 1);
created_at_copy.setHours(8);
created_at_copy.setMinutes(0);
created_at_copy.setSeconds(0);
} else if(created_at_copy.getHours() < workHoursStart) {
created_at_copy.setHours(8);
created_at_copy.setMinutes(0);
created_at_copy.setSeconds(0);
}
if(approved_at_copy1.getHours() >= (workHoursEnd)) {
approved_at_copy1.setDate(approved_at_copy1.getDate() + 1);
approved_at_copy1.setHours(8);
approved_at_copy1.setMinutes(0);
created_at_copy.setSeconds(0);
} else if(approved_at_copy1.getHours() < workHoursStart) {
approved_at_copy1.setHours(8);
approved_at_copy1.setMinutes(0);
created_at_copy.setSeconds(0);
}

Calculate days excluding weekend and holiday in JavaScript

I am trying to write a code where total days will be counted excluding weekends and custom defined holiday. I searched through stackoverflow and adobe forum to find a solution and came with below code.
If public holiday falls in a working day (Saturday-Wednesday) it is excluding from calculation.
My problem is that if public holiday falls in weekend (Thursday-Friday), it is deducting for both (holiday & weekend). Suppose leave duration is 18/09/2018-22/09/2018, total count 2 days is showing in place of 3. Again for 17/10/2018-21/10/2018, total count 1 day is showing in place of 3 days.
Any help or any idea to solve the problem would be great!
Regards
//Thursday and Friday will be excluded as weekend.
var start = this.getField("From").value;
// get the start date value
var end = this.getField("To").value;
var end = util.scand("dd/mm/yyyy H:MM:SS", end + " 0:00:00");
var start =util.scand("dd/mm/yyyy H:MM:SS", start + " 0:00:00");
event.value = dateDifference(start, end);
function dateDifference(start, end) {
// Copy date objects so don't modify originals
var s = new Date(+start);
var e = new Date(+end);
// Set time to midday to avoid daylight saving and browser quirks
s.setHours(12,0,0,0);
e.setHours(12,0,0,0);
// Get the difference in whole days
var totalDays = Math.round((e - s) / 8.64e7);
// Get the difference in whole weeks
var wholeWeeks = totalDays / 7 | 0;
// Estimate business days as number of whole weeks * 5
var days = wholeWeeks * 5;
// If not even number of weeks, calc remaining weekend days
if (totalDays % 7) {
s.setDate(s.getDate() + wholeWeeks * 7);
while (s < e) {
s.setDate(s.getDate() + 1);
// If day isn't a Thursday or Friday, add to business days
if (s.getDay() != 4 && s.getDay() != 5) {
++days;
}
}
}
var hdayar = ["2018/02/21","2018/03/17","2018/03/26","2018/04/14","2018/05/01","2018/08/15","2018/09/2 1","2018/10/18","2018/10/19","2018/12/16","2018/12/25"];
//test for public holidays
var phdays = 0;
for (var i = 0; i <hdayar.length; i++){
if ((Date.parse(hdayar[i]) >= Date.parse(start)) && (Date.parse(hdayar[i]) <= Date.parse(end))) {phdays ++;}}
return days-phdays + 1;
}

You should use a library for this rather than reinventing the wheel.
But if you want to do it yourself you could use .getDay to check if the public holidays are on a weekend.
var weekend = [4, 5], // for Thursday, Friday
holDate, holDay;
for (var i = 0; i < hdayar.length; i++){
holDate = Date.parse(hdayar[i]);
holDay = new Date(holDate).getDay()
if (weekend.indexOf(holDay) == -1 && holDate >= Date.parse(start) && holDate <= Date.parse(end)) {
phdays ++;
}
}
phdays will now contain the number of non-weekend public holidays within the range.

Just have the same requirement and this is the my work around.Hope it helps other
var holiday = ["4/18/2019", "4/19/2019", "4/20/2019", "4/25/2019", "4/26/2019"];
var startDate = new Date();
var endDate = new Date(startDate.setDate(startDate.getDate() + 1));
for (i = 0; i < holiday.length; i++) {
var date = endDate.getDate();
var month = endDate.getMonth() + 1; //Months are zero based
var year = endDate.getFullYear();
if ((month + '/' + date + '/' + year) === (holiday[i])) {
endDate = new Date(endDate.setDate(endDate.getDate() + 1));
if (endDate.getDay() == 6) {
endDate = new Date(endDate.setDate(endDate.getDate() + 2));
} else if (endDate.getDay() == 0) {
endDate = new Date(endDate.setDate(endDate.getDate() + 1));
}
}
}
Here, end date gives you next working day.Here,I'm ignoring current day and start comparing from Next day whether it's holiday or weekend.You can customize dateTime as per your requirement (month + '/' + date + '/' + year).Careful whenever you compares two dates with each other. Because it looks same but actually it's not.So customize accordingly.

output correct format 24 hour after calculation

I'm currently using this function to calculate 2 fields and the results are good but sometimes missing a zero. sample
10:20 + 10:30 current output 0.10
10:20 + 10:30 I want the output to be 00.10
$(function () {
function calculate() {
time1 = $("#start").val().split(':'),
time2 = $("#end").val().split(':');
hours1 = parseInt(time1[0], 10),
hours2 = parseInt(time2[0], 10),
mins1 = parseInt(time1[1], 10),
mins2 = parseInt(time2[1], 10);
hours = hours2 - hours1,
mins = 0;
if(hours < 0) hours = 24 + hours;
if(mins2 >= mins1) {
mins = mins2 - mins1;
} else {
mins = (mins2 + 60) - mins1;
}
// the result
$("#hours").val(hours + ':' + mins);
}
});
also when there is an invalid character I keep getting a nan message is possible to change this to 00 instead?

Instead of dealing with the strings and each value independently, you can use the javascript Date object to calculate the difference...
function calculate() {
// Get time values and convert them to javascript Date objects.
var time1 = new Date('01/01/2017 ' + $('#start').val());
var time2 = new Date('01/01/2017 ' + $('#end').val());
// Get the time difference in minutes. If is negative, add 24 hours.
var hourDiff = (time2 - time1) / 60000;
hourDiff = (hourDiff < 0) ? hourDiff+1440 : hourDiff;
// Calculate hours and minutes.
var hours = Math.floor(hourDiff/60);
var minutes = Math.floor(hourDiff%60);
// Set the result adding '0' to the left if needed
$("#hours").val((hours<10 ? '0'+hours : hours) + ':' + (minutes<10 ? '0'+minutes : minutes));
}
Or even better, you can make the function independent of the DOM elements, so you can reuse it...
function calculate(startTime,endTime) {
// Get time values and convert them to javascript Date objects.
var time1 = new Date('01/01/2017 ' + startTime);
var time2 = new Date('01/01/2017 ' + endTime);
// Get the time difference in minutes. If is negative, add 24 hours.
var hourDiff = (time2 - time1) / 60000;
hourDiff = (hourDiff < 0) ? hourDiff+1440 : hourDiff;
// Calculate hours and minutes.
var hours = Math.floor(hourDiff/60);
var minutes = Math.floor(hourDiff%60);
// Return the response, adding '0' to the left of each field if needed.
return (hours<10 ? '0'+hours : hours) + ':' + (minutes<10 ? '0'+minutes : minutes);
}
// Now you can use the function.
$("#hours").val(calculate($('#start').val(),$('#end').val()));

Add a function
function checkTime(i) {
if (i < 10) {i = "0" + i}; // add zero in front of numbers < 10
return i;
}
and call this function before displaying result

I propose you that :
$(".calculator").on("change",function(){
var isNegative = false;
var hours = "00:00";
var inputStart = $("#start").val();
var inputEnd = $("#end").val();
if(inputStart!="" && inputEnd != ""){
// calculate only if the 2 fields have inputs
// convert to seconds (more convenient)
var seconds1 = stringToSeconds(inputStart);
var seconds2 = stringToSeconds(inputEnd);
var secondsDiff = seconds2 - seconds1;
var milliDiffs = secondsDiff * 1000;
if(milliDiffs < 0){
milliDiffs = milliDiffs *-1;
isNegative = true;
}
// Convert the difference to date
var diff = new Date(milliDiffs);
// convert the date to string
hours = diff.toUTCString();
// extract the time information in the string 00:00:00
var regex = new RegExp(/[0-9]{2}:[0-9]{2}:[0-9]{2}/);
var arr = hours.match(regex);
hours = arr[0];
// Take only hours and minutes and leave the seconds
arr = hours.split(":");
hours=arr[0]+":"+arr[1];
// put minus in front if negative
if(isNegative){
hours = "-"+hours;
}
// Show the result
$("#hours").val(hours);
// Put back the inputs times in case there were somehow wrong
// (it's the same process)
var date1 = new Date(seconds1*1000);
var str1 = date1.toUTCString();
arr = str1.match(regex);
hours = arr[0];
arr = hours.split(":");
hours=arr[0]+":"+arr[1];
$("#start").val(hours);
// idem for time 2
var date2 = new Date(seconds2*1000);
var str2 = date2.toUTCString();
arr = str2.match(regex);
hours = arr[0];
arr = hours.split(":");
hours=arr[0]+":"+arr[1];
$("#end").val(hours);
}
});
function timeElementToString(timeElement){
var output = timeElement.toString();
if(timeElement < 10 && timeElement >=0)
output = "0"+output;
else if(timeElement < 0 && timeElement >=-10)
output = "-0"+Math.abs(output);
return output;
}
function stringToSeconds(input){
var hours = 0;
var arr=input.split(":");
if(arr.length==2){
hours=parseInt(arr[0]);
minutes=parseInt(arr[1]);
if(isNaN(hours)){
hours = 0;
}
if(isNaN(minutes)){
minutes = 0;
}
}
return hours*3600+60*minutes;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<label for="start">Start</label><input type="text" id="start" class="calculator"></input><br />
<label for="end">End</label><input type="text" id="end" class="calculator"></input><br />
<label for="hours">Hours</label><input type="text" id="hours" readonly="readonly"></input>
</form>

get last 7 days when user picks up a date

I have a datetimepicker where the user picks up a date, and my requirement is I need 7 days difference between his selected date.
For eg,
if user has selected 2017-03-01 so i need last 7 days from 2017-03-01 and NOT the current date
All answers i checked here were based on days difference from today.
Can anyone help me out here ?
$("#dateTimePickerIdWhereUserSelectsHisDate").val() - (7 * 24 * 60 * 60 * 1000);
this was on one of the answers but didn't work.
How can I achieve this ?

Try This
SelectDateTime will give you selected date
604800000 is 7 days in miliseconds
prevDate will give you last 7 days Date
$("#startDate").on("dp.change", function(e) {
if (e.oldDate != null) {
if (e.date.format('D') != e.oldDate.format('D')) {
var selectDateTime = e.date["_d"].getTime();
var prevDateTImeMili = selectDateTime - 604800000;
var prevDate = msToDateTime(prevDateTImeMili)
$('#startDate').data("DateTimePicker").hide();
}
}
});
msToDateTime is a function which converts milliseconds to DateTime
function msToDateTime(s) {
Number.prototype.padLeft = function(base,chr){
var len = (String(base || 10).length - String(this).length)+1;
return len > 0? new Array(len).join(chr || '0')+this : this;
}
if(s != null){
s = new Date(s);
// var d = new Date(s);
// var d = new Date(s.getTime()+s.getTimezoneOffset()*60*1000+timeConversionToMilliseconds(sessionStorage.getItem("accounttimezone").split('+')[1]+':00'))
var d = new Date(s.getTime()+(s.getTimezoneOffset()*60*1000)+ (330 *60*1000));
dformat = [ d.getFullYear(),
(d.getMonth()+1).padLeft(),
d.getDate().padLeft()].join('-')+
' ' +
[ d.getHours().padLeft(),
d.getMinutes().padLeft(),
d.getSeconds().padLeft()].join(':');
return dformat;
}else{
return " ";
}
}

function getNDaysBefore(dateString, numberOfDaysBefore) {
let startingDate = new Date(dateString).getTime();
let datesArray = [],
daysCounter = 0,
day = 1000 * 60 * 60 * 24;
while (daysCounter < numberOfDaysBefore + 1) {
let newDateBeforeStaring = startingDate - day * daysCounter;
datesArray.push(new Date(newDateBeforeStaring));
daysCounter++;
}
return datesArray;
}
var dateString = "2016-03-01";
alert(getNDaysBefore(dateString,7));
With that kind of a function you can get any N days before the given date as an array of Date objects

How to count the number of sundays between two dates

I tried the JS below:
var start = new Date("25-05-2016");
var finish = new Date("31-05-2016");
var dayMilliseconds = 1000 * 60 * 60 * 24;
var weekendDays = 0;
while (start <= finish) {
var day = start.getDay()
if (day == 0) {
weekendDays++;
}
start = new Date(+start + dayMilliseconds);
}
alert(weekendDays);
However, it gives the wrong output.
I need to get the total count of Sundays between the two dates.

You use incorrect date format.It will work if init date so:
var start = new Date("2016-05-25");
var finish = new Date("2016-05-31");

Your date format is wrong. Dates' string format is "yyyy-mm-dd". See here for more information.
Also, looping each day of the interval is very inefficient. You may try the following instead.
function getNumberOfWeekDays(start, end, dayNum){
// Sunday's num is 0 with Date.prototype.getDay.
dayNum = dayNum || 0;
// Calculate the number of days between start and end.
var daysInInterval = Math.ceil((end.getTime() - start.getTime()) / (1000 * 3600 * 24));
// Calculate the nb of days before the next target day (e.g. next Sunday after start).
var toNextTargetDay = (7 + dayNum - start.getDay()) % 7;
// Calculate the number of days from the first target day to the end.
var daysFromFirstTargetDay = Math.max(daysInInterval - toNextTargetDay, 0);
// Calculate the number of weeks (even partial) from the first target day to the end.
return Math.ceil(daysFromFirstTargetDay / 7);
}
var start = new Date("2016-05-25");
var finish = new Date("2016-05-31");
console.log("Start:", start);
console.log("Start's week day num:", start.getDay());
console.log("Finish:", finish);
console.log("Finish's week day num:", finish.getDay());
console.log("Number of Sundays:", getNumberOfWeekDays(start, finish));

Your date format and comparison condition should change like the following:
var start = new Date("2016-05-11");
var finish = new Date("2016-05-31");
var dayMilliseconds = 1000 * 60 * 60 * 24;
var weekendDays = 0;
while (start.getTime() <= finish.getTime()) {
var day = start.getDay();
if (day == 0) {
weekendDays++;
}
start = new Date(+start + dayMilliseconds);
}
alert(weekendDays);
Check Fiddle

You are using incorrect date format.
Just Change the format to:
var start = new Date(2016, 4, 25);
var finish = new Date(2016, 4, 31);

Try this function:
function CalculateWeekendDays(fromDate, toDate){
var weekendDayCount = 0;
while(fromDate < toDate){
fromDate.setDate(fromDate.getDate() + 1);
if(fromDate.getDay() === 0){
++weekendDayCount ;
}
}
return weekendDayCount ;
}
console.log(CalculateWeekendDays(new Date(2011, 6, 2), new Date(2011, 7, 2)));
This will give you number of sunday come between 2 dates

change your date format.It will work
var start = new Date("05-16-2016");
var finish = new Date("05-31-2016");
var dayMilliseconds = 1000 * 60 * 60 * 24;
var weekendDays = 0;
while (start <= finish) {
var day = start.getDay()
if (day == 0) {
weekendDays++;
}
start = new Date(+start + dayMilliseconds);
}
console.log(weekendDays);

JS date format doesn't have "dd-MM-yyyy" ,so it will invalid date format .Try recreate date is ok or just change your date format Date Format
Try this:
var start = new Date("25-05-2016");
var end = new Date("31-05-2016");
var startDate = new Date(start);
var endDate = new Date(end);
var totalSundays = 0;
for (var i = startDate; i <= endDate; ){
if (i.getDay() == 0){
totalSundays++;
}
i.setTime(i.getTime() + 1000*60*60*24);
}
console.log(totalSundays);

// Find date of sundays b/w two dates
var fromDate = new Date('2022-10-26')
var toDate = new Date('2022-11-31')
var sunday = 0
var milisec = 1000 * 60 * 60 * 24;
while (fromDate <= toDate) {
var day = fromDate.getDay()
if (day == 0) {
sunday++
console.log('Date of sunday:', fromDate)
}
fromDate = new Date(+fromDate + milisec)
}
console.log('Total no. of sundays:', sunday)