I need a regular expression in Javascript for Indian vehicle NUMBER.
Expression should match following patterns.
GL/48/ED/1220
MH/24/ L/3654
I have tried following pattern but didn't work.
str = "MH/14/AA/2000";
var pattern = /[A-Za-z][A-Za-z]/[0-9][0-9]/[A-Za-z ][a-z]/[0-9][0-9][0-9][0-9]$/;
var result = str.match(pattern);
console.log(result);
result gives null.
Anyone have solution for it?
There are three problems
Un-escaped /
/ will end your regular expression, so you need to escape those which are in the middle of it
var pattern = /[A-Za-z][A-Za-z]\/[0-9][0-9]\/[A-Za-z ][a-z]\/[0-9][0-9][0-9][0-9]$/;
typo - pattern instead of patt1
i.e.
var result = str.match(pattern);
case-sensitive matching
Either use [A-Z] with i to ignore case-sensitive matching or just use [A-Z] in all of them
Finally
str = "MH/14/AA/2000";
var pattern = /[A-Z][A-Z]\/[0-9][0-9]\/[A-Z][A-Z]\/[0-9][0-9][0-9][0-9]$/i;
var result = str.match(pattern);
console.log(result);
Less verbose version
str = "MH/14/AA/2000";
var pattern = /[A-Z]{2}\/[0-9]{2}\/[A-Z]{2}\/\d{4}$/i;
var result = str.match(pattern);
console.log(result);
var pattern = /[A-Za-z][A-Za-z]/[0-9][0-9]/[A-Za-z ][A-Za-z]/[0-9][0-9][0-9][0-9]$/;
The diff to your expression is:
The slashes / need to be escaped with backslash \, the second part of letters missed the uppercase A-Z
Related
How i can select RQR-1BN6Q360090-0001 (without quotes) using Regex in below -
<html><head><title>Object moved</title></head><body>
<h2>Object moved to here.</h2>
</body></html>
I tried this but it does not work
RptNum=([A-Za-z]+)$
You may use
/RptNum=([\w-]+)/
The pattern will match RptNum= and then capture 1 or more occurrences of word chars (letters, digits and _) or hyphens. See the regex demo and the regex graph:
Note that
/RptNum=([A-Z0-9-]+)/
might be a more restrictive pattern that should work, too. It does not match _ and lowercase letters.
In JS, use it with String#match() and grab the second array item upon a match:
var s = 'Object moved to here';
var m = s.match(/RptNum=([\w-]+)/);
if (m) {
console.log(m[1]);
}
Here, we can also use an expression that collects the new lines, such as:
[\s\S]*RptNum=(.+?)"[\s\S]*
[\w\W]*RptNum=(.+?)"[\w\W]*
[\d\D]*RptNum=(.+?)"[\d\D]*
and our desired output is saved in (.+?).
Test
const regex = /[\s\S]*RptNum=(.+?)"[\s\S]*/gm;
const str = `<html><head><title>Object moved</title></head><body>
<h2>Object moved to here.</h2>
</body></html>`;
const subst = `$1`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log(result);
Demo
RegEx
If this expression wasn't desired, it can be modified/changed in regex101.com.
RegEx Circuit
jex.im visualizes regular expressions:
const text = 'RptNum=RQR-1BN6Q360090-0001';
console.log(text.match(/RptNum=.*/).map(m => m.match(/RptNum=.*/)[0])[0].split('RptNum=')[1]);
I suppose that works
match a path for a specific word and a / and any characters that follow.
For example.
const str = 'cars/ford';
const isCars = str.match('cars');
What I want to do is make sure it matches cars and has a slash and characters after the / then return true or false.
The characters after cars/... will change so I can't match it excatly. Just need to match any characters along with the /
Would love to use regex not sure what it should be. Looking into how to achieve that via regex tutorials.
var str = "cars/ford";
var patt = new RegExp("^cars/"); //or var patt = /^cars\//
var res = patt.test(str); //true
console.log(res);
https://www.w3schools.com/js/js_regexp.asp
https://www.rexegg.com/regex-quickstart.html
You could use test() that returns true or false.
const str = "cars/ford";
const str2 = "cars/";
var isCars = (str)=>/^cars\/./i.test(str)
console.log(isCars(str));
console.log(isCars(str2));
Here is a quick regex to match "cars/" followed by any characters a-z.
(cars\/[a-z]+)
This will only match lowercase letters, so you can add the i flag to make it case insensitive.
/(cars\/[a-z]+)/i
It is a basic regular expression
var str = "cars/ford"
var result = str.match(/^cars\/(.*)$/)
console.log(result)
^ - start
cars - match exact characters
\/ - match /, the \ escapes it
(.*) - capture group, match anything
$ - end of line
Visualize it: RegExper
I have regexp that extracts values between parentheses.
It's working most of the time but not when it ends with a parentheses
var val = 'STR("ABC(t)")';
var regExp = /\(([^)]+)\)/;.
var matches = regExp.exec(val);
console.log(matches[1]); //"ABC(t"
What I want is "ABC(t)".
Any ideas how I can modify my regexp to Achive this?
Update
The value is always inside the parentheses.
Some examples:
'ASD("123")'; => '123'
'ASD(123)'; => '123'
'ASD(aa(10)asda(459))'; => 'aa(10)asda(459)'
So first there is some text (always text). Then there is a (, and it always ends with a ). I want the value between.
You may use greedy dot matching inside Group 1 pattern: /\((.+)\)/. It will match the first (, then any 1+ chars other than linebreak symbols and then the last ) in the line.
var vals = ['STR("ABC(t)")', 'ASD("123")', 'ASD(123)', 'ASD(aa(10)asda(459))'];
var regExp = /\((.+)\)/;
for (var val of vals) {
var matches = regExp.exec(val);
console.log(val, "=>", matches[1]);
}
Answering the comment: If the texts to extract must be inside nested balanced parentheses, either a small parsing code, or XRegExp#matchRecursive can help. Since there are lots of parsing codes around on SO, I will provide XRegExp example:
var str = 'some text (num(10a ) ss) STR("ABC(t)")';
var res = XRegExp.matchRecursive(str, '\\(', '\\)', 'g');
console.log(res);
<script src="https://cdnjs.cloudflare.com/ajax/libs/xregexp/2.0.0/xregexp-all-min.js"></script>
In javascript, how do I remove all special characters from the string except the semi-colon?
sample string: ABC/D A.b.c.;Qwerty
should return: ABCDAbc;Qwerty
You can use a regex that removes anything that isn't an alpha character or a semicolon like this /[^A-Za-z;]/g.
const str = "ABC/D A.b.c.;Qwerty";
const result = str.replace(/[^A-Za-z;]/g, "");
console.log(result);
var str = "ABC/D A.b.c.;Qwerty";
var result = str.replace(/[^A-Za-z;]/g, ""); // 21ABCDAbc;Qwerty
Live DEMO
I wrote a regular expression which I expect should work but it doesn't.
var regex = new RegExp('(?<=\[)[0-9]+(?=\])')
JavaScript is giving me the error：
Invalid regular expression :(/(?<=[)[0-9]+(?=])/): Invalid group
Does JavaScript not support lookahead or lookbehind?
This should work:
var regex = /\[[0-9]+\]/;
edit: with a grouping operator to target just the number:
var regex = /\[([0-9]+)\]/;
With this expression, you could do something like this:
var matches = someStringVar.match(regex);
if (null != matches) {
var num = matches[1];
}
Lookahead is supported, but not lookbehind. You can get close, with a bit of trickery.
To increment multiple numbers in the form of lets say:
var str = '/a/b/[123]/c/[4567]/[2]/69';
Try:
str.replace(/\[(\d+)\]/g, function(m, p1){
return '['+(p1*1+1)+']' }
)
//Gives you => '/a/b/[124]/c/[4568]/[3]/69'
If you're quoting a RegExp, watch out for double escaping your backslashes.