I have first data object which has a list of cafe, and second data object which has a list of cafe types.
I need find, get and display the corresponding type value from first data object and ID value from second data object.
For example: in list of cafe, I have Pinta with "type" : "3", it means that 3 is Bar from second object.
First object:
{
"list": {
"item": [
{
"ID": "31",
"name": "Staut",
"type": "1",
},
{
"ID": "34",
"name": "Pinta",
"type": "3",
}
]
}
}
And second object:
{
"list": {
"item": [
{
"ID": "1",
"name": "Restaurant",
},
{
"ID": "2",
"name": "Cafe",
},
{
"ID": "3",
"name": "Bar",
}
]
}
}
I can do it with Lodash. It is right, but I can't display it and it uses high memory.
getValues: function() {
_.forEach(CafeJSON.list.item, function(cafeValue) {
_.forEach(TypeJSON.list.item, function(typeValue){
if (cafeValue.type == typeValue.ID) {
console.log("Cafe name is: ", cafeValue.name, "and type is: ", typeValue.name)
}
})
})
}
Result:
I'd simplify the types object down to a object having key value pairs in the form of '3': 'Bar', then loop the items once, overriding the type property's value.
let list = {
"list": {
"item": [{
"ID": "31",
"name": "Staut",
"type": "1",
},
{
"ID": "34",
"name": "Pinta",
"type": "3",
}
]
}
}
let types = {
"list": {
"item": [{
"ID": "1",
"name": "Restaurant",
},
{
"ID": "2",
"name": "Cafe",
},
{
"ID": "3",
"name": "Bar",
}
]
}
}
let typesSimplified = types.list.item.reduce((a, b) => {
a[b.ID] = b.name;
return a;
}, {});
list.list.item.forEach(e => {
e.type = typesSimplified[e.type];
});
console.log(list);
Related
Is it possible to use the find() method within an array of depth x?
For example, suppose I have the following array of objects, call it test:
[
{
"id": "1",
"title": "First",
},
{
"id": "2",
"title": "Second",
"movies": [
{
"id": "3",
"title": "Happy Gilmore",
"Actors": [
{
"id": "4",
"title": "John Doe",
},
{
"id": "5",
"title": "Jane Doe",
},
],
"Producers": [
{
"id": "6",
"title": "Max Smith",
},
{
"id": "7",
"title": "Richard Rocky",
},
],
},
{
"id": "10",
"title": "Billy Madison",
"Actors": [
{
"id": "40",
"title": "John Smith",
},
{
"id": "50",
"title": "Alex Doe",
},
],
"Producers": [
{
"id": "60",
"title": "Bob Smith",
},
{
"id": "70",
"title": "Polly Rocky",
},
],
}
]
}
]
Suppose I am looking for the "2" id. I can use the find() method to search the first level of the array and return the desired object by doing test.find(element => element.id === "2").
However, suppose I am now looking for the occurrence where the id is 4. As you can see from the above JSON, that element is within a sub array within test. Is there a way therefore where I can still search through test to find the element where id=4?
find cannot do this, but you can use it in a recursive approach:
function findDeep(arr, predicate) {
let res = arr.find(predicate);
if (res !== undefined) return res;
for (let obj of arr) {
for (let value of Object.values(Object(obj)).filter(Array.isArray)) {
res = findDeep(value, predicate);
if (res !== undefined) return res;
}
}
}
let test = [{"id": "1","title": "First",},{"id": "2","title": "Second","movies": [{"id": "3","title": "Happy Gilmore","Actors": [{"id": "4","title": "John Doe",},{"id": "5","title": "Jane Doe",},],"Producers": [{"id": "6","title": "Max Smith",},{"id": "7","title": "Richard Rocky",},],},{"id": "10","title": "Billy Madison","Actors": [{"id": "40","title": "John Smith",},{"id": "50","title": "Alex Doe",},],"Producers": [{"id": "60","title": "Bob Smith",},{"id": "70","title": "Polly Rocky",},],}]}];
let res = findDeep(test, obj => obj.id == "4");
console.log(res);
How can I concatenate this json to obtain it:
complements = ["XYZ 3, CDE TR, AAA 5", "", "NDP 3, DDD FR"] ?
Each address can contain a set of complements which must be concatenated and separated by a comma.
P.s: I'm using javascript.
P.s2: Complements can be null like in the second group in JSON.
[
{
"postalcode": "1234",
"street": "ABC",
"number": "1",
"complement": [
{
"type": "B",
"name": "XYZ",
"description": "3"
},
{
"type": "C",
"name": "CDE",
"description": "TR"
},
{
"type": "D",
"name": "AAA",
"description": "5"
}
]
},
{
"postalcode": "444",
"street": "No complements",
"number": "5"
},
{
"postalcode": "2222",
"street": "BBB",
"number": "2",
"complement": [
{
"type": "E",
"name": "NDP",
"description": "3"
},
{
"type": "F",
"name": "DDD",
"description": "FR"
}
]
}
];
My code I'm getting this.complementsList.forEach is not a function.
getComplement(addressesResponse){
this.complementsList = JSON.parse(addressesResponse);
this.complementsList.forEach((item) => {
Object.defineProperty(item, 'complements', {
get: function() {
return this.complement.map((c) => `${c.name} ${c.description}`).join(', '); }
})
});
Source: https://salesforce.stackexchange.com/questions/367713/how-to-render-a-json-in-the-same-line-lwc
how i solved it :
arr.map((x)=>x.complement != null? (x.complement.map((y)=>y.name+' '+y.description)+"") :'');
Having a javascript object, you can go through the keys of the object and combine some of them into strings
It will look something like this:
const jsonObject = [{...}, {...}, ...]
const complements = [];
jsonObject.forEach((item) => {
let complement = item['complement'].reduce((result, currObj)
=> result += (currObj.name+' '+currObj.description), "");
complements.push(complement);
});
This is just an example. There are many ways to do it.
I have an object that looks like the following {key: id numbers}
var obj = {
"c4ecb": {id: [3]},
"a4269": {id: [34,36]},
"d76fa": {id: [54,55,60,61]},
"58cb5": {id: [67]}
}
How do I loop each above id in the following array, and return the label?
var response =
{
"success": true,
"data": [
{
"key": "c4ecb",
"name": "fruits",
"options": [
{
"label": "strawberry",
"id": 3
},
{
"label": "apple",
"id": 4
},
{
"label": "pineapple",
"id": 5
},
{
"label": "Other",
"id": 31
}
],
}
]
},
{
"success": true,
"data": [
{
"key": "a4269",
"name": "vegetables",
"options": [
{
"label": "lettuce",
"id": 34
},
{
"label": "cucumber",
"id": 35
},
{
"label": "radish",
"id": 36
}
],
}
]
},
{
"success": true,
"data": [
{
"key": "d76fa",
"name": "pasta",
"options": [
{
"label": "spaghetti",
"id": 54
},
{
"label": "rigatoni",
"id": 55
},
{
"label": "linguine",
"id": 56
},
{
"label": "lasagna",
"id": 60
},
{
"label": "fettuccine",
"id": 61
}
],
}
]
}
Finally, what I want to do is look up the key and return a string of id values.
For example, input c4ecb and output strawberry. Input a4269 and output lettuce, radish. Input d76fa and output "spaghetti, rigatoni, lasagna, fettuccine"
I think to join the multiple labels output into one string I could use something like
array.data.vegetables.map(vegetables => vegetables.value).join(', ')].toString();
So in the end I want to have something like
var fruits = [some code that outputs "strawberry"];
var vegetables = [some code that outputs "lettuce, radish"];
var pasta = [some code that outputs "spaghetti, rigatoni, lasagna, fettuccine"];
What I've tried so far:
The following loop will return the id only if there is one id to be called for: e.g. only in case one where {id: 3} but returns null in cases like {id: 34,36} (because it's looking for '34,36' in id, which doesn't exist - I need to look for each one individually.
response.data.forEach(({key, options}) => {
if (obj[key]) {
options.forEach(({id, label}) => {
if (id == obj[key].id) obj[key].label = label;
});
}
});
console.log(obj)
Filter the response object to focus on the category that matches the id.
Map over the options array and select the items which appear in obj[id].
Finally convert the filtered results to a string.
See filteredLabelsAsString() function below for implementation.
var obj = {
"c4ecb": {"id": [3]},
"a4269": {"id": [34,36]},
"d76fa": {"id": [54,55,60,61]},
"58cb5": {"id": [67]}
}
var response =
[{
"success": true,
"data": [
{
"key": "c4ecb",
"name": "fruits",
"options": [
{
"label": "strawberry",
"id": 3
},
{
"label": "apple",
"id": 4
},
{
"label": "pineapple",
"id": 5
},
{
"label": "Other",
"id": 31
}
],
}
]
},
{
"success": true,
"data": [
{
"key": "a4269",
"name": "vegetables",
"options": [
{
"label": "lettuce",
"id": 34
},
{
"label": "cucumber",
"id": 35
},
{
"label": "radish",
"id": 36
}
],
}
]
},
{
"success": true,
"data": [
{
"key": "d76fa",
"name": "pasta",
"options": [
{
"label": "spaghetti",
"id": 54
},
{
"label": "rigatoni",
"id": 55
},
{
"label": "linguine",
"id": 56
},
{
"label": "lasagna",
"id": 60
},
{
"label": "fettuccine",
"id": 61
}
],
}
]
}];
function filteredLabelsAsString(obj_key, obj, content=response) {
// sanity check: obj must contain obj_key
if (Object.keys(obj).includes(obj_key)) {
return content.filter((item) => {
// filter content using value of obj_key
return item.data[0].key == obj_key;
}).map((item) => {
// item : { success: true, data: [] }
// map over options array
return item.data[0].options.map((opt) => {
// option : {id, label}
// return the label if the id is in the obj object's list
if (obj[item.data[0].key].id.includes(opt.id))
return opt.label;
}).filter((label) => {
// filter out empty items
return label !== undefined;
});
}).join(",");
}
// if obj does not contain obj_key return empty string
return "";
}
console.log("fruits: " + filteredLabelsAsString("c4ecb", obj));
console.log("vegetables: " + filteredLabelsAsString("a4269", obj));
console.log("pasta: " + filteredLabelsAsString("d76fa", obj));
Check for the decimal id and group them accordingly.
Below are the sample and recommended JSON's
Sample JSON
{
"results": [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
},
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
},
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
},
{
"name": "Download",
"id": "4.2"
}
]
}
Would like to iterate and Re-structure the above JSON into below recommended format.
Logic: Should check the id(with and without decimals) and group them based on the number.
For Example:
1, 1.1, 1.2.3, 1.4.5 => data1: [{id: 1},{id: 1.1}....]
2, 2.3, 2.3.4 => data2: [{id: 2},{id: 2.3}....]
3, 3.1 => data3: [{id: 3},{id: 3.1}]
Recommended JSON
{
"results": [
{
"data1": [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
}
]
},
{
"data2": [
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
}
]
},
{
"data3": [
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
}
]
},
{
"data4": [
{
"name": "Download",
"id": "4.2"
}
]
}
]
}
I have tried the below solution but it doesn't group the object
var formatedJSON = [];
results.map(function(d,i) {
formatedJSON.push({
[data+i]: d
})
});
Thanks in advance.
You can use reduce like this. The idea is to create a key-value pair for each data1, data2 etc so that values in this object are the values you need in the final array. Then use Object.values to get those as an array.
const sampleJson = {"results":[{"name":"Download","id":"1.1.1"},{"name":"Download","id":"1.2"},{"name":"Download","id":"1.3.2"},{"name":"Download","id":"2"},{"name":"Download","id":"2.3"},{"name":"Download","id":"3.2"},{"name":"Download","id":"3.5"},{"name":"Download","id":"4.2"}]}
const grouped = sampleJson.results.reduce((a, v) => {
const key = `data${parseInt(v.id)}`;
(a[key] = a[key] || {[key]: []})[key].push(v);
return a;
},{});
console.log({results: Object.values(grouped)})
One liner / Code-golf:
let s={"results":[{"name":"Download","id":"1.1.1"},{"name":"Download","id":"1.2"},{"name":"Download","id":"1.3.2"},{"name":"Download","id":"2"},{"name":"Download","id":"2.3"},{"name":"Download","id":"3.2"},{"name":"Download","id":"3.5"},{"name":"Download","id":"4.2"}]},k;
console.log({results:Object.values(s.results.reduce((a,v)=>(k=`data${parseInt(v.id)}`,(a[k] = a[k]||{[k]:[]})[k].push(v),a),{}))})
Here you go:
var data = {
"results": [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
},
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
},
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
},
{
"name": "Download",
"id": "4.2"
}
]
};
let newSet = new Set();
data.results.forEach(e => {
let key = e.id.substring(0, e.id.indexOf('.'));
console.log(key);
if (newSet.has(key) == false) {
newSet.add(key);
newSet[key] = [];
}
newSet[key].push(e.id);
});
console.log(newSet);
Here's how you'd do it:
var data = {
"results": [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
},
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
},
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
},
{
"name": "Download",
"id": "4.2"
}
]
};
var newData = {
"results": {}
};
data.results.forEach(item => {
var num = item.id.slice(0, 1);
if (newData.results["data" + num]) {
newData.results["data" + num].push(item);
} else {
newData.results["data" + num] = [item];
}
})
data = newData;
console.log(data);
What this does is it iterates through each item in results, gets the number at the front of this item's id, and checks if an array of the name data-{num} exists. If the array exists, it's pushed. If it doesn't exist, it's created with the item.
let input = getInput();
let output = input.reduce((acc, curr)=>{
let {id} = curr;
let majorVersion = 'name' + id.split('.')[0];
if(!acc[majorVersion]) acc[majorVersion]= [];
acc[majorVersion].push(curr);
return acc;
},{})
console.log(output)
function getInput(){
return [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
},
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
},
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
},
{
"name": "Download",
"id": "4.2"
}
]
}
One solution with RegEx for finer control as it would differentiate easily between 1 and 11.
Also this will make sure that even if the same version comes in end(say 1.9 in end) it will put it back in data1.
let newArr2 = ({ results }) =>
results.reduce((acc, item) => {
let key = "data" + /^(\d+)\.?.*/.exec(item.id)[1];
let found = acc.find(i => key in i);
found ? found[key].push(item) : acc.push({ [key]: [item] });
return acc;
}, []);
I am trying to merge two json array with objects as element. You may refer to this plunkr file for both json. I have succesfully retrieve the expected final outcome array id, but I do not know how to form back the expected json as below. I am using underscore js for this purpose.
Note: If object exist in newJson and not in currentJson, after merge, it will be inactive state by default.
I am not sure whether I am using the correct approach. This is what I have try:
var newJsonID = _.pluck(newJson, 'id');
var currentJsonID = _.pluck(currentJson, 'id');
var union = _.union(newJsonID, currentJsonID);
var intersection = _.intersection(currentJsonID, newJsonID);
var final = _.difference(union, _.difference( currentJsonID, intersection);
Expected Final Outcome:
[
{
"id": "12",
"property1Name": "1"
"status": "inactive"
},
{
"id": "11",
"property1Name": "1"
"status": "inactive"
},
{
"id": "10",
"property1Name": "1"
"status": "inactive"
},
{
"id": "9",
"property1Name": "1"
"status": "active"
}
]
A solution in plain Javascript with two loops and a hash table for lookup.
function update(newArray, currentArray) {
var hash = Object.create(null);
currentArray.forEach(function (a) {
hash[a.id] = a.status;
});
newArray.forEach(function (a) {
a.status = hash[a.id] || 'inactive';
});
}
var newJson = [{ "id": "12", "property1Name": "1" }, { "id": "11", "property1Name": "1" }, { "id": "10", "property1Name": "1" }, { "id": "9", "property1Name": "1" }],
currentJson = [{ "id": "10", "property1Name": "1", "status": "inactive" }, { "id": "9", "property1Name": "1", "status": "active" }, { "id": "8", "property1Name": "1", "status": "active" }, { "id": "7", "property1Name": "1", "status": "inactive" }];
update(newJson, currentJson);
document.write('<pre>' + JSON.stringify(newJson, 0, 4) + '</pre>');