I am developing a webpage where multiple posts from the Database is shown one by one in a single page much like twitter or facebook.
I need to use Ajax for comments and likes. The comment system should be nested as well.
The problem I am having is each post is having a unique post_id and I need to transfer it through Ajax for inserting the comments into the DB.
The below HTML is inside a PHP for loop for getting the posts from Database. So I have given post_id as every comment element's id to get the unique post comment.
<script>
function addcomment(abc) {
var temp1 = abc;
var post_id = temp1.value; // POST ID
var comment = document.getElementById(post_id).value;
$.ajax({
type: "POST",
url: "addcomment.php",
data: {
post_id:post_id,
comment:comment
},
success: function(response) {
document.getElementsByClassName(post_id).innerHTML = response;
}
});
}
</script>
<div class="comment_section" id="comment_section">
<textarea type="text" id="<?php echo($post_id); ?>" placeholder="comment Here..." value=""></textarea>
<button id="comment_button" value="<?php echo ($post_id); ?>" onclick="return addcomment(this);">Comment</button>
<br>
<span class="<?php echo($post_id); ?>"></span>
</div>
And the addcomment.php looks like this:
<?php
include("connect.php");
$postid = $_POST['post_id'];
$comment = $_POST['comment'];
$sql1 = "INSERT INTO comments (name,comment) VALUES ('$postid','$comment')";
$result = $db->query($sql1);
$sql = "SELECT * FROM comments ORDER BY id DESC LIMIT 0,1";
$result1 = $db->query($sql);
while($row = $result1->fetch_assoc()) {
$post = $row['name'];
$comment_op = $row['comment'];
?>
<?php echo $comment_op; ?>
<br>
<?php echo $post; ?>
<?php } ?>
How can I get the comment when the Comment button clicked and store it in the DB and return the Comment below the comment area using AJAX ?
For display comments on specific post first you create comment section and use
<section id="comments-post_id"></section>
when you successfully add comment via above ajax request code get the response and create comment html and append in your comment section.
$("#comments-post_id").html($response);
make sure you have already create your comment HTML in controller or in ajax file where you get the response.
and for the rendering all post data user inside loop or recursive function to get all comments of your specific post
Need more help feel free and ask :)
Related
I am creating a website that contains different movies, every movie has a specific id_movie, i have added a comment box where the user can add a comment about the movie, however, every movie i click on, they all show the same comments that have been entered, I want every movie to have its own comments, I will be happy if you can help me with that. thanks
comments.php
<body>
<br />
<h2 align="center"><p >Add Comment</p></h2>
<br />
<div class="container">
<form method="POST" id="comment_form">
<div class="form-group">
<input type="text" name="comment_name" id="comment_name" class="form-control" placeholder="Enter Name" />
</div>
<div class="form-group">
<textarea name="comment_content" id="comment_content" class="form-control" placeholder="Enter Comment" rows="5"></textarea>
</div>
<div class="form-group">
<input type="hidden" name="comment_id" id="comment_id" value="0" />
<input type="submit" name="submit" id="submit" class="btn btn-info" value="Submit" />
</div>
</form>
<span id="comment_message"></span>
<br />
<div id="display_comment"></div>
</div>
</body>
<script>
$(document).ready(function(){
$('#comment_form').on('submit', function(event){
event.preventDefault();
var form_data = $(this).serialize();
$.ajax({
url:"add_comment.php",
method:"POST",
data:form_data,
dataType:"JSON",
success:function(data)
{
if(data.error != '')
{
$('#comment_form')[0].reset();
$('#comment_message').html(data.error);
$('#comment_id').val('0');
load_comment();
}
}
})
});
load_comment();
function load_comment()
{
$.ajax({
url:"fetch_comment.php",
method:"POST",
success:function(data)
{
$('#display_comment').html(data);
}
})
}
$(document).on('click', '.reply', function(){
var comment_id = $(this).attr("id");
$('#comment_id').val(comment_id);
$('#comment_name').focus();
});
});
</script>
add_comment.php
<?php
$con = new PDO('mysql:host=localhost;dbname=db_movie', 'root', '');
$error = '';
$comment_name = '';
$comment_content = '';
if(empty($_POST["comment_name"]))
{
$error .= '<p class="text-danger">Name is required</p>';
}
else
{
$comment_name = $_POST["comment_name"];
}
if(empty($_POST["comment_content"]))
{
$error .= '<p class="text-danger">Comment is required</p>';
}
else
{
$comment_content = $_POST["comment_content"];
}
if($error == '')
{
$query = "
INSERT INTO tbl_comment
(parent_comment_id, comment, comment_sender_name, movie_id)
VALUES (:parent_comment_id, :comment, :comment_sender_name)
";
$statement = $con->prepare($query);
$statement->execute(
array(
':parent_comment_id' => $_POST["comment_id"],
':comment' => $comment_content,
':comment_sender_name' => $comment_name
)
);
$error = '<label class="text-success">Comment Added</label>';
}
$data = array(
'error' => $error
);
echo json_encode($data);
?>
fetch_comment.php
<?php
//fetch_comment.php
$con = new PDO('mysql:host=localhost;dbname=db_movie', 'root', '');
$query = "
SELECT * FROM tbl_comment
WHERE parent_comment_id = '0'
ORDER BY comment_id DESC
";
$statement = $con->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
$output = '';
foreach($result as $row)
{
$output .= '
<div class="panel panel-default">
<div class="panel-heading">By <b>'.$row["comment_sender_name"].'</b> on <i>'.$row["date"].'</i></div>
<div class="panel-body">'.$row["comment"].'</div>
<div class="panel-footer" align="right"><button type="button" class="btn btn-default reply" id="'.$row["comment_id"].'">Reply</button></div>
</div>
';
$output .= get_reply_comment($con, $row["comment_id"]);
}
echo $output;
function get_reply_comment($con, $parent_id = 0, $marginleft = 0)
{
$query = "
SELECT * FROM tbl_comment WHERE parent_comment_id = '".$parent_id."'
";
$output = '';
$statement = $con->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
$count = $statement->rowCount();
if($parent_id == 0)
{
$marginleft = 0;
}
else
{
$marginleft = $marginleft + 48;
}
if($count > 0)
{
foreach($result as $row)
{
$output .= '
<div class="panel panel-default" style="margin-left:'.$marginleft.'px">
<div class="panel-heading">By <b>'.$row["comment_sender_name"].'</b> on <i>'.$row["date"].'</i></div>
<div class="panel-body">'.$row["comment"].'</div>
<div class="panel-footer" align="right"><button type="button" class="btn btn-default reply" id="'.$row["comment_id"].'">Reply</button></div>
</div>
';
$output .= get_reply_comment($con, $row["comment_id"], $marginleft);
}
}
return $output;
}
?>
and here when I click on each movie:
<?php include('header.php');
$qry2=mysqli_query($con,"select * from tbl_movie where movie_id='".$_GET['id']."'");
$movie=mysqli_fetch_array($qry2);
?>
<div class="content">
<div class="wrap">
<div class="content-top">
<div class="section group">
<div class="about span_1_of_2">
<h3><?php echo $movie['movie_name']; ?></h3>
<div class="about-top">
<div class="grid images_3_of_2">
<img src="<?php echo $movie['image']; ?>" width="180px" height="280px" alt=""/>
<?php include('ratte.php'); ?>
</div>
<div class="desc span_3_of_2">
<p class="p-link" style="font-size:15px">Type: <?php echo $movie['type']; ?></p>
<p class="p-link" style="font-size:15px">Price: £<?php echo date($movie['price']); ?></p>
<p style="font-size:15px"><?php echo $movie['desc']; ?></p>
Watch Trailer
</div>
<div class="clear"></div>
</div>
<?php $s=mysqli_query($con,"select DISTINCT theatre_id from tbl_shows where movie_id='".$movie['movie_id']."'");
if(mysqli_num_rows($s))
{?>
<table class="table table-hover table-bordered text-center">
<?php
while($shw=mysqli_fetch_array($s))
{
$t=mysqli_query($con,"select * from tbl_theatre where id='".$shw['theatre_id']."'");
$theatre=mysqli_fetch_array($t);
?>
<tr>
<td>
<?php echo $theatre['name'].", ".$theatre['place'];?>
</td>
<td>
<?php $tr=mysqli_query($con,"select * from tbl_shows where movie_id='".$movie['movie_id']."' and theatre_id='".$shw['theatre_id']."'");
while($shh=mysqli_fetch_array($tr))
{
$ttm=mysqli_query($con,"select * from tbl_show_time where st_id='".$shh['st_id']."'");
$ttme=mysqli_fetch_array($ttm);
?>
<button class="btn btn-default"><?php echo date('h:i A',strtotime($ttme['start_time']));?></button>
<?php
}
?>
</td>
</tr>
<?php
}
?>
</table>
<div id='display_comment'></div>
<?php
}
else
{
?>
<h3>No Show Available</h3>
<div id='display_comment'></div>
<?php
}
?>
</div>
<?php include('related-movies.php');
?>
</div>
<div class="clear"></div>
</div>
<?php include('comments.php'); ?>
</div>
</div>
<?php include('footer.php'); ?>
I'll try my best, but there is a lot to cover.
comments.php
//add the target files URL as the form's action
<form method="POST" id="comment_form" action="add_comment.php" >
//add movie to the form, that way when we insert the comment we know what its for
<input type="hidden" name="movie_id" id="movie_id" value="<?php echo $movie_id; ?>" />
//.. in your JS, add the movie id to the fetch comment call
function load_comment()
{
$.ajax({
url:"fetch_comment.php",
method:"POST",
data: {movie_id : <?php echo $movie_id; ?>},
dataType: 'json',
success:function(data){
//...
})
}
//move this below the function definition
load_comment();
add_comment.php
//add movie id here to match what is in the form above
INSERT INTO tbl_comment
(parent_comment_id, comment, comment_sender_name, movie_id)
VALUES (:parent_comment_id, :comment, :comment_sender_name, :movie_id)
// add ':movie_id' => $_POST['movie_id'] to the array you have there for
// $statement->execute([ ....]). The arrays below go the same way
//add those to $statement->execute() for there respective DB calls,
You had the movie in the FIELDS part of the insert, but not the VALUES, which is probably an SQL syntax error. You may not have seen an actual error because this is called with AJAX so it would just break on the client side. You could look in the browser debug window > network [XHR] requests and look at the response. There you would probably find it or you may simply get a 500 error from the server.
fetch_comment.php
//add movie id here to match what is in the AJAX fetch comment call
SELECT * FROM tbl_comment
WHERE parent_comment_id = :parent_comment_id AND movie_id = :movie_id
ORDER BY comment_id DESC
//for execute add
['parent_comment_id'=>0, 'movie_id'=>$_POST['movie_id']]
Important prepare this query properly
$query = "
SELECT * FROM tbl_comment WHERE parent_comment_id = '".$parent_id."'
";
So it should be like this:
$query = "SELECT * FROM tbl_comment WHERE parent_comment_id = :parent_id";
//then add this to execute ['parent_id' => $parent_id]
mainpage.php (not sure the name on this one)
In the last unnamed code chunk you are using mysqli but above your using PDO it's better to use one or the other, personally I prefer PDO, its just better API wise. You are also not preparing these (so convert these to PDO). Using both just adds unnecessary complexity to your application (I think there were 2 of theses in there):
$qry2=mysqli_query($con,"select * from tbl_movie where movie_id='".$_GET['id']."'");
$movie=mysqli_fetch_array($qry2);
It looks like you include the comments.php into that last page <?php include('comments.php'); ?> So what I would do is where the query is above that I said to fix:
require_once `db.php`; //- create a separate file to do the DB connection for you
//then you can add that to the top of all the pages you need the DB for
include 'header.php'; //no need for the ( ) for any of the include* or require* calls.
/*
require will issue an error if the included file is not found
include will fail silently, for things that are required for your
page to work and not produce errors use require (like the DB)
for things you only ever include once, also like the DB stuff use *_once
then no matter how many *_once calls are stacked from including
the other page you don't have to worry about it.
as above those simple rules give us require_once for the DB.
the other pages I am not sure which would be best.
*/
//localize the movie ID - change any use of `$_GET['id']
$movie_id = isset($_GET['id']) ? $movie_id : false;
if(!$movie_id){
//do something if someone goes to this page with no ?id= in the URL
//you could redirect the page
//you could have a default movie id etc...
}
$statement = $con->prepare('select * from tbl_movie where movie_id=:movie_id');
$statement->execute(['movie_id' => $movie_id]);
$movie = $statement->fetch();
//dont forget to fix the other DB call and remove the MySqli stuff.
Above I suggest using a single file for the DB, in your case it can be quite simple,
db.php
<?php $con = new PDO('mysql:host=localhost;dbname=db_movie', 'root', '');
That is literally all you need then, at the very top of each page you use the DB, simply add this file
require_once 'db.php';
This way if you need to change the password or something like that, you can go to one place named in way that is easy to remember and change it. How it is now, you would have to dig though all your code to change it. In that page your including a file named header.php and it looks like from your MySQLi code that it may have some connection stuff in there. I would remove any MySQLi stuff there too. You want to keep the DB file separate as you may need to include it in the AJAX backend parts and any output from header.php would mess you up.
Summery
What I showed above is a simple example of what you need to do, in that AJAX call This may not be all you need to do, these are just the things that were obvious to me.
You don't have to worry about child comment's movie ID, as they inherit it from the parent comment, which wouldn't exist (on the page) if it had the wrong ID. In your current setup, I would still save it as part of the data. It's just you dont need it to get child comments if you know the parent (which you sort of have to know). I didn't add it into one thing that looked like it was for child comment. You can add it, but as I said above, it's not really needed.
Really the question is way to broad, why isn't my code working kind of question. The only reason I took the effort was that you also took the effort to provide well organized code that is relatively minimal.
So thank you for that.
The last suggestion I would make, is clean up the extra line returns in some of the SQL, and format the TABs a bit better. But that is just a readability issue, I am very picky about formatting my code and some of that could be related to creating an question on SO as it takes a bit of getting used the markdown they use.
Hope it helps you!
Update
thanks for your answer, I really dont know what i should post here and what i shouldnt, and the thing that i dont understand is that: i have a tbl_comment which stores all comments from user and this table include movie_id, and i have another tbl_movie which has movie_id as a primary key, how can i link the movie _id with the tbl_comment so that every comment is stored for a specific movie_id
I will try to explain the flow of your application, with an example. For the sake of this example lets say the movie id is 12 and our main page is www.example.com/movies?id=12:
Inserting a comment
User goes to a url with ?id=12
everything after the ? is called the query string
PHP knows to take the query string and populate the supper global $_GET
so in the main page your movie id is now $_GET['id']
We localize this (make a local variable) at the top of the page with some basic checks. $movie_id = isset($_GET['id']) ? $movie_id : false;
if movie id is set ?id=12 then put it in $movie_id
if its not www.example.com/movies then set $movie_id to false
this avoids some errors if someone goes to the page without that set
At the bottom of the page you include this file <?php include('comments.php'); ?> think of it like pasting that code into this place
In comments.php, which runs when it's included above,
if someone inserts a new comment (submits the form) weve added that same $movie_id into the form with this line
<input type="hidden" name="movie_id" id="movie_id" value="<?php echo $movie_id; ?>" />.
-So now when the form submits to add_comment.php which you need to put in the form's action.
<form method="POST" id="comment_form" action="add_comment.php" >
It will contain the id as $_POST['movie_id'] on that page. The $_POST['movie_id'] is basically the same as $_GET['id'] but the form method tells us its post instead of get. Typically Get is used to retrieve resources, Post is used to modify them.
When PHP runs the above piece of HTML it replaces the <?php echo $movie_id; ?> with it's value of 12 so you get this
<input type="hidden" name="movie_id" id="movie_id" value="12" />
Now On add_comment.php (where the form action takes us) we can take that $_POST['movie_id'] and add that to your SQL used to Insert the comment from the form in #4. into the Database.
INSERT INTO tbl_comment
(parent_comment_id, comment, comment_sender_name, movie_id)
VALUES (:parent_comment_id, :comment, :comment_sender_name, :movie_id)
As this is a prepared statement we have the place holder :movie_id in the SQL query. In PDO we can feed that to the PDOStatment object ($statement) you get back from $statment=$conn->prepare($sql) by calling it's execute method or $statement->execute([..other stuff here..., 'movie_id'=>$_POST['movie_id']]).
The query that runs looks like this after PHP is done with it
INSERT INTO tbl_comment
(parent_comment_id, comment, comment_sender_name, movie_id)
VALUES (0, 'foo', 'ArtisticPhoenix', 12) <-- see what I did there.
So you see we took the value from the original URL request, added it to our form and then we wait for user action to submit that form with the movie id embedded in it. The when the form submits it calls our add comment page, where we take it out of the Posted data, and feed it into the DB with the rest of the form data for that comment.
The other ones are exactly the same except in those we are using AJAX to submit the data so instead of a form we just add it to the AJAX call. I will give you an example of how that executes.
Showing a comment
This is the same up to #4 above
In comments.php you call load_comment(); "After" defining the function as it doesn't exist tell you do that, so you cant call it before.
This runs your AJAX request $.ajax, for the purposes of this example think of it like a fancy way to do a form. The url is the form action the method is well the method. The data is the form data, the dataType is the type of encoding in this case JSON or Javascript Object Notation. Which is a fancy way of saying structured data, as in PHP its basically an array (or data with nested elements).
The url (action) points us to fetch_comment.php, so when that runs our data: {movie_id : <?php echo $movie_id; ?>}, becomes data: {movie_id : 12}, which gets sent back to server where PHP sees it as $_POST['movie_id']
Similar to the Insert, we use that ID in our SQL query that pulls the parent comments
SELECT * FROM tbl_comment
WHERE parent_comment_id = :parent_comment_id AND movie_id = :movie_id
ORDER BY comment_id DESC
This says "Select all columns From table tbl_comment WHERE parent_comment_id IS 0 and Movie Id is 12" So it will only return comments for movie 12 that are also parents.
in your code you have just $statement->execute(); But you had the parent_comment_id hard coded as 0. This was fin until we needed to add the movie_id Once we did that it makes more senses to make it part of the prepared statement so it reads better. But like the insert, now we have place holder in place of values so we need to take that data and add it to execute for this query.
So $statement->execute(); becomes $statement->execute(['parent_comment_id'=>0, 'movie_id' => $_POST['movie_id']]); Or when PHP is done with it $statement->execute(['parent_comment_id'=>0, 'movie_id' => 12]); which the Database knows to use the keys to match the placeholders and it completes our query.
SELECT * FROM tbl_comment
WHERE parent_comment_id = 0 AND movie_id = 12
ORDER BY comment_id DESC
Then we take the results and send them back to the success handler for the AJAX with echo and in this case add it to the page with this line $('#display_comment').html(data);
So In conclusion
Your code:
load_comment();
function load_comment()
{
$.ajax({
url:"fetch_comment.php",
method:"POST",
success:function(data)
{
$('#display_comment').html(data);
}
})
}
Correct code (what I said):
//.. in your JS, add the movie id to the fetch comment call
function load_comment()
{
$.ajax({
url:"fetch_comment.php",
method:"POST",
data: {movie_id : <?php echo $movie_id; ?>},
dataType: 'json',
success:function(data){
//...
})
}
load_comment();
What you need to do
//$movie_id = $_GET['id'] in the main page that included this file.. #2 above
function load_comment()
{
$.ajax({
url:"fetch_comment.php",
method:"POST",
data: {movie_id : <?php echo $movie_id; ?>},
dataType: 'json',
success:function(data)
{
$('#display_comment').html(data);
}
});
}
load_comment();
When PHP completes the above code it sends this to the client (using 12 from our example)
//$movie_id = $_GET['id'] in the main page that included this file.. #2 above
function load_comment()
{
$.ajax({
url:"fetch_comment.php",
method:"POST",
data: {movie_id : 12}, //PHP takes the value of $movie_id and puts it here
dataType: 'json',
success:function(data)
{
$('#display_comment').html(data);
}
});
}
load_comment();
Above is what actually runs in the browser
That is pretty much the gist of it. As I said its more beneficial to you to learn how it works. Sure I can post the complete code but I have no way to test it, no way to know if that is all the errors or not. If you learn how it works, you will be better equipped to take on those challenges yourself. I would rather spend 3 or 4 times the effort teaching you how it all works, then to post some code that you have no idea how it works.
Hope that all makes some sense.
I'm learning PHP and SQL and as exercise I'm working on a page that is actually something like admin panel for a website that lists movies. I'm using lampp and phpmyadmin where I have created a simple database that contains two tables, movie list and users list.
Because I'm beginner and my code is probably messy, I'm describing what I tried to achieve. There's login.php page where the only functionality is typing username and password. If info matches info from SQL table, user proceeds to adminpanel.php.
This page should load a list of movies and create a table with that data. At the end of each row I want two buttons, edit and delete. What I'm trying to achieve is to delete current row where delete button is clicked, for delete button. Edit button should show hidden form just for the row where button was clicked. This form would contain button that actually updates data in SQL table after filling form and clicking the button. (I haven't added function that shows form yet, I care about buttons much more) Form for adding movies at the end of the file works.
Here's adminpanel.php
<html>
<head>
<script src="https://code.jquery.com/jquery-3.3.1.js"
integrity="sha256-2Kok7MbOyxpgUVvAk/HJ2jigOSYS2auK4Pfzbm7uH60="
crossorigin="anonymous">
</script>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/core.js"></script>
<script type="text/javascript" src="changes.js"></script>
<script type="text/javascript" src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css"></script>
<style type="text/css">
*{text-align: center;}
.skriveni_input{
display: none;
};
</style>
</head>
<?php
require_once('connection.php');
if(!isset($_POST['btnlogin'])){
exit;
}
$username = $_POST['username'];
$password = $_POST['password'];
$query = "SELECT usrname,password FROM usrs WHERE usrname='$username' AND password='$password' ";
$res = mysqli_query($conn,$query);
$rows = mysqli_num_rows($res);
if($rows == 1){
echo "Welcome ".$_POST['username']."<br><br>";
} else {
echo "<script>
alert('Wrong login info');
window.location.href='login.php';
</script>";
exit;
}
$query = "SELECT * FROM movies";
$result = $conn->query($query);
echo "<table align = center cellspacing = 0 border = 0;><thead><tr><th>Name</th><th>Year</th><th>Genre</th></tr></thead><tbody>";
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo '<td id="row_id" style="display:none;" value="'.$row["movie_id"].'">'.$row["movie_id"].'</td>';
echo '<td>'.$row["name"].'</td>';
echo '<td>'.$row["year"].'</td>';
echo '<td>'.$row["genre"].'</td>';
echo '<td><input type="submit" name="edit" value="edit" data-index="' . $row['movie_id'] . '" class="btnedit" id="btnedit"></input></td>';
echo '<td><input type="submit" name="delete" value="delete" class="btndlt" id="btndlt"></input></td>';
echo "</tr>";
echo "<tr>
<td><input type='text' class='hidden_input' id='hidden_name" . $row['movie_id'] . "'placeholder='hidden name'></input></td>
<td><input type='text' class='hidden_input' id='hidden_year" . $row['movie_id'] . "'placeholder='hidden year'></input></td>
<td><input type='text' class='hidden_input' id='hidden_genre" . $row['movie_id'] . "'placeholder='hidden genre'></input></td>
</tr>";
}
echo "</tbody></table>";
?>
<h3>Add movie form: </h3>
<form action="" method="POST">
<label for="movie_name">Movie name : </label>
<input type="text" name="movie_name" id="movie_name">
<br><br>
<label for="movie_year">Year: </label>
<input type="text" name="movie_year" id="movie_year">
<br><br>
<label for="movie_genre">Genre: </label>
<input type="text" name="movie_genre" id="movie_genre">
<br><br>
<input type="submit" name="submit_movie" id="submit_movie" value="Submit">
</form>
</html>
Here's my javascript file with ajax calls:
$(document).ready(function(e){
$('#submit_movie').click(function(e){
e.preventDefault();
var movie_name = $('#movie_name').val();
var movie_year = $('#movie_year').val();
var movie_genre = $('#movie_genre').val();
$.ajax({
type: 'POST',
data: {movie_name:movie_name, movie_year:movie_year, movie_genre:movie_genre},
url: "insert.php",
success: function(result){
alert('Movie ' + movie_name + ' (' + movie_year + ')' +' added successfully.');
document.location.reload();
}
})
});
$('.btnedit').click(function(e){
var id = $(this).parent().prev().prev().prev().prev().html();
alert(id);
//unfinished function
})
$('.btndlt').click(function(e){
var id = $(this).parent().prev().prev().prev().prev().prev().html();
e.preventDefault();
$.ajax({
type: 'POST',
data: {id:id},
url: 'delete_row.php',
success: function(result){
alert('Successfully deleted.');
document.location.reload();
}
})
})
});
Here's php page for adding a movie, insert.php (this one works, posting it just for more information) :
<?php
require_once('connection.php');
if($_REQUEST['movie_name']){
$name = $_REQUEST['movie_name'];
$year = $_REQUEST['movie_year'];
$genre = $_REQUEST['movie_genre'];
$sql = "INSERT INTO movies(name, year, genre) VALUES ('$name','$year','$genre')";
$query = mysqli_query($conn, $sql);
}
?>
Here's delete_row.php file for deleting entry with delete button:
<?php
require_once('connection.php');
$id = $_REQUEST['id'];
if(isset($_REQUEST['delete'])){
$sql = "DELETE FROM `movies` WHERE movie_id = $id";
$query = mysqli_query($conn, $sql);
}
?>
As you can probably see I was all over the place with php and ajax because I tried to implement multiple solutions or mix them to solve the problem.
At this stage when I click delete button I get alert message that says erasing is successful and adminpanel.php reloads with list of movies. However the movie is still there and in SQL database.
When I tried to debug delete_row.php I found out that index "id" is undefined every time even though I think I'm passing it with ajax call.
Edit
I should've said that security is not my concern right now, I do this exercise just for functionalities I described. :) Security is my next step, I am aware this code is not secure at all.
When I tried to debug delete_row.php I found out that index "id" is
undefined every time even though I think I'm passing it with ajax
call.
The reason this happens is probably because you're accessing delete_row.php directly through the browser, and because the form is not submitted (it will later through ajax) the $_REQUEST variable will always be undefined.
When debugging $_REQUEST (or $_POST) variables in the future, you should use Postman where you can actually request that php file sending your own POST arguments.
On your specific code, the query will never run because of this line:
if(isset($_REQUEST['delete']))
Which is checking for a delete variable that was never sent in the first place, hence will always resolve false
Use this code instead on delete_row.php:
<?php
require_once('connection.php');
if(isset($_REQUEST['id'])){
$id = $_REQUEST['id'];
$sql = "DELETE FROM `movies` WHERE movie_id = $id";
$query = mysqli_query($conn, $sql);
}
?>
So i have this database:
And then i have a php script to create a simple menu, with the 'local' column.
$query = "SELECT * FROM credenciais_sensores where ambiente = '1'";
$results = mysqli_query($conn, $query);
<ul class="treeview-menu">
<?php
foreach ($results as $result){
$local = $result['local'];
$local = substr($local,0,7);
echo "<li><a class='post' href='#'>".$local."</a></li>";
}
?>
</ul>
On the query i select all info, but i only display the 'local'. Now, when i click on one of the items from the menu, i want to somehow send the info of that row by post to another page, without triggering a reload on the page. I know i can do this with GET, but i dont want to show the info on the URL.
I want to send the 'oxi_sensorid' and 'oxi_apikey' by post to another page. Ive tried using jquery post, but i cant get the items to display on the other page...
This is the menu i get printed:
Now, for example, when i click "Pipo 01" i want to send the Pipo 01 oxi_apikey and oxi_apikey by post with javascript to another file, for example getData.php. Ive tried using ajax to post all data to the getdata.php file but the getdata.php is not receiving them...
First, you need to modify your php script:
echo "<li><a class='clsPostData' data-sensorid='".$result['oxi_sensorid']."' data-apikey='".$result['oxi_apikey']."' href='#'>".$local."</a></li>";
And your Jquery code:
$(function(){
$('.clsPostData').click(function(e){
e.preventDefault();
var objPost = {};
objPost.api = $(this).data('apikey');
objPost.sensor = $(this).data('sensorid');
$.ajax({
url: 'getData.php',
type: 'post',
data: objPost
}).done(function(responseFromPhp){
//Do something with the response, like
alert(responseFromPhp.message);
});
});
});
Your getData.php script:
<?php
$apikey = $_POST["api"];
$sensorid = $_POST["sensor"];
$response["message"] = "Grettings from php, we receive your sensorid: ".$sensorid;
echo json_encode($response);
?>
I'm trying to create a comment system on my website where the user can comment & see it appear on the page without reloading the page, kind of like how you post a comment on facebook and see it appear right away. I'm having trouble with this however as my implementation shows the comment the user inputs, but then erases the previous comments that were already on the page (as any comments section, I'd want the user to comment and simply add on to the previous comments). Also, when the user comments, the page reloads, and displays the comment in the text box, rather than below the text box where the comments are supposed to be displayed. I've attached the code. Index.php runs the ajax script to perform the asynchronous commenting, and uses the form to get the user input which is dealt with in insert.php. It also prints out the comments stored in a database.
index.php
<script>
$(function() {
$('#submitButton').click(function(event) {
event.preventDefault();
$.ajax({
type: "GET",
url: "insert.php",
data : { field1_name : $('#userInput').val() },
beforeSend: function(){
}
, complete: function(){
}
, success: function(html){
$("#comment_part").html(html);
window.location.reload();
}
});
});
});
</script>
<form id="comment_form" action="insert.php" method="GET">
Comments:
<input type="text" class="text_cmt" name="field1_name" id="userInput"/>
<input type="submit" name="submit" value="submit" id = "submitButton"/>
<input type='hidden' name='parent_id' id='parent_id' value='0'/>
</form>
<div id='comment_part'>
<?php
$link = mysqli_connect('localhost', 'x', '', 'comment_schema');
$query="SELECT COMMENTS FROM csAirComment";
$results = mysqli_query($link,$query);
while ($row = mysqli_fetch_assoc($results)) {
echo '<div class="comment" >';
$output= $row["COMMENTS"];
//protects against cross site scripting
echo htmlspecialchars($output ,ENT_QUOTES,'UTF-8');
echo '</div>';
}
?>
</div>
insert.php
$userInput= $_GET["field1_name"];
if(!empty($userInput)) {
$field1_name = mysqli_real_escape_string($link, $userInput);
$field1_name_array = explode(" ",$field1_name);
foreach($field1_name_array as $element){
$query = "SELECT replaceWord FROM changeWord WHERE badWord = '" . $element . "' ";
$query_link = mysqli_query($link,$query);
if(mysqli_num_rows($query_link)>0){
$row = mysqli_fetch_assoc($query_link);
$goodWord = $row['replaceWord'];
$element= $goodWord;
}
$newComment = $newComment." ".$element;
}
//Escape user inputs for security
$sql = "INSERT INTO csAirComment (COMMENTS) VALUES ('$newComment')";
$result = mysqli_query($link, $sql);
//attempt insert query execution
//header("Location:csair.php");
die();
mysqli_close($link);
}
else{
die('comment is not set or not containing valid value');
}
The insert.php takes in the user input and then inserts it into the database (by first filtering and checking for bad words). Just not sure where I'm going wrong, been stuck on it for a while. Any help would be appreciated.
There are 3 main problems in your code:
You are not returning anything from insert.php via ajax.
You don't need to replace the whole comment_part, just add the new comment to it.
Why are you reloading the page? I thought that the whole purpose of using Ajax was to have a dynamic content.
In your ajax:
$.ajax({
type: "GET",
url: "insert.php",
data : { field1_name : $('#userInput').val() },
beforeSend: function(){
}
, complete: function(){
}
, success: function(html){
//this will add the new comment to the `comment_part` div
$("#comment_part").append(html);
}
});
Within insert.php you need to return the new comment html:
$userInput= $_GET["field1_name"];
if(!empty($userInput)) {
$field1_name = mysqli_real_escape_string($link, $userInput);
$field1_name_array = explode(" ",$field1_name);
foreach($field1_name_array as $element){
$query = "SELECT replaceWord FROM changeWord WHERE badWord = '" . $element . "' ";
$query_link = mysqli_query($link,$query);
if(mysqli_num_rows($query_link)>0){
$row = mysqli_fetch_assoc($query_link);
$goodWord = $row['replaceWord'];
$element= $goodWord;
}
$newComment = $newComment." ".$element;
}
//Escape user inputs for security
$sql = "INSERT INTO csAirComment (COMMENTS) VALUES ('$newComment')";
$result = mysqli_query($link, $sql);
//attempt insert query execution
mysqli_close($link);
//here you need to build your new comment html and return it
return "<div class='comment'>...the new comment html...</div>";
}
else{
die('comment is not set or not containing valid value');
}
Please note that you currently don't have any error handling, so when you return die('comment is not set....') it will be displayed as well as a new comment.
You can return a better structured response using json_encode() but that is outside the scope of this question.
You're using jQuery.html() which is replacing everything in your element with your "html" contents. Try using jQuery.append() instead.
I am using ajax to post comments to a certain page, I have everything working, except for when the user posts a comment I would like it to show immediately without refreshing. The php code I have to display the comments is:
<?php
require('connect.php');
$query = "select * \n"
. " from comments inner join blogposts on comments.comment_post_id = blogposts.id WHERE blogposts.id = '$s_post_id' ORDER BY comments.id DESC";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
$c_comment_by = $row['comment_by'];
$c_comment_content = $row['comment_content'];
?>
<div class="comment_box">
<p><?php echo $c_comment_by;?></p>
<p><?php echo $c_comment_content;?></p>
</div>
<?php } ?>
</div>
</div>
<?php
}
}
and the code I have to post comments is:
<?php
$post_comment = $_POST['p_post_comment'];
$post_id = $_POST['p_post_id'];
$post_comment_by = "Undefined";
if ($post_comment){
if(require('connect.php')){
mysql_query("INSERT INTO comments VALUES (
'',
'$post_id',
'$post_comment_by',
'$post_comment'
)");
echo " <script>$('#post_form')[0].reset();</script>";
echo "success!";
mysql_close();
}else echo "Could no connect to the database!";
}
else echo "You cannot post empty comments!"
?>
JS:
function post(){
var post_comment = $('#comment').val();
$.post('comment_parser.php', {p_post_comment:post_comment,p_post_id:<?php echo $post_id;?>},
function(data)
{
$('#result').html(data);
});
}
This is what I have for the refresh so far:
$(document).ready(function() {
$.ajaxSetup({ cache: false });
setInterval(function() {
$('.comment_box').load('blogpost.php');
}, 3000);.
});
Now what I want to do is to use ajax to refresh the comments every time a new one is added. Without refreshing the whole page, ofcourse. What am I doing wrong?
You'll need to restructure to an endpoint structure. You'll have a file called "get_comments.php" that returns the newest comments in JSON, then call some JS like this:
function load_comments(){
$.ajax({
url: "API/get_comments.php",
data: {post_id: post_id, page: 0, limit: 0}, // If you want to do pagination eventually.
dataType: 'json',
success: function(response){
$('#all_comments').html(''); // Clears all HTML
// Insert each comment
response.forEach(function(comment){
var new_comment = "<div class="comment_box"><p>"+comment.comment_by+"</p><p>"+comment.comment_content+"</p></div>";
$('#all_comments').append(new_comment);
}
})
};
}
Make sure post_id is declared globally somewhere i.e.
<head>
<script>
var post_id = "<?= $s_post_id ; ?>";
</script>
</head>
Your new PHP file would look like this:
require('connect.php');
$query = "select * from comments inner join blogposts on comments.comment_post_id = blogposts.id WHERE blogposts.id = '".$_REQUEST['post_id']."' ORDER BY comments.id DESC";
$result = mysql_query($query);
$all_comments = array() ;
while ($row = mysql_fetch_array($result))
$all_comments[] = array("comment_by" => $result[comment_by], "comment_content" => $result[comment_content]);
echo json_encode($all_comments);
Of course you'd want to follow good practices everywhere, probably using a template for both server & client side HTML creation, never write MySQL queries like you've written (or that I wrote for you). Use MySQLi, or PDO! Think about what would happen if $s_post_id was somehow equal to 5' OR '1'='1 This would just return every comment.. but what if this was done in a DELETE_COMMENT function, and someone wiped your comment table out completely?