Can you please take a look at this demo and let me know why I am not able to inject clicked element attribute data data-css to data attribute of color-box? as you can see I am able to print it out in the console by
console.log(jQuery(this).data('css'));
But the
jQuery('.current-color').data('css', jQuery(this).data('css'));
is not setting the data attribute for target element .current-color
jQuery(".color").on('click', function() {
jQuery('.current-color').css('background', jQuery(this).data('color'));
jQuery('.current-color').data('css', jQuery(this).data('css'));
console.log(jQuery(this).data('css'));
jQuery('.current-color-name').text(jQuery(this).find('.color-name').text());
});
.color-box {
width: 100px;
height: 100px;
cursor: pointer;
background:#eee;
border:2px solid #444;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="current-color" data-css="">
<div class="color-box current-color-name">Orane</div>
</div>
<div class="colors">
<div class="color-box color" data-css="red.css" data-color="#f44336">
<div class="color-name">red</div>
</div>
</div>
Try to use .attr('data-anything') instead of .data('anything') It works here
$(".color").on('click', function() {
$('.current-color').css('background', $(this).attr('data-color'));
$('.current-color').attr('data-css', $(this).attr('data-css'));
console.log($(this).attr('data-css'));
$('.current-color-name').text($(this).find('.color-name').text());
});
.color-box {
width: 100px;;
height: 100px;
cursor: pointer;
background:#eee;
border:2px solid #444;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="current-color" data-css="">
<div class="color-box current-color-name"></div>
</div>
<div class="colors">
<div class="color-box color" data-css="red.css" data-color="#f44336">
<div class="color-name">red</div>
</div>
<div class="color-box color" data-css="orange.css" data-color="orange">
<div class="color-name">Orange</div>
</div>
<div class="color-box color" data-css="blue.css" data-color="blue">
<div class="color-name">Blue</div>
</div>
</div>
The reason why 'data-' atrribute could not work was that when you first used the $('..').data(' ') method to get the attribute value after you set it by
$('..').data(' ',' ') method,jquery stored the value so that when you clicked again,the value had not changed.
I thought reason was more important than solution for a developer.I hoped this could help.
Related
I have to make a set of buttons that appear and disappear.
How it is supposed to work:
I click on link 1 (link 2 is invisible at this point).
link 2 should then appear.
the problem here is there can be multiple elements of the same type with the same classes and I can't figure out how to distinguish between just showing the "link2"
that corresponds to the clicked "link1" without triggering the other "link2".
there is some code showing the progress I have made.
thank you in advance!
<style>
.hideaction{
visibility: hidden;
}
.showaction{
visibility: visible;
}
</style>
<script>
$(document).ready(function(){
$(".elem_action_showing").click(function(){
$(".elem_action_hiding").removeClass("hideaction").addClass("showaction");
});
</script>
</head>
<body>
<div class="elem_card card_set_click" style=" border: 1px solid black">
<div class="elem_hidden">
<p class="hideaction elem_action_hiding">%link2%</p>
</div>
<div class="elem_showing ">
<p class="elem_action_showing set_click">%link1%</p>
</div>
</div>
<div class="elem_card card_set_click" style=" border: 1px solid black">
<div class="elem_hidden">
<p class="hideaction elem_action_hiding">%link2%</p>
</div>
<div class="elem_showing ">
<p class="elem_action_showing set_click">%link1%</p>
</div>
</div>
</body>
The solution should work irregardless of how many ".elem_card" and ".hideaction" elements are there.
The issue is because you're selecting all .elem_action_hiding elements. To fix this use DOM traversal to find only the one which is related to the .elem_action_showing which was clicked. Try this:
$(".elem_action_showing").click(function() {
$(this).closest('.elem_showing').prev().find(".elem_action_hiding").toggleClass("hideaction showaction");
});
.hideaction {
visibility: hidden;
}
.showaction {
visibility: visible;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="elem_card card_set_click" style=" border: 1px solid black">
<div class="elem_hidden">
<p class="hideaction elem_action_hiding">%link2%</p>
</div>
<div class="elem_showing">
<p class="elem_action_showing set_click">%link1%</p>
</div>
</div>
<div class="elem_card card_set_click" style=" border: 1px solid black">
<div class="elem_hidden">
<p class="hideaction elem_action_hiding">%link2%</p>
</div>
<div class="elem_showing ">
<p class="elem_action_showing set_click">%link1%</p>
</div>
</div>
Is there any way to modify DOM based on amount div after specific class?
For example, if I have a div with a class called row and after that I have 4 div elements. Is there a way to change these 4 div element class depending on how many div elements there are?
Code:
<div class="row">
<div class="col-1-of-4">
some content
</div>
<div class="col-1-of-4">
some content
</div>
<div class="col-1-of-4">
some content
</div>
<div class="col-1-of-4">
some content
</div>
</div>
Another example I have a div class row again, but this time I want 3 div elements after that, then I would want these div elements to have a class called col-1-of-3, not col-1-of-4. If I would have just 2 div elements after that then class col-1-of-2 and if just one div element then no class at all.:
Code:
<div class="row">
<div class="col-1-of-3">
some content
</div>
<div class="col-1-of-3">
some content
</div>
<div class="col-1-of-3">
some content
</div>
</div>
Also these div elements with classes called col-1-of-4, col-1-of-3 and col-1-of-2 have their own div elements inside them, but they should stay like they were.
Is it possible to achieve with JavaScript or PHP?
You would need to write conditional blocks to handle this if I'm understanding you correctly (wanting a JS or PHP solution).
Note: It goes without saying that a similar solution can be completed with a CSS-only approach, as outlined here: Can CSS detect the number of children an element has?
Here's an example (using jQuery) with 3 sets of row's, with varying children (2, 3, 4):
$(function() {
var $rows = $(".row");
$rows.each(function() {
$row = $(this);
var $children = $(">div", $row),
total = $children.size();
$children.addClass("col-1-of-" + total);
});
});
.row {
border: 1px solid #000;
margin: 10px;
}
.row > div {
margin: 10px;
}
.row .col-1-of-2 {
border: 1px solid #f00;
}
.row .col-1-of-3 {
border: 1px solid #0f0;
}
.row .col-1-of-4 {
border: 1px solid #00f;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="row">
<div>
some content
</div>
<div>
some content
</div>
</div>
<div class="row">
<div>
some content
</div>
<div>
some content
</div>
<div>
some content
</div>
</div>
<div class="row">
<div>
some content
</div>
<div>
some content
</div>
<div>
some content
</div>
<div>
some content
</div>
</div>
When you run the snippet, you must inspect the elements. I've added borders so you can see the difference.
Theres a number of ways to achieve this. I'd maybe add another class name so you can easily identify groups of divs, and differentiate between parent and child divs. Does this help you get where you're going? Basically find the number of children in a row and then concatenate that number into the class name.
var x = document.getElementsByClassName('row')[0].childElementCount
var element = document.getElementsByClassName('row')[0];
element.classList.add(`col-1-of-${x}`);
.row {
width: 100%;
display:flex;
flex-grow: 1;
margin-bottom: 2px;
}
.col {
float:left;
background: rgba(255,0,0,.2);
text-align: center;
margin-right: 2px;
}
.col:first-child:nth-last-child(1),
.col:first-child:nth-last-child(1) ~ .col{
width: calc(100% / 1);
}
.col:first-child:nth-last-child(2),
.col:first-child:nth-last-child(2) ~ .col{
width: calc(100% / 2);
}
.col:first-child:nth-last-child(3),
.col:first-child:nth-last-child(3) ~ .col{
width: calc(100% / 3);
}
.col:first-child:nth-last-child(4),
.col:first-child:nth-last-child(4) ~ .col{
width: calc(100% / 4);
}
.col:first-child:nth-last-child(5),
.col:first-child:nth-last-child(5) ~ .col{
width: calc(100% / 5);
}
<div class="row">
<div class="col">1</div>
</div>
<div class="row">
<div class="col">1</div>
<div class="col">2</div>
</div>
<div class="row">
<div class="col">1</div>
<div class="col">2</div>
<div class="col">3</div>
</div>
<div class="row">
<div class="col">1</div>
<div class="col">2</div>
<div class="col">3</div>
<div class="col">4</div>
</div>
<div class="row">
<div class="col">1</div>
<div class="col">2</div>
<div class="col">3</div>
<div class="col">4</div>
<div class="col">5</div>
</div>
so this is with float, can be used in a sass/scss mixin to create code automagically. there should be also a flex solution but i dont have it at hand at the moment
I have following HTML code:
.background {
width: 100%;
height: 800px;
margin: 0 auto;
background-image:url("backimage1.jpg");
background-size: cover;
}
<div class="background">
<div class="wrapper">
<div class="box1">
<span class="title">Pozitivan feedback naših klijenata i njihovih potrošača</span><br />
<span class="description">Vrhunski kvalitet naših proizvoda</span>
</div>
</div>
</div>
What I would like is to when hover on "box1"to change background-image to something else. I know that I can't do that with CSS, tried few things with JS, but seems like I'm only able to select parents element, not parents-parent element though. Any suggestions?
document.getElementsByClassName('') can be use to select element by class name.
<html>
<head>
<style>
.background {
width: 100%;
height: 800px;
margin: 0 auto;
background-image:url("backimage1.jpg");
background-size: cover;
}s
</style>
<script type="text/javascript">
function changeBgMouseOver() {
var x = document.getElementsByClassName("background");
x[0].style.backgroundImage = "url('backimage2.jpg')";
}
function changeBgMouseOut() {
var x = document.getElementsByClassName("background");
x[0].style.backgroundImage = "url('backimage1.jpg')";
}
</script>
</head>
<body>
<div class="background">
<div class="wrapper">
<div class="box1" onmouseover="changeBgMouseOver()" onmouseout="changeBgMouseOut()">
<span class="title">Pozitivan feedback naših klijenata i njihovih potrošaca</span><br />
<span class="description">Vrhunski kvalitet naših proizvoda</span>
</div>
</div>
</div>
</body>
</html>
Using jquery hover function - changing the background-color :
In your case you can try this with background-image css property
$(document).ready(function(){
$(".box1").hover(function(){
$(this).parent().css("background-color","coral");
}, function(){
$(this).parent().css("background-color","");
})
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="background">
<div class="wrapper">
<div class="box1">
<span class="title">Pozitivan feedback naših klijenata i njihovih potrošača</span><br />
<span class="description">Vrhunski kvalitet naših proizvoda</span>
</div>
</div>
</div>
Here is JQ solution for you it's pretty straightforward:
$(".box1").hover(function(){
$('.background').css("background", "url(https://placebear.com/200/300)");
}, function(){
$('.background').css("background", "url(https://placebear.com/300/300)");
});
.background {
width: 100%;
height: 800px;
margin: 0 auto;
background-image:url("https://placebear.com/300/300");
background-size: cover;
}
.box1 {
cursor: pointer;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="background">
<div class="wrapper">
<div class="box1">
<span class="title">Pozitivan feedback naših klijenata i njihovih potrošača</span><br />
<span class="description">Vrhunski kvalitet naših proizvoda</span>
</div>
</div>
</div>
Just using ".closest()" should be fine, ".parent().parent()" could also be a solution.
$(document).ready(function(){
$(".box1").mouseover(function(){
$(this).closest(".background").css("background-image","url('anotherimage.jpg')");
});
});
$(document).ready(function(){
$(".box1").mouseover(function(){
$(this).parent().parent().css("background-image","url('anotherimage.jpg')");
});
});
I have an event listener for when the user clicks in the window. I want to see if the clicked element has any parent element with a certain id. I use the jQuery closest() function for that. But it always returns true.
Here is a fiddle that demonstrates my code.
There must be some major error, because if I change the id from if($(event.target).closest('#activatemenu'))
into any other id
if($(event.target).closest('#rrrrrrr'))
it still returns true.
Code in fiddle:
$(function() {
$(document).click(function(event) {
if($(event.target).closest('#activatemenu')) {
$('.wrap').prepend('<p>the clicked element has a parent with the id of activatemenu</p>');
}else{
$('.wrap p').remove();
}
});
});
.stuff{
width:300px;
height:150px;
border:red 2px solid;
}
.otherstuff{
width:400px;
height:400px;
background:purple;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="wrap">
<div id="activatemenu">
<div>
<div>
<div class="stuff">
<p>Here is some text</p>
</div>
</div>
</div>
</div>
<div class="otherstuff">
<p>Other stuff!</p>
</div>
</div>
Closest always returns a jQuery object which resolves to truthy. You need to check the length of the object.
$(event.target).closest('#rrrrrrr').length
Or, use
$(function() {
$(document).click(function(event) {
if ($(event.target).closest('#activemenu').length) {
$('.wrap').prepend('<p>the clicked element has a parent with the id of activemenu</p>');
} else {
$('.wrap p').remove();
}
});
});
.stuff {
width: 300px;
height: 150px;
border: red 2px solid;
}
.otherstuff {
width: 400px;
height: 400px;
background: purple;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="wrap">
<div id="activemenu">
<div>
<div>
<div class="stuff">
<p>Here is some text</p>
</div>
</div>
</div>
</div>
<div class="otherstuff">
<p>Other stuff!</p>
</div>
</div>
$(event.target).closest('#activatemenu') will always return an object so if condition will always be true, better check for $(event.target).closest('#activatemenu').length
$(function() {
$(document).click(function(event) {
if($(event.target).closest('#activemenu').length) {
$('.wrap').prepend('<p>the clicked element has a parent with the id of activemenu</p>');
}else{
$('.wrap p').remove();
}
});
});
.stuff{
width:300px;
height:150px;
border:red 2px solid;
}
.otherstuff{
width:400px;
height:400px;
background:purple;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="wrap">
<div id="activemenu">
<div>
<div>
<div class="stuff">
<p>Here is some text</p>
</div>
</div>
</div>
</div>
<div class="otherstuff">
<p>Other stuff!</p>
</div>
</div>
You have two problems with your code.
First, you need to search for the closest activemenu not activatemenu. activatemenu does not exist in your code.
Second, jQuery will always return an array so you need to check the length to see whether the element was found as a non-empty array will always return true.
See below for a working example:
$(function() {
$(document).click(function(evt) {
if($(evt.target).closest('#activemenu').length) {
$('.wrap').prepend('<p>the clicked element has a parent with the id of activemenu</p>');
} else {
$('.wrap p').remove();
}
});
});
.stuff {
width: 300px;
height: 150px;
border: red 2px solid;
}
.otherstuff {
width: 400px;
height: 400px;
background: purple;
}
<script src="https://code.jquery.com/jquery-2.2.4.min.js" integrity="sha256-BbhdlvQf/xTY9gja0Dq3HiwQF8LaCRTXxZKRutelT44=" crossorigin="anonymous"></script>
<div class="wrap">
<div id="activemenu">
<div>
<div>
<div class="stuff">
<p>Here is some text</p>
</div>
</div>
</div>
</div>
<div class="otherstuff">
<p>Other stuff!</p>
</div>
</div>
I couldn't think of any better title, so I will try to explain my question here as clear as possible. I'm quite a newbie in JQuery so this is probably a very easy question.
I have some divs with a button on it. When you click the button, another div should pop-up.
My question is: How can I make the div, which is already open, close when clicking on another button?
I made a fiddle with some example code: http://jsfiddle.net/zuvjx775/1/
And the example code here:
HTML:
<div class="wrapper">
<div class="test">
<input type='button' class='showDiv' id="1" value='click!' />
</div>
<div class="show_1">
</div>
</div>
<br>
<div class="wrapper">
<div class="test">
<input type='button' class='showDiv' id="2"value='click!' />
</div>
<div class="show_2">
</div>
</div>
JQuery:
$('.showDiv').on('click', function(){
var id = $(this).attr('id');
$('.show_'+id).show();
});
When show_1 for example is visible, and I click on the button in div2, I want show_2 to come up, which it does, but show_1 to dissapear.
Can someone point me in the right direction?
You can hide all divs that their class starts with 'show' before show the one you want. For example:
$('.showDiv').on('click', function() {
var id = $(this).attr('id');
$("div[class^='show']").hide();//find div class starts with 'show' and hide them
$('.show_' + id).show();
});
.test {
border: 1px solid black;
height: 100px;
width: 450px;
float: left;
}
.show_1 {
width: 50px;
height: 50px;
background-color: yellow;
float: left;
display: none;
}
.show_2 {
width: 50px;
height: 50px;
background-color: green;
float: left;
display: none;
}
.wrapper {
clear: both;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="wrapper">
<div class="test">
<input type='button' class='showDiv' id="1" value='click!' />
</div>
<div class="show_1">
</div>
</div>
<br>
<div class="wrapper">
<div class="test">
<input type='button' class='showDiv' id="2" value='click!' />
</div>
<div class="show_2">
</div>
</div>
Is the structure of the document fixed?
is so... I guess the easiest way of doing this is to just do the following:
$('.showDiv').on('click', function(){
var id = $(this).attr('id');
if(id == 1){
$('.show_1').show();
$('.show_2').hide();
}else{
$('.show_2').show();
$('.show_1').hide();
}
})