This question already has answers here:
Indirect function call in JavaScript
(3 answers)
Why does babel rewrite imported function call to (0, fn)(...)?
(3 answers)
Closed 5 years ago.
onSelect(option, (0, _getOptionText2.default)(option))
I saw this in one of the node modules I use and I'm pretty confused by the second argument which is wrapped by parentheses. How does that work? There is no function which it is invoking.
Related
This question already has answers here:
What is the purpose of calling (0, func)() in JS? [duplicate]
(1 answer)
Why does babel rewrite imported function call to (0, fn)(...)?
(3 answers)
Closed last year.
I'm looking at some javascript code that does this:
const senderPubKey = (0, secp256k1_1.ecdsaRecover)(signature, recovery.toNumber(), msgHash);
I don't understand this syntax. When I do console.log(secp256k1_1.ecdsaRecover) I get [Function: ecdsaRecover] so I'm guessing it's a function call but why not do secp256k1_1.ecdsaRecover(signature, recovery.toNumber(), msgHash)?
This question already has answers here:
Explain the encapsulated anonymous function syntax
(10 answers)
Why are parentheses required around JavaScript IIFE? [duplicate]
(3 answers)
Closed 2 years ago.
Why if I have
function(){...}()
does not work while when I put inside brackets like
(function(){...}())
it works?
This question already has answers here:
JavaScript object functions and `this` when unbound and returned in expression/parens
(2 answers)
Closed 3 years ago.
I came across this (document.createElement)('a');.
How is it different from document.createElement('a');
No difference.
Please read doc for more.
This question already has answers here:
What do multiple arrow functions mean in JavaScript?
(7 answers)
How does the spread syntax in ES6 JS work as a function argument?
(1 answer)
What are these three dots in React doing?
(23 answers)
Closed 5 years ago.
How does this work:
const invert = fn => (...args) => -fn(...args);
Specifically, what is happening with (...args). It behaves as if it is separating the arguments from the function after the first fat arrow, but I suspect there is a better, more specific, explanation. Thanks.
This question already has answers here:
What does (function($) {})(jQuery); mean?
(6 answers)
What is the (function() { } )() construct in JavaScript?
(28 answers)
Closed 5 years ago.
I see in the jQuery code this structure but I don't know the name and how use correctly.
(function($) {
...
})(jQuery);
I suppose it's a form of past arguments to the function.
this will execute the function immediately (immediately invoked)