I want to return data only from the php function not whole page data.
Here is my demo.php file -
<?
echo "Whole Page data";
$name = $_POST['name'];
if ($name == "demo"){
demo();
}
else{
echo "No";
}
function demo(){
echo "demo data";
}
?>
And my ajax funtion is this -
function myAjax () {
$.ajax( { type : 'POST',
url : 'demo.php',
data : "name=demo",
success:function(data){
alert (data);
}
});
}
But it return whole page data with function data but I want only function data.
Check like,
if (!empty($_POST)) {
$name = $_POST['name'];
if ($name == "demo") {
demo();
} else {
echo "No";
}
die;
}
function demo()
{
echo "demo data";
}
This die; is important to halt execution process.
Give it a try, this should work.
Related
I am trying to make an AJAX post to php but for some reason my PHP says that the post is empty. I don't get an error message from PHP or in my console. The alert(data) at the end returns all the HTML in index.php and the var_dump(post) returns empty. first is the console.log(aantal) the second is console.log(data)
End of the console.log
script.js
$(document).ready(function () {
var date = "date";
var begin = "begin";
var eind = "eind";
var aantal = "aantal";
$('#datum').change(function () {
date = $("#datum").val();
console.log(date);
});
$('#beginTijd').change(function () {
begin = ($(this).val());
console.log(begin);
});
$('#Tijdsduur').change(function () {
eind = ($(this).val());
console.log(eind);
});
$('#aantalSloepen').change(function () {
aantal = ($(this).val());
console.log(aantal);
$.ajax({
type: "POST",
url: "index.php",
data: {
date: begin,
quantity: aantal
},
success: function (data) {
alert(data);
console.log(data);
}
});
});
});
index.php
<?php
var_dump($_POST);
$value1 = "";
$value2 = "";
if (isset($_POST['date'])) {
echo "Yes, mail is set";
$value1 = $_POST['date'];
$value2 = $_POST['quantity'];
} else {
echo "No, mail is not set";
}
echo $value1;
echo $value2;
You are calling index.php file from the ajax and the index.php file is loaded on page load. So when you call the ajax it will return whole html code of index.php to prevent that you have to add exit() function to prevent execute further. See code below.
<?php
$value1 = "";
$value2 = "";
if (isset($_POST['date']) && isset($_POST['quantity'])) {
if (isset($_POST['date'])) {
echo "Yes, mail is set";
$value1 = $_POST['date'];
$value2 = $_POST['quantity'];
} else {
echo "No, mail is not set";
}
exit;
}
<html>
<!-- Your Code goes here -->
</html>
I have a problem with my login form. Every time when i write (correct or incorrect) login and password in my login form, my JS script return error and when i try to print "response" it is empty.
Can anyone help?
$(document).ready(function(){
$("#submit").click(function(e){
e.preventDefault();
var name = $("#name").val().trim();
var paw = $("#paw").val().trim();
$.ajax({
url: 'check.php',
type: 'POST',
data: {name:name, paw:paw},
success: function(response){
if(response == 1){
window.location= "home.php";
}
else{
alert("error");
}
}
});
});
});
<?php
session_start();
require_once 'dbconfig.php';
error_reporting(E_ALL ^ E_NOTICE);
if(isset($_POST['submit']))
{
$name = trim($_POST['name']);
$paw1 = trim($_POST['paw']);
$paw = md5($paw1);
try {
$stmt = $pdo->prepare("SELECT * FROM user WHERE login=:nazwa and haslo=:has");
$stmt->execute(array(':nazwa'=>$name, ':has'=>$paw));
$count = $stmt->rowCount();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
if($row['haslo']==$paw){
echo 1;
$_SESSION['user_session'] = $row['login'];
}
else {
echo 0;
}
} catch (\Exception $e) {
echo $e->getMessage();
}
}
?>
Remove the if(isset($_POST['submit'])) line. The reason is that the button key value is not sent via the AJAX call. To verify, do a print_r($_POST);
instead verify that name and password variables are not empty()
if (!empty($_POST['name']) && !empty($_POST['paw'])) {
}
Also do not use md5() for your passwords. use php's password_hash() to hash and password_verify() to verify that the posted password via the form matches the hash stored in the database for that user.
I am in need to send an ajax call to a function in following directory structure
Yii::$app->request->absoluteUrl."protected/humhub/modules/post/controllers/PostController/UploadMusicFile";
my view function
function uploadImage(){
var url = '<?php echo Yii::app()->request->baseUrl."protected/humhub/modules/post/controllers/PostController/UploadMusicFile"; ?>';
console.log(url);
return false;
$.ajax({
url:'<?php echo Yii::$app->createUrl("Post/UploadMusicFile"); ?>',
method:'post',
data:{file:$('input[type="file"]')},
dataType:'',
contentType:false,
processData:false,
success:function(data){
var parsed_data = $.parseJSON(data);
},
error:function(data){
console.log("Error "+data);
}
});
}
function which i am posting to
public function UploadMusicFile(){
$file = Yii::$app->request->post('file');
echo "<pre>";
print_r($file);
echo "</pre>";
exit();
$target_dir = "/home/jmwglobaladmin/public_html/melmory/uploads/music_memory/";
$target_file = $target_dir . basename($_FILES["files"]["name"][0]);
foreach ($_FILES["files"]["error"] as $key => $error) {
if ($error == UPLOAD_ERR_OK) {
$tmp_name = $_FILES["files"]["tmp_name"][$key];
move_uploaded_file($tmp_name, $target_file);
$connection = Yii::$app->getDb();
$command = $connection->createCommand('select id from post order by id desc limit 1');
$result = $command->queryAll();
$new_id = $result[0]['id']+1;
$file_name = "abc.mp3";
$connection = Yii::$app->getDb();
$command_insert = $connection->createCommand('insert into memory_music (post_id,memory_music) values ("'.$new_id.'","'.$file_name.'")');
$result = $command_insert->execute();
}
}
}
I get the error of 404. How to pass proper url in yii to a function which is present in directory structure like mentioned above?
Basics. Your function is not an action.
Change this:
public function UploadMusicFile()
To this:
public function actionUploadMusicFile()
I was making a form to post data, combined with Ajax. Below is all code associated with it. The problem is that when filling the form in and submitting, on the first click it does the XHR request, and get's a success call back so changes the button to Done!.
But the results don't appear in the database. When clicking the submit button again, it does another XHR request that DOES get through. Any ideas what could cause this? Thanks!
// Method for updating the post in User.php
public function updatePost($id, $title, $content){
$query1 = $this->conn->prepare("UPDATE posts SET post_title=:post_title, post_content=:post_content WHERE post_id=:post_id");
$query1->bindparam(":post_title", $title);
$query1->bindparam(":post_content", $content);
$query1->bindparam(":post_id", $id);
try {
$query1->execute();
} catch (Exception $e) {
echo $e->getMessage();
}
} ?>
// Backend for the authenication and validation (where the form posts to)
<?php
session_start();
require_once("../User.php");
$login = new User();
$errors = [];
$post_title = $_POST['post-title'];
$post_content = $_POST['post-content'];
$post_id = $_POST['post-id'];
if( isset($post_title) && isset($post_content) && isset($post_id) ){
if( empty($post_title) ){
$errors[] = "The entered title is invalid in some way.";
}
elseif (empty($post_content)) {
$errors[] = "The entered content is invalid in some way.";
}
elseif(empty($post_id)){
$errors[] = "An internal error has occured, please contact the system administrator.";
}
else{
try {
if( !$login->updatePost($post_id, $post_title, $post_content) ){
echo "allrighty";
}
else{
echo "charliewegotaproblem";
}
} catch (Exception $e) {
echo $e->getMessage();
}
}
}
?>
// JS for the Ajax request itself
$("form").submit(function(evt){
evt .preventDefault();
var url = $(this).attr("action");
var formData = $(this).serialize();
$.ajax(url, {
data: formData,
type: "POST",
success: function(response){
if(response == "allrighty"){
$(".update-submit").prop("value", "Done!")
}
else if (response == "charliewegotaproblem") {
$(".update-submit").prop("value", "Something went wrong...")
}
}
}); // Ajax OBJECT END;
});// Submit END
<?php
==> First return success message, if post update query has executed successfully in updatePost function
// Method for updating the post in User.php
public function updatePost($id, $title, $content){
$success = false; // Here I changed the code
$query1 = $this->conn->prepare("UPDATE posts SET post_title=:post_title, post_content=:post_content WHERE post_id=:post_id");
$query1->bindparam(":post_title", $title);
$query1->bindparam(":post_content", $content);
$query1->bindparam(":post_id", $id);
try {
$query1->execute();
if($query1){ $success = true; } // Here I changed the code
} catch (Exception $e) {
echo $e->getMessage();
}
return $success;
}
==> Now here if $login has return true than an only than "allrighty" will return
// Backend for the authenication and validation (where the form posts to)
session_start();
require_once("../User.php");
$login = new User();
$errors = [];
$post_title = $_POST['post-title'];
$post_content = $_POST['post-content'];
$post_id = $_POST['post-id'];
if( isset($post_title) && isset($post_content) && isset($post_id) ){
if( empty($post_title) ){
$errors[] = "The entered title is invalid in some way.";
}
elseif (empty($post_content)) {
$errors[] = "The entered content is invalid in some way.";
}
elseif(empty($post_id)){
$errors[] = "An internal error has occured, please contact the system administrator.";
}
else{
try {
if($login->updatePost($post_id, $post_title, $post_content)){ // Here I changed the code
echo "allrighty";
}
else{
echo "charliewegotaproblem";
}
} catch (Exception $e) {
echo $e->getMessage();
}
}
}
?>
i'm creating a plugin for WooCommerce
in my plugin php file when i call a php file with jquery ajax i get empty result
this is my ajax code:
jQuery(function() {
jQuery.ajax({
url: '<?php echo RAKHSH_WC_QUICK_VIEW_URL ?>/rakhsh-data-for-pop.php',
success: function(output) {
alert(output);
}
});
});
and this is my php file:
<?php
$output = 'test';
return $output;
?>
You should change this:
<?php
$output = 'test';
return $output;
?>
To this:
<?php
$output = 'test';
die($output); // or echo or print
?>
Returning a variable will not return it as a response to an ajax call.
try this
<?php
$output = 'test';
echo $output;
?>
You can try this:
create a empty variable and insert your data to this.
var response = '';
$.ajax({ type: "GET",
url: '<?php echo RAKHSH_WC_QUICK_VIEW_URL ?>/rakhsh-data-for-pop.php',
async: false,
success : function(text)
{
response = text;
}
return response;
});