This question already has answers here:
jQuery Ajax POST example with PHP
(17 answers)
Closed 5 years ago.
Hi i trying make form using ajax. But i get some problems to sending form vars to php file. I get error: Undefined index: name.
I check chrome dev tools and i see variable is sending. But when made echo json_encode i see in php file i get empty array. So i dont have any idea where i made misstake.
file Main.js
var name = $('#user_name').val();
var lname = $('#user_lastname').val();
function formLogin(name, lname)
{
$.ajax({ url: 'database/register.php',
data: {
'name' : name,
'lname' : lname
},
type: 'post',
dataType:'json',
success: function(data) {
alert(data);
}
});
}
Html form:
<form class="circleForm" id="registerForm">
Imię: <input type="text" id="user_name"><br>
Nazwisko: <input type="text" id="user_lastname">
<br>
<input class="btnCircle" type="button" id="submit" value="Przejdź dalej" onclick="formLogin(name, lname)">
</form>
Php Code:
$dane = $_POST;
echo json_encode($dane);
Chrome dev:
I just want figure how can i echo this variables(name,lname) in php file register.php
Version with serialize:
function formLogin() {
var dane = $('form').serialize();
$.ajax({
url: 'database/register.php',
data: {'dane': dane},
method: 'post',
success: function(data) {
console.log(data);
}
});
}
Then result console:
<pre class='xdebug-var-dump' dir='ltr'>
<small>D:\xampp\htdocs\szkola\database\register.php:8:</small>
<b>array</b> <i>(size=1)</i>
'dane' <font color='#888a85'>=></font> <small>string</small> <font color='#cc0000'>''</font> <i>(length=0)</i>
</pre>
jquery-3.2.1.min.js:4 XHR finished loading: POST "http://localhost/szkola/database/register.php".
But when i go to http://localhost/szkola/database/register.php
i get this:
D:\xampp\htdocs\szkola\database\register.php:8:
array (size=0)
empty
You need to change the way you define your variables in your Javascript and declare them inside your function, not outside :
function formLogin(){
var name = $('#user_name').val();
var lname = $('#user_lastname').val();
$.ajax({ url: 'database/register.php',
data: {
'name' : name,
'lname' : lname
},
type: 'post',
dataType:'json',
success: function(data) {
alert(data);
}
});
}
And you need to update your HTML the same way (formLogin() instead of formLogin(...,...)) :
<form class="circleForm" id="registerForm">
Imię: <input type="text" id="user_name"><br>
Nazwisko: <input type="text" id="user_lastname">
<br>
<input class="btnCircle" type="button" id="submit" value="Przejdź dalej" onclick="formLogin()">
</form>
Try using method instead of type.
The HTML:
<form class="circleForm" id="registerForm">
Imię: <input type="text" id="user_name" name="name"><br />
Nazwisko: <input type="text" id="user_lastname" name="lname"><br />
<input class="btnCircle" type="button" id="submit" value="Przejdź dalej" onclick="formLogin();">
</form>
The JavaScript:
function formLogin() {
// Serialize the form
var data = $('form').serialize();
// Ajax call
$.ajax({
url: 'database/register.php',
data: data,
method: 'post',
dataType: 'json',
success: function(data) {
console.log(data);
}
});
}
Also remember that you're requesting a JSON so you have to echo a json_encode($array) in your PHP file for a simple string will not be returned.
Related
in my form code there is text input, checkbox input, file input type...etc,
everything working fine except the file input it's only taking one value ( multiple files upload isn't sending through ajax call ) how can i send arrays inside the serialize() function ?
Code :
<form action="#" id="postAdd" enctype="multipart/form-data">
<input accept=".png,.jpg,.jpeg" type="file" class="form-control-file d-none" id="file-upload" name="file[]" multiple required>
<input autocomplete="off" type="text" class="form-control bg-white" name="discName[]">
<button id="postAdbtn" class="btn btn-primary d-block mt-2">Submit</button>
</form> $(document).ready(function() {
$('#postAdbtn').click(function() {
var form = $('#postAdd').serialize();
$.ajax({
url: 'add-product-done.php',
method: "POST",
data: {
form: form
},
success: function(data) {
$('.fetchData').html(data);
}
})
});
});
one more thing, how can i get the files in PHP ?
and thanks
Can you try something like this?
var form = new FormData($("postAdd"));
$.ajax({
url: 'add-product-done.php',
data: form,
contentType: "multipart/form-data",
type: 'POST',
success: function(data){
console.log(data);
},
error: function(err){
console.error(err);
}
});
This question already has answers here:
How to use FormData for AJAX file upload?
(9 answers)
Closed 3 years ago.
i have this code for upload file to flask.
client side:
<form id="upload-file" method="post" enctype="multipart/form-data">
<fieldset>
<label for="file">Select a file</label>
<input name="file8" type="file">
</fieldset>
<fieldset>
<button id="upload-file-btn" type="button">Upload</button>
</fieldset>
</form>
<script>
$(function() {
$('#upload-file-btn').click(function() {
var form_data = new FormData($('#upload-file')[0]);
$.ajax({
type: 'POST',
url: '/uploading',
data: form_data,
contentType: false,
cache: false,
processData: false,
success: function(data) {
console.log('Success!');
},
});
});
});
</script>
server side:
#app.route('/uploading', methods = ['POST'])
def uploading():
if request.method == 'POST':
file = request.files['file8']
if file and a
this code upload file and work. How can i send more info to flask same time ?like time = 2020 , age=20 , ...
i find my answer but i cant answer to my question, so i write my ans here:
i use header,send more info like id , ... with user (but this is unsafe):
client side:
<script>
$(function() {
$('#upload-file-btn').click(function() {
var form_data = new FormData($('#upload-file')[0]);
form_data.append('username', 'Chris');
//form_data.append ('id',$('#upload-file')[0]);
console.log(form_data);
$.ajax({
type: 'POST',
url: '/uploading',
data: form_data, headers: {
'Id': 2528,'age':20
},
contentType: false,
cache: false,
processData: false,
success: function(data) {
console.log('Success!');
},
});
});
});
</script>
server side:
#app.route('/uploading', methods = ['POST'])
def uploading():
if request.method == 'POST':
file = request.files['file8']
id=request.headers['Id']
age=request.headers['age']
Put the data in the form, then pass the form to new FormData instead of just the file input.
e.g.
<form id="upload-file" method="post" enctype="multipart/form-data">
<fieldset>
<label for="file">Select a file</label>
<input name="file8" type="file">
</fieldset>
<fieldset>
<button id="upload-file-btn">Upload</button>
</fieldset>
<input type=hidden name=time value=2020>
<input type=hidden name=age value=20>
</form>
and
$("form").on("submit", function (e) {
e.preventDefault();
const form = this;
const form_data = new FormData(form);
// etc
});
I am trying to call data from a PHP file where it takes the data entered and tells if it is validated or not. How do you do this in the javascript file using an AJAX call?
$("#PersonForm").submit(function()
{
$.ajax({
url: 'backend.php', type: 'post', data: { act:'validate'},
dataType: 'json',
function(result) {
if($validateData==1){
$('#success').html('validated');
}
else{
$('#errors').html('Not Correct');
}
}
//});
});
return false;
});
Here is the PHP file
<?php
if ($_REQUEST['act'] == 'validate')
{
$validateData = array();
if (preg_match("/^[A-Za-z]{3,20}$/",$_REQUEST['name'])) $validateData['name'] = 1;
else $validateData['name'] = 0;
if (preg_match("/^[0-9]{10}$/",$_REQUEST['phone'])) $validateData['phone'] = 1;
else $validateData['phone'] = 0;
if (preg_match("/^[A-Z][0-9][A-Z][0-9][A-Z][0-9]$/",
$_REQUEST['postal'])) $validateData['postal'] = 1;
else $validateData['postal'] = 0;
if (preg_match("/^[0-9]{3} [A-Za-z]{3,10} Street$/",
$_REQUEST['address'])) $validateData['address'] = 1;
else $validateData['address'] = 0;
echo json_encode($validateData);
}
else echo "Should not happen";
?>
HTML file:
<html>
<body>
<h1>Form Validation</h1>
<form id="PersonForm">
Name: <input type="text" id="name" name="name"> <br>
Postal Code: <input type="text" id="postal" name="postal"> <br>
Phone Number: <input type="text" id="phone" name="phone"> <br>
Address: <input type="text" id="address" name="address"> <br>
<input id="sub" type="submit">
</form>
Refresh
<a id="InsertDefault" href="">Insert Default Data</a>
<br>
<ul id="errors"></ul>
<p id="success"></p>
</body>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<script type="text/javascript" src="main.js"></script>
</html>
First, you're not sending the any of the inputs in your data: parameter. So $_REQUEST['name'], $_REQUEST['phone'], etc. won't exist.
Second, you can't access PHP variables in Javascript. The JSON that the PHP echoes at the end will be decoded into the result variable in the success: callback function.
Third, your syntax is wrong, the callback function needs to be in the success: option.
So it should be:
$("#PersonForm").submit(function()
{
$.ajax({
url: 'backend.php',
type: 'post',
data: 'act=validate&' + $(this).serialize(),
dataType: 'json',
success: function(result) {
if(result.name && result.phone && result.post && result.address){
$('#success').html('validated');
}
else{
$('#errors').html('Not Correct');
}
}
});
return false;
});
You should use the success and error callbacks so that you are waiting for the promise from the ajax call to come back. I am assuming you are trying to figure out how to get to the data that comes back. If you need further assistance with then validating the real data, I can help with that as well.
$.ajax({
url: 'backend.php', type: 'post', data: { act:'validate'},
dataType: 'json',
success: function (data) {
if($validateData==1){
$('#success').html('validated');
}
else{
$('#errors').html('Not Correct');
}
},
error: function (request, status, error) {
// Error occurred calling API
}
});
I have a html file where users can input a value.
I wrote a script in PHP that checks if this value is present in the databse. If it's present it returns
{"active":true}
Now my goals is that when the user inputs their value and submit they will be redirected to a certain page if this active is true. If it's false they should see an error message.
So here's what I've tried with my AJAX call:
$("document").ready(function(){
$(".checkform").submit(function(e){
e.preventDefault();
$.ajax({
type: "GET",
dataType: "json",
url: "api/check.php",
data: data,
success: function(data) {
if(data.active=="true"){
alert("success");
location.href="where_you_want";
}else{
alert("failure");
}
}
});
return false;
});
});
Here is my HTML:
<form action="api/check.php" id="requestacallform" method="GET" name="requestacallform" class="formcheck">
<div class="form-group">
<div class="input-group">
<input id="#" type="text" class="form-control" placeholder="Jouw subdomein" name="name"/>
</div>
</div>
<input type="submit" value="Aanmelden" class="btn btn-blue" />
</form>
For some reason I get an error:
Uncaught ReferenceError: data is not defined
I am new to AJAX and I am not sure if what I am trying is correct.
Any help would be greatly appreciated!
Thanks in advance.
Can you try:
$(".aanmeldenmodal").submit(function(e){
e.preventDefault();
I am updating my answer in whole
<html>
<body>
<form action="api/check.php" id="requestacallform" method="GET" name="requestacallform" class="formcheck">
<div class="form-group">
<div class="input-group">
<input id="txt1" type="text" class="form-control" placeholder="Jouw subdomein" name="name"/>
</div>
</div>
<input type="submit" value="Aanmelden" class="btn btn-blue checkform" />
</form>
</body>
</html>
jQuery part is like
$("document").ready(function () {
$("body").on("click", ".checkform", function (e) {
e.preventDefault();
var request = $("#txt1").value;
$.ajax({
type: 'GET',
url: 'ajax.php',
data: {request: 'request'},
dataType: 'json',
success: function (data) {
if(data.active==true){
alert("success");
}else{
alert("failure");
}
}
});
});
});
ajax.php should be like this
if(isset($_GET['request'])){
//check for the text
echo json_encode($arr);
}
In api/check.php
You can pass data in json format
$json = json_encode($data);
retrun $json;
You can also not share any data so You can remove data from jQuery.
data:data
Your Jquery look like this:
$("document").ready(function(){
$(".checkform").submit(function(e){
e.preventDefault();
$.ajax({
type: "GET",
dataType: "json",
url: "api/check.php",
success: function(data) {
if(data.active=="true"){
alert("success");
location.href="where_you_want";
}else{
alert("failure");
}
}
});
return false;
});
});
sorry for ask this question again , but I still don't slove this problem!!
half years ago , I got some problem about receive value from server , and show the value in input field.
the question is below:
when I click the button "new" , and I can get the max number from ID table.
I write some code for this and try to use AJAX receive and show in input, it's not working,if I open the debug tools in chrome,I will get a error message :"Uncaught ReferenceError: maxnum is not defined "
(when I only use browser to open the page /localhost/index.php/static_data/kungfu_maxquery,I can get correct json and print on screen. )
what else I can do ...... Σ( ￣□￣；)
sorry again , sorry all , I am a construction laborer , don't know too much about program code, I read the book and practice along , please teach me .
View : （views/kungfu.php）
<div class="hero-unit">
<div style="width:250px;float:left;">
<form id="pr_form" action="<?php echo site_url();?>/static_data/kungfu_act" method="post">
ID：<input id="num" name="num" type="text" class="field_set"><br>
NAME：<input id="name" name="name" type="text" class="field_set"><br>
LOCAL：<input id="local" name="local" type="text" class="field_set"><br>
KUNGFU：<input id="kungfu" name="kungfu" type="text" class="field_set"><br>
</div>
<div style="clear:both;height:50px;padding-top:10px">
<input id="go" name="go" class="btn" type="submit" value="submit">
<input id="query" name="query" class="btn" type="button" value="query">
<input id="newone" name="newone" class="btn" type="button" value="new">
</div>
</form>
</div>
Controller（controllers/static_data.php）:
class Static_data extends CI_Controller {
public function kungfu_maxquery()
{
$this->load->model("pr_model");
$data = $this->pr_model->pr_maxquery();
echo json_encode($data);
}
}
Model（models/pr_model.php）:
class Pr_model extends CI_Model {
function __construct()
{
parent::__construct();
$this->load->helper('form');
$this->load->helper('html');
$this->load->database();
}
function pr_maxquery()
{
$this->db->select_max("num");
$maxquery=$this->db->get("kungfu_table");
return $maxquery;
}
JS(js/try.js):
$("#newone").click(function () {
$.ajax({
url: "<?php echo base_url()?>/static_data/kungfu_maxquery",
type: "POST",
cache: "false",
data: {'num':maxnum},
datatype: "json",
}).done(function () {
$("#num").val(maxnum);
});
});
In the data of the ajax call you are setting the data, not getting!!!
You should use something like this:
$("#newone").click(function () {
$.ajax({
url: "<?php echo base_url()?>/static_data/kungfu_maxquery",
type: "POST",
cache: "false",
datatype: "json",
}).done(function (result) {
$("#num").val(result);
});
});
The function in the done recibe the result of the callback.
you try like this
$("#newone").click(function () {
$.ajax({
url: "<?php echo base_url()?>/static_data/kungfu_maxquery",
type: "POST",
cache: "false",
datatype: "json",
}).done(function (resp) {
var json = $.parseJSON(resp);
$("#num").val(json);
});
});