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Page reload and redirect using PHP and Ajax

I have a registration form using php, I'm checking the inputs with a validations and control the submitting form using ajax.
Everything works fine, except, after clicking submit button, Ajax loads the success result, in same registration form, and also not reload the page and redirect.
I want to reload and redirect register.php page to register.php?action=joined using Ajax form submit.
Before Ajax register.php have its own statement, if the registration succsessful ($_GET['action'] == 'joined')* its redirect and destroy the registration form and show success form.*
Please refer on the codes. Can someone help me how to figure this out.
registercontrol.php
<?php
if(isset($_POST['fullname'])){
//fullname validation
$fullname = $_POST['fullname'];
if (! $user->isValidFullname($fullname)){
$infofn = 'Your name must be alphabetical characters';
echo '<p>'.$infofn.'</p>';
}
}
// If form has been submitted process it
if(isset($_POST['submit']) && $_POST['submit'] == 'register')
{
// Create the activasion code
$activasion = md5(uniqid(rand(),true));
try
{
// Insert into database with a prepared statement
$stmt = $db->prepare('INSERT INTO members (fullname) VALUES (:fullname, :email, :active)');
$stmt->execute(array(
':fullname' => $fullname,
':email' => $email,
':active' => $activasion
));
$id = $db->lastInsertId('memberID');
// Send email
$to = $_POST['email'];
$subject = "Verify Your Account";
$body = "<p>Thank you for registering on the demo site.</p>
<p>Hello ".$fullname.", Please click this link to activate your account: <a href='".DIR."activate.php?x=$id&y=$activasion'>".DIR."activate.php?x=$id&y=$activasion</a></p>";
$mail = new Mail();
$mail->setFrom(SITEEMAIL);
$mail->addAddress($to);
$mail->subject($subject);
$mail->body($body);
$mail->send();
// Redirect to index page
header('Location: register.php?action=joined');
exit;
// Else catch the exception and show the error.
}
catch(PDOException $e)
{
$error[] = $e->getMessage();
}
}
?>
register.php and ajax validations
<script type="text/javascript">
$(document).ready(function() {
$("#fullname").keyup(function(event) {
event.preventDefault();
var fullname = $(this).val().trim();
if(fullname.length >= 1) {
$.ajax({
url: 'registercontrol.php',
type: 'POST',
data: {fullname:fullname},
success: function(response) {
// Show response
$("#vfullname").html(response);
}
});
} else {
$("#vfullname").html("");
}
});
$('#submit').click(function(event) {
event.preventDefault();
var formData = $('#register-form').serialize();
console.log(formData);
$.ajax({
url: 'registercontrol.php',
method: 'post',
data: formData + '&submit=register'
}).done(function(result) {
$('.hidden').show();
$('#result').html(result);
})
});
});
</script>
<?php
// If action is joined show sucesss
if(isset($_GET['action']) && $_GET['action'] == 'joined')
{
echo '<div>
<p>Registration is successful, please check your email to activate your account.</p>
</div>';
}
else
{ ?>
<div>
<h1>Create an Account!</h1>
</div>
<form id="register-form" role="form" method="post"
action="registercontrol.php" autocomplete="off">
<input type="text" name="fullname" id="fullname" placeholder="Your name" value="" required>
<div id="vfullname"></div>
<input type="email" name="email" id="email" placeholder="Your Email" value="" required>
<input id="submit" type="submit" name="submit" value="Create Account">
<p class="hidden">Please check everything.</p>
<div id="result"></div>
</form>
<?php } ?>
Thank you.

Check the done block and perform your redirect with JavaScript:
$('#submit').click(function(event){
event.preventDefault();
var formData = $('#register-form').serialize();
console.log(formData);
$.ajax({
url: 'registercontrol.php',
method: 'post',
data: formData + '&submit=register'
}).done(function(result){
var url_to_redirect = "register.php?action=joined";
window.location.href = url_to_redirect;
})
});

Laravel JS autocomplete

I can't figure out what's going on here. I'm trying to make a pretty simple ajax post to do an autocomplete in laravel.
I have an input box and a spot for the results:
<div class="form-group">
<input type="text" name="tag_name" id="tag_name" class="form-control input-lg" placeholder="Enter Country Name" />
<div id="tagList">
</div>
</div>
and my JS
$('#tag_name').keyup(function(){
var query = $(this).val();
if(query != '')
{
//var _token = $('input[name="_token"]').val();
$.ajax({
url:"{{ route('campaigns.search') }}",
method:"POST",
data:{query:query, _token: '{{ csrf_token() }}'},
success:function(data){
$('#tagList').fadeIn();
$('#tagList').html(data);
}
});
}
});
$(document).on('click', 'li', function(){
$('#tag_name').val($(this).text());
$('#tagList').fadeOut();
});
});
The route points to my controller function:
public function searchTags(Request $request)
{
if($request->get('query'))
{
$query = "%" . $request->get('query') . "%";
$data = CampaignTags::where('TAG_DATA', 'LIKE', $query)->get();
$output = '<ul>';
foreach ($data as $row) {
$output .= '<li>' .$row->TAG_DATA. '</li>';
}
}
return json_encode($data);
}
When I inspect as I type, I get 200 codes on the search but I'm not getting actual results to show from the database, the response seems to be null

I did this using typeahead. and answered it in another thread. before
heres the link. Auto Complete Laravel

Ajax Button to fetch data without refresh?

I would like to know how a button submit can interact with AJAX to SELECT FROM data as a MySQL query without refreshing the page . I already have a text box interacting with AJAX so that the page does not refresh when the user inputs the text and presses enter but have no idea how to make the button do it my code below shows how im getting the text box to insert data without refreshing
Here is my script for the textbox
<div id="container">
About me<input type="text" id="name" placeholder="Type here and press Enter">
</div>
<div id="result"></div>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#name').focus();
$('#name').keypress(function(event) {
var key = (event.keyCode ? event.keyCode : event.which);
if (key == 13) {
var info = $('#name').val();
$.ajax({
method: "POST",
url: "about_me_action.php",
data: {name: info},
success: function(status) {
$('#result').append(status);
$('#name').val('');
}
});
};
});
});
</script>
Here is the action
<?php
if (isset($_POST['name'])) {
echo '<h1>'.$_POST['name'];
include('..\db.php');
$con = mysqli_connect($dbsrvname, $dbusername, $dbpassword, $dbname);
$name = $_POST['name'];
$name= mysqli_real_escape_string($con, $name);
$q = mysqli_query($con,"SELECT * FROM tbl1 WHERE username = '".$_COOKIE[$cookie_name]."'");
while($row = mysqli_fetch_assoc($q)){
//echo $row['id'];
$id = $row['id'];
}
$result=$con ->query=("REPLACE INTO about_user (about_me,number) VALUES ('".$name."','".$id."')");
$insert = $con->query($result);
echo "About Me Updated";
}
?>
Now all I need to do is have the below example of a button do something similar but instead of INSERTING just SELECT , how can i change the above script to allow a button to handle the action please?
<form
action="action_mail_view.php" method="post">
<input type="submit" class="button" name='msubmit' value="View Mail"/>
</form>

function callServer() {
$('#mail-button').on('click', function() {
var info = $('#name').val();
$.ajax({
method: "POST",
url: "about_me_action.php",
data: {
name: info
},
success: function(status) {
$('#result').append(status);
$('#name').val('');
}
});
});
}
$(document).ready(function() {
$('#name').focus();
$('#name').keypress(function(event) {
var key = (event.keyCode ? event.keyCode : event.which);
if (key == 13) {
$('#mail-button').trigger('click');
};
});
});
<form action="action_mail_view.php" method="post">
<input type="submit" class="button" id="mail-button" name='msubmit' value="View Mail" />
</form>

You haven't showed us how you tried to make your button work so how can we give you feedback? Basically you want a similar ajax call that calls action_mail_view.php using the GET method
Ajax
$.ajax({
method: "GET",
url: "action_mail_view.php",
data: {},
success: function(results) {
var userinfo = JSON.parse(results);
//Todo: do what you want with the user's info
}
});
On the PHP side, you should first authenticate the user (not shown here), then SELECT her info from the DB and return it
action_mail_view.php
//Todo: authenticate
//this works with your setup, but it's a bad idea to trust
//a cookie value or anything else coming from the
//browser without verification
$username= mysqli_real_escape_string($con, $_COOKIE[$cookie_name]);
//get the user's info from your DB. By using a JOIN, we can execute
//just one query instead of two.
$sql = "SELECT t2.* FROM tbl1 as t1 "
."LEFT JOIN about_user as t2 "
."ON t1.id = t2.number"
."WHERE t1.username = $username";
//Todo: execute query. see what results you get and refine
// the SELECT clause to get just what you want
if($q = mysqli_query($con,$sql)):
$userinfo = mysqli_fetch_assoc($q);
//tell the browser to expect JSON, and return result
header('Content-Type: application/json');
echo json_encode($userinfo);
else:
//Todo: error handling
endif;

Updating div content with jQuery ajax function over PHP

I am trying to update my div content (#update_div) by sending the value of two input fields to a php file (search_value.php) using the .ajax() function from jQuery.
It works, if I just redirect the two values of the input fields using the html form POST method. So the search_value.php should be correct.
My HTML Code:
<form id="my_form">
<input id="food" name="food">
<input id="amount" value="amount in gram" name="amount">
<input type="button" value="Update" id="submit" name="submit" />
</form>
<div id="update_div">
</div>
My Javascript Code:
$("#submit").click(function() {
var food = $("#food").val();
var amount = $("#amount").val();
$.ajax({
url: 'search_value.php',
type: 'GET',
data: {"food":food,"amount":amount},
success: function(data)
{
$('#update_div').html(data);
}
});
});
My PHP Code:
<?php
$pdo = new PDO('mysql:host=localhost;dbname=calotools', 'root', '');
$food = $GET_['food'];
$amount = $GET_['amount'];
$query="SELECT * FROM nahrungsmittel WHERE name = '$food'";
$user = $pdo->query($query)->fetch();
echo $user['name']."<br />";
echo $user['kcal'] / 100 * $amount;
?>
I do not really get a feedback by clicking the button. Maybe you guys can tell me why?

For GET request, there should not be data part, make it as a query string as below js code:
$("#submit").click(function() {
var food = $("#food").val();
var amount = $("#amount").val();
$.ajax({
url: 'search_value.php?food='+ food + '&amount='+amount,
type: 'GET',
datatype: "html",
success: function(data)
{
$('#update_div').html(data);
},
failure : function(ex)
{
console.log(ex);
}
});
});
And use $_GET instead of $GET_ in php

Are you running your code after the page has loaded? I've made that mistake several times, and if you're not, I suggest wrapping the whole thing in a $(function(){ /* Everything you have */ });

I prefer using post
in your php script replace $GET_ by $_POST
<?php
$pdo = new PDO('mysql:host=localhost;dbname=calotools', 'root', '');
$food = $_POST['food'];
$amount = $_POST['amount'];
$query="SELECT * FROM nahrungsmittel WHERE name = '$food'";
$user = $pdo->query($query)->fetch();
echo $user['name']."<br />";
echo $user['kcal'] / 100 * $amount;
?>
in your javascript code the result is found in data.responseText
here the new script
$("#submit").click(function() {
var food = $("#food").val();
var amount = $("#amount").val();
$.ajax({
url: 'search_value.php',
type: 'POST',
data: {"food":food,"amount":amount},
success: function(data)
{
$('#update_div').html(data.responseText);
}
});
});

Tested and your JavaScript code works. The issue may be in the PHP code.
Have you tried correcting the "$_GET" as suggested by others?

Ajax autocomplete doesn't return correct value

I have an ajax autocomplete where it returns the full name of the user. However, when there are instances where some names or values are the same, it doesn't return the correct value. Rather, it returns the first value in the dropdown. Even if it has 4 same occurences, it still returns the first value.
When I click Stannis Arryn Baratheon, it returns Stannis Targaryen Baratheon.
Here is my php code (sql/php code; ad.php):
<?php
include('config.php');
if($_POST)
{
if($_POST['search_keyword'])
{
$similar = mysql_real_escape_string($_POST['search_keyword']);
$result=mysqli_query($conn, "SELECT * FROM person WHERE (firstName like '" . $_POST["search_keyword"] . "%' OR lastName like '" . $_POST["search_keyword"] . "%') AND residentOrNot = 'Yes' ");
if (mysqli_num_rows($result) > 0) {
while($row=mysqli_fetch_array($result))
{
//$name = $row['fullname'];
//$copiedname = $row['fullname'];
//$b_name= '<strong>'.$similar.'</strong>';
//$final_name = str_ireplace($similar, $b_name, $name);
?>
<div class="show" align="left">
<span class="returnName"><?php echo $row["firstName"].' '.$row["middleName"].' '.$row["lastName"]; ?></span>
<span class="returnID" style="display:none"><?php echo $row['idPerson'];?></span>
</div>
<?php
}
}
else {
?>
<div class="show" align="left">
<span class="returnMessage">No matching records found.</span>
</div>
<?php
}
}
mysqli_close($conn);
}
?>
HTML input form:
<form method="post" action="try.php" name="try">
<div class='web'>
<input type="text" class="search_keyword" id="search_keyword_id" placeholder="Search" />
<input type="hidden" name="resID" id="resID"/>
<div id="result"></div>
<input type="submit" name="try" value="Submit">
</div>
AJAX/JS/JQUERY CODE (i think this is where the problem occurs):
<script type="text/javascript">
$(function(){
$(".search_keyword").keyup(function()
{
var search_keyword_value = $(this).val();
var dataString = 'search_keyword='+ search_keyword_value;
if(search_keyword_value!='')
{
$.ajax({
type: "POST",
url: "ad.php",
data: dataString,
cache: false,
success: function(html)
{
$("#result").html(html).show();
}
});
}
return false;
});
jQuery("#result").on("click", function(e)
{
/*var $clicked = $(e.target);
var $name = $clicked.find('.returnName').html();
var decoded = $("<div/>").html($name).text();
$('#search_keyword_id').val(decoded);
var $clicked = $(e.target);
var $id = $clicked.find('.returnID').html();
var id = $("<div/>").html($id).text();
$('#resID').val(id);
*/
$name = $('span.returnName',this).html();
$name = $("<div/>").html($name).text().toString();
$('#search_keyword_id').val($name);
$id = $('span.returnID',this).html();
$id = $("<div/>").html($id).text().toString();
$('#resID').val($id);
});
jQuery(document).on("click", function(e) {
var $clicked = $(e.target);
if (! $clicked.hasClass("search_keyword")){
jQuery("#result").hide();
}
});
});
</script>
It really returns the first value even if I click the second or third or fourth value. Where did I go wrong in my code? Please help me. Thank you so much!

Your code is currently collecting all elements with class returnName in #result, and by calling .html() on that collection jQuery will only return the html of the first element found. The same goes for the your returnID search. This is why you are only getting the first returned entry.
Modify your #result click handler to only trigger for elements with class show, since that is the element that will contain your data.
jQuery("#result").on("click", ".show", function(e){
Then all you have to do is search for the elements with class returnName and returnID and call .text().
var showName = $('.returnName',this).text();
var showId = $('.returnID',this).text();
$('#search_keyword_id').val(showName);
$('#resID').val(showId);
So all together
jQuery("#result").on("click", ".show", function(e){
var showName = $('.returnName',this).text();
var showId = $('.returnID',this).text();
$('#search_keyword_id').val(showName);
$('#resID').val(showId);
});
Though note there are probably better ways of returning your data, and utilizing it rather than transporting it in html elements. For example use data-* attributes instead of using a separate span element to contain your id.
Another option is to use jQuery-UI's autocomplete that does most of the client side work for you and just return the raw data in JSON format from your php script.

In your php code, change this:
<div class="show" align="left">
<span class="returnName"><?php echo $row["firstName"].' '.$row["middleName"].' '.$row["lastName"]; ?></span>
<span class="returnID" style="display:none"><?php echo $row['idPerson'];?></span>
</div>
With this:
<div class="show" align="left">
<span class="returnName" data-id="<?php echo $row['idPerson'];?>"><?php echo $row["firstName"].' '.$row["middleName"].' '.$row["lastName"]; ?></span>
</div>
And your new jquery function:
jQuery("#result").on("click","'.returnName" function(e)
{
var choosenName = $(this).html();
var choosenId = $(this).data('id');
$('#search_keyword_id').val(choosenName );
$('#resID').val(choosenId );
});