I have been trying different ways to draw an image from a videostream of size 1920*1080 on a canvas of size 1080*1920. I want to rotate the video -90ยบ so it fits exactly on the canvas (not resizing the original video by shrinking and expanding). The following is what I tried:
canvas = document.createElement('canvas');
canvas.height = 1920;
canvas.width = 1080;
context = canvas.getContext('2d');
context.drawImage(videoSrc, 0, 0, 1080, 1920, 1080, -1920, 1080, 1920);
// I have been trying different combinations of above numbers
return canvas;
I haven't used context.rotate() or any other translation method as I don't want to rotate the canvas but just draw the video starting from a different position in the canvas. Maybe I'm wrong. Thanks for reading
You need to call to rotate() within your context prior to drawing your image. Like so:
canvas = document.createElement('canvas');
canvas.height = 1920;
canvas.width = 1080;
//Angle to rotate, negative for counter clockwise
degrees = 45;
context = canvas.getContext('2d');
//Rotation calculated in radians (hence the math).
context.rotate(degrees * Math.PI / 180);
context.drawImage(videoSrc, 0, 0, 1080, 1920, 1080, -1920, 1080, 1920);
//Reset rotation
context.resetTransform();
return canvas;
Related
I am trying to put image data 100x100 to canvas 1000x1000 , but cant able to do it ,
let width=1000; //canvas width
let height=1000; //canvas height
let img_w=100; //image width
let img_h=100; //image height
let img=new Image();
img.width=img_w
img.height=img_h
img.src="./flower.jpg"
var canvas = document.getElementById('mycanvas');
var context = canvas.getContext('2d');
canvas.width = width;
canvas.height = height;
let pixels,scannedimg;
img.onload=()=>{
context.drawImage(img, 0, 0,width,height );
scannedimg = context.getImageData(0, 0, img.width, img.height);
pixels=scannedimg.data
console.log(pixels)
redraw();
}
let row=4*img_w;
let col=img_h;
function redraw(){
for(let i=0;i<row;i+=4){
for(let j=0;j<col;j++){
pixels[i+j*row]=0;
pixels[i+j*row+1]=0;
pixels[i+j*row+2]=0;
//pixels[i+j*400+3]=0;
}
}
scannedimg.data=pixels;
console.log(scannedimg);
context.putImageData(scannedimg,0,0,0,0,width,height);
}
i have converted the original array into a black image array (array of zeros) , but while putting on canvas , it is still 100x100
How to scale it to 1000x1000?
i don't want to iterate through 1000x1000 and set it to zero ,
i need a computationally efficient answer
Unless you outsource the pixel calculations to a WebAssembly module a JavaScript-only approach would indeed be rather slow for a large image.
Honestly I'm not sure what you are actually doing in your code.
First your drawing an unknown-sized .jpg to a 1000x1000 canvas which - unless the .jpg is also 1000x1000 - will scale and eventually distort the source image.
let width=1000;
let height=1000;
context.drawImage(img, 0, 0, width, height);
Secondly you're obtaining the pixel data of a 100x100 region from the top-left of your 1000x1000 canvas.
let img_w=100;
let img_h=100;
img.width=img_w;
img.height=img_h;
scannedimg = context.getImageData(0, 0, img.width, img.height);
Finally in your redraw() function you're rather randomly setting some of the pixels to black and draw it back to the canvas at 1000x1000 (which doesn't work that way but I will get into it later).
Let's do it a little different. Say we have a 300x200 image. First we need to draw it to a 100x100 canvas while maintaining it's aspect ratio to get the 100x100 imagedata.
This can be done using a dynamically created off-screen <canvas> element as we don't need to see it.
Now the tricky part is the CanvasRenderingContext2D putImageData() method. I assume you were thinking that the last pair of parameters for the width & height would stretch existing pixel data to fill the region specifid by (x, y, width, height). Well that's not the case. Instead we need to - again - paint the 100x100 pixel data to a same-sized off-screen canvas (or for simlicity re-use the existing) and draw it to the final canvas using the drawImage() method.
Here's everything put together:
let pixelsWidth = 100;
let pixelsHeight = 100;
let finalWidth = 500;
let finalHeight = 500;
let tempCanvas = document.createElement('canvas');
let tempContext = tempCanvas.getContext('2d');
tempCanvas.width = pixelsWidth;
tempCanvas.height = pixelsHeight;
let pixelData;
let img = new Image();
img.crossOrigin = 'anonymous';
img.onload = (e) => {
let scale = e.target.naturalWidth >= e.target.naturalHeight ? pixelsWidth / e.target.naturalWidth : pixelsHeight / e.target.naturalHeight;
let tempWidth = e.target.naturalWidth * scale;
let tempHeight = e.target.naturalHeight * scale;
tempContext.drawImage(e.target, pixelsWidth / 2 - tempWidth / 2, pixelsHeight / 2 - tempHeight / 2, tempWidth, tempHeight);
pixelData = tempContext.getImageData(0, 0, pixelsWidth, pixelsHeight);
redraw();
}
img.src = 'https://picsum.photos/id/237/300/200';
function redraw() {
let canvas = document.getElementById('canvas');
let context = canvas.getContext('2d');
canvas.width = finalWidth;
canvas.height = finalHeight;
tempContext.putImageData(pixelData, 0, 0);
context.drawImage(tempCanvas, 0, 0, finalWidth, finalHeight);
}
canvas {
background: #cccccc;
}
<canvas id="canvas"></canvas>
I'm using node-canvas and I was wonder how style an imported image in canvas similar to how you would an image in CSS.
For example, how would I crop a square image in canvas to a circle. In CSS, all you need to do is set border radius to 50%.
Well obviously you cannot use CSS in this case since CSS is applied to the DOM and not the the pixel based content of a Canvas element.
However the Canvas element has its own set of draw functions which allow to you replicate or at least approximate CSS rules.
Since you mentioned cropping an image to a circle I'll focus on this example. To achieve this effect you want to specify a clipping region before drawing the image. Every pixel outside of the clipped region will not be drawn. Effectively this will crop the image to the clipped region.
In code:
// Retrieve canvas and get context
var canvas = document.getElementById("canvas");
var context = canvas.getContext("2d");
// Save the context so we can undo the clipping region at a later time
context.save();
// Define the clipping region as an 360 degrees arc at point x and y
context.beginPath();
context.arc(x, y, radius, 0, 2 * Math.PI, false);
// Clip!
context.clip();
// Draw the image at imageX, imageY.
context.drawImage(image, imageX, imageY);
// Restore context to undo the clipping
context.restore();
I'd advice taking a look at this page to give you an idea of what you can do with the Canvas element and the 2D rendering context.
I don't know if this would work in node, However you can do this with canvas;
The simplest way of doing it is using, as you intended, border-radius:
canvas{border-radius:50%;}
An other way of doing it is by using the ctx.clip() method.
let canvas = document.querySelector("canvas");
let ctx = canvas.getContext("2d");
ctx.beginPath();
ctx.arc(125,120,100,0,2*Math.PI);
// you clip the context
ctx.clip();
let img = document.querySelector("#testImg");
ctx.drawImage(img, 0, 20);
<canvas width="250" height="240" >
<img id="testImg" src="theImage.jpg">
</canvas>
Yet an other way of doing it is by using ctx.globalCompositeOperation = "destination-atop"in this way:
const canvas = document.getElementById("canvas");
const ctx = canvas.getContext("2d");
let cw = canvas.width = 400,
cx = cw / 2;
let ch = canvas.height = 400,
cy = ch / 2;
ctx.globalCompositeOperation = "destination-atop";
let img = document.querySelector("#testImg");
ctx.drawImage(img, 0, 0);
ctx.beginPath();
ctx.fillStyle = "#f00";
ctx.arc(cx, cx, 100, 0, 2 * Math.PI);
ctx.fill();
I have two canvases. When I use drawImage() to copy from one canvas to the other, it is blurring the image slightly.
Why is this happening?
This seems like the kind of thing that occurs when theres some sub-pixel rounding. Maybe this is caused by the 45 degree 'rotation'?
Here is an example showing it occur:
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
var tempCanvas = document.getElementById("tmpCanvas");
var tempCtx = tempCanvas.getContext("2d");
canvas.width = canvas.height = 200;
tempCanvas.width = canvas.width;
tempCanvas.height = canvas.height;
// translate origins
ctx.translate(canvas.width / 2, canvas.height / 2);
tempCtx.translate(canvas.width / 2, canvas.height / 2);
// Create a red square
ctx.fillStyle = "rgba(255,0,0, 0.1)";
ctx.fillRect(-50, -50, 100, 100);
var angle = 0;
// Each draw we copy the current canvas to the tmpCanvas. Then copy it back to the original canvas.
function draw() {
angle += 45;
tempCtx.save();
tempCtx.rotate(angle * Math.PI / 180);
tempCtx.drawImage(
canvas,
0, // sourceX
0, // sourceY - note that source ignores translation. It's not a canvas context, so we choose top left corner of the canvas to start copying pixels.
canvas.width, // sourceWidth
canvas.height, // sourceHeight
-0.5 * canvas.width, // destinationX
-0.5 * canvas.height, // destinationY
canvas.width, // destinationWidth
canvas.height // destinationHeight
);
tempCtx.restore();
ctx.drawImage(
tempCanvas,
0,
0,
canvas.width,
canvas.height,
-0.5 * canvas.width,
-0.5 * canvas.height,
canvas.width,
canvas.height
);
// requestAnimationFrame(draw);
}
document.addEventListener("click", draw);
canvas {
border: 1px solid blue;
}
<p>
Click to trigger a "draw".
<br/>
A draw will do this:<br/>
1. rotate the bottom canvas by 45 degrees.<br/>
2. copy the top canvas to the bottom canvas<br/>
3. copy the bottom canvas to the top canvas<br/>
</p>
<br/>
<p>
Clicking repeatedly will "blur" the squares. Why?
</p>
<br/>
</p>
<canvas id="canvas"></canvas>
<canvas id="tmpCanvas"></canvas>
This is just antialiasing in action. When rotating twice by 45 degrees, the antialised edges fall slightly outside the original square, and these add up over time.
My goal is to make a canvas where you can draw on it, as the existing contents rotate about the origin.
You can make the drawing actions happen on the original canvas (apply the inverse rotation to the position of the mouse), and then repeatedly draw the original canvas rotated to the output canvas. Data flows in just one direction, from the original to the output, so there's no degradation.
There's quite a few topics here about rotating images with canvas on js. I read most of them, and couldn't figure out a solution for my problem.
I'm receiving an image (from an upload component) of whatever resolution. I'm resizing it to 1024x768 like:
var canvas = document.createElement('canvas');
var ctx = canvas.getContext("2d");
if (img.width >= img.height) {
canvas.width = 1024;
canvas.height = 768;
} else {
canvas.width = 768;
canvas.height = 1024;
}
ctx.drawImage(img, 0, 0, canvas.width, canvas.height);
It works fine.
But on Safari/iOs, when I take a picture and upload, the image has ALWAYS a higher width value than height, so the code above doesn't work.
So I decided to use exif-js to detect the image's orientation. When the Orientation attribute is higher than 4, I need to rotate the image 90 degrees, and swap height and width values.
I tried to rotate the image like this:
canvas.width = 768; // swapping values
canvas.height = 1024;
ctx.translate(canvas.width/2, canvas.height/2); // translate to center
ctx.rotate(Math.PI/2); // rotate 90 degrees
ctx.drawImage(img, -img.width/2,-img.height/2); // not sure of the dx and dy values here...
The image is rotated. But it has taken just a small portion of the original image to display on the canvas, so it feels "zoomed in"... it seems that I'm using the wrong values on the drawImage method, but not sure how to fix.
How can I fix this rotation with fixed height and width values?
To rotate 90 deg clockwise on a new canvas.
const canvas = document.createElement("canvas");
canvas.width = image.height;
canvas.height = image.width;
const ctx = canvas.getContext("2d");
ctx.setTransform(
0,1, // x axis down the screen
-1,0, // y axis across the screen from right to left
image.height, // x origin is on the right side of the canvas
0 // y origin is at the top
);
ctx.drawImage(image,0,0);
ctx.setTransform(1,0,0,1,0,0); // restore default
If you need to scale the image to fit a size (assuming image will be rotated)
const width = 1024; // after rotation
const height = 768; // after rotation
const scale = width / image.height; // how much to scale the image to fit
const canvas = document.createElement("canvas");
canvas.width = width;
canvas.height = height;
const ctx = canvas.getContext("2d");
ctx.setTransform(
0,scale, // x axis down the screen
-scale,0, // y axis across the screen from right to left
width, // x origin is on the right side of the canvas
0 // y origin is at the top
);
ctx.drawImage(image,0,0);
ctx.setTransform(1,0,0,1,0,0); // restore default
I am getting pixels values from an image using canvas. The image size is 170*170 pixels. Here is my code:
var canvas = document.createElement("canvas");
canvas.style.width = img.width;
canvas.style.height = img.height;
canvas.getContext('2d').drawImage(img, 0, 0, img.width, img.height);
var pixelData = canvas.getContext('2d').getImageData(0, 0, img.width, img.height).data;
It works well, I have values in pixelData, until I reach pixelData[102000]... I've test it with a white image, and all the values from pixelData[0] to pixelData[101999] are 255, but then it is 0 until the end...
Somebody sees why? Maybe this is about canvas width and height?
Your canvas size is not what you think it is.
You are only setting the size of the canvas element not the canvas bitmap:
canvas.style.width = img.width;
canvas.style.height = img.height;
This means your bitmap is actually 300 x 150 pixels in size, the default size, and you're just scaling that to the size of the image (since it's all white you won't be able to detect this so easily).
Since your image is 170 x 170 pixels you will only paint part of the canvas leaving the rest to default RGBA value [0,0,0,0].
In order to properly set the size of the canvas you must edit the above mentioned lines to be:
canvas.width = img.width;
canvas.height = img.height;