Hi guys I was making a javascript function for dismissing or hiding a div Ive search through the internet and found some answers but it does not apply on my code
Here is my code:
<script>
function Displayout()
{
$("#siteicon").mouseout(function () {
$("#map_tooltip").hide("drop", { direction: "down" }, "slow");
});
}
</script>
And here is the div that will trigger the function
<div id='siteicon' style="background-image:url('src/images/redbutton.png');margin-top:0px;margin-left:-8px;height:10px;width:10px;background-repeat:no-repeat;" onmouseover="displayData();" onmouseout="Displayout();"></div>
UPDATE:
and here is the id of the div I want to hide
<div id='infocontainer'></div>
Thank you in advance
Seems like there is syntax wrong with your hide() method. Try this:
function displayData()
{
$("#map_tooltip").show("slow");
}
function displayOut()
{
$("#map_tooltip").hide("slow");
}
<script src="https://code.jquery.com/jquery-3.2.1.min.js" integrity="sha256-hwg4gsxgFZhOsEEamdOYGBf13FyQuiTwlAQgxVSNgt4=" crossorigin="anonymous"></script>
<div id='siteicon' style="background-color:grey;margin-top:0px;margin-left:-8px;height:20px;width:60px;background-repeat:no-repeat;" onmouseover="displayData();" onmouseout="displayOut();">SiteIcon</div>
<div id='map_tooltip' hidden="true">Should be hidden on mouseout of #siteicon</div>
The parameters for hide are wrong, it's giving error "Uncaught TypeError: n.easing[this.easing] is not a function". You can use "slow" to slow up the hiding effect but you can't specify the direction. You order is wrong as well. Please have a look at JSFiddle for Demo and api.jquery.com for for hide function.
You don't need onmouseout since you are using JQuery, and there seems to be a problem in the hide() of yours, so try removing the parameter inside.
$('#test').mouseout(function() {
$(this).hide();
})
#test {
height: 200px;
width: 200px;
background-color:pink}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="test">content</div>
Related
I have managed to create a button that shows my div. but I want to have the button disappear as that happens.
At the moment my button only disappears the second time I click it. Any help appreciated.
$(document).ready(function() {
$('.click').click(function() {
$('#contact-form').toggle('slide', 500)
$('.click').toggle();
});
});
.click {
display: block;
}
#contact-form {
display:none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button class="click">click</button>
<div id="contact-form"></div>
The reason why it is not working is, you are mixing the display between CSS and JavaScript. jQuery uses the current inline style to check if the button is hidden to display it, when you use .toggle(). Since it doesn't have anything at first, it adds a display: block (or whatever the initial value is) and then when you do the second time, it correctly identifies and removes.
The best thing to do is to use classes. I would suggest something like this parent class.
$(document).ready(function() {
$('.click').click(function() {
$("body").toggleClass("contact-form-open");
});
});
.contact-form-open .click,
#contact-form {
display: none;
}
.contact-form-open #contact-form {
display: block;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button class="click">Click Me</button>
<div id="contact-form">
Contact Form
</div>
This way, you control everything using CSS and you don't mess up with the event listeners or add the yucky inline CSS.
I've tried what you've tried and it seems to be working. Maybe it's because you don't close the div tag ?
$(function() {
$('.click').click(function() {
$('.myDiv').toggle();
$('.click').toggle();
})
});
http://plnkr.co/edit/wD0bwf8XK3CFXXM7rVWF?p=preview
but I want to have the button disappear as that happens.
So just use hide() instead of toggle :
$('.click').click(function() {
$('.click').hide();
$('#contact-form').toggle('slide', 500)
});
Hope this helps.
$(document).ready(function() {
$('.click').click(function() {
$('.click').hide();
$('#contact-form').toggle('slide', 500)
});
});
#contact-form {
display:none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button class="click">click</button>
<div id="contact-form">Form content</div>
More easy:
$(document).ready(function() {
$('.click').click(function() {
$("#contact-form").show();
$(this).remove();
});
});
#contact-form{display:none;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button class="click">Click Me</button>
<div id="contact-form">
Contact Form
</div>
I am looking for javascript command that would do the following:
Click on image -> open spoiler
Click on image again -> hide spoiler
Here is what I got so far:
javascript in my html
<script>
function myFunction() {
document.getElementById("prvy").innerHTML = document.getElementById('spoiler_id').style.display='';}
</script>
Spoiler
<a id="show_id"
onclick="document.getElementById('spoiler_id').style.display=''; document.getElementById('show_id').style.display='none';"
class="link"></a><span id="spoiler_id"
style="display: none">[Show]<button onclick="document.getElementById('spoiler_id').style.display='none';
document.getElementById('show_id').style.display='';"
class="link">[Hide]</button>
<br><h1 id="bz">Heading</h1><br><br><p>text</p></span>
And my button:
<div id="prvy" onclick="myFunction()"></div>
What I managed to do, is to click on a image, wich will open spoiler. Hovewer, I've been unable to do the second part, onclick again it will close the spoiler.
I also did serach for solution alredy, nothing worked for me, not even this: Link
I also tired if{} else{} statement but didn't work for me either.
Help would be really appreciated, as I am getting desperate on this one.
You can use jQuery .toggle() to toggle show/hide
$("#prvy").click(function() {
$("#spoiler_id").toggle();
});
Note : You need to include jQuery in your document as
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
Working snippet :
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<a id="show_id"
onclick="document.getElementById('spoiler_id').style.display=''; document.getElementById('show_id').style.display='none';"
class="link"></a><span id="spoiler_id"
style="display: none">[Show]<button onclick="document.getElementById('spoiler_id').style.display='none';
document.getElementById('show_id').style.display='';"
class="link">[Hide]</button>
<br><h1 id="bz">Heading</h1><br><br><p>text</p></span>
<div id="prvy" onclick="myFunction()">button</div>
<script>
$("#prvy").click(function() {
$("#spoiler_id").toggle();
});
</script>
In the JavaScript where you click the button use the simple jQuery function toggle.
$('#spoiler_id').toggle();
Toggle will hide the element selected if it is currently shown or display the element if it is currently hidden.
you would need some state that flips when the function is called.
like this.
<script>
var state = false;
function myFunction() {
state = !state;
if(state){
//do something
}else{
//do something else
}
}
</script>
Is that all of your code, it would be easier for you and less confusing too if you just gave the buttons an on click function and then called that function in your js.
Can I see all of your html
I am giving an example to concerned question using javascript.
HTML:
<script type="text/javascript">
var permit = 'true';
function showhide() {
var getcont = document.getElementsByClassName('hidshowcont');
if (permit === 'true') {
permit = 'false';
getcont[0].style.display = 'block';
}
else {
permit = 'true';
getcont[0].style.display = 'none';
}
}
</script>
<style type="text/css">
.hidshowcont{
height: 200px;
width: 300px;
border: 1px solid #333333;
display: none;
}
</style>
<img src="https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcR1cSDTn18ufwjuMihttTvCPJOnFY-4hxbPcaOVd87nSPaQakbP9IERaQ" />
<br />
<br />
<div class="hidshowcont">
This is an example of hide and show the container by clicking of an image.
</div>
This will help u much
Have a fairly simple show/hide script for a set of data filters from a button. I've been looking at solutions on how to animate the transition but can't seem to see how this script differs from what's described on the jQuery site.
I read somewhere else that CSS3 animations might be easier or better but that also remains a mystery to me.
Is there an easy modification to this script:
$('.toggle').click(function (event) {
event.preventDefault();
var target = $(this).attr('href');
$(target).toggleClass('hidden show');
});
Instead of changing the classes, you can use the built-in toggleX methods (eg toggle() and slideToggle()).
If you want to do something more fancy such as animating colours, you'll need to look at the animate method and possibly including jquery-ui, which is where css3 transitions may be easier / less overhead unless you're already including jquery-ui.
$("#toggle").click(function() {
$("#target").toggle(500);
});
$("#slide").click(function() {
$("#target").slideToggle(500);
});
Basic fiddle: https://jsfiddle.net/t2j03v6d/
$('.target').on( 'click', function () {
var $stuff = $(this).find('.stuff');
if ( $stuff.is(':visible') ) {
$stuff.slideUp('slow');
} else {
$stuff.slideDown('slow');
}
});
.target .stuff {
display: none;
height: 400px;
background-color: #F00;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<ul>
<li class="target">
Show/Hide
<div class="stuff"></div>
</li>
</ul>
I'm not sure what animation you're looking for but here I've used slideToggle() (http://api.jquery.com/slidetoggle/) using some of the code you've provided: https://jsfiddle.net/8gavvmnL/1/
HTML:
<a class="toggle" href="#pop">Click Me</a>
<div id="pop">
I'm hidden until the button is clicked!
</div>
jQuery:
$("#pop").hide();
$('.toggle').click(function (event) {
event.preventDefault();
var target = $(this).attr('href');
$(target).slideToggle();
});
can anyone help me fix this, what am I missing?
<script type="text/javascript">
$('#loginButton').click(function() {
$('#toplogin').animate({
height: '0px'
});
});
</script>
The onClick doesn't even execute!
The div I want the onClick event to work on is here:
<div id="loginButton">Login »</div>
The div I want the animation to affect is here:
div id="toplogin"> <!-- more stuff --> </div>
Remove the semicolon after height: '0px' to make your JavaScript valid.
<script type="text/javascript">
$('#loginButton').click(function() {
$('#toplogin').animate({ height:'0px' });
});
</script>
However, unless you have overflow:hidden set for #toplogin the element will still be visible, even though it's height is 0px. An easier way is just using slideUp().
<script type="text/javascript">
$('#loginButton').click(function(){ $('#toplogin').slideUp(); });
</script>
try this:
$('#loginButton').click(function() {
$('#toplogin').animate({
height: 0
},
function() {
$(this).css('display', 'none');
});
});
you should wrap your code in following construction to make it valid as jQuery code:
$(document).ready(function(){
your code;
})
Hey there guys, Im good with HTML and CSS but have only jsut started to scratch the surface of jQuery. I'm looking to make 3 divs fade in on page load one after another.
So far I have this
<script type="text/javascript">
$('#1').hide().fadeIn(1500);
$('#2').hide().fadeIn(1500);
$('#3').hide().fadeIn(1500);
</script>
I heard that to use css to set the display to none is a nightmare for anyone with a non JavaScript browser so I used the hide function to initially hide the divs.
But this only fades them in all at once.
Any ideas?
You can .delay() each so the one before fades in at the right time, for example:
$("#1, #2, #3").hide().each(function(i) {
$(this).delay(i*1500).fadeIn(1500);
});
This fades them in...in the same order they occur in the page which is usually what you're after, the first is delayed 0 so it's instant, the second is delayed 1500ms (so when the first finishes, etc). In the .each() callback i is the index, starting with 0 so you can use that to quickly calculate the right delay here.
Another advantage here is this approach is much easier to maintain, give them a class for example then you can just do:
$(".fadeMe").hide().each(function(i) {
$(this).delay(i*1500).fadeIn(1500);
});
Then you require zero maintenance on the JavaScript side to add additional <div> elements to fade.
The fade in command contains a call back function, see documentation. This means you could chain the events.
<script type="text/javascript">
$('#1, #2, #3').hide();
$('#1').fadeIn(1500, function(){ $('#2').fadeIn(1500, function(){$('#2').fadeIn(1500)})});
</script>
<script type="text/javascript">
$('#1').hide().fadeIn(1500, function(){
$('#2').hide().fadeIn(1500, function(){
$('#3').hide().fadeIn(1500);
});
});
</script>
Using the Delay function as following:
<script type="text/javascript">
$('#1').hide().fadeIn(1500);
$('#2').hide().delay(1500).fadeIn(1500);
$('#3').hide().delay(3000).fadeIn(1500);
</script>
Here is a cleaner and generic way to achieve this effect:
check it out on http://jsfiddle.net/BztLx/20/
Logic trick relies on the callback functionality of the fadeIn and using .eq() as an iterator over the selected elements.
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
$(document).ready(function() {
function sequentialFadeIn(selectorText, speed, display, callBack) {
display = typeof display !== 'undefined' ? display : "block";
var els = $(selectorText), i = 0;
(function helper() {
els.eq(i++).fadeIn(speed, helper).css("display", display);
if (callback && i === els.length) callback();
})();
}
sequentialFadeIn(".toBeFaddedIn", "slow", "inline-block", function() {
console.log("I am just an optional callback");
});
});
</script>
</head>
<body><style media="screen" type="text/css">
.hello {
background-color: blue;
height:50px;
width: 50px;
display: none;
}
</style>
<div class="hello toBeFaddedIn"></div>
<div class="hello toBeFaddedIn"></div>
<div class="hello toBeFaddedIn"></div>
<div class="hello toBeFaddedIn"></div>
<div class="hello toBeFaddedIn"></div>
</body></html>