How to enable disable field with radio in looping - javascript

I have some problem in looping to make an action if radio with value = 1 then input field is enable.
here is my code, but imagine that the field and radio in a looping :
<form name="form" id="form">
<table>
<?php
$arr = array(0=>"Disable", 1=>"Enable");
for($i=0; $i<5; $i++):
?>
<tr>
<td><input type='text' name='input[]' id='input'></td>
<td>
<?php
foreach($arr as $key=>$val):
?>
<input type='radio' name='ans[<?php echo $i; ?>]' id='ans' value='<?php echo $key; ?>' onClick="d_e(this.value)"> <?php echo $val;
<?php endforeach; ?>
</td>
</tr>
<?php endfor; ?>
</table>
<script>
function d_e(id){
var i = document.form.input;
for(var c=0; c<i.length; c++){
if(id==1){
i[c].disabled = false;
}else{
i[c].disabled = true;
}
}
}
</script>

Related

How to use PHP loop variable in javascript?

I have run an SQL statement to get all the records I need to show in a HTML table.
I have then run a while loop to display the records from the database. (The code for this is below.)
<table class="projects-table">
<tr>
<th>Complete?</th>
<th>Paid?</th>
<th>Project Name</th>
<th>£ / hr</th>
<th>End Date</th>
<th>Hours Logged</th>
<th><i class="fa fa-trash"></i></th>
</tr>
<?php
$select_id_jobs = mysqli_query($mysqli, "SELECT id FROM users WHERE username='$login_user'");
while($row = mysqli_fetch_array($select_id_jobs)) {
$id_jobs = $row['id'];
}
$select_jobs_with_usrid = mysqli_query($mysqli, "SELECT * FROM jobs WHERE username_id = '$id_jobs';");
while($row = mysqli_fetch_array($select_jobs_with_usrid)) {
?>
<tr id="<?php echo $rowId; ?>">
<td>
<!-- Complete Checkbox -->
<input type="checkbox" id="<?php echo $completeCheck;?>" onclick="compTask();">
</td>
<td>
<!-- Paid checkbox -->
<input type="checkbox" onclick="paidTask()">
</td>
<td>
<?php echo $row['project_title']; ?>
</td>
<td>
<?php echo $row['cost_hour']; ?>
</td>
<td>
<?php echo $row['completion_date']; ?>
</td>
<td>
<?php echo $row['time_spent']; ?>
</td>
<td>
<div class="delete-btn"><a onclick="deleteTask()">DELETE</a></div>
</td>
</tr>
<?php } ?>
</table>
As you can see from the checkbox for completing a task. What I want to do is use javascript so that when the checkbox is checked the text from the other records turns green.
I have included the javascript I am trying to use below. I don't know why but I can't access the inputs ID in order to change the css.
<script>
function compTask() {
if (document.getElementById("<?php echo 'complete-' . $row['id'] ?>").checked == true) {
document.getElementById("<?php echo 'tr' . $row['id']; ?>").style.color = "green";
alert("hello");
} else {
document.getElementById("<?php echo 'tr' . $row['id']; ?>").style.color = "black";
}
}
Okay easy way to do that is to print id as parameter in js function
something like that:
<input type="checkbox" id="<?php echo $completeCheck;?>"
onclick="compTask( '<?php echo $row['id'];?>' );">
and in js function deal with id from parameter:
function compTask(id) {
if (document.getElementById('complete-' + id).checked == true) {
document.getElementById('tr' + id).style.color = "green";
alert("hello");
}
}
Hy,
You need to add id in onclick="deleteTask('<?php echo $row['id']; ?>')">
Now in you function have id:
function deleteTask(id) { console.log(id) }

Updating quantity in cart table

I want that update button should be in that field which I choose.But it appears only in first row and is updating for first row quantity field.
<form action="cart.php?action=update" method="post">
<table>
<tr>
<th colspan="2">ITEM</th>
<th>QUANTITY</th>
<th>PRICE</th>
<th>SUBTOTAL</th>
<th>REMOVE</th>
</tr>
<?php
$query = "select * from cart where customer_id='$user' ";
$result = mysqli_query($con,$query);$b = 0;$c = 0;
while($row = mysqli_fetch_array($result))
{
$productid = $row['product_id'];
$query2 = "select * from product where product_id='$productid'";
$result2 = mysqli_query($con,$query2);
while($row2=mysqli_fetch_array($result2))
{
?>
<tr>
<td rowspan="3"><img src="upload/<?php echo $row2['pimage']; ?>" height="50px" width="50px"></td>
<td rowspan="3"><?php echo $row2['pname']; ?></td>
<td rowspan="3">
<input tpe="text" name="newqty" value="<?php echo $qty = $row['quantity']; ?>" onkeypress="showsubmit()">
<input style="visibility:hidden;width:80px;border-radius:10px;background-color:green;border:none;padding:5px;color:white;" type="submit" name="sub1" id="sub1" value="UPDATE">
<input type="hidden" name="hidcartid" value="<?php echo $row['cart_id'] ?>"/>
<input type="hidden" name="hidproductid" value="<?php echo $row['product_id']; ?>"/>
<script>
function showsubmit()
{
document.getElementById("sub1").style.visibility = "visible";
}
</script>
</td>
<td>Price:<?php echo $sp = $row2['psellingprice']; ?></td>
<?php
$total = $sp * $qty;
?>
<td rowspan="3">
<?php
echo $t = $total;
$b = $b + $t;
?></td>
<td rowspan="3">REMOVE</td>
</tr>
<?php
$action = ( array_key_exists( 'action', $_REQUEST) ? $_REQUEST['action'] : "" );
if($action =="delete")
{
deletecart($_REQUEST['cid']);
}
if($action=="update")
{
echo "update function called";
updatecart();
echo "update function executed";
}
?>
<tr>
<td>Selling Price:<?php echo $p = $row2['pprice']; ?></td>
</tr>
<tr>
<td>You Saved:
<?php
$d = $row2['pdiscount'];
$s = ($p*$d)/100;
echo $q = $s * $qty;
$c = $c + $q;
?> rs.</td>
</tr>
<?php
}
}
?>
</table>
and cart2.php
<?php
function deletecart($cartid)
{
include 'connection.php';
$sql1="delete from cart where cart_id=$cartid";
$executequery = mysqli_query($con,$sql1);
header('location:cart.php');
}
function updatecart()
{
include 'connection.php';
$cartId = $_POST['hidcartid'];
$productId = $_POST['hidproductid'];
$newqty = $_POST['newqty'];
echo("inside update function");
// update product quantity
$sql = "UPDATE cart
SET quantity = $newqty
WHERE cart_id = $cartId";
mysqli_query($con,$sql);
header('location:cart.php');
}?>
For row onw everything is fine.But for row2 update button appears in row1 and not updating at all.
<input tpe="text" name="newqty" value="<?php echo $qty = $row['quantity']; ?>" onkeypress="showsubmit(<?php echo $row['cart_id'] ?>)">
<input style="visibility:hidden;width:80px;border-radius:10px;background-color:green;border:none;padding:5px;color:white;"
type="submit"
name="sub_<?php echo $row['cart_id'] ?>"
id="sub_<?php echo $row['cart_id'] ?>"
value="UPDATE">
<script>
function showsubmit(id)
{
document.getElementById("sub_"+id).style.visibility ="visible";
}
</script>

single id alerting same time in a while loop

I am having a table from where i am fetching activities and displaying in a table ...like this
<table width="1000px;" style="border:0px;" >
<tr>
<?php
$sql_activities="select * from tb_activities";
$query_activities=mysql_query($sql_activities);
while($row_activities=mysql_fetch_array($query_activities))
{
?>
<td width="50">
<input type="radio" value="<?php echo $row_activities['activity_name']; ?>" name="activities" onclick="hi() " id="activities" /><?php echo " ".$row_activities["activity_name"]; ?></td>
<?php
}
?>
</tr>
</table>
Now i have applied it in an onlick event of a radio button and the script for the function is:
<script type="text/javascript">
function hi()
{
a = document.getElementById("activities").value;
alert(a);
}
</script>
i want to alert the name of the activity chosen but when i click on any activity, it shows the same. The first activity.ven if i have clicked on any other activity...can anyone help me ??
what you should do is change this:
onclick="hi()"
to this:
onclick="hi(this);
then your function would be:
function hi(who) {
var a = who.value;
alert(a);
}
In PHP side of things change:
<td width="50"><input type="radio" value="<?php echo $row_activities['activity_name']; ?>" name="activities" onclick="hi() " id="activities" /><?php echo " ".$row_activities["activity_name"]; ?></td>
To: ( YOU NEED Unique IDs on Input/ Radio Buttons to be generated dynamically & Sent to JS)
<?php $i = 1; ?>
<td width="50"><input type="radio" value="<?php echo $row_activities['activity_name']; ?>" name="<?php echo $row_activities['activity_name'].$i; ?>" id ="<?php echo $row_activities['activity_name'].$i; ?>" onclick="hi("<?php echo $row_activities['activity_name'].$i; ?> ")" /></td>
<?php $i++; ?>
In Javascript Change to This:
function hi(elementID) {
var value = document.getElementById(elementID).value;
alert(value);
}
Code may have some escape errors, but logically this should give you idea how to do it, Hope that helps.

Radio Button Value: "on"

i have this form, when user clicks on the submit button, a script open a popup where i need to print the radio button value. My problem is the printed value on the popup window: "on" but the result should be a number (selected person's id)
My PHP Code:
<form method="post" action="edit.php" onsubmit="target_popup(this,'edit.php')"><input type="submit" value="Modifica Giocatore" /><br /><br /><br />
<?php
//my queries (work)
?>
<table cellspacing="2" cellpadding="2">
<tr>
<th></th>
<th>Name</th>
<th>Surname</th>
</tr>
<?php
$i=0;
while ($i < $num) {
$id=mysql_result($results,$i,"ID");
$name=mysql_result($results,$i,"Name");
$surname=mysql_result($results,$i,"Surname");
?>
<tr>
<td><input type="radio" name="radioEdit" value"<?= $id; ?>" /><?= $id; ?></td>
<td><?=$name?></td>
<td><?=$surname?></td>
</tr>
<?php
$i++;
}
?>
<?php
echo "</table></form>"
?>
And this is my script:
function target_popup(form,page)
{
window.open(page, 'formpopup', 'left=100,top=100,width=600,height=400,menubar,toolbar,resizable');
form.target = 'formpopup';
}
edit.php file:
<?php
$prova = $_POST['radioEdit'];
echo $prova;
?>
Thanks.
The only way I could get this to work was to use sessions.
Here is what I could test without setting up an entire DB.
PHP
<?php
session_start();
$id="12345"; // test ID number
// works with sessions
$prova = $_POST['radioEdit'] = $_SESSION['id'] = $id;
echo $prova;
?>
<form method="post" action="edit.php" onsubmit="target_popup(this,'edit.php')">
<td><input type="radio" name="radioEdit" value"<?php echo $id; ?>" /><?= $id; ?></td>
<input type="submit" value="Modifica Giocatore" />
</form>
<script>
function target_popup(form,page)
{
window.open(page, 'formpopup', 'left=100,top=100,width=600,height=400,menubar,toolbar,resizable');
form.target = 'formpopup';
}
</script>
edit.php
<?php
session_start();
echo $_SESSION['id'];
echo $id;
echo "<br>";
var_dump($_SESSION['id']);
?>
What happens when you echo $id? Are you sure that it returns a value? Also isn't <?= ;?> considered really old and deprecated PHP? You should be using <?php echo ;?>

Cart is updated only once using Jquery and Codeigniter

I am working on Updating Codeigntier Cart with Jquery using Ajax call to update. Here is my jquery function
$(function() {
$('.cart_form select').on('change', function(ev) {
var rowid = $(this).attr('class');
var qty = $(this).val();
var postData_updatecart = {
'rowid' : rowid,
'qty' : qty
};
//posting data to update cart
$.ajax({
url : base_url + 'bookings/update_booking_cart',
type : 'post',
data : postData_updatecart,
beforeSend : function() {
$('#cart_content').html('Updating...');
},
success : function(html) {
//window.location.href = "postproperty.php?type="+suffix+'&page=page1';
$('#cart_content').html(html);
}
});
});
});
I have cart view file as
<div class="cart_form">
<?php echo form_open(base_url().'index.php/bookings/customerdetails', array('class' => 'bookings_form_customer', 'id' => 'bookings_form_customer')); ?>
<table cellpadding="6" cellspacing="1" style="width:100%" border="0">
<tr>
<th style="text-align:left">Item Description</th>
<th style="text-align:left">QTY</th>
<th style="text-align:right">Item Price</th>
<th style="text-align:right">Sub-Total</th>
</tr>
<?php $i = 1; ?>
<?php foreach ($this->cart->contents() as $items): ?>
<?php echo form_hidden($i.'[rowid]', $items['rowid']); ?>
<tr>
<td>
<?php echo $items['name']; ?>
<?php if ($this->cart->has_options($items['rowid']) == TRUE): ?>
<p>
<?php foreach ($this->cart->product_options($items['rowid']) as $option_name => $option_value): ?>
<strong><?php echo $option_name; ?>:</strong> <?php echo $option_value; ?><br />
<?php endforeach; ?>
</p>
<?php endif; ?>
</td>
<td>
<select name="<?php echo $i.'[qty]'; ?>" class="<?php echo $items['rowid']; ?>">
<?php
for($tt=0; $tt<=10; $tt++)
{
?>
<option value="<?php echo $tt; ?>" <?php if($tt==$items['qty']) echo 'selected="selected"'; ?>><?php echo $tt; ?></option>
<?php
}
?>
</select>
</td>
<td style="text-align:right"><?php echo $this->cart->format_number($items['price']); ?></td>
<td style="text-align:right">$<?php echo $this->cart->format_number($items['subtotal']); ?></td>
</tr>
<?php $i++; ?>
<?php endforeach; ?>
<tr>
<td colspan="2"> </td>
<td class="right"><strong>Total</strong></td>
<td class="right">$<?php echo $this->cart->format_number($this->cart->total()); ?></td>
</tr>
</table>
<p><?php echo form_submit('update_cart', 'Update your Cart'); ?></p>
</form>
</div>
Things are working Nice. But, lets say if I have 2 products, if i select one item's qty from 1 to 2, cart is updated and updated cart is shown using AJAX. But, if I immediately change another item's qty then it doesnt work.
The cart view file is inside class 'cart_form'.
Helping hands are appreciated.
I got an answer. You can refer below link
Ajax Request works only once
OR
Directly follow this
REPLACE jquery code part by
$(function() {
$(document).on( "change", "#bookings_form_customer select", function(ev) {
// your code goes here
});
});

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