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Is there a way to cause the JS engine to load a .js file without explicitly importing something from it?

Maybe I'm trying to do something silly, but I've got a web application (Angular2+), and I'm trying to build it in an extensible/modular way. In particular, I've got various, well, modules for lack of a better term, that I'd like to be able to include or not, depending on what kind of deployment is desired. These modules include various functionality that is implemented via extending base classes.
To simplify things, imagine there is a GenericModuleDefinition class, and there are two modules - ModuleOne.js and ModuleTwo.js. The first defines a ModuleOneDefinitionClass and instantiate an exported instance ModuleOneDefinition, and then registers it with the ModuleRegistry. The second module does an analogous thing.
(To be clear - it registers the ModuleXXXDefinition object with the ModuleRegistry when the ModuleXXX.js file is run (e.g. because of some other .js file imports one of its exports). If it is not run, then clearly nothing gets registered - and this is the problem I'm having, as I describe below.)
The ModuleRegistry has some methods that will iterate over all the Modules and call their individual methods. In this example, there might be a method called ModuleRegistry.initAllModules(), which then calls the initModule() method on each of the registered Modules.
At startup, my application (say, in index.js) calls ModuleRegistry.initAllModules(). Obviously, because index.js imports the exported ModuleRegistry symbol, this will cause the ModuleRegistry.js code to get pulled in, but since none of the exports from either of the two Module .js files is explicitly referenced, these files will not have been pulled in, and so the ModuleOneDefinition and ModuleTwoDefinition objects will not have been instantiated and registered with the ModuleRegistry - so the call to initAllModules() will be for naught.
Obviously, I could just put meaningless references to each of these ModuleDefinition objects in my index.js, which would force them to be pulled in, so that they were registered by the time I call initAllModules(). But this requires changes to the index.js file depending on whether I want to deploy it with ModuleTwo or without. I was hoping to have the mere existence of the ModuleTwo.js be enough to cause the file to get pulled in and the resulting ModuleTwoDefinition to get registered with the ModuleRegistry.
Is there a standard way to handle this kind of situation? Am I stuck having to edit some global file (either index.js or some other file it references) so that it has information about all the included Modules so that it can then go and load them? Or is there a clever way to cause JavaScript to execute all the .js files in a directory so that merely copying the files it would be enough to get them to load at startup?

a clever way to cause xxJavaScriptxx Node.js to execute all the .js files in a directory:
var fs = require('fs') // node filesystem
var path = require('path') // node path
function hasJsExtension(item) {
return item != 'index.js' && path.extname(item) === '.js'
}
function pathHere(item) {
return path.join('.', item)
}
fs.readdir('./', function(err, list) {
if (err) return err
list.filter(hasJsExtension).map(pathHere).forEach(require) // require them all
})
Angular is pretty different, all the more if it is ng serve who checks if your app needs a module, and if so serves the corresponding js file, at any time needed, not at first load time.
In fact your situation reminds me of C++ with header files Declaration and cpp files with implementation, maybe you just need a defineAllModules function before initAllModules.
Another way could be considering finding out how to exclude those modules from ng-serve, and include them as scripts in your HTML before the others, they would so be defined (if present and so, served), and called by angular if necesary, the only cavehat is the error in the console if one script tag is not fetched, but your app will work anyway, if it supposed to do so.
But anyway, it would be declaring/defining those modules somewhere in ng-serve and also in the HTML.
In your own special case, and not willing to under-evalute ng-serve, but is the total js for your app too heavy to be served at once? (minified and all the ...), since the good-to-go solution may be one of the many tools to build and rebuild your production all.js from your dev js folder at will, or like you said, with a drag&drop in your folder.
Such tool is, again, server-side, but even if you only can push/FTP your javascript, you could use it in your prefered dev environment and just push your new version. To see a list of such tools google 'YourDevEnvironment bundle javascript'.

To do more with angular serve and append static js files under specific conditions, you should use webpack so the first option i see here is eject your webpack configuration and after that you can specify what angular should load or not.
With that said, i will give an example:
With angular cli and ng serve any external javascript files you wanna include, you have to put them inside the scripts array in the angular-cli.json file.However you can not control which file should be included and which one not.
By using webpack configuration you can specify all these thing by passing a flag from your terminal to the webpack config file and do all the process right there.
Example:
var env.commandLineParamater, plugins;
if(env.commandLineParamater == 'production'){
plugins = [
new ScriptsWebpackPlugin({
"name": "scripts",
"sourceMap": true,
"filename": "scripts.bundle.js",
"scripts": [
"D:\\Tutorial\\Angular\\demo-project\\node_moduels\\bootstrap\\dist\\bootstrap.min.js",
"D:\\Tutorial\\Angular\\demo-project\\node_moduels\\jquery\\dist\\jquery.min.js"
],
"basePath": "D:\\Tutorial\\Angular\\demo-project"
}),
]}else{
plugins = [
new ScriptsWebpackPlugin({
"name": "scripts",
"sourceMap": true,
"filename": "scripts.bundle.js",
"scripts": [
"D:\\Tutorial\\Angular\\demo-project\\node_moduels\\bootstrap\\dist\\bootstrap.min.js"
],
"basePath": "D:\\Tutorial\\Angular\\demo-project"
}),
]
}
then:
module.exports = (env) => {
"plugins": plugins,
// other webpack configuration
}
The script.js bundle will be loaded before your main app bundle and so you can control what you load when you run npm run start instead of ng-serve.
To Eject your webpack configuration, use ng eject.
Generally speaking, when you need to control some of angular ng-serve working, you should extract your own webpack config and customize it as you want.

Make pdf.js 1.5 and require.js play nice together

In my project I have long used require.js together with the pdf.js library. Pdf.js have until recently been putting itself on the global object. I could still use it in my requirejs config by using a shim. The pdfjs library will in turn load another library called pdf.worker. In order to find this module the solution was to add a property to the global PDFJS object called workerSrc and point to the file on disk. This could be done before or after loading the pdfjs library.
The pdfjs library uses the pdf.worker to start a WebWorker and to do so it needs the path to a source file.
When I tried to update the pdfjs library in my project to a new version (1.5.314) the way to load and include the library have changed to use UMD modules and now everything get's a bit tricky.
The pdfjs library checks if the environment is using requirejs and so it defines itself as a module named "pdfjs-dist/build/pdf". When this module loads it checks for a module named "pdfjs-dist/build/pdf.worker". Since I have another folder structure I have added them to my requirejs config object with a new path:
paths: {
"pdfjs-dist/build/pdf": "vendor/pdfjs/build/pdf",
"pdfjs-dist/build/pdf.worker": "vendor/pdfjs/build/pdf.worker"
}
This is to make the module loader to find the modules at all. In development this works great. When I try to use the requirejs optimizer in my grunt build step however, it will put all of my project files into one single file. This step will try to include the pdf.worker module as well and this generates an error:
Error: Cannot uglify2 file: vendor/pdfjs/build/pdf.worker.js. Skipping
it. Error is: RangeError: Maximum call stack size exceeded
Since the worker source needs to be in a single file on disk I don't want this module to be included.
So I've tried two different config-settings in the requirejs config.
The first attempt was to override the paths property in my grunt build options:
paths: {
"pdfjs-dist/build/pdf.worker": "empty:"
}
The second thing to test is to exclude it from my module:
modules: [{
name: "core/app",
exclude: [
"pdfjs-dist/build/pdf.worker"
]
}]
Both techniques should tell the optimizer not to include the module but both attempts ended up with the same error as before. The requirejs optimizer still tries to include the module into the build and the attempt to uglify it ends up with a RangeError.
One could argue that since the uglify step fails it will not be included and I can go about my bussiness, but if the uglify step should happen to start working at a new update of pdfjs - what then?
Can anyone help me figure out why the requirejs config won't just exclude it in the build step and how to make it do so.

I found out what the core of my problem was and now I have a way to solve the problem and make my build process to work. My build step in grunt is using grunt-contrib-requirejs and I needed to override some options in the config for this job.
I didn't want the pdf.worker module to be included in my concatenated and minified production code.
I didn't want r.js to minify it only to later exclude it from the concatenated file.
I tried to solve the first problem thinking that it would mean that the second problem also should be solved. When I figured out the two were separate I finally found a solution.
In the r.js example on github there is a property named fileExclusionRegExp. This is what I now use to tell r.js not to copy the file over to the build folder.
fileExclusionRegExp: /pdf.worker.js/
Second, I need to tell the optimizer to not include this module in the concatenated file. This is done by overriding the paths property for this module to the value of "empty:".
paths: {
"pdfjs-dist/build/pdf.worker": "empty:"
}
Now my grunt build step will work without errors and all is well.
Thanks to async5 for informing me about the bug with uglify and the pdf.worker. The workaround is applied in another grunt task that uglify the worker and copies it into the build-folder separately. The options object for the grunt-contrib-uglify task will need this property in order to not break the pdf.worker file:
compress: {
sequences: false
}
Now my project works great when built for production.

Loading specific module from concatenated file using RequireJS

Trying to use the URI.js library in a project, but having trouble with RequireJS. URI's readme indicates that it works with requirejs - which is true when you're using the source - but not when using the minified/concatenated distribution file on its own - as you would in production.
Their build process scoops several libraries into a single .min file, and they all define themselves as modules.
No matter how I require that script, the only argument I receive is the first module in their distribution file (IPv6) which is not what I need.
Is there something trivial I'm missing?
<script>
require.config({
paths: {
urijs: 'dist/URI'
}
});
require(['urijs'], function(URI) {
console.log(URI);
});
</script>

Indeed the minified file cannot be used because it is not correctly built. All the define calls in it are anonymous whereas they should include the module name. If they had, you'd be able to use the minified file.
To get it to work, in the paths configuration, I've put urijs to point to the directory that contains all the individual .js files of the modules, and then I require URI.js as 'urijs/URI'. I let r.js minify it for distribution of my code.
I've installed it with npm but I've just checked with bower and the process should be exactly the same.

Assemble every module into a single .js file

I want to minimize the number of HTTP requests from the client to load scripts in the browser. This is going to be a pretty general question but I still hope I can get some answers because module management in javascript has been a pain so far.
Current situation
Right now, in development, each module is requested individually from the main html template, like this:
<script src="/libraries/jquery.js"></script>
<script src="/controllers/controllername.js"></script>
...
The server runs on Node.js and sends the scripts as they are requested.
Obviously this is the least optimal way of doing so, since all the models, collections, etc. are also separated into their own files which translates into numerous different requests.
As far as research goes
The libraries I have come across (RequireJS using AMD and CommonJS) can request modules from within the main .js file sent to the client, but require a lot of additional work to make each module compliant with each library:
;(function(factory){
if (typeof define === 'function' && define.amd) define([], factory);
else factory();
}(function(){
// Module code
exports = moduleName;
}));
My goal
I'd like to create a single file on the server that 'concatenates' all the modules together. If I can do so without having to add more code to the already existing modules that would be perfect. Then I can simply serve that single file to the client when it is requested.
Is this possible?
Additionally, if I do manage to build a single file, should I include the open source libraries in it (jQuery, Angular.js, etc.) or request them from an external cdn on the client side?

What you are asking to do, from what I can tell, is concat your js files into one file and then in your main.html you would have this
<script src="/pathLocation/allMyJSFiles.js"></script>
If my assumption is correct, then the answer would be to use one of the two following items
GULP link or GRUNT link
I use GULP.
You can either use gulp on a case by case basis, which means calling gulp from the command line to execute gulp code, or use a watch to do it automatically on save.
Besides getting gulp to work and including the gulp files you need to do what you need, I will only provide a little of what I use to get your answer.
In my gulp file I would have something like this
var gulp = require('gulp');
var concat = require('gulp-concat');
...maybe more.
Then I have the file paths I need to be reduced into one file.
var onlyProductionJS = [
'public/application.js',
'public/directives/**/*.js',
'public/controllers/**/*.js',
'public/factories/**/*.js',
'public/filters/**/*.js',
'public/services/**/*.js',
'public/routes.js'
];
and I use this info in a gulp task like the one below
gulp.task('makeOneFileToRuleThemAll', function(){
return gulp.src(onlyProductionJS)
.pipe(concat('weHaveTheRing.js'))
.pipe(gulp.dest('public/'));
});
I then run the task in my command line by calling
gulp makeOneFileToRuleThemAll
This call runs the associated gulp task which uses 'gulp-concat' to get all the files together into one new file called 'weHaveTheRing.js' and creates that file in the destination 'public/'
Then just include that new file into your main.html
<script src="/pathLocation/weHaveTheRing.js"></script>
As for including all your files into one file, including your vendor files, just make sure that your vendor code runs first. It's probably best to keep those separate unless you have a sure fire way of getting your vendor code to load first without any issues.
UPDATE
Here is my gulp watch task.
gulp.task('startTheWatchingEye', function () {
gulp.watch(productionScripts, ['makeOneFileToRuleThemAll']);
});
Then I start up my server like this (yours may differ)
npm start
// in a different terminal window I then type
gulp startTheWatchfuleye
NOTE: you can use ANY movie or show reference you wish! :)
Now just code it up, every time you make a change in the specified files GULP will run your task(s).
If you want to say run Karma for your test runner...
add the following to your gulp file
var karma = require('karma').server;
gulp.task('karma', function(done){
karma.start({
configFile: __dirname + '/karma.conf.js'
}, done);
});
Then add this task karma to your watch I stated above like this...
gulp.task('startTheWatchingEye', function(){
gulp.watch(productionScripts, ['makeOneFileToRuleThemAll', 'karma']);
});
ALSO
Your specific settings may require a few more gulp modules. Usually, you install Gulp globally, as well as each module. Then use them in your various projects. Just make sure that your project's package.json has the gulp modules you need in dev or whatever.
There are different articles on whether to use Gulp or Grunt. Gulp was made after Grunt with a few additions that Grunt was lacking. I don't know if Grunt lacks them anymore. I like Gulp a lot though and find it very useful with a lot of documentation.
Good luck!

I'd like to create a single file on the server that 'concatenates' all the modules together. If I can do so without having to add more code to the already existing modules that would be perfect.
Sure you can. You can use Grunt or Gulp to do that, more specifically grunt-contrib-concat or gulp-concat
Here's an example of a Gruntfile.js configuration to concat every file under a js directory:
grunt.initConfig({
concat: {
dist: {
files: {
'dist/built.js': ['js/**/**.js'],
},
},
},
});
Also, you can minify everything after concatenating, using grunt-contrib-minify.
Both libraries support source maps so, in the case a bug gets to production, you can easily debug.
You can also minify your HTML files using grunt-contrib-htmlmin.
There's also an extremely useful library called grunt-usemin. Usemin let's you use HTML comments to "control" which files get minified (so you don't have to manually add them).
The drawback is that you have to explicitely include them in your HTML via script tags, so no async loading via javascript (with RequireJS for instance).
Additionally, if I do manage to build a single file, should I include the open source libraries in it (jQuery, Angular.js, etc.) or request them from an external cdn on the client side?
That's debatable. Both have pros and cons. Concatenating vendors assures that, if for some reason, the CDN isn't available, your page works as intended. However the file served is bigger so you consume more bandwidth.
In my personal experience, I tend to include vendor libraries that are absolutely essential for the page to run such as AngularJS for instance.

If I understand you correctly, you could use a task runner such as Grunt to concatenate the files for you.
Have a look at the Grunt Concat plugin.
Example configuration from the docs:
// Project configuration.
grunt.initConfig({
concat: {
dist: {
src: ['src/intro.js', 'src/project.js', 'src/outro.js'],
dest: 'dist/built.js',
}
}
});
Otherwise, as you have stated, a 'module loader' system such as Require JS or Browserify may be the way to go.

Concatenate modules in RequireJS

I am using RequireJS to modularize my code. The website I am using will have several distinct page categories. For each one of them I want to load general JS file with all the dependencies that exist across all page categories, jQuery being most obvious one. I have managed to do that already.
For the rest of the pages, I want to have separate JS files. Each page has its own module but I am thinking that it would make more sense if I download several pages modules all at once and this way when the user comes to other pages, he will have the JS file already cached and won't have to download.
For now I tried to concatenate these modules which did work rather well. However, I am not sure how to load the specific module from a file. So far I am doing this:
require(['./js/common'], function (common) {
require(['public']);
});
common is the dependencies file and public is my concatenated file with all the dependencies. Inside it has modules for each page but I don't know how to call a specific one. Any ideas?

Take a look at the bundles option for RequireJS' runtime configuration. In your case it would be something like:
bundles: {
public: ['mod1', 'mod2', ...]
}
I've used mod1, mod2 because I don't see the name of the actual modules in your question but what you'd want there are the names of the modules inside the public bundle and that you want to load individually. With this, RequireJS will know that when you want to load such module, it has to get them from public instead of searching for them indivdually.
Then you should be able to change your loading code to:
require(['./js/common'], function (common) {
require(['mod1']);
});
Again, mod1 is for illustration.

Take a look at require-lazy.
It allows you to bundle independent parts of the application into separate bundles. From the developer's point of view, instead of:
define(["module1", "module2"], function(module1, module2) {...});
you write:
define(["lazy!module1", "lazy!module2"], function(module1, module2) {...});
Modules 1 & 2 will not be loaded upfront; they and their dependencies will be loaded lazilly when you call:
module1.get().then(function(realModule1) {
// here you have access to the real module1
});
Check out the examples for a few use cases.