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Hide or Collapse a single specific row in ag-grid using Javascript

After a lot of search in SO without any particular solution, I am compelled to ask this question.
In Simple words - I want to collapse or hide a specific row using Javascript in ag-grid. I have tried several methods explained in ag-grid documentation and also in SO, but none has worked till now.
All the following methods have been tried and none of the codes worked.
Let rowNode = gridOptions.api.getRowNode(params.value);
Method #1. params.api.getDisplayedRowAtIndex(2).setExpanded(false);
Method #2. params.api.getRowNode(params.value).setExpanded(false);
Method #3. gridOptions.api.setRowNodeExpanded(rowNode,false);
Method #4. gridOptions.api.getRowNode(rowId).style.visibility = "collapse";
I have also tried using plain CSS, like this - Data has disappeared but the white blank row is visible
rowNode.setDataValue('class', 'hidden'); //Where “class” is a field
const gridOptions = {
//Other grid options...
getRowClass: params => {
if (params.data.class === "hidden") {
return 'hidden';
}
},
https://stackblitz.com/edit/js-nvtqhz?file=infoCellRenderer.js

setExpand / setRowNode Expanded only works on collapsible rows, i.e it will collapse an expanded row. it will not hide it.
I edited your stackblitz,
I made a couple of changes to make it work.
Selectable Rows
So, when you click a row, I'm marking it as selected. There is a property on ag-grid rowSelection: 'single' | 'multiple. If you want to hide only one row at a time, use 'single' if you can hide multiple rows use 'multiple'
External filtering
So, ag grid can filters rows if we provide a criteria.It can be a check on any of data property as well. For your problem, I have added a filter that says if any row is selected, remove it from the grid.
Following are the changes
/// method called on clicking the button
function hideRow(params) {
let rowNode = gridOptions.api.getRowNode(params.value); // get the clicked row
rowNode.setSelected(true); //mark as selected
gridOptions.api.onFilterChanged(); // trigger filter change
}
Triggering the filter change will call this method for each row
function doesExternalFilterPass(node) {
return !node.selected; // if row node is selected dont show it on grid.
}
You can access the rows hidden any time using
gridOptions.api.getSelectedRows() //Returns an array of data from the selected rows. OR
gridOptions.api.getSelectedNodes() //Returns an array of the selected nodes.
And, if you want to show a row again, just filter from this above mentioned method and do these steps
rowNode.setSelected(false); //mark as unselected
gridOptions.api.onFilterChanged(); // trigger filter change
This will automatically show the row on grid.
Hope this helps! :)

How to add checkboxes with possibility to choose all in datatable jQuery

I work wit library datatables, and i want to add in table row check box for some actions, i add checkboxes to the table,and one check box in table header for choose all boxes.
Script:
$('#checkAll').click(function () {
$(':checkbox.checkbox-mark').prop('checked', this.checked);
});
In jsfiddle you can see more.
But problem is, i have pages, and in case if i tap on header checkbox, it's choose only all boxes in curent page, but i want in the all pages, how i can solve this?

like you discussed already you can use service/api to set selectAll values but if you want to it using front end then you can use DataTable().cells().nodes(); to get all the nodes and iterate through them and set the checkbox value to each node.
// update your checkAll logic like this
$('#checkAll').click(function() {
var allPagesData = $("#test1").DataTable().cells().nodes(); // this will give you all data in datatable.
$(allPagesData).find('input[type="checkbox"]').prop('checked', this.checked);
});
check out this fiddle

jQuery DataTables check Checkboxes on header click

I'm having a table in my current project and using DataTables to provide search and sort function on this table.
Now, I am adding checkboxes in front of every row, so one can check a row, to later only process checked rows.
What I would love is to be able to click the header (which is a checkbox as well) and then 1. not having a sort function for that column, as well as checking all checkbox when clicking, and unchecking all, if all are ticked already.
So I could do something like use the jQuery selector :checkbox to find the checkboxes and set the property checked to true, then if clicking again, check every if its checked and if yes uncheck them, if not check all, and so on.
But is there a more elegant, respectively a better way to do this? Also, how can I disable the sort, so its not a asc/desc sort icon showing in that column?

See jQuery DataTables Checkboxes plug-in that adds support for checkboxes and "select all" control in the header.
var table = $('#example').DataTable({
'columnDefs': [
{
'targets': 0,
'checkboxes': {
'selectRow': true
}
}
],
'select': {
'style': 'multi'
},
'order': [[1, 'asc']]
});
See this example for code and demonstration.

Getting length of toggle classes

This might be similar to getting length of a class. But I am not getting the actual output for toggle class.
So here is the scenario: I have a table in which there is a checkbox in every row. If check all option is selected, all checkbox is marked. Now the problem is that I want to pass flag as true when all checkbox are checked and false when only some checkboxes are checked. Now I use toggling functionality. So I don't know how I get length of 'unchecked' checkboxes rather than 'unchecked checked' checkboxes.(I am using Div's for styling instead of checkboxes. )
Here is the jsfiddle
Script for counting length:
$("#cntCheck").click(function(){
alert($('.isChecked').length); //Counting Checked CheckBox(Working right).
});
$("#cntUncheck").click(function(){
alert($('.checkBox isChecked').length); //Counting Unchecked CheckBox Except CheckAll checkbox(This is not working)
});

If I understand your (very confusing) question correctly, you're asking how to count the elements that do have the checkBox class but don't have the isChecked class. If so, you can use the .not() method:
$(".checkBox").not(".isChecked").length
Or, the :not() selector:
$(".checkBox:not(.isChecked)").length
Regarding your styling:
"I am using Div's for styling instead of checkboxes."
I would strongly recommend against doing this, because users who don't like to (or are physically unable to) use a mouse or other pointing device can't click your pseudo-checkboxes.

See this fiddle - http://jsfiddle.net/Yp56c/3/
$("#cntUncheck").click(function(){
var notChecked = $('.checkBox').not('.isChecked').length;
alert(notChecked); //This is working
});

jqGrid - How to remove the page selection on the pager but keep the buttons?

I want to remove the paging buttons on the grid, but I want to keep the add, edit, refresh, etc buttons on the bottom left. I don't want the pager there because I will be displaying all records in this particular grid implementation.
I want to keep what is in GREEN but remove what is in RED:
Currently, my solution is to empty out the center of the grid's navigation
$('#pager_center').empty();
But this means that the pager renders to the page, and then gets emptied, I'm wondering if I can just prevent it from even being rendered in the first place.

You can use my following JqGrid option to disable RED zone from JqGrid. It should be the best way to solve this question because you don't need to hack JqGrid rendering via CSS style sheet that be caused of problem if JqGrid change pattern for generating pager or you change pager id.
$('#grid').jqGrid
({
rowList: [], // disable page size dropdown
pgbuttons: false, // disable page control like next, back button
pgtext: null, // disable pager text like 'Page 0 of 10'
viewrecords: false // disable current view record text like 'View 1-10 of 100'
});

You could apply a CSS style to hide it...?
#pager1_center {
visibility: hidden;
}
There are also options like pgbuttons and recordtext that settings in the init might cause that part not to render any HTML.
jQuery("#grid_id").jqGrid({pgbuttons:false, recordtext: ''});

Using this will remove the paging/view records area with buttons and everything.
jQuery("#WebsitesGrid").jqGrid({
...
pginput: false,
pgbuttons: false,
viewrecords: false,
....

Or if you would like to have more space in the footer of your jqGrid, you can simply hide desired part of
navigation.
gridComplete: function()
{
$( '#' + gridId + 'Pager_center' ).hide();
$( '#' + gridId + 'Pager_left' ).hide();
},
where gridId is id of your jqGrid.

$('#grid').jqGrid({pgbuttons:false, recordtext:'', pgtext:'')}

If you're looking for a solution to avoid Pager in jqGrid then just add following code in loadcomplete callback or as a statement after your jqgrid call, with or without #Soul_Master's solution,
$("#divPager").css({ "height": "0px", "border": "0px" });
It worked for me.

even you can set align property of pager details like no of records dropdown, pager text, record text. to acheive this need to change pagerpos and recordpos to right or left or center as we required. Details has to be updated in jquery.jqGrid.min.js or just do search for these keywords in your js files and do the update.