I was looking for a way to change image A to B and B to A by just
clicking them.
So far, this is what I'm using.
<img id="pixelbutton" src="images/pixelbutton.png" />
<img id="pixelbutton2" src="images/pixelbutton_press.png" style="display: none;" />
<script type="text/javascript">
$(document).ready(function(){
$("#pixelbutton").click(function(){
$("#pixelbutton").css({'display':'none'})
$("#pixelbutton2").css({'display':'block'});
})
$("#pixelbutton2").click(function(){
$("#pixelbutton2").css({'display':'none'})
$("#pixelbutton").css({'display':'block'});
})
})
</script>
The script works well for a pair of image.
Now if I have 100 pair of image.
"A <--> B"
"C <--> D"
"E <--> F"
and so on...
Do I have to copy the body HTML and script 100 times and change their ID+URL or there is another more efficient way?
To create hundreds of them... First, use a class.
Then, use a data attribute to store the "alternate" URL.
<img class="pixelbutton" src="images/pixelbutton.png" data-altsrc="images/pixelbutton_press.png"/>
<script type="text/javascript">
$(document).ready(function(){
$(".pixelbutton").click(function(){
// Get the two values
var src = $(this).attr("src");
var altSrc = $(this).data("altsrc");
// Switch them
$(this).attr("src",altSrc).data("altsrc",src);
});
})
</script>
This will work for thousands of .pixelbutton...
;)
EDIT
As per this other .data() documentation, (I wonder why there's two different documentation pages...) the data-* have to be lowercase... Because when trying to get altSrc, it is interpreted as alt-src.
I just learned that... That is quite a strange new standard, from jQuery 3.
So here is your CodePen updated.
You could probably set a naming pattern and use delegation to make an event handler on the images' container.
You could check if the event's target is an image and retrieve its id. Using that id, you could use the pattern you've set to change the images interchangeably.
There are multiple solutions to this, but this is by far the simplest approach:
Wrap your image pairs in a parent <div>
Use .toggleClass() to toggle a class, say .hide, in the images in the element
This solution assumes that you have images in pairs :) see proof-of-concept example:
$(document).ready(function() {
$('img').click(function() {
console.log($(this).siblings());
$(this).add($(this).siblings()).toggleClass('hide');
});
});
/* For layout only */
div {
display: inline-block;
}
/* Used to hide image */
.hide {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<img src="http://via.placeholder.com/100x100/999999/ffffff" />
<img src="http://via.placeholder.com/100x100/b13131/ffffff" class="hide" />
</div>
<div>
<img src="http://via.placeholder.com/100x100/999999/ffffff" />
<img src="http://via.placeholder.com/100x100/b13131/ffffff" class="hide" />
</div>
<div>
<img src="http://via.placeholder.com/100x100/999999/ffffff" />
<img src="http://via.placeholder.com/100x100/b13131/ffffff" class="hide" />
</div>
<div>
<img src="http://via.placeholder.com/100x100/999999/ffffff" />
<img src="http://via.placeholder.com/100x100/b13131/ffffff" class="hide" />
</div>
<div>
<img src="http://via.placeholder.com/100x100/999999/ffffff" />
<img src="http://via.placeholder.com/100x100/b13131/ffffff" class="hide" />
</div>
<div>
<img src="http://via.placeholder.com/100x100/999999/ffffff" />
<img src="http://via.placeholder.com/100x100/b13131/ffffff" class="hide" />
</div>
Try this one:
jQuery(document).ready(function($) {
var $imgBlock = $('#images');
var html = '';
var imgArr = [
'http://i0.wallpaperscraft.com/image/surface_shape_metal_116716_200x300.jpg',
'http://i0.wallpaperscraft.com/image/universe_space_face_rocket_116714_200x300.jpg',
'http://i0.wallpaperscraft.com/image/letter_surface_wooden_116674_200x300.jpg',
'http://i0.wallpaperscraft.com/image/mountains_lake_reflection_116663_200x300.jpg',
'http://i1.wallpaperscraft.com/image/leaf_drops_surface_116678_200x300.jpg',
'http://i1.wallpaperscraft.com/image/candle_spruce_christmas_decoration_116684_200x300.jpg'
];
$.each(imgArr, function(index, url) {
html += (index % 2 === 0) ? '<div>' : '';
html += '<img src="' + url + '"/>';
html += (index % 2 === 1 || index === imgArr.length - 1) ? '</div>' : '';
});
$imgBlock.append(html);
$imgBlock.on('click', 'img', function(e) {
$(this).parent('div').find('img').removeClass('red');
$(this).addClass('red');
});
});
img {
border: 2px solid #ccc;
}
.red {
border: 2px solid red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="images"></div>
Related
I'm trying to delete all images from page. The page is in HTML. This is my HTML button:
<input id="clickMe" type="button" value="Delete Images" onclick="click();" />
And the function is:
<script type="text/javascript">
function click(){
var images = document.getElementsByTagName('img');
for (var i = 0; i < images.length; i++) {
images[i].Node.removeChild(images[0]);
}
}
</script>
All elements are tagged "img"
Removing a child can only be done from the parent:
function removeImages() {
var images = [].slice.call(document.getElementsByTagName('img'), 0); // get the images as array like object, and turn it into an array using slice
images.forEach(function(img) { // iterate the images array
img.parentNode.removeChild(img); // remove the child node via the parent node
});
}
<button type="button" onclick="removeImages()">Remove Images</button>
<div>
<img src="http://static.wixstatic.com/media/60d837_94f714500a3145a1b98efd7a6fe78ce7~mv2_d_3456_3456_s_4_2.jpg_256" />
<img src="https://static-s.aa-cdn.net/img/ios/442131982/82d94c67fc3d8eb87e07d9bb568c5d4d?v=1" />
<img src="https://pbs.twimg.com/profile_images/625769159339737088/2dwpQAXA.jpg" />
</div>
You can also use img.remove() instead of the cumbersome img.parentNode.removeChild(img), but it won't work in IE - see ChildNode.remove() on MDN.
You cannot have click as the function name because click is a reserved js method.
For deleting you just need to use delete() on that node.
<script type="text/javascript">
function c(){
var images = document.getElementsByTagName('img');
for (var i = images.length - 1; i >= 0; i--) {
images[0].parentNode.removeChild(images[0]);
}
}
</script>
<img src="http://unsplash.it/200/300/"/>
<img src="http://unsplash.it/200/300/"/>
<img src="http://unsplash.it/200/300/"/>
<img src="http://unsplash.it/200/300/"/>
<img src="http://unsplash.it/200/300/"/>
<input id="clickMe" type="button" value="Delete Images" onclick="c()"/>
Few inputs:
click function will never get fired as it is reserved and take precedence over the click() handler attached to onclick event. Change the handler name to something meaningful.
Use querySelectorAll to find the img elements. It returns a non-live NodeList of all elements descended from the element on which it is invoked that match the specified group of CSS selectors.
the code images[i].Node.removeChild(images[0]); is not correct as we should remove the element from the parentNode; Indexing was not correct (images[0])
function deleteImages() {
// query non-live NodeList of all `img` elements
var images = document.querySelectorAll('img');
// Loop through each `image` object.
Object.values(images).forEach(function(element, index, array) {
element.parentNode.removeChild(element);
});
}
img {
width: 200px;
height: 200px;
margin: 5px;
}
<div>
<div>My List of ducks</div>
<img src="https://upload.wikimedia.org/wikipedia/commons/thumb/d/dd/Tufted_duck_%28aythya_fuligula%29.JPG/120px-Tufted_duck_%28aythya_fuligula%29.JPG" />
<img src="https://upload.wikimedia.org/wikipedia/commons/thumb/d/d6/Tufted_Duck_pangolakha_Wildlife_Sanctuary_East_Sikkim_India_27.03.2016.jpg/120px-Tufted_Duck_pangolakha_Wildlife_Sanctuary_East_Sikkim_India_27.03.2016.jpg" />
</div>
<div>
<div>My List of Flowers</div>
<img src="https://upload.wikimedia.org/wikipedia/commons/thumb/a/a4/Lillium_Stamens.jpg/300px-Lillium_Stamens.jpg" />
<img src="https://upload.wikimedia.org/wikipedia/commons/thumb/5/5d/Crateva_religiosa.jpg/220px-Crateva_religiosa.jpg" />
</div>
<input id="clickMe" type="button" value="Delete Images" onclick="deleteImages();" />
I have a div act like button that contain an image. I want when I click the div the image inside it will change I put a jquery but my jquery only work in 1 way it can switch to second image but cant switch back to first image.
HTML :
<div class="post-like m-30">
<img class="img-responsive" src="img/like.png" alt="">
<h4 class="bold text-center capital">appreciate this!</h4>
</div>
CSS :
.post-like{
cursor: pointer;
}
.post-like img{
margin: auto;
}
JS :
$(document).ready(function() {
$('.post-like').click(function(){
$(".post-like img").attr('src',"img/like.jpg");
return false;
});
});
Can you teach me why my jquery didnt work?
To toggle between the both src attributes, you could add condition in your click event :
$(document).ready(function() {
$('.post-like').click(function(){
var src = $(".post-like img").attr('src');
if(src=="https://upload.wikimedia.org/wikipedia/commons/2/2f/MRT_Singapore_Destination_1.png")
$(".post-like img").attr('src',"https://upload.wikimedia.org/wikipedia/commons/1/10/MRT_Singapore_Destination_2.png");
else
$(".post-like img").attr('src',"https://upload.wikimedia.org/wikipedia/commons/2/2f/MRT_Singapore_Destination_1.png");
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="post-like m-30">
<img class="img-responsive" src="https://upload.wikimedia.org/wikipedia/commons/2/2f/MRT_Singapore_Destination_1.png" alt="">
<h4 class="bold text-center capital">appreciate this!</h4>
</div><!-- post-like -->
Grab the value of the src attribute and store it in a variable. Use this variable as your reference in an if statement to determine which image to switch to:
$(document).ready(function() {
$('.post-like').click(function(){
var img=$(this).attr('src');
if(img=="img/like.jpg"){
$(".post-like img").attr('src',"img/like.jpg");
return false;
}else{
$(".post-like img").attr('src',"img/otherimage.jpg");
return false;
}
});
});
There was nothing wrong with your code, it changed the source just fine.
In order to create a 'click to toggle'-flow, you need to know both sources, I tend to do this by having two variables (one with the 'special' source and one empty, which is set on first use).
$(function() {
var specialSrc = 'http://lorempixel.com/image_output/nightlife-q-g-160-100-10.jpg',
img = $('.post-like img'),
normalSrc;
$('.post-like').click(function(){
var src = img.attr('src');
if (!normalSrc) {
normalSrc = src;
}
img.attr('src', src === normalSrc ? specialSrc : normalSrc);
return false;
});
});
.post-like{
cursor: pointer;
}
.post-like img{
margin: auto;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="post-like m-30">
<img class="img-responsive" src="http://lorempixel.com/image_output/nightlife-q-c-160-100-4.jpg" alt="">
<h4 class="bold text-center capital">appreciate this!</h4>
</div><!-- post-like -->
I've also stored the image in the img variable, so you don't need to look for it every click, and I've replace $(document).ready(function() {..}) with the shorter syntax $(function() {..}) which does the same thing)
make it simpler and do toggle
$(".post-like").click(function() {
$(this).find('img').toggle();
});
TOGGLE
I have a long list (dynamically created) that can contain only one of two images; red.png or green.png and look like this:
<img src="red.img" id="choice1" onclick=" changeIcon('1')">
<img src="red.img" id="choice2" onclick=" changeIcon('2')">
...
<img src="red.img" id="choiceN" onclick=" changeIcon('N')">
I manage to toggle between red and green by using the following java script:
function changeIcon(line){
var l = "choice".concat(line);
if (document.getElementById(l).src == "red.png")
{document.getElementById(l).src = "green.png";
}else {
document.getElementById(l).src = "red.png";
}
}
What I am trying to do is that when I click on the red image only this (id?) become green and the rest of the list become red and if I click on a green then this become back to red so the entire list is red again.
The concept is similar to the radio buttons but without using form
Well, try using:
var l = "choice" + line;
Or, even better, I would suggest you to change your code this way, using jQuery:
$(function () {
// Replace "body" with some static parent of "img.toggle".
$("body").on("click", ".toggle", function () {
if ($(this).attr("src") == "red.img")
this.src = "green.img";
else
this.src = "red.img";
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<img src="red.img" class="toggle" />
<img src="red.img" class="toggle" />
<img src="red.img" class="toggle" />
As mentioned in the comments, if you want it to act like a radio button, you can use this:
$(function () {
// Replace "body" with some static parent of "img.toggle".
$("body").on("click", ".toggle", function () {
// Reset everything.
$(".toggle").attr("src", "red.img");
this.src = "green.img";
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<img src="red.img" class="toggle" />
<img src="red.img" class="toggle" />
<img src="red.img" class="toggle" />
The same thing can be achieved without using images:
$(function () {
$(".radios").on("click", "span", function () {
$(".radios span").removeClass("active");
$(this).addClass("active");
});
});
.radios span {display: inline-block; width: 12px; height: 12px; border: 1px solid #999; cursor: pointer; border-radius: 100%;}
.radios span.active {border-color: #000; background-color: #666;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="radios">
<span></span>
<span></span>
<span></span>
<span></span>
<span></span>
</div>
To change all the items at once add a class to your images (I'll use a class named img as an example):
<img src="red.png" class="img" id="choice1" onclick=" changeIcon('1')">
<img src="red.png" class="img" id="choice2" onclick=" changeIcon('2')">
...
<img src="red.png" class="img" id="choiceN" onclick=" changeIcon('N')">
Then when you trigger the event change them all to a certain color, and then this to the desired color. Below is an example of when clicking a "red" item, changing the item clicked to green and the rest to red:
$(".img").click(function(){
if( $(this).attr('src') == "red.png" ) {
$(".img").attr('src', "red.png"); // Make them all red
$(this).attr('src', "green.png"); // Change the clicked one to green
}
});
Example Fiddle (Note you will need to look at the src of the images directly to see the changes)
just use class attribute to change whole list to red then this to toggle clicked item
//the jQuery function
function toggleSrc()
{
var nextSrc = "red.png";
if( $(this).attr("src") == "red.png" )
nextSrc = "green.png";
$(".image").attr("src","red.jpg");
$(this).attr("src",nextSrc);
}
//binding function to .image
$( document ).ready(function() {
$(".image").click( toggleSrc );
});
//and the HTML:
<img src="red.png" class="image" id="choice1">
<img src="red.png" class="image" id="choice2">
Essentially I have an interactive map which contains 4 div statements each of which contains an image of an island. I would like to create an on hover event which will display a corresponding sailing timetable depending on which image the user hovers. e.g. island 1 should display timetable 1.
I have the following code so far and ideally I am looking for a javascript or css solution:
<div class="Map">
<div id="Island_Morar">
<img src="images/IsleOfMorar.jpg"/>
</div>
<div id="Island_Rum">
<img src="images/IsleOfRum.jpg"/>
</div>
<div id="Island_Eigg">
<img src="images/IsleOfEigg.jpg"/>
</div>
<div id="Island_Muck">
<img src="images/IsleOfMuck.jpg"/>
</div>
</div>
<img id="TimetableEigg" src="images/TimetableEigg.jpg">
any help is appreciated.
You need some different markup if you want a plain css solution. If you want to have different timetables for each hover you should go with something like this:
markup
<div class="tt-container" id="Island_Rum">
<img src="images/IsleOfRum.jpg"/>
<img class="timetable" src="images/TimetableRum.jpg">
</div>
<div class="tt-container" id="Island_Eigg">
<img src="images/IsleOfEigg.jpg"/>
<img class="timetable" src="images/TimetableEigg.jpg">
</div>
<div class="tt-container" id="Island_Muck">
<img src="images/IsleOfMuck.jpg"/>
<img class="timetable" src="images/TimetableMuck.jpg">
</div>
</div>
css
.timetable {
display : none;
}
.tt-container:hover .timetable {
display : block;
}
That should do the trick
If you want to keep your current HTML code, I'd make three image blocks for timetables, and initially set them all to display: none; and add onmouseover event handlers to island elements which would contain Javascript statement which will set disply: block; on appropriate timetable.
Something like this:
<div class="Map">
<div id="Island_Morar" onmouseover="document.getElementById('TimetableEigg1').style.display = 'block';">
<img src="images/IsleOfMorar.jpg"/>
</div>
<div id="Island_Rum" onmouseover="document.getElementById('TimetableEigg2').style.display = 'block';" >
<img src="images/IsleOfRum.jpg"/>
</div>
<div id="Island_Eigg" onmouseover="document.getElementById('TimetableEigg3').style.display = 'block';" >
<img src="images/IsleOfEigg.jpg"/>
</div>
<div id="Island_Muck" onmouseover="document.getElementById('TimetableEigg4').style.display = 'block';" >
<img src="images/IsleOfMuck.jpg"/>
</div>
</div>
<img id="TimetableEigg1" src="images/TimetableEigg1.jpg">
<img id="TimetableEigg2" src="images/TimetableEigg2.jpg">
<img id="TimetableEigg3" src="images/TimetableEigg3.jpg">
<img id="TimetableEigg4" src="images/TimetableEigg4.jpg">
Seems you barely know the basics of HTML and already trying to jump too deep. External libraries will help you and speed up your progress. I see people gave you CSS solutions so here is a JS solution.
First thing is download the well known JS library called jQuery.
then load this file to your page and add a script at the bottom of your body tag:
$("div.map").on("mouseover", "#Island_Morar", function(e) {
$(this).show(); // option one
//$(this).addClass("class-name"); // option two
}).on("mouseout", "#Island_Morar", function(e) {
$(this).hide(); // option one
//$(this).removeClass("class-name"); // option two
});
With this script you can do whatever you want, for example - use the second option of adding and removing classes in order to animate your Timetables (see Example).
Possible CSS / JQuery solution:
$(".Map a").hover(
function() {
$('#' + $(this).attr('class')).show();
}, function() {
$('#' + $(this).attr('class')).hide();
}
);
.timetables img { display:none; }
<div class="Map">
<a href="#" class="islandmorar">
<img src="images/IsleOfMorar.jpg"/>
</a>
<a class="islandrum">
<img src="images/IsleOfRum.jpg"/>
</a>
<a class="islandeigg">
<img src="images/IsleOfEigg.jpg"/>
</a>
<a class="islandmuck">
<img src="images/IsleOfMuck.jpg"/>
</a>
</div>
<div class="timetables">
<img id="islandmorar" src="images/TimetableEigg.jpg"/>
<img id="islandrum" src="images/TimetableEigg.jpg"/>
<img id="islandeigg" src="images/TimetableEigg.jpg"/>
<img id="islandmuck" src="images/TimetableEigg.jpg"/>
</div>
Pure CSS solution but you need to place the large image in .main div
the first image will be displayed first and will change on hover on other images and when you leave move out of the main div it will show the first image
Note: used random images
.Map > div {
display: inline-block;
}
img.two,
img.three,
img.four,
#Island_Rum:hover ~ img.one,
#Island_Muck:hover ~ img.one,
#Island_Eigg:hover ~ img.one {
display: none;
}
img.one {
display: block;
}
#Island_Morar:hover ~ img.one {
display: block;
}
#Island_Rum:hover ~ img.two {
display: block;
}
#Island_Eigg:hover ~ img.three {
display: block;
}
#Island_Muck:hover ~ img.four {
display: block;
}
<div class="Map">
<div id="Island_Morar">
<img src="http://placeimg.com/100/100/any/animals" />
</div>
<div id="Island_Rum">
<img src="http://placeimg.com/100/100/any/arch" />
</div>
<div id="Island_Eigg">
<img src="http://placeimg.com/100/100/any/nature" />
</div>
<div id="Island_Muck">
<img src="http://placeimg.com/100/100/any/tech" />
</div>
<img class="one" src="http://placeimg.com/400/400/any/animals" />
<img class="two" src="http://placeimg.com/400/400/any/arch" />
<img class="three" src="http://placeimg.com/400/400/any/nature" />
<img class="four" src="http://placeimg.com/400/400/any/tech" />
</div>
Don't put class="map" to the wrapper div, give it to every div with id beginning with "Island_...".
Do the same with your timeTable images, give them a class "timeTable".
Put this before your "head" end tag :
<script>
"use strict";
//wait for every element to be loaded
window.onload = function(){initialization();}
</script>
Then, put this before your "body" end tag :
<script>
"use strict";
//first create a function that hides elements with class 'timeTable'
function hide(elements){
var htmlClass = document.getElementsByClassName(elements);
//hide every element with class
for (var i = 0 ; i < htmlClass.length ; i++){
htmlClass[i].style.display = "none";
htmlClass[i].style.visibility = "hidden";
}
}
//create a function that show only the timeTable you want
function show(element){
document.getElementById(element).style.display = "block";
document.getElementById(element).style.visibility = "visible";
}
function initialization(){
//replace 'someMapId' with the id of the image you are hovering
//replace 'someTimeTableId' with the id of the image you want to show
//replace 'timeTable' with the name of a class you want to hide
document.getElementById("someMapId").onmouseover = function(){
hide("timeTable");
show("someTimeTableId");
}
//repeat these 3 lines for every image the user will hover
}
</script>
Don't forget the quotes when using the functions.
You should use css for styling and javascript for interactions.
You don't need jQuery for basic scripts like that, it only slows page loading and keeps you away from learning basic javascript.
(Ok, I edited mistakes, now it works ;)
jsFiddle
I printed to the screen 16 icons (little pictures).
Now I want to be able to select icons,
and when I press a button the selected icons ids will be sent in a form.
I saw in the net only checkboxes and lists multiselect,
what's the best way to do this?
(I'm pretty new to web design)
thanks ahead!
Although jQuery isn't in your tags, you should introduce yourself to jQuery. It'll make your life easier, for what you're trying to do. Here is the basic steps both if you use jQuery and if use just Javascript:
With jQuery
Give all your icons a class and each one a unique id:
<img src='icon1.png' data-iconID=2233 class='myIcons' />).
Then bind that class to a click event
$('.myIcons').bind('click', function() {
$(this).toggleClass('selectIcon');
});
Attach form submit function to onsubmit:
<form ... onsubmit="submitForm();">
Build submitForm function:
function submitForm() {
var csvIconIds = '';
$.each($('.myIcons.selectIcon'), function (index, value) {
csvIconIds += $(value).attr('data-iconID');
});
//submit scvIconIds here along with other form data (ajax?)
}
With Javascript
Similar as above but way more complicated...
To toggle classes see this thread: How to add/remove a class in JavaScript?
To getting attributes by class see this site: http://www.actiononline.biz/web/code/how-to-getelementsbyclass-in-javascript-the-code/
This could be a way using just plain Javascript or jQuery. I prefer the jQuery version, since it separates the click handler from the markup, instead of using inline onclick handlers, which are in general discouraged.
What this does is use an input element array, which you can create by adding [] to the element name. This same technique can be used on SELECTs and other elements, since it signals to the server that an array has been submitted, as opposed to value known by a single key.
<html>
<head>
<style type="text/css">
div img {
cursor: pointer;
border: 1px solid #f00;
}
</style>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.js"></script>
<script>
function setFormImage(id) {
if (id != '' && !document.getElementById('input_'+id)) {
var img = document.createElement('input');
img.type = 'text';
img.id = 'input_'+id;
img.name = 'images[]';
img.value = id;
document.imageSubmit.appendChild(img);
}
}
$(document).ready(function(){
$('#jqueryimages img').click(function(){
setFormImage(this.id);
});
});
</script>
</head>
<body>
<pre><?php
if (count($_GET['images'])) {
print_r($_GET['images']);
}
?></pre>
<div style="float: left; width: 49%;">
<h1>Plain ol' HTML</h1>
1. <img src="http://www.gravatar.com/avatar/e1122386990776c6c39a08e9f5fe5648?s=128&d=identicon&r=PG" id="img-1" onclick="setFormImage(this.id)"/>
<br/>
2. <img src="http://www.gravatar.com/avatar/e1122386990776c6c39a08e9f5fe5648?s=128&d=identicon&r=PG" id="img-2" onclick="setFormImage(this.id)"/>
<br/>
3. <img src="http://www.gravatar.com/avatar/e1122386990776c6c39a08e9f5fe5648?s=128&d=identicon&r=PG" id="img-3" onclick="setFormImage(this.id)"/>
<br/>
4. <img src="http://www.gravatar.com/avatar/e1122386990776c6c39a08e9f5fe5648?s=128&d=identicon&r=PG" id="img-4" onclick="setFormImage(this.id)"/>
</div>
<div id="jqueryimages" style="float: left; width: 49%;">
<h1>jQuery</h1>
5. <img src="http://www.gravatar.com/avatar/e1122386990776c6c39a08e9f5fe5648?s=128&d=identicon&r=PG" id="img-5"/>
<br/>
6. <img src="http://www.gravatar.com/avatar/e1122386990776c6c39a08e9f5fe5648?s=128&d=identicon&r=PG" id="img-6"/>
<br/>
7. <img src="http://www.gravatar.com/avatar/e1122386990776c6c39a08e9f5fe5648?s=128&d=identicon&r=PG" id="img-7"/>
<br/>
8. <img src="http://www.gravatar.com/avatar/e1122386990776c6c39a08e9f5fe5648?s=128&d=identicon&r=PG" id="img-8"/>
</div>
<h1>Form Submit</h1>
<form name="imageSubmit" method="get">
<input type="submit" value="View Selected"/>
</form>
</body>
</html>
try this
var idArray = [];
$("#container-id img").each(function(index,value){
idArray.push($(value).attr("id"));
});
//do anything with the array