How to get JSON data into option list - javascript
I am getting JSON in the following format (as array of objects)
[{"0":"Ahmednagar","city_name":"Ahmednagar","1":"1","city_id":"1"},{"0":"Akola","city_name":"Akola","1":"2","city_id":"2"},{"0":"Amravati","city_name":"Amravati","1":"3","city_id":"3"},{"0":"Aurangabad","city_name":"Aurangabad","1":"4","city_id":"4"},{"0":"Beed","city_name":"Beed","1":"5","city_id":"5"},{"0":"Bhandara","city_name":"Bhandara","1":"6","city_id":"6"},{"0":"Buldhana","city_name":"Buldhana","1":"7","city_id":"7"},{"0":"Chandrapur","city_name":"Chandrapur","1":"8","city_id":"8"},{"0":"Dhule","city_name":"Dhule","1":"9","city_id":"9"},{"0":"Gadchiroli","city_name":"Gadchiroli","1":"10","city_id":"10"},{"0":"Gondia","city_name":"Gondia","1":"11","city_id":"11"},{"0":"Hingoli","city_name":"Hingoli","1":"12","city_id":"12"},{"0":"Jalgaon","city_name":"Jalgaon","1":"13","city_id":"13"},{"0":"Jalna","city_name":"Jalna","1":"14","city_id":"14"},{"0":"Kolhapur","city_name":"Kolhapur","1":"15","city_id":"15"},{"0":"Latur","city_name":"Latur","1":"16","city_id":"16"},{"0":"Mumbai City","city_name":"Mumbai City","1":"17","city_id":"17"},{"0":"Mumbai Suburban","city_name":"Mumbai Suburban","1":"18","city_id":"18"},{"0":"Nagpur","city_name":"Nagpur","1":"19","city_id":"19"},{"0":"Nanded","city_name":"Nanded","1":"20","city_id":"20"},{"0":"Nandurbar","city_name":"Nandurbar","1":"21","city_id":"21"},{"0":"Nashik","city_name":"Nashik","1":"22","city_id":"22"},{"0":"Osmanabad","city_name":"Osmanabad","1":"23","city_id":"23"},{"0":"Palghar","city_name":"Palghar","1":"36","city_id":"36"},{"0":"Parbhani","city_name":"Parbhani","1":"24","city_id":"24"},{"0":"Pune & Pimpri-Chinchwad ","city_name":"Pune & Pimpri-Chinchwad ","1":"25","city_id":"25"},{"0":"Raigad","city_name":"Raigad","1":"26","city_id":"26"},{"0":"Ratnagiri","city_name":"Ratnagiri","1":"27","city_id":"27"},{"0":"Sangli","city_name":"Sangli","1":"28","city_id":"28"},{"0":"Satara","city_name":"Satara","1":"29","city_id":"29"},{"0":"Sindhudurg","city_name":"Sindhudurg","1":"30","city_id":"30"},{"0":"Solapur","city_name":"Solapur","1":"31","city_id":"31"},{"0":"Thane","city_name":"Thane","1":"32","city_id":"32"},{"0":"Wardha","city_name":"Wardha","1":"33","city_id":"33"},{"0":"Washim","city_name":"Washim","1":"34","city_id":"34"},{"0":"Yavatmal\t","city_name":"Yavatmal\t","1":"35","city_id":"35"}]
ajax call to get json
$(document).ready(function(){
$("#select_state").change(function() {
var $state_var=$('#select_state').val();
alert("Selected State Value "+$state_var);
//make the ajax call
$.ajax({
url: 'ajax/location.php',
type:'GET',
data: {
state_name : $state_var
},
success: function(city_list) {
console.log(city_list);
var options = '';
for (var i = 0; i < city_list.length; i++) {
var city = city_list[i];
options += '<option value="' + city.city_id + '">' + city.city_name + '</option>';
}
$('#select_city').html(options);
$('#select_city').show();
}
});
});
});
Now it gives me only undefined is option list
You need to add:-
dataType;'json',
In your $.ajax code so that your response is automatically parsed and success function will execute properly.
Like below:-
$.ajax({
url: 'ajax/location.php',
type:'GET',
dataType:'json', // add this
data: {
state_name : $state_var
},.....rest code
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I want to add the values inot the database but I am not to able to do that. var Array; $(document).ready(function () { $.ajax({ url: '../api/Emp/GetAll', type: 'Get', cache: false, datatype: 'json', success: function (text) { Array = text.Table; var List = JSON.stringify(text); for (var i = 0; i < data.length; i++) { var Id = Array[i].id; var Name =Array[i].name; var city = Array[i].city; $('#table body').append('<tr><td>' + Id + '</td><td><input type="text" value="' + Name + '" id="txt' + Id + '" /></td><td>' + city + '</td> </tr>'); } } })
If you need to put it back into the database you just need to reverse the process. Use post for your type and send the data back with ajax to a php script page that inserts the data into your database. You can edit the data on the php page before you insert it into the database or you can edit the data with javascript then send it back to php page. Create an ajax post $.ajax({ type: "post", datatype: "json", url: "insertPage.php", data: {dataNameHere: editedDataGoesHere}, success: function(data){ alert("SUCCESS"); }, error: function(e){ alert("ERROR"); } }); And then in your PHP: $obj = $_POST['dataNameHere']; and insert it into your database like you normally would.
how to clean option values under select - html tag
I am using two drop down(first drop-down category and second drop-down sub category) in a page,both drop-down will be loaded dynamically, in which I will be selecting a value from first drop-down accordingly I have to load value to second drop-down.I has done that,but thing is that it will get done for first time. But when I click on some other option in states drop-down, its not getting updated on second drop-down. And My code is: This piece of code is to get list of category while loading page ie under document.ready $.ajax({ url : "../category/getCategory", type : "post", contentType : "application/json", dataType : "json", success : function(data) { var categoryBOs = data.categoryBOs; $.each(categoryBOs, function(key, value) { $("#productCategory").append( '<option value='+value.categoryId+'>' + value.categoryName + '</option>'); }); } }); This part of ajax is to load sub category $("#productCategory").on('change', function() { alert($(this).val()); $.ajax({ url : "../category/getSubCategory", type : "post", cache : false, dataType : "json", data : "categoryId=" + $(this).val(), success : function(data) { var subCategoryBOs = data.subCategoryBOs; $.each(subCategoryBOs, function(key, subCategoryBO) { subCategories.push({lable:subCategoryBO.categoryId , value:subCategoryBO.categoryName}); $("#productSubCategory").append( '<option value='+subCategoryBO.categoryId+'>' + subCategoryBO.categoryName + '</option>'); }); } }); });
From what I see in your code you always append new entries, yet never remove old ones before. So possibly your list just keeps getting longer with new entries at its end? Try to remove the entries before append new ones: $("#productSubCategory option").remove(); $("#productSubCategory").append( '<option value=' + subCategoryBO.categoryId + '>' + subCategoryBO.categoryName + '</option>'); In my experience $.each with $.append can get very slow at some amount of list entries. I would rewrite it in native javascript with for() and createElement().
Try adding $("#productCategory").empty() before the first $.each and $("#productSubCategory").empty() before the second $.each.
you need to make html in .each and append after .each end. No option change from first drop down you need to remove the previous on by using $("#productSubCategory option").remove(); $.ajax({ url: "../category/getCategory", type: "post", contentType: "application/json", dataType: "json", success: function (data) { var categoryBOs = data.categoryBOs; var html = ''; $.each(categoryBOs, function (key, value) { html += '<option value=' + value.categoryId + '>' + value.categoryName + '</option>'; }); $("#productCategory").append(html); } }); $("#productCategory").on('change', function () { alert($(this).val()); $.ajax({ url: "../category/getSubCategory", type: "post", cache: false, dataType: "json", data: "categoryId=" + $(this).val(), success: function (data) { var subCategoryBOs = data.subCategoryBOs; var html = ''; $.each(subCategoryBOs, function (key, subCategoryBO) { subCategories.push({ lable: subCategoryBO.categoryId, value: subCategoryBO.categoryName }); html += '<option value=' + subCategoryBO.categoryId + '>' + subCategoryBO.categoryName + '</option>'; }); $("#productSubCategory").append(html); } }); });
Just simple thing you have to do here is that every time when you load sub-categories just place following before that . $(dropdown).empty(); Thanks !
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