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JavaScript Regex finding all substrings that matches with specific starting and ending pattern

I want a Javascript regex or with any possible solution,
For a given string finds all the substrings that start with a particular string and end with a particular character. The returned set of subStrings can be an Array.
this string can also have nested within parenthesis.
var str = "myfunc(1,2) and myfunc(3,4) or (myfunc(5,6) and func(7,8))";
starting char = "myfunc" ending char = ")" . here ending character should be first matching closing paranthesis.
output: function with arguments.
[myfunc(1,2),
myfunc(3,4),
myfunc(5,6),
func(7,8)]
I have tried with this. but, its returning null always.
var str = "myfunc(1,2) and myfunc(3,4) or (myfunc(5,6) and func(7,8))";
var re = /\myfunc.*?\)/ig
var match;
while ((match = re.exec(str)) != null){
console.log(match);
}
Can you help here?

I tested your regex and it seems to work fine:
let input = "myfunc(1,2) and myfunc(3,4) or (myfunc(5,6) and func(7,8))"
let pattern = /myfunc.*?\)/ig
// there is no need to use \m since it does nothing, and NO you dont need it even if you use 'm' at the beginning.
console.log(input.match(pattern))
//[ "myfunc(1,2)", "myfunc(3,4)", "myfunc(5,6)" ]
If you use (?:my|)func\(.+?\) you will be able to catch 'func(7,8)' too.
(?:my|)
( start of group
?: non capturing group
my| matches either 'my' or null, this will match either myfunc or func
) end of group
Test the regex here: https://regex101.com/r/3ujbdA/1

Getting strings between certain string and a special character

I am trying to get data between string and special character.
How can I do this in JS?
Below is my code:
var string = '(CATCH: dummy)';
var TitleRegex = /\((CATCH:.*?)\)/;
var titleData = string.match(TitleRegex);
Output should be : dummy

You could possibly fix the current expression by moving the opening ( to the location right after :, /\(CATCH:(.*?)\)/, and then grabbing Group 1 value using something like var titleData = string.match(TitleRegex)[1].
I'd suggest a bit more precise pattern here:
var string = '(CATCH: dummy)';
var TitleRegex = /\(CATCH:\s*([^()]*)\)/;
var titleData = string.match(TitleRegex);
if (titleData) {
console.log(titleData[1]);
}
The regex is \(CATCH:\s*([^()]*)\):
\(CATCH: - a (CATCH: substring
\s* - 0+ whitespaces
([^()]*) - Capturing group 1: any 0 or more chars other than ( and )
\) - a ) char.
You may actually use /\(CATCH:([^()]*)\)/ (without \s*) and just use titleData[1].trim() to get rid of any eventual whitespace on both ends of the required value.

getting values from a string using regular expression

Could anyone help me with this regular expression issue?
expr = /\(\(([^)]+)\)\)/;
input = ((111111111111))
the one I would need to be working is = ((111111111111),(222222222),(333333333333333))
That expression works fine to get 111111 from (input) , but not when there are also the groups 2222... and 3333.... the input might be variable by variable I mean could be ((111111111111)) or the one above or different (always following the same parenthesis pattern though)
Is there any reg expression to extract the values for both cases to an array?
The result I would like to come to is:
[0] = "111111"
[1] = "222222"
[2] = "333333"
Thanks

If you are trying to validate format while extracting desired parts you could use sticky y flag. This flag starts match from beginning and next match from where previous match ends. This approach needs one input string at a time.
Regex:
/^\(\(([^)]+)\)|(?!^)(?:,\(([^)]+)\)|\)$)/yg
Breakdown:
^\(\( Match beginning of input and immedietly ((
( Start of capturing group #1
[^)]+ Match anything but )
)\) End of CG #1, match ) immediately
| Or
(?!^) Next patterns shouldn't start at beginning
(?: Start of non-capturing group
,\(([^)]+)\) Match a separetd group (capture value in CG #2, same pattern as above)
| Or
\)$ Match ) and end of input
) End of group
JS code:
var str = '((111111111111),(222222222),(333333333333333))';
console.log(
str.replace(/^\(\(([^)]+)\)|(?!^)(?:,\(([^)]+)\)|\)$)/yg, '$1$2\n')
.split(/\n/).filter(Boolean)
);

You can replace brackes with , split it with , and then use substring to get the required number of string characters out of it.
input.replace(/\(/g, '').replace(/\)/g, '')
This will replace all the ( and ) and return a string like
111111111111,222222222,333333333333333
Now splitting this string with , will result into an array to what you want
var input = "((111111111111),(222222222),(333333333333333))";
var numbers = input.replace(/\(/g, '').replace(/\)/g, '')
numbers.split(",").map(o=> console.log(o.substring(0,6)))

If the level of nesting is fixed, you can just leave out the outer () from the pattern, and add the left parentheses to the [^)] group:
var expr = /\(([^()]+)\)/g;
var input = '((111111111111),(222222222),(333333333333333))';
var match = null;
while(match = expr.exec(input)) {
console.log(match[1]);
}

Allow only certain character in string. Javascript

I have no idea, why this simple code is not working. I am planning to match a string against the allowed pattern.
The string should ONLY have a-z, A-Z, 0-9, _ (underscore), . (dot) , - (hiphen).
Below is code:
var profileIDPattern = /[a-zA-Z0-9_.-]./;
var str = 'Heman%t';
console.log('hemant',profileIDPattern.test(str));
The code logs 'true' for below string, although these string DOES NOT match the pattern.
'Heman%t' -> true
'#Hemant$' -> true
I dont know what is the problem.

Try changing it to this RegExp (/^[a-zA-Z0-9_.-]*$/):
var profileIDPattern = /^[a-zA-Z0-9_.-]*$/;
var str1 = 'Hemant-._67%'
var str2 = 'Hemant-._67';
console.log('hemant1',profileIDPattern.test(str1));
console.log('hemant2',profileIDPattern.test(str2));

Issues : [a-zA-Z0-9_.-] will match any character inside [] and . will match anything after so basically it will match the mention character and any other character
Use ^ and $ anchor to mention start and end of match and remove .
^[a-zA-Z0-9_.-]+ : starting with any given value inside []
[a-zA-Z0-9_.-]+$ : one or more matches and $ to end the match
var profileIDPattern = /^[a-zA-Z0-9_.-]+$/;
console.log('hemant', profileIDPattern.test('Heman%t')); // no match -
console.log('hemant-._', profileIDPattern.test('hemant-._')); // valid match
console.log('empty', profileIDPattern.test('')); // no match ,empty

Remove punctuation, retain spaces, toLowerCase, add dashes succinctly

I need to do the following to a string:
Remove any punctuation (but retain spaces) (can include removal of foreign chars)
Add dashes instead of spaces
toLowercase
I'd like to be able to do this as succinctly as possible, so on one line for example.
At the moment I have:
const ele = str.replace(/[^\w\s]/, '').replace(/\s+/g, '-').toLowerCase();
Few problems I'm having. Firstly the line above is syntactically incorrect. I think it's a problem with /[^\w\s] but I am not sure what I've done wrong.
Secondly I wonder if it is possible to write a regex statement that removes the punctuation AND converts spaces to dashes?
And example of what I want to change:
Where to? = where-to
Destination(s) = destinations
Travel dates?: = travel-dates
EDIT: I have updated the missing / from the first regex replace. I am finding that Destination(s) is becoming destinations) which is peculiar.
Codepen: http://codepen.io/anon/pen/mAdXJm?editors=0011

You may use the following regex to only match ASCII punctuation and some symbols (source) - maybe we should remove _ from it:
var punct = /[!"#$%&'()*+,.\/:;<=>?#\[\\\]^`{|}~-]+/g;
or a more contracted one since some of these symbols appear in the ASCII table as consecutive chars:
var punct = /[!-\/:-#\[-^`{-~]+/g;
You may chain 2 regex replacements.
var punct = /[!"#$%&'()*+,.\/:;<=>?#\[\\\]^`{|}~-]+/g;
var s = "Where to?"; // = where-to
console.log(s.replace(punct, '').replace(/\s+/, '-').toLowerCase());
s = "Destination(s)"; // = destinations
console.log(s.replace(punct, '').replace(/\s+/, '-').toLowerCase());
console.log(s.replace(punct, '').replace(/\s+/, '-').toLowerCase());
Or use an anonymous method inside the replace with arrow functions (less compatibility, but succint):
var s="Travel dates?:"; // = travel-dates
var o=/([!-\/:-#\[-^`{-~]+)|\s+/g;
console.log(s.replace(o,(m,g)=>g?'':'-').toLowerCase());
Note you may also use XRegExp to match any Unicode punctuation with \pP construct.

Wiktor touched on the subject, but my first thought was an anonymous function using the regex /(\s+)|([\W])/g like this:
var inputs = ['Where to?', 'Destination(s)', 'Travel dates?:'],
res,
idx;
for( idx=0; idx<inputs.length; idx++ ) {
res = inputs[idx].replace(/(\s+)|([\W])/g, function(a, b) {return b ? '-' : '';}).toLowerCase();
document.getElementById('output').innerHTML += '"' + inputs[idx] + '" -> "'
+ res + '"<br/>';
}
<!DOCTYPE html>
<html>
<body>
<p id='output'></p>
</body>
</html>
The regex captures either white space (1+) or a non-word characters. If the first is true the anonymous function returns -, otherwise an empty string.