bootstrap-slider link input number with slide change - javascript

I am using bootstrap-slider.js. My problem is that I can't link input number with a slide. I want to slide to change too if the input number is changed.
Slider
<div id="slider-year" class="search-block">
<h2 class="title">Production year</h2>
<div class="slider-year-amount">
<span class="pull-left">1900</span>
<span class="pull-right">2017</span>
</div>
<input type="text" class="year-slider" style="width:100%" data-slider-min="1900" data-slider-max="2017" data-slider-step="1" data-slider-value="[1900,2017]" />
<div class="row">
<div class="year-box">
<div class="col-lg-6">
<label>From</label>
<input type="number" min="1900" max="2019" class="form-control" placeholder="1900" id="minYear" value="1900" name="year_since">
</div>
<div class="col-lg-6">
<label>To</label>
<input type="number" min="1901" max="2020" class="form-control" placeholder="2017" id="maxYear" value="2017" name="year_to">
</div>
</div>
</div>
</div>
How I try to update slider:
jQuery("#minYear").change(function () {
jQuery("#slider-year").slider('setValue', jQuery(this).val());
});
Also here is documentation for this slider if anyone is curious, I couldn't find solution there: http://www.eyecon.ro/bootstrap-slider
JsFiddle: https://jsfiddle.net/y95vfds3/6/

Many years have passed... Anyway, here is my solution:
$('#year-slider').slider()
.on('slide', function(ev) {
$('#minYear').val(ev.value[0]);
$('#maxYear').val(ev.value[1]);
});
$('.form-control').on('input', function() {
let minVal = parseInt($('#minYear').val());
let maxVal = parseInt($('#maxYear').val());
$('#year-slider').slider('setValue', [minVal, maxVal])
});
https://jsfiddle.net/p98bcxuv/

Do you want like this?
$("#minYear").change(function() {
$("#slider-year").slider('setValue', jQuery(this).val());
});
val = $('.year-slider').slider();
$('.year-slider').on('slide', function(ev) {
$('#minYear').val(ev.value[0]);
$('#maxYear').val(ev.value[1]);
});
https://jsfiddle.net/gnanavelr/y95vfds3/7/
https://jsfiddle.net/gnanavelr/y95vfds3/8/

Related

How can I validate form fields using JavaScript in Multi-step HTML Form?

I'm working on registration form that has three sections. A user moves to the next section of the form when the button "Next" is clicked. Everything is working well except that validation errors are only showing on the last section of the Form. I would like to validate the form before moving to the next section. For now, when "Next" button is clicked, the user can move to the next section even without filling the fields. I'm not so experienced in JavaScript, please help.
HTML:
<section>
<div class="container">
<form>
<div class="step step-1 active">
<div class="form-group">
<label for="firstName">First Name</label>
<input type="text" id="firstName" name="first-name">
</div>
<div class="form-group">
<label for="lastName">Last Name</label>
<input type="text" id="lastName" name="last-name">
</div>
<div class="form-group">
<label for="nickName">Nick Name</label>
<input type="text" id="nickName" name="nick-name">
</div>
<button type="button" class="next-btn">Next</button>
</div>
<div class="step step-2">
<div class="form-group">
<label for="email">Email</label>
<input type="text" id="email" name="email">
</div>
<div class="form-group">
<label for="phone">Phone</label>
<input type="number" id="phone" name="phone-number">
</div>
<button type="button" class="previous-btn">Prev</button>
<button type="button" class="next-btn">Next</button>
</div>
<div class="step step-3">
<div class="form-group">
<label for="country">country</label>
<input type="text" id="country" name="country">
</div>
<div class="form-group">
<label for="city">City</label>
<input type="text" id="city" name="city">
</div>
<div class="form-group">
<label for="postCode">Post Code</label>
<input type="text" id="postCode" name="post-code">
</div>
<button type="button" class="previous-btn">Prev</button>
<button type="submit" class="submit-btn">Submit</button>
</div>
</form>
</div>
</section>
JavaScript:
const steps = Array.from(document.querySelectorAll("form .step"));
const nextBtn = document.querySelectorAll("form .next-btn");
const prevBtn = document.querySelectorAll("form .previous-btn");
const form = document.querySelector("form");
nextBtn.forEach((button) => {
button.addEventListener("click", () => {
changeStep("next");
});
});
prevBtn.forEach((button) => {
button.addEventListener("click", () => {
changeStep("prev");
});
});
form.addEventListener("submit", (e) => {
e.preventDefault();
const inputs = [];
form.querySelectorAll("input").forEach((input) => {
const { name, value } = input;
inputs.push({ name, value });
});
console.log(inputs);
form.reset();
});
function changeStep(btn) {
let index = 0;
const active = document.querySelector(".active");
index = steps.indexOf(active);
steps[index].classList.remove("active");
if (btn === "next") {
index++;
} else if (btn === "prev") {
index--;
}
steps[index].classList.add("active");
}
If you want to validate one section of the form before moving on to the next one you should do something like this:
nextBtn.forEach(button => {
button.addEventListener("click", () => {
handleEvent("next")
})
})
prevBtn.forEach(button => {
button.addEventListener("click", () => {
handleEvent("prev")
})
})
where handleEvent is:
function handleEvent(btn) {
if (!handleFormValidation(btn)) return "error message here";
changeStep(btn)
}
Here handleFormValidation would be a function that checks weather the input is correct and returns true if it is and false if it isn't
If you want to make sure the user fills in the first form first before going to the second you can do it by making the second form appear only after the next button is pressed, but that would require a major rework of your system. (i do however advise it because when i copied your code to test it i noticed quite a lot of bugs)
Here are some mdn articles describing how to make, delete and append elements using javascript:
making an element
removing an element
removing an element
appending an element to another element
appending an element to another element
I highly encourage you to do your own research as well.
I also just want to apologise if anything in my answer isn't understandable. I'm new at contributing to this community so there will likely be mistakes I've made.

How to validate number in inputs with javascript when pressing button?

Right now I have an Input Field (number) that shows a message when the numbers are over 120 or below 135.
//Message on Age
$("#age").keyup(function() {
if ($('#age').val() < 35 || $('#age').val() > 120) {
$('#errorMsg').show();
} else {
$('#errorMsg').hide();
}
<!-- AGE -->
<div class="card-2 p-20 hidden">
<div class="bg-white max-width p-20 mb-20">
<h2 style="margin-bottom: 50px;">What is your age?</h2>
<div class="options">
<input id="age" name="age" type="number" step="1" min="35" max="120" required="true" class="form-custom">
<span id="errorMsg" style="display:none;">Only policyholders between 35 and 120 years are elegible</span>
</div>
</div>
<div>
<button type="button" class="btn-previous">
Previous
</button>
<button type="button" class="btn-next">
Next
</button>
</div>
</div>
The issue is that user's still can press the button with the error message on the screen, I want to show the error message when they hit the button or invalidate the button if the age field isn't in range.
Thank you so much to anyone who can help on this!
You can use .prop function to disable your button if the condition matches and enable it if its all good.
Also, you can use $(this) to get the value of your input instead using if using #age id again in your .val().
In addtion you need to add + to your val() to make sure that strings value which are sting initially are converted into integers when checking the if condition.
Live Demo:
$("#age").on('input keyup', function() {
let btn = $('.btn-next')
let errorMsg = $('#errorMsg')
if (+$(this).val() < 35 || +$(this).val() > 120) {
errorMsg.show();
btn.prop('disabled', true)
} else {
errorMsg.hide();
btn.prop('disabled', false)
}
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="card-2 p-20 hidden">
<div class="bg-white max-width p-20 mb-20">
<h2 style="margin-bottom: 50px;">What is your age?</h2>
<div class="options">
<input id="age" name="age" type="number" step="1" min="35" max="120" required="true" class="form-custom">
<span id="errorMsg" style="display:none;">Only policyholders between 35 and 120 years are elegible</span>
</div>
</div>
<div>
<button type="button" class="btn-previous">
Previous
</button>
<button type="button" class="btn-next">
Next
</button>
</div>
</div>
You can change keyup to change jQuery method and implement sort of controller like this
// Controller
let cont = true;
// Validator
$("#age").on('change', function() {
if ($('#age').val() < 35 || $('#age').val() > 120) {
$('#errorMsg').show();
cont = true;
} else {
$('#errorMsg').hide();
cont = false;
}
});
$(".btn-next").on('click', function(event) {
if(cont) {
// Here do some warning you want
$('#errorMsg').show(function() {
alert($('#errorMsg').text());
});
// ALSO if this button gonna be SUBMIT
// button, you can set here prevent
// default mode like this:
//
//event.preventDefault();
} else {
// Validation ok, continue your logic
// ...
//
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<!-- AGE -->
<div class="card-2 p-20 hidden">
<div class="bg-white max-width p-20 mb-20">
<h2 style="margin-bottom: 50px;">What is your age?</h2>
<div class="options">
<input id="age" name="age" type="number" step="1" min="35" max="120" required="true" class="form-custom">
<span id="errorMsg" style="display:none;">Only policyholders between 35 and 120 years are elegible</span>
</div>
</div>
<div>
<button type="button" class="btn-previous">Previous</button>
<button type="button" class="btn-next">Next</button>
</div>
</div>

Ajax post is fired twice when using a keyup event

I have a zipcode checker which posts using ajax after the length of an input field is equal to 6. This works, except the ajax is posted twice. Why is that? I am using an api which has 1000 calls each month, so this behaviour already cuts that in half.
Maybe it would make sense to me that because of some bug it fires again when typing a 7th character, but that is not even the case, when I type exactly 6 characters the ajax is fired twice.
$("body").on("keyup", "#billing_postcode", function() {
var value = $(this).val();
var housenumber = $("#billing_streetnumber").val();
if (housenumber.length >= 1) {
if (value.length == 6) {
url = 'catalog/postcodecheck.php';
var $postcode = $('#billing_postcode').val();
var $huisnummer = $('#billing_streetnumber').val();
var posting = $.post(url, {
postcode: $postcode,
huisnummer: $huisnummer
});
posting.done(function(data) {
var content = $($.parseHTML(data));
$("#postcoderesult").empty().append(content);
});
} else {
}
} else {
alert('Vul eerst je huisnummer in voor dat je verder kan.');
$("#billing_postcode").val('');
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="col-lg-3">
<p class="single-form-row">
<label>Huisnummer <span class="required">*</span></label>
<input type="text" name="billing_streetnumber" id="billing_streetnumber" required>
</p>
</div>
<div class="col-lg-4">
<p class="single-form-row">
<label>Toevoeging (optioneel)</label>
<input type="text" name="billing_streetextra" id="billing_streetextra">
</p>
</div>
<div class="col-lg-5">
<p class="single-form-row">
<label>Postcode<span class="required">*</span></label>
<input type="text" name="billing_postcode" id="billing_postcode" required>
</p>
</div>
<div id="postcoderesult" class="col-lg-12">
<div class="row">
<div class="col-lg-6">
<p class="single-form-row">
<label>Straatnaam <span class="required">*</span></label>
<input type="text" name="billing_street" id="billing_street" disabled required>
</p>
</div>
<div class="col-lg-6">
<p class="single-form-row">
<label>Stad<span class="required">*</span></label>
<input type="text" name="billing_city" id="billing_city" disabled required>
</p>
</div>
</div>
</div>

Need to append html element as user keep clicking a button with jquery

I am trying to append a div multiple times when clicking a button, the problem is that is only appending once. I need to append same div as user keeps clicking.
DIV I need to append multiple times is stored in a variable named $htmlDivForm in the jquery code.
I'm using bootstrap.
HTML code:
<div class="container">
<div class="row">
<div class="col-md-3">
<form id="formUser" action="index.html" method="post">
<div class="text-center">
<button id="moreFieldsBtn" class="btn" type="button" name="button">+</button>
</div>
</form>
</div>
<div class="col-md-9">
More Content...
</div>
</div>
</div>
jquery code:
var $moreFieldsBtn = $("#moreFieldsBtn");
var $formUser = $("#formUser");
var $htmlDivForm = $('<div class="form-group"><label class="labelName" for="inputText">Nombre</label><input class="form-control inputTextField" type="text" name="inputText" value=""></div>');
//Add input text field
$($moreFieldsBtn).click (function() {
$($formUser).append($htmlDivForm);
});
I had gone through your question.
I have Updated the example.
Removed the Object and just inserting plain HTML
var $moreFieldsBtn = $("#moreFieldsBtn");
var $formUser = $("#formUser");
var $htmlDivForm = $('<div class="form-group"><label class="labelName" for="inputText">Nombre</label><input class="form-control inputTextField" type="text" name="inputText" value=""></div>');
var htmltext = '<div class="form-group"><label class="labelName" for="inputText">Nombre</label><input class="form-control inputTextField" type="text" name="inputText" value=""></div>'
//Add input text field
$($moreFieldsBtn).click (function() {
$($formUser).append(htmltext);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<div class="row">
<div class="col-md-3">
<form id="formUser" action="index.html" method="post">
<div class="text-center">
<button id="moreFieldsBtn" class="btn" type="button" name="button">+</button>
</div>
</form>
</div>
<div class="col-md-9">
More Content...
</div>
</div>
</div>
<div>
You can't append the same div multiple times, you need to instantiate new divs and attach those. You also don't need to re-wrap the jQuery objects to attach the handlers:
var $moreFieldsBtn = $("#moreFieldsBtn");
var $formUser = $("#formUser");
//Add input text field
$moreFieldsBtn.click(function() {
var $htmlDivForm = $('<div class="form-group"><label class="labelName" for="inputText">Nombre</label><input class="form-control inputTextField" type="text" name="inputText" value=""></div>');
$formUser.append($htmlDivForm);
});

Jquery - find next element in each loop

I have a question like so.
I have HTML structure:
<form id="form">
<div class="row">
<div class="item-input">
<label for="A1">A1</label>
<input type="text" name ="A1" />
<span class="input-require">(*)</span>
<span class="info">(Enter A1)</span>
</div>
<div class="item-input">
<label for="A2">A2</label>
<input type="text" name ="A2" />
<span class="input-require">(*)</span>
<span class="info">(Enter A2)</span>
</div>
</div>
<div class="row">
<div class="item-input">
<label for="B1">B1</label>
<input type="text" name ="B1" />
<span class="input-require">(*)</span>
<span class="info">(Enter B1)</span>
</div>
<div class="item-input">
<label for="B2">B2</label>
<input type="text" name ="B2" />
<span class="input-require">(*)</span>
<span class="info">(Enter B2)</span>
</div>
</div>
...
</form>
Now I want to selected 'span' has class "info" behind input[type=text] each.
I try:
<script type="text/javascript">
$(document).ready(function() {
$("#form input[type=text]").each(function(){
var spanInfo = $(this).closest("item-input").next().find('span.info');
console.log(spanInfo.text()); // Result is empty
});
});
</script>
Why is empty? Help me please. How do I, thanks
var spanInfo = $(this).closest("item-input").next().find('span.info');
Should be
var spanInfo = $(this).closest(".item-input").next().find('span.info');
You are missing the . (dot, class)
Your mean is show "(Enter A2)" and "(Enter B2)" or show all 4 element value: (Enter A1), (Enter A2), (Enter B1), (Enter B2)
If only show 2 value then CODE HERE
else You want to show 4 value, you can code:
$(document).ready(function() {
$("#form input[type=text]").each(function(){
var spanInfo = $(this).closest(".item-input").find('span.info');
console.log(spanInfo.text());
});
});

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