Can you please take a look at this snippet and let me know why I am not able to target the closest image element to file input
$('.file').on('change', function(ev) {
var f = ev.target.files[0];
var fr = new FileReader();
fr.onload = function(ev2) {
$(this).closest('.img').attr('src', ev2.target.result);
$(this).find('.img').attr('src', ev2.target.result);
$(this).next('.img').attr('src', ev2.target.result);
};
fr.readAsDataURL(f);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="file" class="file" name="image" />
<img class="img" />
<input type="file" class="file" name="image" />
<img class="img" />
As you can see I already tried
$(this).closest('.img').attr('src', ev2.target.result);
$(this).find('.img').attr('src', ev2.target.result);
$(this).next('.img').attr('src', ev2.target.result);
but it is not doing the job
you have to find img closest to the input file which changes, so you must use ev.target because inside the second function scope changes and this does not refer to file input anymore, something like this seems to work:
$('.file').on('change', function(ev) {
var f = ev.target.files[0];
var fr = new FileReader();
fr.onload = function(ev2) {
$(ev.target).next('.img').attr('src', ev2.target.result);
};
fr.readAsDataURL(f);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="file" class="file" name="image" />
<img class="img" />
<input type="file" class="file" name="image" />
<img class="img" />
Related
Right now I have a url that displays an image when it's loaded. However, there will be an option for this image to be replaced via a form input. I would like the uploaded image to be displayed as soon as it's uploaded so it can be evaluated by the user.
I'm trying to accomplish this via jQuery, but I can't get it to work.
Here's my code:
HTML:
<div class="form-group">
<label for="Image">Image</label>
<input type="file" id="Image" name="Image" accept="image/*">
<img src="..\{{ workshop_info[4] }}" id="output">
</div>
JQuery:
<script>
$(document).ready(function() {
$("#Image").change(function(e){
$("#output").attr("src", e.target.files[0]);
});
});
</script>
You can do this by using FileReader functionality.
I have recreated your example which displays an image when it's loaded
Once i upload my own image by clicking choose file and selected the file. That file will be getting previewed after selection with that image load_images div i created.
As soon as the file is selected i am replace the src of your existing image to the new src which come from readAsDataURL
You can read more about FileReader here in detail.
Working Demo: https://jsfiddle.net/usmanmunir/w5cbgLsk/
Run snippet below to see it working.
$(function() {
//Preview image function
var previewImage = function(image) {
if (image.files) {
//Check all images
var filesAmount = image.files.length;
for (i = 0; i < filesAmount; i++) {
var reader = new FileReader();
reader.onload = function(event) {
//Replace images on form upload selected image
$('#output').attr('src', event.target.result)
}
reader.readAsDataURL(image.files[i]);
}
}
};
//Select image and call imagePreview function
$('#Image').on('change', function() {
previewImage(this);
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="form-group">
<label for="Image">Image</label>
<input type="file" id="Image" name="Image" accept="image/*">
<div class="load_images">
<img src="http://mandarinazul.co/images/mandarinas.png" id="output">
</div>
</div>
<img src="../yourimage/path/image.jpeg" onclick="previmg()" id="displayimage" />
<input type="file" class="form-control" onchange="selectedimg(this)" id="selectphoto" style="display: none" name="photo">
</div>
function previmg(){
document.querySelector('#selectphoto').click();
}
function selectedimg(e){
if(e.files[0]) {
var reader = new FileReader();
reader.onload = function(e) {
document.querySelector('#displayimage').setAttribute('src', e.target.result);
}
reader.readAsDataURL(e.files[0]);
}}
OR you can try this too,
<input type="file" onchange="previewFile()"><br>
<img src="" height="200" alt="image has to be load">
function previewFile() {
const preview = document.querySelector('img');
const file = document.querySelector('input[type=file]').files[0];
const reader = new FileReader();
reader.addEventListener("load", function () {
preview.src = reader.result;
}, false);
if (file) {
reader.readAsDataURL(file);
}}
try this, both will work charm if any doubt feel free to ask.:-)
Is there a better way of doing this in js? Or more so, how would I do this better in js?
So I don't have 3 scripts basically the same.
Thank you for any help in advance
<label for="img1">Image 1:</label>
<input type="file" id="img1" name="img1" />
<img id="image1"/>
<script>
document.getElementById("img1").onchange = function () {
var reader = new FileReader();
reader.onload = function (e) {
document.getElementById("image1").src = e.target.result;
};
reader.readAsDataURL(this.files[0]);
};
</script>
<label for="img2" >Image 2:</label>
<input type="file" id="img2" name="img2" />
<img id="image2"/>
<script>
document.getElementById("img2").onchange = function () {
var reader = new FileReader();
reader.onload = function (e) {
document.getElementById("image2").src = e.target.result;
};
reader.readAsDataURL(this.files[0]);
};
</script>
<label for="img3">Image 3:</label>
<input type="file" id="img3" name="img3" />
<img id="image3"/>
<script>
document.getElementById("img3").onchange = function () {
var reader = new FileReader();
reader.onload = function (e) {
document.getElementById("image3").src = e.target.result;
};
reader.readAsDataURL(this.files[0]);
};
</script>
Trying to explain myself a little better.
For example in python, loop through something and use the i in the function.
gg = ("a", "q", "f", "4", "f", "h")
for i in range(len(gg)):
print ('thing'+str(i))
<label for="img1">Image 1:</label>
<input type="file" id="img1" name="img1" />
<img id="image1"/>
<label for="main_img">Image 2:</label>
<input type="file" id="img2" name="img2" />
<img id="image2"/>
<label for="main_img">Image 3:</label>
<input type="file" id="img3" name="img3" />
<img id="image3"/>
<script>
imgOnChange('img1','image1');
imgOnChange('img2','image2');
imgOnChange('img3','image3');
function imgOnChange(imgId, imageId) {
document.getElementById(imgId).onchange = function () {
var reader = new FileReader();
reader.onload = function (e) {
document.getElementById(imageId).src = e.target.result;
};
reader.readAsDataURL(this.files[0]);
};
}
</script>
HTML Code:
<input type="file" name="img1" id="img1" required>
<input type="file" name="img2" id="img2">
<input type="file" name="img3" id="img3">
<input type="file" name="img4" id="img4">
jQuery Code:
for(var i = 1; i <= 4; i++){
if($("#img"+i).val() != ''){
file = document.getElementById('img' + i).files[0];
fileread(file);
}
}
function fileread(file){
var result = '';
reader = new FileReader();
reader.onload = function(){
result = reader.result;
//return result;
localStorage.setItem("lostimage1", result);
}
reader.readAsDataURL(file);
}
I want to read multiple files when user click on submit button. but it not working. How can I resolve this error? please help me.
Using Jquery and each() method I suggest this:
var checkValue;
var valueArray=[];
$('#button').on('click',function(){
$('input').each(function(){
checkValue=$(this).val();
if(checkValue===''){
return;
}
valueArray.push(checkValue);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="file" name="img1" id="img1" required>
<input type="file" name="img2" id="img2">
<input type="file" name="img3" id="img3">
<input type="file" name="img4" id="img4">
<button id="button">Click Me</button>
Attach click event to <input type="submit">, call event.preventDefault() to prevent <form> submission, use .each() to iterate <input type="file"> elements, pass this.files[0] to readfile function.
Adjust within FileReader load handler to not overwrite same key at localStorage.
FileReader throws an error if a Blob or File object is not passed as parameter to .readAsDataURL(), for example, ifis clicked andfilereadis called in loop and one ofelements.filesproperty doe not containFileobject inFileList. Check if element.fileshas.lengthgreater than0before callingfilereadreferencing the.files[0]property of the current` element.
$(function() {
function fileread(file, id) {
var reader = new FileReader();
reader.onload = function() {
localStorage.setItem("lostimage" + id, reader.result);
}
reader.readAsDataURL(file);
}
$("input[type=submit]").on("click", function(e) {
e.preventDefault();
$(":file[id^=img]").each(function() {
if (this.files.length) fileread(this.files[0], this.id.replace(/\D/g, ""))
})
});
});
plnkr http://plnkr.co/edit/1Sec8uWlK2pbXMTlfpCj?p=preview
I create script for show image until upload , how i use 5 input files for upload , the script must let show one image , or preview image for each input file
The Script :
<script>
function handleFileSelect(evt,ids) {
var files = evt.target.files;
var f = files[0];
var reader = new FileReader();
reader.onload = (function(theFile) {
return function(e) {
document.getElementById('list'+ids).innerHTML = ['<img src="', e.target.result,'" title="', theFile.name, '" width="50"/>'].join('');
///alert("ok"+ids);
};
})(f);
reader.readAsDataURL(f);
}
</script>
HTML CODE
<input type="file" id="files2" />
<output id="list2"></output>
CALLING SCRIPT FOR THIS INPUT FILE ID
<script>
document.getElementById('files2').addEventListener('change', function(){handleFileSelect('','2');},false);
</script>
As you can see i try send vars from handleFileSelect('','2') , but don´t works never and i think the code it´s well , but sure i forget something , i hope here can help me in this issue , thank´s community
The Best Regards
Try this code
$(function () {
var _URL = window.URL || window.webkitURL;
$(".UploadImage").on("change", function () {
var preview = $(this).attr("data-img");
var file, img;
if ((file = this.files[0])) {
img = new Image();
img.onload = function () {
document.getElementById(preview).src = _URL.createObjectURL(file);
};
img.src = _URL.createObjectURL(file);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<input type="file" data-img="preview1" class="UploadImage" />
<img src="" id="preview1"/>
</div>
<div>
<input type="file" data-img="preview2" class="UploadImage" />
<img src="" id="preview2"/>
</div>
<div>
<input type="file" data-img="preview3" class="UploadImage" />
<img src="" id="preview3"/>
</div>
<div>
<input type="file" data-img="preview4" class="UploadImage" />
<img src="" id="preview4"/>
</div>
It's better if you use CreateObjectURL instead (saves more memory/cpu) it's also faster
var wrapper = document.getElementById('files')
var URL = window.URL || window.webkitURL;
wrapper.addEventListener('change', function(evt){
var input = evt.target
if (input.matches('input[type="file"]') && (input.files || [])[0]) {
var img = new Image
img.width = 50
img.onload = function() {
var output = document.getElementById(input.dataset.for)
output.appendChild(this)
}
img.onerror = function(){
console.log("You uploaded something that is not an image")
}
img.src = URL.createObjectURL(input.files[0])
}
})
output {
display: block;
}
<div id="files">
<!-- Recomend adding accept attribute so you only get images -->
<!-- just made one example -->
<input type="file" data-for="list1" accept="image/*">
<output id="list1"></output>
<input type="file" data-for="list2">
<output id="list2"></output>
<input type="file" data-for="list3">
<output id="list3"></output>
<input type="file" data-for="list4">
<output id="list4"></output>
</div>
Hi in the below code I am going to upload the image using following java script function.for the first input working fine.In the same way how to call second input field when I am passing the id it's got changes the first one and second one images are displaying same.
html
<div class="person_pic">
<label>Please upload your photo</label><input type='file' name="image" onchange="readURL(this);" />
<img id="blah" src="#" alt="your image" />
</div>
<div class="person_pic">
<label>Please upload your family photo</label>
<input type='file' name="image" onchange="readURL(this);" />
<img id="blah1" src="#" alt="your image" />
</div>
javascript
function readURL(input) {
if (input.files && input.files[0]) {
var reader = new FileReader();
reader.onload = function (e) {
$('#blah')
.attr('src', e.target.result)
.width(150)
.height(200);
};
reader.readAsDataURL(input.files[0]);
}
if (input.files && input.files[0]) {
var reader = new FileReader();
reader.onload = function (e) {
$('#blah1')
.attr('src', e.target.result)
.width(150)
.height(200);
};
reader.readAsDataURL(input.files[0]);
}
}
You can try passing the id of the img element that you want to change.As you are using $('#blah') for both the function call , hence both the time same image is being displayed.You can do this:
<script>
function readURL(input,x) {
if (input.files && input.files[0]) {
var reader = new FileReader();
x = '#'+x;
reader.onload = function (e) {
$(x)
.attr('src', e.target.result)
.width(150)
.height(200);
};
reader.readAsDataURL(input.files[0]);
}
}
</script>
<div class="person_pic">
<label>Please upload your photo</label>
<input type='file' name="image" onchange="readURL(this,'blah');" />
<img id="blah" src="#" alt="your image" />
</div>
<div class="person_pic">
<label>Please upload your family photo</label>
<input type='file' name="image" onchange="readURL(this,'blah1');" />
<img id="blah1" src="#" alt="your image" />
</div>