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Function with two switch cases will only log one string

Im new to coding and javascript, atm im doing som tests in school.
I have this function with two different switch cases with strings which i want to add together and return. But it only returns one of the strings. If i use switch(card.value) on the first and switch(card.suit) on the second it only returns the first one. But if i take it away on the frist one:
switch(value) and switch(card.suit) it return string from the lower switch-case. Why is that? And how do i get it to return A♥? Here is the code. Sorry for my messy description.
const prettyCard = function (card) {
let suit, value
switch (card.value) {
case 1:
return 'A';
break;
case 10:
return 'T';
break;
case 11:
return 'J';
break;
case 12:
return 'Q';
break;
case 13:
return 'K';
break;
case 2:
return '2';
break;
case 3:
return '3';
break;
case 4:
return '4';
break;
case 5:
return '5';
break;
case 6:
return '6';
break;
case 7:
return '7';
break;
case 8:
return '8';
break;
case 9:
return '9';
break;
}
switch (card.suit) {
case 'HEARTS':
return '♥';
break;
case 'SPADES':
return '♠';
break;
case 'DIAMONDS':
return '♦';
break;
case 'CLUBS':
return '♣';
break;
}
return value + suit
}
console.log(prettyCard({ suit: 'HEARTS', value: 1 }))

In addition to the fix suggested in comments, the code can shrink considerably by looking-up suits and values in an object, rather than a long switch.
const prettyCard = card => {
const values = { 1: 'A', 11: 'J', 12: 'Q', 13: 'K' }
const suits = { 'HEARTS': '♥', 'SPADES': '♠', 'DIAMONDS': '♦', 'CLUBS': '♣' };
const suit = suits[card.suit];
const value = card.value > 1 && card.value < 11 ? `${card.value}` : values[card.value];
return { suit, value };
}
console.log(prettyCard({ value: 12, suit: 'HEARTS' }))

Switch case doesn't work and give 0 values

I tried this switch and loop, but it only gives me 0 values when I expected it should be incrementing for all display "yes". May I know where goes wrong?
I am new to this javascript.
for (var i=3; i<=62; i++){
var quesNum = i - 2;
if (activeSheet.getRange(row, i).getDisplayValue() == "yes") {
switch (quesNum) {
case 1: case 3: case 5: case 12:
++realistic;
break;
case 2: case 6: case 9: case 14:
++investigative;
break;
case 4: case 8: case 11: case 15:
++artistic;
case 7: case 10: case 13: case 16:
++conventional;
break;
default:

Why can I not view an updated count for a variable with console.log in Javascript?

I currently have this code below, it is supposed to emulate a card counting system, in which different characters increment/decrement the count when passed. The code below runs successfully, but when I attempt console.log(cc(2,3,4,5,6); it returns 1 Bet, when I know the code runs 5 Bet, as those characters should increment the count, yet console.log does not return the accurate count, I assume this is due to scope? But I would like if someone could explain why count isn't accurately returned.
var count = 0;
function cc(card) {
switch(card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count += 1;
break;
case 7:
case 8:
case 9:
count += 0;
break;
case 10:
case 'J':
case 'Q':
case 'K':
case 'A':
count -= 1;
break;
}
if (count > 0) {
return count + " Bet";
}
else {
return count + " Hold";
}
}
cc(2,3,4,5,6); \\ returns 5 Bet
console.log(cc(2,3,4,5,6)); \\ returns 2 Bet

var count = 0;
const bet = card => {
switch (card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count += 1;
break;
case 7:
case 8:
case 9:
count += 0;
break;
case 10:
case "J":
case "Q":
case "K":
case "A":
count -= 1;
break;
}
};
function cc(...moves) {
moves.forEach(bet);
if (count > 0) {
return count + " Bet";
} else {
return count + " Hold";
}
}
console.log(cc(2, 3, 4, 5, 6)); // returns 5 Bet
console.log(cc(2, 3, 4, 5, 6)); // returns 10 Bet

Use arguments or splat operator to get all arguments passed and then loop it:
function cc(...cards) {
var count = 0;
var card;
for (var i = 0; i < cards.length; i++) {
card = cards[i];
switch (card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count += 1;
break;
case 7:
case 8:
case 9:
count += 0;
break;
case 10:
case 'J':
case 'Q':
case 'K':
case 'A':
count -= 1;
break;
}
}
if (count > 0) {
return count + " Bet";
} else {
return count + " Hold";
}
}
cc(2, 3, 4, 5, 6); // returns 5 Bet
console.log(cc(2, 3, 4, 5, 6)); // returns 2 Bet

You have two major problems.
First, your count need to start at zero every time you call cc(). Because you have declared count outside the function, its values is preserved between calls to cc(). By declaring it inside the function, it's initialized to zero before it starts counting the card values.
(Unless you want to continue to the previous count, in which case you should keep it declared outside the function)
Second, your function only accepts one argument. You need to make it accept a list of arguments. This can be done simply with the spread operator .... Then you need to loop through each card value and do the count.
function cc(...cards) { // accept a list of card values as arguments.
let count = 0
for (const card of cards) { // loop through all card values.
switch (card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count += 1
break
case 7:
case 8:
case 9:
count += 0
break
case 10:
case 'J':
case 'Q':
case 'K':
case 'A':
count -= 1
break
}
}
if (count > 0) {
return `${count} Bet`
}
return `${count} Hold`
}
cc(2, 3, 4, 5, 6) // returns 5 Bet
console.log(cc(2, 3, 4, 5, 6)) // returns 5 Bet
console.log(cc(2, 3, 4, 5, 6)) // returns 5 Bet

Compare if a-z or A-Z and give output with switch JavaScript function

I'm learning JavaScript. Very new and know basic. I'm playing with various options of JavaScript.
I'm comparing a-z (lower case) and A-Z (upper case) from user input. and giving an answer base on the input.
Normally i can do this with this long code:
var x = prompt("Enter Your character");
switch (x) {
case 'a':
case 'b':
case 'c':
case 'd':
case 'e':
case 'f':
case 'g':
case 'h':
case 'i':
case 'j':
case 'k':
case 'l':
case 'm':
case 'n':
case 'o':
case 'p':
case 'q':
case 'r':
case 's':
case 't':
case 'u':
case 'v':
case 'w':
case 'x':
case 'y':
case 'z':
document.write("Lower case");
break;
case 'A':
case 'B':
case 'C':
case 'D':
case 'E':
case 'F':
case 'G':
case 'H':
case 'I':
case 'J':
case 'K':
case 'L':
case 'M':
case 'N':
case 'O':
case 'P':
case 'Q':
case 'R':
case 'T':
case 'U':
case 'V':
case 'W':
case 'X':
case 'Y':
case 'Z':
document.write("Upper case");
break;
default:
document.write("It is number");
break;
}
With switch I want to achieve same output but with less code! Something like this:
var x = prompt("Enter Your character");
switch(x) {
case x >= 'a'|| x <= 'z':
document.write("Lower case");
break;
case x >= 'A' || x <= 'Z':
document.write("Upper case");
break;
default:
document.write("It is number");
break;
}
Any Help?
Please I want to do this with only switch function. I know i can do this with if/else function but i want to do this with switch. If its not possible with switch let me know :-)

The switch statement compares the input expression with each case statement using strict comparison.
So use true inside the switch clause and specify expressions that evaluate to true in case clause:
var x = prompt("Enter Your character");
switch (true) {
case x >= "a" && x <= "z":
alert("Lower case");
break;
case x >= "A" && x <= "Z":
alert("Upper case");
break;
default:
alert("Something else");
break;
}
I personally do not recommend this. This is only for learning.

You can try it with something like this.
<script>
var x=prompt("Enter Your character");
if (x.test(/[a-z]/)) {
document.write("Lower case");
} else if (x.test(/[A-Z]/)) {
document.write("Upper case");
} else {
document.write("It is number");
}
</script>
You can see more info here: https://developer.mozilla.org/es/docs/Web/JavaScript/Reference/Global_Objects/RegExp/test

You could do a simple if/else
var x=prompt("Enter Your character");
if(!isNaN(x))
console.log("It is number");
else if(x.toLowerCase()==x)
console.log("Lower case");
else if(x.toUpperCase()==x)
console.log("Upper case"););

Check if the character is in in between other characters:
var x=prompt("Enter Your character");
if (x >= '0' && x <= '9')
alert("number!");
else if(x >= 'a' && x <= 'z')
alert("lowercase!");
else if(x >= 'A' && x <= 'Z')
alert("uppercase!");
else
alert("not a letter!");

The parameter to a case statement is something to perform an equality comparison with, you don't put a comparison there. If you want to do a comparison, use if, not switch. Also, you should be combining the comparisons with &&, not ||
if (x >= 'a' && x <= 'z') {
document.write('Lower case');
} else if (x >= 'A' && x <= 'Z') {
document.write('Upper case');
} else if (x >= '0' && x <= '9') {
documennt.write('Number');
} else {
document.write('Something else');
}

Try also:
var x = prompt("Enter Your character");
var find = x.match(/([a-z]*)([A-Z]*)([0-9]*)/);
var type = ["Lower case","Upper case", "It is number"];
document.write(find ? type[find.lastIndexOf(x)-1] : "Unknown char")

Javascript case statement in the switch Statement

I have a problem with the 'case' statement in the 'switch' statement in java script.
My question is how to write more than one number in the 'case' statement and save all the work on writing multiple of commands for each number , ill try to explain myself better. i want to write in the case statement the
number 10-14 (10,11,12,13,14).
how can i write it?
thanks for helping and sorry for my bad english.
name = prompt("What's your name?")
switch (name)
{
case "Ori":
document.write("<h1>" + "Hello there Ori" + "<br>")
break;
case "Daniel":
document.write("<h1>" + "Hi, Daniel." + "<br>")
break;
case "Noa":
document.write("<h1>" + "Noa!" + "<br>")
break;
case "Tal":
document.write("<h1>" + "Hey, Tal!" + "<br>")
break;
default:
document.write("<h1>" + name + "<br>")
}
age = prompt ("What's your age?")
switch (age)
{
case "10":
document.write("you are too little" + name)
break;
case "14":
document.write("So , you are in junior high school" + name)
break;
case "18":
document.write("You are a grown man" + name)
break;
default:
document.write("That's cool" + name)
break;
}

Check out this answer Switch on ranges of integers in JavaScript
In summary you can do this
var x = this.dealer;
switch (true) {
case (x < 5):
alert("less than five");
break;
case (x > 4 && x < 9):
alert("between 5 and 8");
break;
case (x > 8 && x < 12):
alert("between 9 and 11");
break;
default:
alert("none");
break;
}
but that sort of defeats the purpose of a switch statement, because you could just chain if-else statments. Or you can do this:
switch(this.dealer) {
case 1:
case 2:
case 3:
case 4:
// Do something.
break;
case 5:
case 6:
case 7:
case 8:
// Do something.
break;
default:
break;
}

use this, if you dont provide break then control will fall down, In this way you can match for group of numbers in switch.
case 10:
case 11:
case 12:
case 14:
case 15: document.write("i am less than or equal to 15");break;

Say you wanted to switch on a number 10-14 (10,11,12,13,14) you can chain the cases together:
switch(number) {
case 10:
case 11:
case 12:
case 13:
case 14:
alert("I'm between 10 and 14");
break;
default:
alert("I'm not between 10 and 14");
break;
}

You can simply omit the break; statement.
switch (2) {
case 1: case 2: case 3:
console.log('1 or 2 or 3');
break;
default:
console.log('others');
break;
}
I wanted to play with the concept a bit, I do not recommend this approach, however you could also rely on a function that will create a control flow function for you. This simply allows some syntaxic sugar.
var createCaseFlow = (function () {
var rangeRx = /^(\d)-(\d)$/;
function buildCases(item) {
var match = item.match(rangeRx),
n1, n2, cases;
if (match) {
n1 = parseInt(match[1], 10);
n2 = parseInt(match[2], 10);
cases = [];
for (; n1 <= n2; n1++) {
cases.push("case '" + n1 + "':");
}
return cases.join('');
}
return "case '" + item + "':";
}
return function (cases, defaultFn) {
var fnStrings = ['switch (value.toString()) { '],
k;
for (k in cases) {
if (cases.hasOwnProperty(k)) {
fnStrings.push(k.split(',').map(buildCases).join('') + "return this[0]['" + k + "'](); break;");
}
}
defaultFn && fnStrings.push('default: return this[1](); break;');
return new Function('value', fnStrings.join('') + '}').bind(arguments);
};
})();
var executeFlow = createCaseFlow({
'2-9': function () {
return '2 to 9';
},
'10,21,24': function () {
return '10,21,24';
}
},
function () {
return 'default case';
}
);
console.log(executeFlow(5)); //2 to 9
console.log(executeFlow(10)); //10,21,24
console.log(executeFlow(13)); //default case

You have already gotten a few answers on how to make this work. However, I want to point out a few more things. First off, personally, I wouldn't use a switch/case statement for this as there are so many similar cases – a classic if/elseif/else chain feels more appropriate here.
Depending on the use-case you could also extract a function and then use your switch/case (with more meaningful names and values, of course):
function getCategory (number) {
if(number > 20) {
return 3;
}
if(number > 15) {
return 2;
}
if(number > 8) {
return 1;
}
return 0;
}
switch( getCategory( someNumber ) ) {
case 0:
// someNumber is less than or equal to 8
break;
case 1:
// someNumber is any of 9, 10, 11, 12, 13, 14, 15
break;
// ...
}
If the intervals are equally spaced, you could also do something like this:
switch( Math.floor( someNumber / 5 ) ) {
case 0:
// someNumber is any one of 0, 1, 2, 3, 4
break;
case 1:
// someNumber is any one of 5, 6, 7, 8, 9
break;
// ...
}
Also, it should be noted that some people consider switch/case statements with fall-throughs (= leaving out the break; statement for come cases) bad practice, though others feel it's perfectly fine.