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How to convert Seconds to Time in Javascript

I have to convert seconds to time format:
seconds_1 = 540;
seconds_2 = -2820;
convert_1 = new Date(seconds_1 * 1000).toISOString().substr(11, 8);
convert_2 = new Date(seconds_2 * 1000).toISOString().substr(11, 8);
console.log(convert_1);
console.log(convert_2);
it will return,
convert_1 : 00:09:00
convert_2 : 23:13:00
first one (convert_1) is correct, but the second one should return -00:47:00 .
The Actual issue is, the negative value is not converting to time correctly.
Please help.
I tried this,
function toTime(duration) {
// Hours, minutes and seconds
var hrs = ~~(duration / 3600);
var mins = ~~((duration % 3600) / 60);
var secs = ~~duration % 60;
let ret = hrs+ ":" + mins + ":" + secs;
return ret;
}
seconds_1 = 540;
seconds_2 = -2820;
console.log(toTime(seconds_2 ));

A pragmatic solution is to remove the sign and then add it again:
function toTime(seconds) {
if (seconds < 0) return "-" + toTime(-seconds);
return new Date(seconds * 1000).toISOString().substr(11, 8);
}
console.log(toTime(540));
console.log(toTime(-2820));

Just test
const convert = secs => {
const sign = secs < 0
const hhmmss = new Date(Math.abs(secs) * 1000).toISOString().substr(11, 8);
return sign ? '-' + hhmmss : hhmmss
}
console.log(convert(540));
console.log(convert(-2820));

How can I do sum two time values in javascript

I've been trying to implement the function that sums two values as hours.
"Example: 01:30 + 00:30 = 02:00"
So I have this function below that works only if the sum of the two values is equal to a round number such as the example above. But the problem is when the values are say 01:45 + 00:20 it gives me 33:05 instead of 02:05.
I've tried several combinations but nothing has worked so far.
function sumOFHoursWorked(){
var time1 = "00:45";
var time2 = "01:20";
var hour=0;
var minute=0;
var second=0;
var splitTime1= time1.split(':');
var splitTime2= time2.split(':');
hour = parseInt(splitTime1[0])+parseInt(splitTime2[0]);
minute = parseInt(splitTime1[1])+parseInt(splitTime2[1]);
hour = hour + minute/60;
minute = minute%60;
second = parseInt(splitTime1[2])+parseInt(splitTime2[2]);
minute = minute + second/60;
second = second%60;
var REalhourstime = ('0' + hour).slice(-2)+':'+('0' + minute).slice(-2);
alert(REalhourstime);
document.getElementById('realhorasTB').innerHTML = REalhourstime;
}

It actually depends on how your time will be, i mean it will be in mm:ss formet or hh:mm:ss or maybe hh:mm:ss:msms but for just simple second and minutes you can do something like this
function sumOFHoursWorked(){
var time1 = "00:45".split(':');
var time2 = "01:20".split(':');
let secondSum = Number(time1[1]) + Number(time2[1]);
let minSum = Number(time1[0]) + Number(time2[0]);
if(secondSum > 59){
secondSum = Math.abs(60 - secondSum);
minSum += 1;
}
if(secondSum < 10){
secondSum = `0${secondSum}`;
}
if(minSum < 10){
minSum = `0${minSum}`;
}
return `${minSum}:${secondSum}`;
}
console.log(sumOFHoursWorked());

I would convert it to minutes and subtract and then calculate hours and minutes.
function totalMinutes (time) {
var parts = time.split(":")
return +parts[0] * 60 + +parts[1]
}
function timeDiff (time1, time2) {
var mins1 = totalMinutes(time1)
var mins2 = totalMinutes(time2)
var diff = mins2 - mins1
var hours = '0' + (Math.floor(diff/60))
var minutes = '0' + (diff - hours * 60)
return (hours.slice(-2) + ':' + minutes.slice(-2))
}
console.log(timeDiff("00:45", "01:20"))
It will fail for times that go over midnight, a simple less than check can fix that.
function totalMinutes (time) {
var parts = time.split(":")
return +parts[0] * 60 + +parts[1]
}
function timeDiff (time1, time2) {
var mins1 = totalMinutes(time1)
var mins2 = totalMinutes(time2)
if (mins2 < mins1) {
mins2 += 1440
}
var diff = mins2 - mins1
var hours = '0' + (Math.floor(diff/60))
var minutes = '0' + (diff - hours * 60)
return (hours.slice(-2) + ':' + minutes.slice(-2))
}
console.log(timeDiff("23:45", "00:45"))

First of all, the time1 and time2 strings are missing the seconds at the end. For example, var time1 = "00:45:00". Otherwise, your calculation will have some NaN values.
The main issue is that hour is a floating point number (~ 2.083333333333333), so ('0' + hour) is '02.083333333333333'.
You could use something like this instead: ('0' + Math.floor(hour)).

CALCULATING TIME in javascript

I am using this formula to calculate time between 2 different fields but result is in whole numbers and I need hours/minutes
time after dateFromString is example
var date1 = dateFromString(06: 00: 00);
var date2 = dateFromString(17: 30: 00);
var hours = Math.abs(date1 - date2) / 36e5;
return hours;
function dateFromString(isoDateString) {
var parts = isoDateString.match(/\d+/g);
var isoTime = Date.UTC(parts[0], parts[1] - 1, parts[2], parts[3], parts[4], parts[5]);
var isoDate = new Date(isoTime);
return isoDate;
}

Your code has some syntax errors, but try this, it should give you the time difference in an hours:minutes format:
var startTime = '06:00:00';
var endTime = '17:30:00';
var timeStart = new Date("01/01/2007 " + startTime);
var timeEnd = new Date("01/01/2007 " + endTime);
var minutesDiff = diff_minutes(timeStart, timeEnd);
var hoursAndMinsDiff = convertMinsToHrsMins(minutesDiff);
console.log(hoursAndMinsDiff)
function diff_minutes(dt2, dt1) {
var diff = (dt2.getTime() - dt1.getTime()) / 1000;
diff /= 60;
return Math.abs(Math.round(diff));
}
function convertMinsToHrsMins(mins) {
let h = Math.floor(mins / 60);
let m = mins % 60;
h = h < 10 ? '0' + h : h;
m = m < 10 ? '0' + m : m;
return `${h}:${m}`;
}
Is that what you're looking for?

Use division to get the hours, and then get the minutes using the remainder operation.
Also, dateFromString() expects the string to have both the date and time, not just a time, and it needs to be a quoted string.
var date1 = dateFromString("2018-12-01 06:00:00");
var date2 = dateFromString("2018-11-30 17:30:00");
var diffmin = Math.floor(Math.abs(date1 - date2) / 60000);
var hours = Math.floor(diffmin/60);
var minutes = diffmin % 60;
console.log(hours, minutes);
function dateFromString(isoDateString) {
var parts = isoDateString.match(/\d+/g);
var isoTime = Date.UTC(parts[0], parts[1] - 1, parts[2], parts[3], parts[4], parts[5]);
var isoDate = new Date(isoTime);
return isoDate;
}

calculate time difference between two date in HH:MM:SS javascript

I have created one timer application in javascript.
Firstly it takes the current UTC date to init timer with some reference. here's the code
on_timer: function(e) {
var self = this;
if ($(e.target).hasClass("pt_timer_start")) {
var current_date = this.get_current_UTCDate();
this.project_timesheet_db.set_current_timer_activity({date: current_date});
this.start_interval();
this.initialize_timer();
this.$el.find(".pt_timer_start,.pt_timer_stop").toggleClass("o_hidden");
Now, Once timer is started and after some time span timer has some elapsed time with reference to above on_timer: function(e) function.
This function is
start_interval: function() {
var timer_activity = this.project_timesheet_db.get_current_timer_activity();
var self = this;
this.intervalTimer = setInterval(function(){
self.$el.find(".pt_duration").each(function() {
var el_hour = $(this).find("span.hours");
var el_minute = $(this).find("span.minutes");
var minute = parseInt(el_minute.text());
if(minute >= 60) {
el_hour.text(_.str.sprintf("%02d", parseInt(el_hour.text()) + 1));
minute = 0;
}
el_minute.text(_.str.sprintf("%02d", minute));
var el_second = $(this).find("span.seconds");
var seconds = parseInt(el_second.text()) + 1;
if(seconds > 60) {
el_minute.text(_.str.sprintf("%02d", parseInt(el_minute.text()) + 1));
seconds = 0;
}
el_second.text(_.str.sprintf("%02d", seconds));
});
}, 1000);
},
Now, considering el_hour, el_minute, el_seconds How to can i count time difference between init time and current timer value in HH:MM:SS manner.
thanks in advance for help

To convert H:M:S to seconds, you can use a simple function like:
// Convert H:M:S to seconds
// Seconds are optional (i.e. n:n is treated as h:s)
function hmsToSeconds(s) {
var b = s.split(':');
return b[0]*3600 + b[1]*60 + (+b[2] || 0);
}
Then to convert seconds back to HMS:
// Convert seconds to hh:mm:ss
// Allow for -ve time values
function secondsToHMS(secs) {
function z(n){return (n<10?'0':'') + n;}
var sign = secs < 0? '-':'';
secs = Math.abs(secs);
return sign + z(secs/3600 |0) + ':' + z((secs%3600) / 60 |0) + ':' + z(secs%60);
}
var a = '01:43:28';
var b = '12:22:46';
console.log(secondsToHMS(hmsToSeconds(a) - hmsToSeconds(b))); // -10:39:18
console.log(secondsToHMS(hmsToSeconds(b) - hmsToSeconds(a))); // 10:39:18
You may want to abbreviate the function names to say:
toHMS(toSec(a) - toSec(b)); // -10:39:18
Note that this doesn't cover where the time may cross a daylight saving boundary. For that you need fully qualified dates that include the year, month and day. Use the values to create date objects, find the difference, convert to seconds and use the secondsToHMS function.
Edit
The question title mentions dates, however the content only seems to mention strings of hours, minutes and seconds.
If you have Date objects, you can get the difference between them in milliseconds using:
var diffMilliseconds = date0 - date1;
and convert to seconds:
var diffSeconds = diffMilliseconds / 1000;
and present as HH:MM:SS using the secondsToHMS function above:
secondsToHMS((date0 - date1) / 1000);
e.g.
var d0 = new Date(2014,10,10,1,43,28);
var d1 = new Date(2014,10,10,12,22,46);
console.log( secondsToHMS((d0 - d1) / 1000)); // -10:39:18

I think there is a simpler solution.
function dateDiffToString(a, b){
// make checks to make sure a and b are not null
// and that they are date | integers types
diff = Math.abs(a - b);
ms = diff % 1000;
diff = (diff - ms) / 1000
ss = diff % 60;
diff = (diff - ss) / 60
mm = diff % 60;
diff = (diff - mm) / 60
hh = diff % 24;
days = (diff - hh) / 24
return days + ":" + hh+":"+mm+":"+ss+"."+ms;
}
var today = new Date()
var yest = new Date()
yest = yest.setDate(today.getDate()-1)
console.log(dateDiffToString(yest, today))

const dateDiffToString = (a, b) => {
let diff = Math.abs(a - b);
let ms = diff % 1000;
diff = (diff - ms) / 1000;
let s = diff % 60;
diff = (diff - s) / 60;
let m = diff % 60;
diff = (diff - m) / 60;
let h = diff;
let ss = s <= 9 && s >= 0 ? `0${s}` : s;
let mm = m <= 9 && m >= 0 ? `0${m}` : m;
let hh = h <= 9 && h >= 0 ? `0${h}` : h;
return hh + ':' + mm + ':' + ss;
};

This may be the simple answer
var d1 = new Date(2014,10,11,1,43,28);
var d2 = new Date(2014,10,11,2,53,58);
var date = new Date(d2-d1);
var hour = date.getUTCHours();
var min = date.getUTCMinutes();
var sec = date.getUTCSeconds();
var day = date.getUTCDate() - 1;
console.log(day + ":" + hour + ":" + min + ":" + sec)

More intuitive and easier to read.
function hmsToSeconds(t) {
const [hours, minutes, seconds] = t.split(':')
return Number(hours) * 60 * 60 + Number(minutes) * 60 + Number(seconds)
}
function secondsToHMS(secs) {
return new Date(secs * 1000).toISOString().substr(11, 8)
}
var startTime = '01:43:28';
var endTime = '12:22:46';
console.log(secondsToHMS(hmsToSeconds(endTime) - hmsToSeconds(startTime))); //10:39:18

show time in HH:MM only in this javascript code [duplicate]

This question already has answers here:
Current time formatting with Javascript
(16 answers)
Closed 8 years ago.
The following JS shows the time in HH:MM:SS format while I need it to show HH:MM only
setInterval(function() {
var d = new Date();
var t = d.getTime();
var interval = 5*60*1000;
var last = t - t % interval;
var next = last + interval + 10*60000;
d.setTime(next);
var time = d.toLocaleTimeString();
$(".clock").html(time);
}, 1000);
Any idea on how to achieve that?
Fiddle: http://jsfiddle.net/7z9boag8/

There's getHours() and getMinuets() methods available.
example:
http://jsfiddle.net/0todu2y7/
jQuery(function($) {
setInterval(function() {
var d = new Date();
var t = d.getTime();
var interval = 5*60*1000;
var last = t - t % interval;
var nextt = last + interval + 5*60000;
d.setTime(nextt);
var hours = d.getHours();
var min = d.getMinutes();
$(".clock").html(hours+":"+min);
}, 1000);
});

i am sorry . i m not edit your code . i just give you another procedure
String.prototype.toHHMMSS = function () {
var sec_num = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(sec_num / 3600);
var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
var seconds = sec_num - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
var time = hours+':'+minutes+':'+seconds;
return time;
}
Second Formula is
function checkTime(i) {
if (i < 10) {
i = "0" + i;
}
return i;
}
function yourTime() {
var today = new Date();
var h = today.getHours();
var m = today.getMinutes();
var s = today.getSeconds();
// add a zero in front of numbers<10
m = checkTime(m);
s = checkTime(s);
document.getElementById('time').innerHTML = h + ":" + m + ":" + s;
t = setTimeout(function () {
startTime()
}, 500);
}
yourTime();

Try this:
var time = d.toLocaleTimeString().match(/(\d+:\d+):\d+( \w{2})*/);
var time = time[1] + (time[2] ? time[2] : "");

setInterval(function() {
var d = new Date();
var t = d.getTime();
var interval = 5*60*1000;
var last = t - t % interval;
var next = last + interval + 10*60000;
d.setTime(next);
var time = d.toLocaleTimeString().split(':')
time.pop()
time.join(':')
$(".clock").html(time);
}, 60000);
I don't think that u shuold run tins function every second. U may do it once in minute.