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How can I execute a query on success of jQuery

I am using jQuery to delete some data from database. I want some functionality that when jQuery returns success I want to execute a query. I want to update a another table on success of jQuery without page refresh. Can I do this and if yes how can I do this?
I am newbie to jQuery so please don't mind if it's not a good question for stackoverflow.
This is my script:
<script type="text/javascript">
$(document).ready(function () {
function delete_comment(autoid, btn_primary_ref) {
$.ajax({
url: 'rootbase.php?do=task_manager&element=delete_comment',
type: "POST",
dataType: 'html',
data: {
autoid: autoid
},
success: function (data) {
// I want to execute the Update Query Here
alert("Comment Deleted Successfully");
$(btn_primary_ref).parent().parent().hide();
var first_visible_comment = $(btn_primary_ref).parent().parent().parent().children().find('div:visible:first').eq(0).children('label').text();
if (first_visible_comment == "") {} else {
$(btn_primary_ref).parent().parent().parent().parent().parent().parent().prev().children().text(first_visible_comment);
}
load_comment_function_submit_button(autoid, btn_primary_ref);
},
});
}
$(document).on('click', '.delete_user_comment', function (event) {
var autoid = $(this).attr('id');
var btn_primary_ref = $(this);
var r = confirm("Are you sure to delete a comment");
if (r == true) {
delete_comment(autoid, btn_primary_ref);
} else {
return false;
}
});
});
</script>

You can't do database operations directly in Javascript. What you need to do is to simply make a new AJAX request on success to a php file on the backend to update given table. However this would mean two AJAX requests to the backend, both of which manages database data. Seems a bit unnecessary. Why not just do the update operation after the delete operation in the php file itself?

add a server sided coded page that will execute your query.
example :
lets say you add a page named executequery.php.
with this code:
when you want to execute your query do the following :
$.post("executequery.php",//the URL of the page
{
param1:value1,
param2:value2....//if you want to pass some parameters to the page if not set it to null or {}
},
function(data){
//this is the callback that get executed after the page finished executing the code in it
//the "data" variable contain what the page returened
}
);
PS : tha paramters sent to the page are conidired like $_POST variables in the php page
there is an other solution but its UNSAFE i recomand to NOT use it.
its to send the query with the paramters and that way you can execute the any query with the same page example :
$.post("executequery.php",//the URL of the page
{
query:"insert into table values("
param1:value1,
param2:value2....//if you want to pass some parameters to the page if not set it to null or {}
},
function(data){});

How to export a model function from a controller to a view in Laravel 4

I am trying to display some data from my database that is dependent on some input from the user. I am using an ajax request to get the data, send it back to a function in my controller, and then export it back to my view. I would like to collect this data and display it without going to another view (I just hide the previous form and unhide the new form).
Here is the relevant code:
Javascript:
$('#submit_one').on('click', function(event) {
event.preventDefault();
if(! $(this).hasClass('faded')) {
var fbid = $("input[name='like']:checked").val();
//variable to be collected is fbid
request = $.ajax({
url: "http://crowdtest.dev:8888/fans/pick_favorite",
type: "post", success:function(data){},
data: {'fbid': fbid} ,beforeSend: function(data){
console.log(data);
}
});
to_welcome_two();
}
});
function to_welcome_two()
{
$('#welcome_one').addClass('hidden');
$('#welcome_two').removeClass('hidden');
}
Controller functions:
public function pick_favorite() {
$fbid=Input::get('fbid');
return Artist::specific_artist($fbid);
}
public function getWelcome() {
return View::make('fans.welcome')
->with('artists', Artist::artists_all())
->with('favorite_artist', Artist::favorite_artist())
->with('pick', FansController::pick_favorite());
}
Model function:
public static function specific_artist($fbid) {
$specific_artist = DB::table('artists')
->where('artists.fbid', '=', $fbid)
->get();
return $specific_artist;
}
The view is on the "welcome" page. My question is how do I display the model data in my view and make sure it is printing out the correct data from the fbid input?
I tried something like this:
#foreach($pick as $p)
<span class="artist_text">{{$p->stage_name}}</span>
<br>
<span class="artist_city">{{$p->city}}</span>
#endforeach
but this is not printing out anything. Any ideas?

i see lots of issues here.
Server side:
public function pick_favorite().... what does it do? it just returns some data.
in public function getWelcome() { , you wrote, FansController::pick_favorite(). supposing both are the same method, you are accessing a static method whilst the method is non static. you are getting an error for this but you are not seeing it because you didn't define fail().
and i don't see what the point of declaring a method which does nothing else then a model call which you can do directly.
e.g let's say i have a fooModel
public function index(){}
in controller, i can just write,
public function bar()
{
$model = new fooModel;
return View::make(array('param1'=>$model->index()));
}
or if i declare index() method in fooModel as static, then i can write,
public function bar()
{
return View::make(array('param1'=>fooModel::index()));
}
Client side:
now in your javascript,
$('#submit_one').on('click', function(event) {
event.preventDefault();
if(! $(this).hasClass('faded')) {
var fbid = $("input[name='like']:checked").val();
//variable to be collected is fbid
request = $.ajax({
url: "http://crowdtest.dev:8888/fans/pick_favorite",
type: "post", success:function(data){},
data: {'fbid': fbid} ,beforeSend: function(data){
console.log(data);
}
});
to_welcome_two();
}
});
function to_welcome_two()
{
$('#welcome_one').addClass('hidden');
$('#welcome_two').removeClass('hidden');
}
why it should print any data? you didn't asked the script to print anything. where is your .done or .success param in your code?
If you look at your console, you'l get lots of php errors, i am almost sure of.
an advice, you need to lear some basics. e.g. jquery ajax call.
a basic ajax call can be
var request = $.ajax({
url: "script.php",
type: "POST",
data: { id : menuId },
dataType: "html"
});
request.done(function( msg ) {
$( "#log" ).html( msg );
});
request.fail(function( jqXHR, textStatus ) {
alert( "Request failed: " + textStatus );
});
implement it in your code and then see what errors it throws.
Conclusion:
1st one will be (supposing rest of your codes are ok) the static error. if you want to call it as static, declare it as static. but a static function in controller? i don't see any purpose of it.
and then start the debug. your problem is both client and server side. deal one by one.

Reading a input email address from html and using in JSP scriplet

Hi I have an html field that takes an email. I would like to take the entered value and ensure it exists in the database before proceeding.
<script>
function updateUserData()
{
document.getElementById(picker_email).value;
alert( "INVALID EMAIL ");
}
</script>
Is there anyway I can pass the picker_email to the JSP...so the outcome would be :
...
value = document.getElementById(picker_email).value;
<%
DatabaseHelper db_h = new DatabaseHelper();
boolean email_exists = db_h.verifyEmail( value );
%>
if( <%email_exists%> )
proceedToServlet();
else
alert( "INVALID EMAIL ");
Any help would be greatly appreciated.

#user2747139 developerwjk is correct. Why don't you try some ajax call to server. Writing scriptlet in jsp (Especially for server oriented purpose) is not a good practice. Here is some snippet. All you need to do is include jquery plugin in your jsp page. You can try like this,
function updateUserData(){
var value = $("#picker_email").val();
$.ajax({
url: "ur_servlet_url&value="+value,
type: "POST",
success: function(data){
//If you want to return anything in jsp.
alert("Invalid Email");
}
});
}
You do your validation in server side. If the validation succeeds/not succeeds return some text like success or failure. Based on this you will get response data in ajax. You can do alert if(data == 'failure') then alert('Invalid Email');. Let me know if this helps.

submit a form with jQuery function

i have a html page, which contains a form and i want when the form is successfully submited, show the below div:
<div class="response" style="display: none;">
<p>you can download ithere</p>
</div>
i also have a jquery function:
<script type="text/javascript">
$(function() {
$('#sendButton').click(function(e) {
e.preventDefault();
var temp = $("#backupSubmit").serialize();
validateForm();
$.ajax({
type: "POST",
data: temp,
url: 'backup/',
success: function(data) {
$(".response").show();
}
});
});
});
</script>
and in my views.py (code behind) i create a link and pass it to html page. i have:
def backup(request):
if request.is_ajax():
if request.method=='POST':
//create a link that user can download a file from it. (link)
variables = RequestContext(request,{'link':link})
return render_to_response('backup.html',variables)
else:
return render_to_response('backup.html')
else:
return render_to_response("show.html", {
'str': "bad Request! :(",
}, context_instance=RequestContext(request))
backup = login_required(backup)
my problem: it seems that my view doesn't execute. it doesn't show me the link that i send to this page. it seems that only jQuery function is executed. i'm confused. how can i make both of them to execute(i mean jQuery function and then the url i set in this function which make my view to be executed.)
i don't know how to use serialize function. whenever i searched, they wrote that:
The .serialize() method creates a text string in standard URL-encoded notation and produces query string like "a=1&b=2&c=3&d=4&e=5.
i don't know when i have to use it, while i can access to my form field in request.Post["field name"]. and i don't know what should be the data which is in success: function(data) in my situation.
thank very much for your help.

You have to get and display the data from your ajax post function, where data is the response you render through your DJango server, for example:
t = Template("{{ link }}")
c = Context({"link": link})
t.render(c):
Your JS / jQuery should become something like this:
<script type="text/javascript">
$(function() {
$('#sendButton').click(function(e) {
e.preventDefault();
var temp = $("#backupSubmit").serialize();
validateForm();
$.ajax({
type: "POST",
data: temp,
url: 'backup/',
success: function(data) {
// 'data' is the response from your server
// (=the link you want to generate from the server)
// Append the resulting link 'data' to your DIV '.response'
$(".response").html('<p>you can download ithere</p>');
$(".response").show();
}
});
});
});
</script>
Hope this helps.

Calling ASP.NET MVC Action Methods from JavaScript

I have sample code like this:
<div class="cart">
<a onclick="addToCart('#Model.productId');" class="button"><span>Add to Cart</span></a>
</div>
<div class="wishlist">
<a onclick="addToWishList('#Model.productId');">Add to Wish List</a>
</div>
<div class="compare">
<a onclick="addToCompare('#Model.productId');">Add to Compare</a>
</div>
How can I write JavaScript code to call the controller action method?

Use jQuery ajax:
function AddToCart(id)
{
$.ajax({
url: 'urlToController',
data: { id: id }
}).done(function() {
alert('Added');
});
}
http://api.jquery.com/jQuery.ajax/

Simply call your Action Method by using Javascript as shown below:
var id = model.Id; //if you want to pass an Id parameter
window.location.href = '#Url.Action("Action", "Controller")/' + id;

You are calling the addToCart method and passing the product id. Now you may use jQuery ajax to pass that data to your server side action method.d
jQuery post is the short version of jQuery ajax.
function addToCart(id)
{
$.post('#Url.Action("Add","Cart")',{id:id } function(data) {
//do whatever with the result.
});
}
If you want more options like success callbacks and error handling, use jQuery ajax,
function addToCart(id)
{
$.ajax({
url: '#Url.Action("Add","Cart")',
data: { id: id },
success: function(data){
//call is successfully completed and we got result in data
},
error:function (xhr, ajaxOptions, thrownError){
//some errror, some show err msg to user and log the error
alert(xhr.responseText);
}
});
}
When making ajax calls, I strongly recommend using the Html helper method such as Url.Action to generate the path to your action methods.
This will work if your code is in a razor view because Url.Action will be executed by razor at server side and that c# expression will be replaced with the correct relative path. But if you are using your jQuery code in your external js file, You may consider the approach mentioned in this answer.

If you do not need much customization and seek for simpleness, you can do it with built-in way - AjaxExtensions.ActionLink method.
<div class="cart">
#Ajax.ActionLink("Add To Cart", "AddToCart", new { productId = Model.productId }, new AjaxOptions() { HttpMethod = "Post" });
</div>
That MSDN link is must-read for all the possible overloads of this method and parameters of AjaxOptions class. Actually, you can use confirmation, change http method, set OnSuccess and OnFailure clients scripts and so on

If you want to call an action from your JavaScript, one way is to embed your JavaScript code, inside your view (.cshtml file for example), and then, use Razor, to create a URL of that action:
$(function(){
$('#sampleDiv').click(function(){
/*
While this code is JavaScript, but because it's embedded inside
a cshtml file, we can use Razor, and create the URL of the action
Don't forget to add '' around the url because it has to become a
valid string in the final webpage
*/
var url = '#Url.Action("ActionName", "Controller")';
});
});

Javascript Function
function AddToCart(id) {
$.ajax({
url: '#Url.Action("AddToCart", "ControllerName")',
type: 'GET',
dataType: 'json',
cache: false,
data: { 'id': id },
success: function (results) {
alert(results)
},
error: function () {
alert('Error occured');
}
});
}
Controller Method to call
[HttpGet]
public JsonResult AddToCart(string id)
{
string newId = id;
return Json(newId, JsonRequestBehavior.AllowGet);
}

You can simply add this when you are using same controller to redirect
var url = "YourActionName?parameterName=" + parameterValue;
window.location.href = url;

You can set up your element with
value="#model.productId"
and
onclick= addToWishList(this.value);

I am using this way, and worked perfectly:
//call controller funcntion from js
function insertDB(username,phone,email,code,filename) {
var formdata = new FormData(); //FormData object
//Iterating through each files selected in fileInput
formdata.append("username", username);
formdata.append("phone", phone);
formdata.append("email", email);
formdata.append("code", code);
formdata.append("filename", filename);
//Creating an XMLHttpRequest and sending
var xhr = new XMLHttpRequest();
xhr.open('POST', '/Home/InsertToDB');//controller/action
xhr.send(formdata);
xhr.onreadystatechange = function () {
if (xhr.readyState == 4 && xhr.status == 200) {
//if success
}
}
}
in Controller:
public void InsertToDB(string username, string phone, string email, string code, string filename)
{
//this.resumeRepository.Entity.Create(
// new Resume
// {
// }
// );
var resume_results = Request.Form.Keys;
resume_results.Add("");
}
you can find the keys (Request.Form.Keys), or use it directly from parameters.

You can easily make a <a> link in your view.
<a hidden asp-controller="Home" asp-action="Privacy" id="link"></a>
then in you javascript code use this:
location.href = document.getElementById('link').href;