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How do I detect submitted button with ajax and php?

I have a form on my front-end and when the submit button is clicked I want to send the details to my get-emp.php file without page reload.
The code looks like this:
index.html
<form class="form-emp-details hide" action="">
<div class="form-group">
<label for="">First name:</label>
<input type="text" class="form-control input-emp-firstname" name="input_emp_firstname">
</div>
<div class="form-group">
<label for="">Last name:</label>
<input type="text" class="form-control input-emp-lastname" name="input_emp_lastname">
</div>
<div class="form-group">
<label></label>
<button type="submit" class="btn btn-default btn-submit-1" name="submit_emp_details">Save</button>
</div>
</form>
custom.js
$(".form-emp-details").("submit", function(e) {
var input_first_name = $(".input-emp-firstname").val();
$.ajax({
type: "POST",
url: "get-emp.php",
data: {
input_emp_firstname:input_first_name,
},
success: function(data) {
console.log(data)
},
error: function(xhr,status,error) {
console.log(error);
}
});
});
get-emp.php
if(isset($_POST['submit_emp_details'])) {
$firstname = $_POST['input_emp_firstname'];
echo $firstname;
}
I want to display the submitted form data on get-emp.php file but it seems that I am not able to detect the submitted button and echo the form data on.
My goal is to capture all form data with a single request variable or identifier $_POST['submit_emp_details']
Any help is greatly appreciated. Thanks

$("#MyformId").submit(function(e) {
e.preventDefault();
var form = $(this);
var url = form.attr('action');
$.ajax({
type: "POST",
url: url,
data: form.serialize(),
success: function(data)
{
// success..
}
});
});

You passing the POST data of firstname and lastname by:
input_emp_firstname
input_emp_lastname
so, you need to change the $_POST['submit_emp_details'] to $_POST['input_emp_firstname'] on file get-emp.php to
<?php
if(isset($_POST['input_emp_firstname'])) {
$firstname = $_POST['input_emp_firstname'];
echo $firstname;
}
Edit 2:
$.ajax({
type: "POST",
url: "get-emp.php",
cache: false,
data: {
submit_emp_details: {
input_emp_firstname:input_first_name,
input_emp_lastname:input_last_name
}
},
success: function(data) {
console.log(data)
},
error: function(xhr,status,error) {
console.log(error);
}
});

Form submission using AJAX in Laravel 5.5

I am trying to submit a form using ajax in Laravel 5.5
The problem is the page is refreshing and not submitting data in the database. I need to store data in the database without refreshing the page.
Here is my code:
Controller
public function new_timing_table(Request $request)
{
if (Request::ajax()) {
$timing_tables = new Timing_Table;
$timing_tables->timing_tables_name = $request->timing_tables_name;
$timing_tables->save();
$msg = "yes";
} else {
$msg = "yes";
}
return ['msg'=> $msg];
}
View
<form id="timeForm" class="form-horizontal form-material" >
<div class="form-group">
{{ csrf_field() }}
<div class="col-md-12 m-b-20">
<label> Table Name</label>
<input type="text" id="timing_tables_name" class="form-control"
name="timing_tables_name" />
</div>
<div class="modal-footer">
<input type="button" value="Replace Message" id='btnSelector'>
</div>
</div>
</form>
Ajax script
const xCsrfToken = "{{ csrf_token() }}";
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': xCsrfToken
}
});
jQuery(document).ready(function() {
jQuery('#btnSelector').click(function(e) {
event.preventDefault();
getMessage();
});
});
var getMessage = function() {
var timing_tables_name = $("input[name=timing_tables_name]").val();
$.ajax({
type: 'post',
url: '/new_timing_table',
dataType: 'json', //Make sure your returning data type dffine as json
data: timing_tables_name,
//data:'_token = <php echo csrf_token() ?>',
success: function(data) {
console.log(data); //Please share cosnole data
if (data.msg) //Check the data.msg isset?
{
$("#msg").html(data.msg);
}
}
});
}
Router
Route::post('/new_timing_table','Timing_TableControoler#new_timing_table');

You got a typo or a mistake in your script.
jQuery('#btnSelector').click(function(e){
// An error here - it should be e.preventDefault();
event.preventDefault();
getMessage();
});

My code is working now after adding beforeSend: function (request) in Ajax script
var getMessage = function(){
var timing_tables_name = $("#timing_tables_name").val();
console.log(timing_tables_name);
$.ajax({
type:'GET',
url:'/new_timing_table', //Make sure your URL is correct
dataType: 'json', //Make sure your returning data type dffine as json
data:
{
timing_tables_name
},
beforeSend: function (request) {
return request.setRequestHeader('X-CSRF-Token', $("meta[name='csrf-
token']").attr('content'));
},
success:function(data){
console.log(data); //Please share cosnole data
if(data.msg) //Check the data.msg isset?
{
$("#msg").html(data.msg); //replace html by data.msg
}
}
});
}
and editing the controller to be simple as this one
public function new_timing_table(Request $request){
$timing_tables = new Timing_Table;
$timing_tables->timing_tables_name = $request->timing_tables_name;
$timing_tables->save();
$msg = "This is a simple message.";
return ['msg'=> $msg];
}
Thank you all for your help

Invisible google captcha v2 is not working properly

The following code is working fine when the form is submitted correctly with all valid data in the first attempt. If there is any server side error after submitting the form then when user resubmits the form the recaptcha does not reset.
Following is the sample code:
html-form
<script src="https://www.google.com/recaptcha/api.js"></script>
<div>
<form name="signupForm" method="POST" action="/signup">
<div class="form-group mobile-number">
<input type="tel" id="mobileNo" class="form-control" name="mobileNumber" maxlength="10"
autofocus>
<label for="mobile"> Your Mobile no. </label>
</div>
<div class="g-recaptcha"
data-sitekey="{key}"
data-callback="setResponse"
data-badge="inline"
data-size="invisible">
</div>
<input type="hidden" id="captcha-response" name="captcha-response"/>
<button id="submitButon" type="submit">Sign me up!</button>
</form>
</div>
javascript
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<script>
function setResponse(response) {
document.getElementById('captcha-response').value = response;
submitForm();
}
function submitForm() {
var $form = $("form");
var data = JSON.stringify($form.serializeObject());
var myJsonObject = JSON.parse(data);
data = JSON.stringify(myJsonObject);
$.ajax({
type: "POST",
url: "dummy url",
contentType: "application/json",
xhrFields: {withCredentials: true},
data: data,
success: function (data, textStatus, request) {
// success
},
error: function (xhr, err) {
// logics here
grecaptcha.execute();
setResponse;
}
});
}
</script>
<script>
jQuery(document).ready(function () {
//homepage form
$('form[name="signupForm"]').validate({
onfocusout: function (element) {
$(element).valid();
},
rules: {
mobileNumber: {
required: true,
minlength: 10,
maxlength: 10
}
},
// Specify validation error messages
messages: {
mobileNumber: "A valid mobile number is of 10-digit",
},
//submit handler
submitHandler: function (form) {
submitForm();
}
});
});
</script>
I think the error is in ajax call but not able to figure out why the captcha is not resetting again.

How to validate data in an AJAX call

I am trying to call data from a PHP file where it takes the data entered and tells if it is validated or not. How do you do this in the javascript file using an AJAX call?
$("#PersonForm").submit(function()
{
$.ajax({
url: 'backend.php', type: 'post', data: { act:'validate'},
dataType: 'json',
function(result) {
if($validateData==1){
$('#success').html('validated');
}
else{
$('#errors').html('Not Correct');
}
}
//});
});
return false;
});
Here is the PHP file
<?php
if ($_REQUEST['act'] == 'validate')
{
$validateData = array();
if (preg_match("/^[A-Za-z]{3,20}$/",$_REQUEST['name'])) $validateData['name'] = 1;
else $validateData['name'] = 0;
if (preg_match("/^[0-9]{10}$/",$_REQUEST['phone'])) $validateData['phone'] = 1;
else $validateData['phone'] = 0;
if (preg_match("/^[A-Z][0-9][A-Z][0-9][A-Z][0-9]$/",
$_REQUEST['postal'])) $validateData['postal'] = 1;
else $validateData['postal'] = 0;
if (preg_match("/^[0-9]{3} [A-Za-z]{3,10} Street$/",
$_REQUEST['address'])) $validateData['address'] = 1;
else $validateData['address'] = 0;
echo json_encode($validateData);
}
else echo "Should not happen";
?>
HTML file:
<html>
<body>
<h1>Form Validation</h1>
<form id="PersonForm">
Name: <input type="text" id="name" name="name"> <br>
Postal Code: <input type="text" id="postal" name="postal"> <br>
Phone Number: <input type="text" id="phone" name="phone"> <br>
Address: <input type="text" id="address" name="address"> <br>
<input id="sub" type="submit">
</form>
Refresh
<a id="InsertDefault" href="">Insert Default Data</a>
<br>
<ul id="errors"></ul>
<p id="success"></p>
</body>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<script type="text/javascript" src="main.js"></script>
</html>

First, you're not sending the any of the inputs in your data: parameter. So $_REQUEST['name'], $_REQUEST['phone'], etc. won't exist.
Second, you can't access PHP variables in Javascript. The JSON that the PHP echoes at the end will be decoded into the result variable in the success: callback function.
Third, your syntax is wrong, the callback function needs to be in the success: option.
So it should be:
$("#PersonForm").submit(function()
{
$.ajax({
url: 'backend.php',
type: 'post',
data: 'act=validate&' + $(this).serialize(),
dataType: 'json',
success: function(result) {
if(result.name && result.phone && result.post && result.address){
$('#success').html('validated');
}
else{
$('#errors').html('Not Correct');
}
}
});
return false;
});

You should use the success and error callbacks so that you are waiting for the promise from the ajax call to come back. I am assuming you are trying to figure out how to get to the data that comes back. If you need further assistance with then validating the real data, I can help with that as well.
$.ajax({
url: 'backend.php', type: 'post', data: { act:'validate'},
dataType: 'json',
success: function (data) {
if($validateData==1){
$('#success').html('validated');
}
else{
$('#errors').html('Not Correct');
}
},
error: function (request, status, error) {
// Error occurred calling API
}
});

XML request from ajax form

Hello everyone I am newbie in java-script so i hope you can help me with my issue. So I have the form, it look something like this:
<form method="post">
Field1: <input type="text" name="field1"><br>
Field2: <input type="text" name="field2"><br>
<input type="submit" value="Submit">
</form>
I need to take data from the form and make xml request, the xml request should look like this
<root>
<header section>
<section>data</section>
</header section>
<data section>
<field1>data</field2>
<field2>data</field2>
</data section>
</root>
After that i have to display xml response on the page.
I made xml request
<script>
$('.button').click( function() {
$(".results").append("<ul></ul>");
$.ajax({
type: "GET",
dataType: 'xml',
url: 'response.xml',
success: function(xml) {
$(xml).find('root').each(function(){
var sField1 = $(this).find('field1').text();
var sField2 = $(this).find('field2').text();
$("<li></li>").html(sTitle + ", " + sPublisher).appendTo(".results ul");
});
},
error: function() {
alert("An error occurred while processing XML file.");
}
});
});
</script>
But I don't know how to take data from the form and make request. Can you help me with it? Thanks a lot.

// You can use jQuery to build XML document:
function buildXmlFromForm(form) {
var xml = $('<XMLDocument />');
xml.append (
$('<header-section />').append(
$('<section />').text('data')
)
).append (
$('<data-section />').append(
$('<field1 />').text(form.find("input[name='field1']").val())
).append(
$('<field2 />').text(form.find("input[name='field2']").val())
)
);
return xml.html();
}
// you should use POST or PUT method (not GET) to post xml-data to server side
$( "#form1" ).submit(function(event) {
event.preventDefault();
$("#results").append("<ul></ul>");
var xmlString = buildXmlFromForm($(this));
$("#xmlSrc").val(xmlString);
$.ajax({
type: "POST",
dataType: 'xml',
url: 'response.xml',
data: xmlString,
success: function(respData) {
$("<li></li>").html("ok: "+respData).appendTo("#results ul");
console.log(respData);
},
error: function(errorData) {
$("<li></li>").html("error: "+errorData.statusText).appendTo("#results ul");
console.log(errorData);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="post" id="form1">
Field1: <input type="text" name="field1" value="***v1***"><br/>
Field2: <input type="text" name="field2" value="***v2***"><br/><br/>
<input type="submit" value="Submit">
</form>
<hr/>
<textarea id="xmlSrc" cols="70" rows="5"></textarea>
<div id="results"/>

Try this:
serialize will return formData of current form
You must have unique identifier for your form to be used as querySelector
$('#myForm').on('submit', function(e) {
e.preventDefault();
var formData = $(this).serialize();
$(".results").append("<ul></ul>");
$.ajax({
type: "GET",
dataType: 'xml',
url: 'response.xml',
data: formData,
success: function(xml) {
$(xml).find('root').each(function() {
var sField1 = $(this).find('field1').text();
var sField2 = $(this).find('field2').text();
$("<li></li>").html(sTitle + ", " + sPublisher).appendTo(".results ul");
});
},
error: function() {
alert("An error occurred while processing XML file.");
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="post" id="myForm">
Field1:
<input type="text" name="field1">
<br>Field2:
<input type="text" name="field2">
<br>
<input type="submit" value="Submit">
</form>