I am struggling to make a simple ajax request. I have no idea why it doesn't work.
<script>
function checkdata() {
var reqdata = "aha";
alert(reqdata);
$.ajax({
type: "POST",
url: "https://example.com/cs/test.php",
data: reqdata,
cache: false,
success: function(returnedata) {
alert(returnedata);
}
}); //end of ajax
return true;
}
</script>
<input type="button" value="CheckData" onclick="checkdata();">
The file https://example.com/cs/test.php has one: echo "done"; which works properly. When I navigate to the page with the browser I see just "Done"
What is the problem here? Thanks.
Don't forget to include https://cdnjs.cloudflare.com/ajax/libs/jquery/3.1.1/jquery.min.js
your code will not work without this
here is something that worked ,, change your function declaration to match this
checkdata = function () {
var reqdata = "aha";
....
Related
On my website I am trying to basically generate a random code (which I will set up later) and then pass that code into a PHP file to later retrieve it when the client needs it. But my code just isn't working.
Here is the code:
Javascript/HTML:
function init() {
var code = "12345";
$.ajax({
type: 'POST',
url: 'codes.php',
data: { code: code},
success: function(response) {
$('#result').html(response);
}
});
}
PHP:
<?php
$code = $_POST['code'];
echo $code
?>
So what I understand that is supposed to happen is that the code is uploaded or 'posted' to the php file and then the #result is the echo $code. None of that happens and I have no idea.
Your code working perfect with some basic changes.
You need a html element with id 'result'.
And then you need to call your init() as per requirement.
<div id="result"></div>
<script>
function init() {
var code = "12345";
$.ajax({
type: 'POST',
url: 'codes.php',
data: { code: code},
success: function(response) {
$('#result').html(response);
}
});
}
init();
</script>
I tried this on my server in the head of my document, and it worked :)
I used on complete instead of on success.
<script type="text/javascript" src="https://code.jquery.com/jquery.min.js"></script>
<script>
function init() {
$.ajax({
type: "POST",
url: "codes.php",
data: {
'code': '12345'
},
complete: function(data){
document.getElementById("result").innerHTML = data.responseText
},
});
}
init();
</script>
with codes.php the same as you have :)
just a few notes:
Make sure you point your url to the correct file. You can check it by using the console network. Or you can simply print anything out, not just the $_POST data. e.g:
echo 'Test info';
Open browser developer panel, to see if is there any client code issue. For example, document with id 'result' existed, or you have not included jquery in. The developer console will tell you everything on the client side. For Chrome, check it out here https://developer.chrome.com/devtools
Have you actually called init() ?
The following code is not working for me and I don't know why...
this is my js code:
var getEventsFunctionScript = document.createElement('script');
getEventsFunctionScript.setAttribute('type', 'text/javascript');
getEventsFunctionScript.innerHTML = "function getEvents(){$.ajax({url:'myPHP_file.php',type:'post',data:{'ajaxData':'1'},success:function(response){alert('AJAX executed!!');}});}";
w.document.body.appendChild(getEventsFunctionScript);
this us my php code:
if (isset($_POST['ajaxData'])) {
exit;
}
My problem is that this is not working, Ajax is never executed (I never see the alert)
could someone give any idea about why this is not working?
thank you very much
You need to call your function afterwards:
getEventsFunctionScript.innerHTML = "function getEvents() {
$.ajax({
url: 'myPHP_file.php',
type: 'post',
data: {
'ajaxData': '1'
},
success: function (response) {
alert('AJAX executed!!');
}
});
}
getEvents();";
The title is quite self-explanatory: I need to read a HTML file through jQuery and store its contents into a string variable.
I tried using .load and $.get, but they wouldn't do what I needed.
This is the code I've tried so far, based on the comments below, but they didn't populate my template variable at all:
var template = "";
$.ajax({
url: 'includes/twig/image_box.twig',
type: 'get',
success: function(html) {
var twig = String(html);
template.concat(twig);
}
});
console.log(template);
AND:
var template = "";
var fileUrl = "includes/twig/image_box.twig";
jQuery.get(fileUrl).then(function(text, status, xhr){
var html = String(text);
template.concat(html);
// console.log(html); // WORKS!
});
console.log(template); // Does not work
It's weird why this isn't working. Weird for me at least. This is how I'd populate a variable in PHP so I've carried the same logic to JS. Maybe there is an alternative way?
P.S:V I've also tried all alternative ways, like concatenating with += and assigning inside the callback function to template with =, but nothing worked.
Thanks to the ones who are trying to help me!
Maybe you should try a AJAX request with $.ajax()
Check the jQuery API here
$.ajax({
url: 'yourHTMLfile.html',
type: 'get',
async: false,
success: function(html) {
console.log(html); // here you'll store the html in a string if you want
}
});
DEMO
EDIT: Added a demo!
I reread your question and I noticed you're calling the console log right above the ajax request but you forgot the ajax is asynchronous that means the page will do a request and only will set the template value when the response return with success(if it returns). So the console.log(template) don't appears because it may be not loaded yet.
var template = "";
$.ajax({
url: 'includes/twig/image_box.twig',
type: 'get',
success: function(html) {
var twig = String(html);
template.concat(twig);
console.log(template); // the change!
}
});
or
$.ajax({
url: 'includes/twig/image_box.twig',
type: 'get',
async: false,
success: function(html) {
var twig = String(html);
template.concat(twig);
}
});
console.log(template); // the change!
You can try this:
//as you see I have used this very page's url to test and you should replace it
var fileUrl = "/questions/20400076/reading-a-file-into-a-string-in-jquery-js";
jQuery.get(fileUrl).then(function(text, status, xhr){
//text argument is what you want
});
and if it won't work try if your browser can open the file. if it could you'd better try ajax method in jQuery if not you might have some problems regarding permissions or somethings like that in you application server.
I am trying to add users to a database using jquery ajax calls. The users get added just fine to the database, but the ajax always returns with error. I'm not sure how to retrieve the specific error either. Below is my code, form, php, and jquery.
Here is the jquery
$(document).ready(function() {
//ajax call for all forms.
$('.button').click(function() {
var form = $(this).closest('form');
$.ajax({
type: "POST",
url: form.attr('data'),
dataType: 'json',
data: form.serialize(),
success: function (response) {
alert('something');
},
error: function() {
alert('fail');
}
});
});
});
Here is the PHP
<?php
include 'class_lib.php';
if(isset($_POST['username'])) {
$user = new Users;
$user->cleanInput($_POST['username'], $_POST['password']);
if($user->insertUser()) {
echo json_encode('true');
} else {
echo json_encode('false');
}
}
Here is the HTML
<div id='newUser' class='tool'>
<h3>New User</h3>
<form method='post' name='newUser' data='../php/newUser.php'>
<span>Username</span><input type='text' name='username'><br>
<span>Password</span><input type='password' name='password'>
<input type='submit' name='submit' class='button' style='visibility: hidden'>
</form>
<span class='result'> </span>
</div>
#Musa, above you mentioned
My guess is its a parsing error, try removing dataType: 'json', and see if it works
You absolutely solved the problem I was having! My ajax post request was similar to above and it just kept returning to the 'error' section. Although I checked using firebug, the status was 200(ok) and there were no errors.
removing 'dataType:json' solved this issue for me. Thanks a lot!
Turns out I had to add async: false to the $.ajax function. It wasn't getting a response back from the php.
I know this is an old question but I have just run into a weird situation like this ( jquery ajax returns success when directly executed, but returns error when attached to button, even though server response is 200 OK )
And found that having the button inside the form tags caused JQuery to always return error. Simply changing the form tags to div solved the problem.
I believe JQuery assumes the communication should be form encoded, even though you say it is application/json.
Try moving your button outside your form and see what happens...
I had the same problem and discovery there. All the time the problem is the version of my jQuery, I had use jquery version (jquery-1.10.2.js) but this version is not Ajax stablish. So, I change version for (jquery-1.8.2.js) and this miracle heppened.
Good Luck Guy!
You should specify status Code 200 for successful response.
<?php
http_response_code(200);
?>
See here: http://php.net/manual/en/function.http-response-code.php
The first solution
Try to remove dataType in your js file like that:
$(document).ready(function() {
$('.button').click(function() {
var form = $(this).closest('form');
$.ajax({
type: "POST",
url: form.attr('data'),
data: form.serialize(),
success: function (response) {
alert('something');
},
error: function() {
alert('fail');
}
});
});
});
The second solution
Send a real clean JSON to AJAX like that:
PHP
if(isset($_POST['username'])) {
$user = new Users;
$user->cleanInput($_POST['username'], $_POST['password']);
if($user->insertUser()) {
$error = [
"title"=> 'true',
"body"=> 'some info here ... '
];
echo json_encode($error);
} else {
$error = [
"title"=> 'false',
"body"=> 'some info here ... '
];
echo json_encode($error);
}
}
JavaScript
$(document).ready(function() {
$('.button').click(function() {
var form = $(this).closest('form');
$.ajax({
type: "POST",
url: form.attr('data'),
dataType: 'json',
data: form.serialize(),
success: function (data) {
let x = JSON.parse(JSON.stringify(data));
console.log(x.title);
console.log(x.body);
},
error: function() {
//code here
}
});
});
});
Is it possibe to simply load a php script with a url with js?
$(function() {
$('form').submit(function(e) {
e.preventDefault();
var title = $('#title:input').val();
var urlsStr = $("#links").val();
var urls = urlsStr.match(/\bhttps?:\/\/[^\s]+/gi);
var formData = {
"title": title,
"urls": urls
}
var jsonForm = JSON.stringify(formData);
$.ajax({
type: 'GET',
cache: false,
data: { jsonForm : jsonForm },
url: 'publishlinks/publish'
})
//load php script
});
});
Edit:
function index() {
$this->load->model('NewsFeed_model');
$data['queryMovies'] = $this->NewsFeed_model->getPublications();
$this->load->view('news_feed_view', $data);
}
simple
jQuery and:
<script>
$.get('myPHP.php', function(data) {});
</script>
Later edit:
for form use serialize:
<script>
$.post("myPHP.php", $("#myFormID").serialize());
</script>
like this ?
$.get('myPHP.php', function(data) {
$('.result').html(data);
alert('Load was performed.');
});
There are various ways to execute a server side page using jQuery. Every method has its own configuration and at the minimum you have to specify the url which you want to request.
$.ajax
$.ajax({
type: "Get",//Since you just have to request the page
url:"test.php",
data: {},//In case you want to provide the data along with the request
success: function(data){},//If you want to do something after the request is successfull
failure: function(){}, //If you want to do something if the request fails
});
$.get
$.get("test.php");//Simplest one if you just dont care whether the call went through or not
$.post
var data = {};
$.post("test.php", data, function(data){});
You can get the form data as a json object as below
var data = $("formSelector").searialize();//This you can pass along with your request