Is there any method to replace/remove colors by color range in Javascript, Opencv or anything else that can be operated on website?
As the above image. Is that possible to replace all the white color(It can be white or near white colors) with transparent color? Any suggestion would be appreciated.
With imagemagick this can be done quickly.
convert input.jpg -fuzz 6% -transparent white output.png
The value of -fuzz 6% can be adjusted to match "near white" thresholds.
Note: The format of JPEG has changed to PNG; which, supports transparency.
You could create a canvas and draw that image onto it, that way you're able to get pixel colors and manipulate them. (And also save the result)
This might lead you somewhere to start with. If you require further help, just comment.
EDIT: Little sample of what this should work like:
//Sets up canvas containing the image:
var img = document.getElementById("image");
img.crossOrigin = "Anonymous";
img.src = "https://i.imgur.com/X1fKQsK.jpg";
loadedBefore = false;
img.onload = function(){
if(loadedBefore) return;
else loadedBefore = true;
var canvas = document.createElement("canvas");
var ctx = canvas.getContext("2d");
canvas.width = img.width;
canvas.height = img.height;
ctx.drawImage(img,0,0,img.width,img.height);
//Finds pixels matching color black:
for(x=0; x<canvas.width; x++){
for(y=0; y<canvas.height; y++){
imgdata = ctx.getImageData(x,y,1,1);
color = imgdata.data; //Gets color of coordinate (with 1 pixel in size)
if(color[0] > 250 && color[1] > 250 && color[2] > 250){ //Checks if color is pretty white
color[3] = 0; //Sets alpha to 0 -> Makes color transparent
ctx.putImageData(imgdata,x,y);
}
}
}
img.src = canvas.toDataURL(); //Set image to display canvas content / update image
console.log("done!");
}
<img id="image"/>
You can apparently not just load an image from some other website and modifiy it in the canvas, unless you set img.crossOrigin = "Anonymous" and the other website allows it. I got no clue on what exactly happens there, I just know that it works with imgur.com. (That's why everything's in the onload function now)
The loadedBefore stuff is because StackOverflow apparently calls the img.onload function pretty often, you won't have this issue if you use your own image so you don't need the crossOrigin and onload stuff.....
Just a function to do the stuff:
function whiteToTransparent(img){
var canvas = document.createElement("canvas");
var ctx = canvas.getContext("2d");
canvas.width = img.width;
canvas.height = img.height;
ctx.drawImage(img,0,0,img.width,img.height);
//Finds pixels matching color black:
for(x=0; x<canvas.width; x++){
for(y=0; y<canvas.height; y++){
imgdata = ctx.getImageData(x,y,1,1);
color = imgdata.data;
if(color[0] > 250 && color[1] > 250 && color[2] > 250){
color[3] = 0;
ctx.putImageData(imgdata,x,y);
}
}
}
img.src = canvas.toDataURL();
}
I have a background image for a canvas, and added a few basic elements to the canvas. Now I want to save the canvas (in .png), with the background image of the canvas style.
Tried:
var canvas = document.getElementById("mycanvas");
var img = canvas.toDataURL("image/png");
But this doesn't seem to save the background image of the canvas. Is there a way out?
When you want to save the Canvas + background as an image, you will need to do a sequence of events:
Create an in-memory canvas just as big as your normal canvas. Call it can2
ctx2.drawImage(can1, 0, 0) // paint first canvas onto new canvas
ctx.clearRect(0, 0, width, height) // clear first canvas
ctx.drawImage(background, 0, 0) // draw image on first canvas
ctx.drawImage(can2, 0, 0) // draw the (saved) first canvas back to itself
To save an image location, I believe your looking for:
window.location = canvas.canvas.toDataURL('image/png');
The first canvas call is your variable the second is the canvas object.
You should probably rename your variable to something unique.
To set an image in canvas and make that the background requires some more work:
var myCanvas = document.querySelector('myCanvas'),
img = document.createElement('img'),
ctx = myCanvas.getContext ? myCanvas.getContext('2d') : null;
myCanvas.width = window.innerWidth;
myCanvas.height = window.innerHeight;
img.onload = function () {
ctx.drawImage(img, 0, 0, myCanvas.width, myCanvas.height);
};
img.src = 'image.png';
updated to redraw the image.
Not sure this is possible, but looking to write a script that would return the average hex or rgb value for an image. I know it can be done in AS but looking to do it in JavaScript.
AFAIK, the only way to do this is with <canvas/>...
DEMO V2: http://jsfiddle.net/xLF38/818/
Note, this will only work with images on the same domain and in browsers that support HTML5 canvas:
function getAverageRGB(imgEl) {
var blockSize = 5, // only visit every 5 pixels
defaultRGB = {r:0,g:0,b:0}, // for non-supporting envs
canvas = document.createElement('canvas'),
context = canvas.getContext && canvas.getContext('2d'),
data, width, height,
i = -4,
length,
rgb = {r:0,g:0,b:0},
count = 0;
if (!context) {
return defaultRGB;
}
height = canvas.height = imgEl.naturalHeight || imgEl.offsetHeight || imgEl.height;
width = canvas.width = imgEl.naturalWidth || imgEl.offsetWidth || imgEl.width;
context.drawImage(imgEl, 0, 0);
try {
data = context.getImageData(0, 0, width, height);
} catch(e) {
/* security error, img on diff domain */
return defaultRGB;
}
length = data.data.length;
while ( (i += blockSize * 4) < length ) {
++count;
rgb.r += data.data[i];
rgb.g += data.data[i+1];
rgb.b += data.data[i+2];
}
// ~~ used to floor values
rgb.r = ~~(rgb.r/count);
rgb.g = ~~(rgb.g/count);
rgb.b = ~~(rgb.b/count);
return rgb;
}
For IE, check out excanvas.
Figured I'd post a project I recently came across to get dominant color:
Color Thief
A script for grabbing the dominant color or a representative color palette from an image. Uses javascript and canvas.
The other solutions mentioning and suggesting dominant color never really answer the question in proper context ("in javascript"). Hopefully this project will help those who want to do just that.
"Dominant Color" is tricky. What you want to do is compare the distance between each pixel and every other pixel in color space (Euclidean Distance), and then find the pixel whose color is closest to every other color. That pixel is the dominant color. The average color will usually be mud.
I wish I had MathML in here to show you Euclidean Distance. Google it.
I have accomplished the above execution in RGB color space using PHP/GD here: https://gist.github.com/cf23f8bddb307ad4abd8
This however is very computationally expensive. It will crash your system on large images, and will definitely crash your browser if you try it in the client. I have been working on refactoring my execution to:
- store results in a lookup table for future use in the iteration over each pixel.
- to divide large images into grids of 20px 20px for localized dominance.
- to use the euclidean distance between x1y1 and x1y2 to figure out the distance between x1y1 and x1y3.
Please let me know if you make progress on this front. I would be happy to see it. I will do the same.
Canvas is definitely the best way to do this in the client. SVG is not, SVG is vector based. After I get the execution down, the next thing I want to do is get this running in the canvas (maybe with a webworker for each pixel's overall distance calculation).
Another thing to think about is that RGB is not a good color space for doing this in, because the euclidean distance between colors in RGB space is not very close to the visual distance. A better color space for doing this might be LUV, but I have not found a good library for this, or any algorythims for converting RGB to LUV.
An entirely different approach would be to sort your colors in a rainbow, and build a histogram with tolerance to account for varying shades of a color. I have not tried this, because sorting colors in a rainbow is hard, and so are color histograms. I might try this next. Again, let me know if you make any progress here.
First: it can be done without HTML5 Canvas or SVG.
Actually, someone just managed to generate client-side PNG files using JavaScript, without canvas or SVG, using the data URI scheme.
Edit: You can simply create a PNG with document.getElementById("canvas").toDataURL("image/png", 1.0)
Second: you might actually not need Canvas, SVG or any of the above at all.
If you only need to process images on the client side, without modifying them, all this is not needed.
You can get the source address from the img tag on the page, make an XHR request for it - it will most probably come from the browser cache - and process it as a byte stream from Javascript.
You will need a good understanding of the image format. (The above generator is partially based on libpng sources and might provide a good starting point.)
function get_average_rgb(img) {
var context = document.createElement('canvas').getContext('2d');
if (typeof img == 'string') {
var src = img;
img = new Image;
img.setAttribute('crossOrigin', '');
img.src = src;
}
context.imageSmoothingEnabled = true;
context.drawImage(img, 0, 0, 1, 1);
return context.getImageData(0, 0, 1, 1).data.slice(0,3);
}
console.log(get_average_rgb(document.querySelector('#img1')));
console.log(get_average_rgb(document.querySelector('#img2')));
<img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAADUlEQVR42mNk+M/wHwAEBgIApD5fRAAAAABJRU5ErkJggg==" width="32" height="32" id="img1">
<img src="https://lh3.googleusercontent.com/a/AEdFTp4Wi1oebZlBCwFID8OZZuG0HLsL-xIxO5m2TNw=k-s32" id="img2" crossOrigin="anonymous">
Less accurate but fastest way to get average color of the image with datauri support:
function get_average_rgb(img) {
var context = document.createElement('canvas').getContext('2d');
if (typeof img == 'string') {
var src = img;
img = new Image;
img.setAttribute('crossOrigin', '');
img.src = src;
}
context.imageSmoothingEnabled = true;
context.drawImage(img, 0, 0, 1, 1);
return context.getImageData(0, 0, 1, 1).data.slice(0,3);
}
I would say via the HTML canvas tag.
You can find here a post by #Georg talking about a small code by the Opera dev :
// Get the CanvasPixelArray from the given coordinates and dimensions.
var imgd = context.getImageData(x, y, width, height);
var pix = imgd.data;
// Loop over each pixel and invert the color.
for (var i = 0, n = pix.length; i < n; i += 4) {
pix[i ] = 255 - pix[i ]; // red
pix[i+1] = 255 - pix[i+1]; // green
pix[i+2] = 255 - pix[i+2]; // blue
// i+3 is alpha (the fourth element)
}
// Draw the ImageData at the given (x,y) coordinates.
context.putImageData(imgd, x, y);
This invert the image by using the R, G and B value of each pixel. You could easily store the RGB values, then round up the Red, Green and Blue arrays, and finally converting them back into an HEX code.
This is #350D's answer but async (as some images may take time to load) and in typescript
async function get_average_rgb(src: string): Promise<Uint8ClampedArray> {
/* https://stackoverflow.com/questions/2541481/get-average-color-of-image-via-javascript */
return new Promise(resolve => {
let context = document.createElement('canvas').getContext('2d');
context!.imageSmoothingEnabled = true;
let img = new Image;
img.src = src;
img.crossOrigin = "";
img.onload = () => {
context!.drawImage(img, 0, 0, 1, 1);
resolve(context!.getImageData(0, 0, 1, 1).data.slice(0,3));
};
});
}
I recently came across a jQuery plugin which does what I originally wanted https://github.com/briangonzalez/jquery.adaptive-backgrounds.js in regards to getting a dominiate color from an image.
EDIT: Only after posting this, did I realize that #350D's answer does the exact same thing.
Surprisingly, this can be done in just 4 lines of code:
const canvas = document.getElementById("canvas"),
preview = document.getElementById("preview"),
ctx = canvas.getContext("2d");
canvas.width = 1;
canvas.height = 1;
preview.width = 400;
preview.height = 400;
function getDominantColor(imageObject) {
//draw the image to one pixel and let the browser find the dominant color
ctx.drawImage(imageObject, 0, 0, 1, 1);
//get pixel color
const i = ctx.getImageData(0, 0, 1, 1).data;
console.log(`rgba(${i[0]},${i[1]},${i[2]},${i[3]})`);
console.log("#" + ((1 << 24) + (i[0] << 16) + (i[1] << 8) + i[2]).toString(16).slice(1));
}
// vvv all of this is to just get the uploaded image vvv
const input = document.getElementById("input");
input.type = "file";
input.accept = "image/*";
input.onchange = event => {
const file = event.target.files[0];
const reader = new FileReader();
reader.onload = readerEvent => {
const image = new Image();
image.onload = function() {
//shows preview of uploaded image
preview.getContext("2d").drawImage(
image,
0,
0,
preview.width,
preview.height,
);
getDominantColor(image);
};
image.src = readerEvent.target.result;
};
reader.readAsDataURL(file, "UTF-8");
};
canvas {
width: 200px;
height: 200px;
outline: 1px solid #000000;
}
<canvas id="preview"></canvas>
<canvas id="canvas"></canvas>
<input id="input" type="file" />
How it works:
Create the canvas context
const context = document.createElement("canvas").getContext("2d");
This will draw the image to only one canvas pixel, making the browser find the dominant color for you.
context.drawImage(imageObject, 0, 0, 1, 1);
After that, just get the image data for the pixel:
const i = context.getImageData(0, 0, 1, 1).data;
Finally, convert to rgba or HEX:
const rgba = `rgba(${i[0]},${i[1]},${i[2]},${i[3]})`;
const HEX = "#" + ((1 << 24) + (i[0] << 16) + (i[1] << 8) + i[2]).toString(16).slice(1);
There is one problem with this method though, and that is that getImageData will sometimes throw errors Unable to get image data from canvas because the canvas has been tainted by cross-origin data., which is the reason you need to upload images in the demo instead of inputting a URL for example.
This method can also be used for pixelating images by increasing the width and height to draw the image.
This works on chrome but may not on other browsers.
Javascript does not have access to an image's individual pixel color data. At least, not maybe until html5 ... at which point it stands to reason that you'll be able to draw an image to a canvas, and then inspect the canvas (maybe, I've never done it myself).
All-In-One Solution
I would personally combine Color Thief along with this modified version of Name that Color to obtain a more-than-sufficient array of dominant color results for images.
Example:
Consider the following image:
You can use the following code to extract image data relating to the dominant color:
let color_thief = new ColorThief();
let sample_image = new Image();
sample_image.onload = () => {
let result = ntc.name('#' + color_thief.getColor(sample_image).map(x => {
const hex = x.toString(16);
return hex.length === 1 ? '0' + hex : hex;
}).join(''));
console.log(result[0]); // #f0c420 : Dominant HEX/RGB value of closest match
console.log(result[1]); // Moon Yellow : Dominant specific color name of closest match
console.log(result[2]); // #ffff00 : Dominant HEX/RGB value of shade of closest match
console.log(result[3]); // Yellow : Dominant color name of shade of closest match
console.log(result[4]); // false : True if exact color match
};
sample_image.crossOrigin = 'anonymous';
sample_image.src = document.getElementById('sample-image').src;
This is about "Color Quantization" that has several approachs like MMCQ (Modified Median Cut Quantization) or OQ (Octree Quantization). Different approach use K-Means to obtain clusters of colors.
I have putted all together here, since I was finding a solution for tvOS where there is a subset of XHTML, that has no <canvas/> element:
Generate the Dominant Colors for an RGB image with XMLHttpRequest
As pointed out in other answers, often what you really want the dominant color as opposed to the average color which tends to be brown. I wrote a script that gets the most common color and posted it on this gist
To get the average (not the dominant) color of an image, create a tiny canvas of the scaled-down original image (of max size i.e: 10 px). Then loop the canvas area imageData to construct the average RGB:
const getAverageColor = (img) => {
const max = 10; // Max size (Higher num = better precision but slower)
const {naturalWidth: iw, naturalHeight: ih} = img;
const ctx = document.createElement`canvas`.getContext`2d`;
const sr = Math.min(max / iw, max / ih); // Scale ratio
const w = Math.ceil(iw * sr); // Width
const h = Math.ceil(ih * sr); // Height
const a = w * h; // Area
img.crossOrigin = 1;
ctx.canvas.width = w;
ctx.canvas.height = h;
ctx.drawImage(img, 0, 0, w, h);
const data = ctx.getImageData(0, 0, w, h).data;
let r = g = b = 0;
for (let i=0; i<data.length; i+=4) {
r += data[i];
g += data[i+1];
b += data[i+2];
}
r = ~~(r/a);
g = ~~(g/a);
b = ~~(b/a);
return {r, g, b};
};
const setBgFromAverage = (img) => {
img.addEventListener("load", () => {
const {r,g,b} = getAverageColor(img);
img.style.backgroundColor = `rgb(${r},${g},${b})`;
});
};
document.querySelectorAll('.thumb').forEach(setBgFromAverage);
.thumbs { display: flex; flex-wrap: wrap; gap: 0.5rem; }
.thumb { height: 100px; padding: 20px; }
<div class="thumbs">
<img class="thumb" alt="image" src="https://i.imgur.com/22BrBjx.jpeg">
<img class="thumb" alt="image" src="https://i.imgur.com/MR0dUpw.png">
<img class="thumb" alt="image" src="https://i.imgur.com/o7lpiDR.png">
<img class="thumb" alt="image" src="https://i.imgur.com/egYvHp6.jpeg">
<img class="thumb" alt="image" src="https://i.imgur.com/62EAzOY.jpeg">
<img class="thumb" alt="image" src="https://i.imgur.com/3VxBMeF.jpeg">
</div>
There is a online tool pickimagecolor.com that helps you to find the average or the dominant color of image.You just have to upload a image from your computer and then click on the image. It gives the average color in HEX , RGB and HSV. It also find the color shades matching that color to choose from. I have used it multiple times.