I have two different buttons like this :
<input type="button" name="but1" id="but1" value="page1" onclick="f('WebForm1')" />
<input type="button" name="but2" id="but2" value="page2" onclick="f('WebForm2')" />
and obviously two other webforms ("WebForm1" and "WebForm2").
using JavaScript, how can I submit the information from the default webform (which I have the buttons in it) to the page that is the value of its button?
(I mean when I click the first button, it should go to WebForm1 and submit data and when I click the second button, it should go to WebForm2 and submit the data)
I've never tried this before so in JavaScript I wrote
function f(t){
var a;
a = document.getElementById['form1'];
a.submit(t); }
but its not working.
Are all these functionalities to be implemented on the same page?
How I see it, you can make the two input buttons the submit buttons of the two different forms.
<form action = "WebForm1">
<input type= submit name="but1" id="but1" value="page1" />
</form>
<form action = "WebForm2">
<input type= submit name="but2" id="but2" value="page2" />
</form>
Also, I'm not sure if anything like a.submit(t) even works.
In HTML5 you can use <button> with form attribute:
<button type="submit" form="form1" value="Submit">Submit</button>
with form attribute you can specify the form element the <button> element belongs to.
Then, in your form:
<form action="WebForm1" method="get" id="form1">
...
</form>
hope this will help. t is the name of the form.
function f(t){
// <form name="WebForm1">
// t is the name of the form
document.t.submit();
}
this work only if the two form are in the same page as where the button are.
Related
When I submit form by using below function it is submitting but values are not passed through this function. I use all functions but nothing found:
document.getElementById("postad").submit();
Form is given below.
<form action="register.php" id="postad" method="post">
<input class="textfield2" type="text" id="post_title" style="width:640px;" placeholder="Ad Title" onBlur="check('post_title')" />
<input class="button" type="button" name="save" value="Publish" onclick="send();" />
</form>
Your form contains two form controls. Neither will be a successful control (i.e. one that appears in the submitted data), but for different reasons.
Only form controls with name attributes can be successful. Your text input doesn't have a name. (It also doesn't have a default value, so you need to type in it first).
Buttons can only be successful if they are the submit button used to submit the form. Your button isn't a submit button and you use JavaScript to submit the form.
There is no name attribute in your input text fields
<input name="post_title" class="textfield2" type="text" id="post_title" style="width:640px;" placeholder="Ad Title" onBlur="check('post_title')" />
.........^
Here's my HTML:
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="test" method="get" action="">
<input type="hidden" name="var1" value="true" />
<input type="submit" name="var2" value="submit" />
</form>
<script>
$("#test").submit();
</script>
The resultant request that that makes has var1 in it but not var2. My question is why and what can I do to get var2?
Here's a live demo:
http://www.frostjedi.com/terra/dev/submit.php
try: method="post" in form or use <button type="submit"></button>
A form should submit the value of a submit button only if it's clicked to submit the form (see HTML5 4.10.22.4 Constructing the form data set). Calling the submit method doesn't click the button, so it doesn't submit the value.
The code you've posted will endlessly submit the form, thanks.
You can call the click method of the button, but that may not work (i.e. submit the button's value) everywhere:
<form id="test" method="get" action="">
<input type="hidden" name="var1" value="true">
<input type="submit" name="var2" value="submit">
</form>
<button onclick="$('#test')[0].var2.click()">submit form</button>
Or, as user3701524 suggests, use method=post if that suits.
The value on button will only be submitted when u actually CLICK that button. To make it all work nice, I recommend binding to
$('form').on('submit', function(e) {
// here you have the button value if it was clicked.
e.preventDefault(); // optional this prevent default submission.
});
either way, calling $('form').submit() will NOT send the button value because is not triggered by the button itself.
Hope it helps!
I am working on a web project using structs2. I have a form with submit button and another button. I am using javascript functions for form validation. My problem is that when I click the other button the form validation function works.
my jsp:
<h2>New Form</h2>
<s:form action="aa.action" name="myform" method="post" onsubmit="return(validateForm())">
<s:textfield name="formnumber" size="20" />
.
.
<button value="add" name="add">Add</button>
.
.
<s:submit method="create" key="xxx" value="xxx" />
When i click anyone of the the button the validation function will excecute.I dont want excecute the validation function on add button click.
Default button always submit the form so add type="button" it will stop
<button type="button" value="add" name="add">Add</button>
OR Use
<input type="button" name="add" value="Add" />
Get rid of the onclick. You don't need it here. The type="add" already submits the form. Your concrete problem is likely caused because the onclick of the <form> has returned false.
<input type="button" name="method" value="Add" class="button"
onclick="location.href='Employeelist.jsp'" />
You should mention type="button".
Otherwise it will submit the current URL again.
<button type="button" value="Add" name="add"/>
details about "type" in html
http://www.w3schools.com/tags/att_button_type.asp
Java Script Form validation can be
w3schools
Tutorials point
javaScript Coder
if you familier with java script libraries you can use validate.js
type : What type of widget you want.
vlaue : The text what you want in that.
name : The id of that purticulat widget.
I have used jquery wizard plugin to create this form.
The form get submitted when I use the ID = "next" submit button.
when I use the ID = "quick" button it will redirect to the Feedback.Form but it will not submitted properly. (I cant see the db has been updated properly.)
$j("#quick").click(function(){
$j('#feedbackForm').submit();
});
<form id="feedbackForm" method="post" action="<openmrs:contextPath/>/module/feedback/addFeedback.form" class="bbq" enctype="multipart/form-data" >
<div id="bottomNavigation">
<input id="back" value="Back" type="reset" />
<input id="next" value="Next" type="submit" />
<input id="quick" value="Just submit now with all the defaults!" type="button" />
</div>
Please can any one help me on this?
Thanks,
Harsha
Full source : https://gist.github.com/3227043
Convert the "next" button to normal button and add and if or switch selection into the jquery code. So both buttons were normal and Jquery will decide which ones takes to submit getting the name of the button who calls the click event. Or you can do it trough a javascript function, well, you can do it in any way as you want, but both buttons must be "button" type
I want my submit button to be positioned somewhere that outside my form element? Do I have any options? With the exception of jquery.
Thanks,
rodchar
Another approach to this is merely to set the form attribute on the button:
<form id="first">
<input type="submit" form="second" value="Submit Second" />
</form>
<form id="second">
<input type="submit" form="first" value="Submit First" />
</form>
Fiddle: http://jsfiddle.net/52wgc2ym/
Original Answer
The natural behavior of a submit button is to submit the nearest form up its hierarchy. The only other way to get a button to submit a form which it doesn't reside in is to use JavaScript (which is what jQuery is, basically).
If necessary, you could reposition the submit button so that it appears as though it's not in the form visually when the page is rendered. You would do this using CSS, which may give the desired result(s).
The submit button needs to be inside the form, yes.
It seems strange to me to want it any other way, anyway. What would be the point if the input controls were in one place on the page, and the submit button was waaay over there somewhere else?
Yes, structurally the submit button needs to be inside a form element for the document to be valid X/HTML. But visually you can position the submit button anywhere you want with appropriate CSS (float, absolute/relative positioning, etc). You could also write JavaScript that will trigger the form submission and tie it to another element.
This is a common situation. I think this will do it (haven't tested it):
<form id="form1" action="someAction.cgi" method="GET">
<!-- other fields go here -->
</form>
<form id="form2" action="someOtherAction.cgi" method="GET">
<!-- other fields go here -->
</form>
<form>
<input value="Form One" type="button"
onclick="document.getElementById('form1').submit();"/>
<input value="Form Two" type="button"
onclick="document.getElementById('form2').submit();"/>
</form>
I'm not sure if you need that last <form>. I seem to remember browsers ignoring events if the button wasn't in a form.
Inputs of type submit only make sense as children of <form> elements. But using CSS I'm sure you can position it wherever you like. Remember form elements are "invisible" so just expand the tags around more of your content and you're covered. Here's the documentation on forms for HTML4, it's still appropriate.
This is the another type of answer getting more clear view from egrunin answer
<form id="form1" name="form1" action="someAction.cgi" method="GET">
<!-- other fields go here -->
</form>
<form id="form2" name="form2" action="someOtherAction.cgi" method="GET">
<!-- other fields go here -->
</form>
Calling by form id:
<form>
<input value="Form One" type="button"
onclick="document.getElementById('form1').submit();"/>
<input value="Form Two" type="button"
onclick="document.getElementById('form2').submit();"/>
</form>
or Calling by form name:
<form>
<input value="Form One" type="button"
onclick="document.form1.submit();"/>
<input value="Form Two" type="button"
onclick="document.form2.submit();"/>
</form>