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Hashed value regex

I want like to capture value in the last part of the string between two tildes, {TE,TAE} and for that I thought of defining the pre look up which is hashed password also in between two
tildes:
{$2a$10$3Ncp3zpxqVp5VgXk/e2MkOTQQVA2lQ51ujQPzy7ra57QRQ.nvXbVq}.
So can anyone tell me what will be the regex for the hashsed password value so I can use this as my pre look up. Entire string is mentioned below.
I have tired
~isma407~$2a$10$3Ncp3zpxqVp5VgXk/e2MkOTQQVA2lQ51ujQPzy7ra57QRQ.nvXbVq~TE,TAE~

There is no ~ in the first string you provided as an example
if you want an example regex with the 2nd string, and we are assuming the length of the strings you are checking are relatively similar in length, you can capture it with the regex below
https://regex101.com/r/BlaCRC/2
.{3,65}.+~(.+)~

Regex validation quick fix most likely

I am try to validate a form to make the user enter their full name like the following..
First, Last
The user must have some string of alphabetic only chars, then a comma, then a space, then a last name, which can again be any string of chars.
This is my current regex..
var alphaExp = /^[a-zA-Z,+ a-zA-Z]+$/;
However, it lets the user submit something as simple as john. I want it to force them to submit something such as john, smith.

What you are doing is creating a character class ([]) that matches any of the following characters: a-zA-Z,+. This allows john to match the whole regex.
This is what you want:
/^[a-zA-Z]+, [a-zA-Z]+$/
However, I would like to advise you that making assumptions about names is a little wrong. What if some guy is named John O'Connor? Or Esteban Pérez? Or just Ng (only a first name)?
"Code that believes someone’s name can only contain certain characters is stupid, offensive, and wrong" - tchrist
Sure, you don't want to let people to enter just gibberish, but leave an option for users to enter something that doesn't necessarily fit your idea of correctness, but is nonetheless correct.

That's not how character sets work:
/^[a-zA-Z]+, [a-zA-Z]+$/
Things to consider:
Any validation you do on the client can be bypassed
Some people may have names with accented letters
Some cultures don't use just two names

^[a-zA-Z]+, [a-zA-Z]+$
Should work, however, do you want to prevent '.'? As in J. Hooker? And more words, like 'Jan van Hoogstrum'? Note also that you are preventing any accented characters being used. An option (although it allows underscores) is to use \w:
^(\w+ )$
Which would give you 'name name name...'. 'First, last' is not a common way to enter your name, so you'll frustrate a lot of users that way.

The correct regexp for allowing only the first letter to be capital would be:
/^[A-Z][a-z]+, [A-Z][a-z]+$/

Need regex to match unformatted phone number syntax

I need a regex for Javascript that will match a phone number stripped of all characters except numbers and 'x' (for extension). Here are some example formats:
12223334444
2223334444
2223334444x5555
You are guaranteed to always have a minimum of 10 numerical digits, as the leading '1' and extension are optional. There is also no limit on the number of numerical digits that may appear after the 'x'. I want the numbers to be split into the following backreferences:
(1)(222)(333)(4444)x(5555)
The parenthesis above demonstrate how I want the number to be split up into backreferences. The first set of parenthesis would be assigned to backreference $1, for example.
So far, here is what I've come up with for a regex. Keep in mind that I'm not really that great with regex, and regexlib.com hasn't really helped me out in this department.
(\d{3})(\d{3})(\d{4})
The above regex handles the 2nd case in my list of example test cases in my first code snippet above. However, this regex needs to be modified to handle both the optional '1' and extension. Any help on this? Thanks!

Regex option seems perfectly fine to me.
var subject = '2223334444';
result = subject.replace(/^1?(\d{3})(\d{3})(\d{4})(x\d+)?$/mg, "1$1$2$3$4");
alert(result);
if(!result.match(/^\d{11}(?:x\d+)?/))
alert('The phone number came out invalid. Perhaps it was entered incorrectly');
This will say 12223334444 when there is no extension
I expect you want to tweak this out some, let me know how it should be.

If I were you, I would not go with a regular expression for this — it would cause more headaches than it solved. I would:
Split the phone number on the "x", store the last part in the extension.
See how long the initial part is, 9 or 10 digits
If it's 10 digits, check that the first is a 1, slice it off, and then continue with the 9-digit process:
If it's 9 digits, split it up into 3-3-4 and split them into area code, exchange, number.
Validate the area code and exchange code according to the rules of the NANP.
This will validate your phone number and be much, much easier and will make it possible for you to enforce rules like "no X11 area codes" or "no X11 exchange codes" more-easily — you'd have to do this anyway, and it's probably easier to just use plain string manipulation to split it into substrings.

I did a bit more testing and here's a solution I've found. I haven't found a case where this breaks yet, but if someone sees something wrong with it please let me know:
(1)?(\d{3})(\d{3})(\d{4})(?:x(\d+))?
Update:
I've revised the regex above to handle some more edge cases. This new version will fail completely if something unexpected is present.
(^1|^)(\d{3})(\d{3})(\d{4})($|(?:x(\d+))$)

My regex is:
/\+?[0-9\-\ \(\)]{10,22}/g

Regex to validate textbox length

I have this RegEx that validates input (in javascript) to make sure user didn't enter more than 1000 characters in a textbox:
^.{0,1000}$
It works ok if you enter text in one line, but once you hit Enter and add new line, it stops matching. How should I change this RegEx to fix that problem?

The problem is that . doesn't match the newline character. I suppose you could use something like this:
^[.\r\n]{0,1000}$
It should work (as long as you're not using m), but do you really need a regular expression here? Why not just use the .length property?
Obligatory jwz quote:
Some people, when confronted with a problem, think "I know, I'll use regular expressions." Now they have two problems.
Edit: You could use a CustomValidator to check the length instead of using Regex. MSDN has an example available here.

What you wish is this:
/^[\s\S]{0,1000}$/
The reason is that . won't match newlines.
A better way however is to not use regular expressions and just use <text area element>.value.length

If you just want to verify the length of the input wouldn't it be easier to just verify the length of the string?
if (input.length > 1000)
// fail validation

Match a specific sequence or everything else with regex

Been trying to come up with a regex in JS that could split user input like :
"Hi{user,10,default} {foo,10,bar} Hello"
into:
["Hi","{user,10,default} ","{foo,10,bar} ","Hello"]
So far i achieved to split these strings with ({.+?,(?:.+?){2}})|([\w\d\s]+) but the second capturing group is too exclusive, as I want every character to be matched in this group. Tried (.+?) but of course it fails...
Ideas fellow regex gurus?

Here's the regex I came up with:
(:?[^\{])+|(:?\{.+?\})
Like the one above, it includes that space as a match.

Use this:
"Hi{user,10,default} {foo,10,bar} Hello".split(/(\{.*?\})/)
And you will get this
["Hi", "{user,10,default}", " ", "{foo,10,bar}", " Hello"]
Note: {.*?}. The question mark here ('?') stops at fist match of '}'.

Beeing no JavaScript expert, I would suggest the following:
get all positive matches using ({[^},]*,[^},]*,[^},]*?})
remove all positive matches from the original string
split up the remaining string
Allthough, this might get tricky if you need the resulting values in order.