This question already has answers here:
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
(7 answers)
How do I return the response from an asynchronous call?
(41 answers)
Closed 6 years ago.
I have a promise/global object that outputs as follows in the console:
console.log(globalInfo);
Promise
__proto__:Promise
[[PromiseStatus]]:"resolved"
[[PromiseValue]]:globalInfo
item1:"12345"
item2:"something else"
item3:"www.stackoverflow.com"
__proto__:Object
And am successfully pulling out the value for "item2" as such:
globalInfo.then(function(val) {
newVar = val.item2;
console.log('newVar inside: ' + newVar);
});
console.log('newVar outside: ' + newVar);
But, I am not able to pass that variable/value outside of the then() function. Nothing outputs to the console for the second console.log ("newVar outside").
How do I make the variable "newVar" with the the value for "item2" available globally outside of the then() function?
Related
This question already has answers here:
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
(7 answers)
Using async/await with a forEach loop
(33 answers)
How do I return the response from an asynchronous call?
(41 answers)
Closed 11 months ago.
I have this code in my Node.js application.
The log inside forEach gives desired result but the one outside forEach gives an empty array.
let biddedListings = [];
bids.forEach(async (bid) => {
const listing = await ListingModel.find({ _id: bid.bidOn });
biddedListings.push(listing[0]);
// console.log("bidded", biddedListings);
});
console.log("bidded", biddedListings);
Whys is it that the same global variable is giving different results? What am I doing wrong here?
This question already has answers here:
How to return value from an asynchronous callback function? [duplicate]
(3 answers)
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
(7 answers)
Closed 1 year ago.
I need to get a local storage value outside the call, to use it in another function,
I see this is an async function and outside log gets called first, but cant rly wrap how it works and why I get the value on the second call, but not it the first call.
So the question is how do I get the value outside the call and make First Call work as second call ?
var Credentials = []
chrome.storage.local.get(["Key"], function(result) {
const o = result.Key.email
console.log("this is email", result.key.email)
Credentials.push({"email": result.key.email})
console.log("Second Call",Credentials[0].email)
});
console.log("First Call",Credentials[0])
This question already has answers here:
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
(7 answers)
How do I return the response from an asynchronous call?
(41 answers)
Closed 5 years ago.
I have following code to store some string value in storage:
function setData(dat) {
chrome.storage.sync.set({'key': dat}, function() {});
}
function getData() {
chrome.storage.sync.get('key', function (obj) {
alert('Your code is: ' + obj);
});
}
And following usage of this code in my content script:
alert('processing');
setData('someVal');
getData();
But "getData" function always returns "object Object" instead of "someVal". What exactly I am doing wrong?
This question already has answers here:
How do I return the response from an asynchronous call?
(41 answers)
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
(7 answers)
Closed 5 years ago.
I have a function that I call which hits an API and returns a JSON, which I am calling getData. Inside that function is a nested function that processes the JSON and saves it to a new variable processedData when it's done making the request from the API.
I'd then like to return that processed JSON, but the console is telling me it's undefined. I didn't declare the variable so it should be treated as global. Why am I still having this issue?
The code won't work with the snippet because the API is only local, but processedData essentially looks like this: {'A': '123'}
function hitAPI() {
var getData = $.get('http://127.0.0.1:5000/myroute');
getData.done(function() {
processedData = (JSON.parse(getData['responseJSON']['data']));
});
return processedData;
};
var x = hitAPI()
console.log(x);
This question already has answers here:
How do I return the response from an asynchronous call?
(41 answers)
Closed 8 years ago.
I want to store a value from a JSON object in a global variable to use later in my code. Apparently this does not work even though it should make the country variable global.
$.getJSON(reverseGeoRequestURL, function(reverseGeoResult){
window.country = reverseGeoResult.results[0].locations[0].adminArea1;
});
console.log(window.country);
The getJSON call is asynchronous. Put that console.log call inside the callback and it will not be undefined.