I'm trying to call an ajax before user leaving a page, this what i have done so far. But it doesn't even hit the ajax page.
This is what i have done so far.
window.onbeforeunload = closeIt();
function closeIt()
{
var key="save-draft";
$.ajax({
url: "app/ajax_handler.php",
type:"GET",
data:{key:key},
success: function(data) {
return data;
}
});
}
I Have tried this one also both failed in my case.
$( window ).unload(function() {});
The only way I think is to let the user know that it's a process on background with a confirm message, that will block the exit until user click on Accept or you've got the response.
Something like that:
window.onbeforeunload = closeIt();
function closeIt()
{
/*var key="save-draft";
$.ajax({
url: "app/ajax_handler.php",
type:"GET",
data:{key:key},
success: function(data) {
return data;
}
});*/
setTimeout(function() {
return confirm("There is a process that isn't finished yet, you will lose some data. Are you sure you want to exit?");
}, 1000);
}
Related
In the below code I am making an API call to my backend node.js app using setTimeout() which calls my AJAX at every 5 seconds. Inside my AJAX success I am displaying divContent1 & divContent2 based on certain condition which should execute at least once. After that only divContent2 should be visible at each setTimeout() calls.
index.html
<script type="text/javascript">
$(document).ready(function(){
$.ajax({
url: "http://localhost:8070/api/route1",
type: 'POST',
dataType:'json',
success: function(res) {
//Some Task
}
});
$("#myButton").click(function(){
const route2 = function() {
$.ajax({
url: "http://localhost:8070/api/route2",
type: "POST",
dataType: "json",
data: { var1: val1 },
success: function (res) {
// Various tasks
if(res.flag){
$("#divContent1").hide();
$("#divContent2").show();
}
else{
$("#divContent1").show();
}
//Functions that handle div content data
},
beforeSend: function() {
$("#divContent1").hide();
$("#divContent2").hide();
},
complete: function() {
setTimeout(route2,5000);
},
});
};
$(function(){
route2();
})
});
});
</script>
The setTimeout() calls the entire route2 function which handles all the display and insertion of div content. However, the ask is to only display divContent2 from the second call.
Looking for a solution for this
The setTimeout() calls the entire route2 function which handles all
the display and insertion of div content. However, the ask is to only
display divContent2 from the second call.
You're calling route2 recursively with setTimeout(route2,5000); under complete. So this will run infinitely as complete occur each time an ajax call is completed (wether success or error). So what you can do is to create a timer and clear it after the second execution, something like this:
var ctr = 0, timer =0;
const route2 = function() {
$.ajax({
...
success: function (res) {
//Write you logic based on ctr
}
complete: function() {
if(ctr>0){
clearTimeout(timer)
}else{
timer = setTimeout(route2,5000);
ctr = ctr+ 1;
}
},
});
};
Will an external variable be enough? Just define it in the outer context and set/check it to choose the behavior:
// before declaring button click handler
var requestDoneAtLeastOnce = false;
// ...
// somewhere in success handler
success: function (res) {
if (!requestDoneAtLeastOnce) {
requestDoneAtLeastOnce = true;
// do something that belongs only to handling the first response
}
else {
// this is at least the second request, the other set of commands belongs here
}
}
In order to prevent getting an error twice I use beforeSend.
hasSent = false
function submit() {
if (!hasSent)
$.ajax({
url: "${createLink(controller:'userInvitation', action:'ajaxUpdate')}",
type: "POST",
data: $("#invitationForm").serialize(),
success: function(data, textStatus, jqXHR) {
$('#invitationForm')[0].reset();
$('.thank-you-modal').modal('show');
hasSent = true;
console.log(hasSent)
},
complete: function() {
hasSent = false;
console.log(hasSent)
}
});
}
As you can see the ajax should happen only if hasSent=false.
For some reason the ajax happens also if the user clicks multiple time (very quick) on the submit button
To prevent this kind of issue disable the button before sending the ajax and then anable inside the success function
$(mybutton).prop("disabled",true);
// ajax call here
then
success: function(data, textStatus, jqXHR) {
$(mybutton).prop("disabled",false);
// code here
}
You can create another flag such as isSending
function submit() {
if(isSending)
return;
isSending = true
$.ajax({
// ...
complete: function() {
isSending = false;
}
});
}
there are two ways you can do this.
1) create a flag and check if the button is pressed. If pressed then do not execute the ajax code
change the flag back once the request is successful, like this
success:function(...)
{
flag=false;
}
Or you can disable the button at the button click so the request will be carried out and double click situation won't arise. Enable the button on complete like this
complete:function(..){ $("yourbutton").attr("disabled",false)}
Here is the scenario:
I am sending ajax request when user click on anchor tag to fecht & update instagram media status.
But it take sometime to retrieve the response, in that time user clicked N number of time on that anchor tag.
So each time it sends the request, I am don't want such behaviour ..
Is there any easy way to handle such situation?
Currently I am adding the class when user clicked on it, and using that I am deciding user has click on anchor tag or not??
Please let me know, if it is correct way or not..
Here is fiddle URL (Not clicked on link at least 2+ times, it send 2+ request which is i don't want )
http://jsfiddle.net/bkvaiude/mxb8x/
thanks
You should use should remove the click event and then set it up again when the ajax call is complete:
Instead of setting it in the success call as the others do; you should use the complete callback to set it. To make sure if the server returns an error it is still binding the click event again.
http://jsfiddle.net/eWwZt/
(function (){
console.log("bhushan");
var ajaxCall = function(e){
$("#test").off("click");
console.log("click");
e.preventDefault();
var is_liked_url = "https://api.instagram.com/v1/media/popular?client_id= b52e0c281e584212be37a59ec77b28d6";
$.ajax({
method: "GET",
url: is_liked_url,
dataType: "jsonp",
success: function(data) {
console.log("data...");
},
complete: function(){
$("#test").on("click", ajaxCall);
}
});
}
$("#test").on("click", ajaxCall);
})();
Put a flag to check if ajax call completed or not this way:
(function (){
var RequestInProgress = false;
console.log("bhushan");
$("#test").on("click", function(e){
e.preventDefault();
if(!RequestInProgress) // if request not in progress send
{
RequestInProgress = true;
var is_liked_url = "https://api.instagram.com/v1/media/popular?client_id= b52e0c281e584212be37a59ec77b28d6";
$.ajax({
method: "GET",
url: is_liked_url,
dataType: "jsonp",
success: function(data) {
console.log("data...");
RequestInProgress = false;
}
});
}
});
})();
UPDATED FIDDLE
You can use .off() to unbind click to element.
(function () {
console.log("bhushan");
var Myfunction = function (e) {
$("#test").off("click"); //Unbind click
e.preventDefault();
var is_liked_url = "https://api.instagram.com/v1/media/popular?client_id= b52e0c281e584212be37a59ec77b28d6";
$.ajax({
method: "GET",
url: is_liked_url,
dataType: "jsonp",
success: function (data) {
console.log("data...");
$("#test").on("click", Myfunction);
}
});
};
$("#test").on("click", Myfunction);
})();
DEMO
try this
var gettingData =false;
$('selector').click(function() {
gettingData = false;
if (!gettingData) {
gettingData =true;
$.ajax(//do ajax logic)
.success(
gettingData = false;
//parse data)
.error(
gettingData = false;
//display some error
);
} else {
return false;
}
});
Look at this code please - how could I kill / update or restart an ajax call (not content that Ajax calls) after the content has already been called?
I mean the $('#posting_main') is called onclick and animated - how to stop ajax and make it another $('#posting_main') on another click?
$(document).ready(function() {
$("#img_x_ok").click(function(e){
e.preventDefault();
var post_text = $.trim($("#main_text_area").val());
var data_text = 'post_text='+ post_text;
if (post_text === "") return;
var xhr = $.ajax({
type: "POST",
url: "comm_main_post.php",
data: data_text,
cache: false,
success: function (data){
//content
$("#posting_main").fadeIn();
$("#posting_main").load("pull_comm.php");
$("#main_text_area").attr("value", "");
$("#posting_main").animate({
marginTop: "+=130px",
}, 1000 );
}
}); //ajax close
}); }); //both functions close
You can abort the current request with:
xhr.abort();
After having done that, you can run another $.ajax(...) to make a second request.
You could implement it like the following. Note that indenting code makes it a lot more readable!
$(document).ready(function() {
var xhr; // by placing it outside the click handler, you don't create
// a new xhr each time. Rather, you can access the previous xhr
// and overwrite it this way
$("#img_x_ok").click(function(e){
e.preventDefault();
var post_text = $.trim($("#main_text_area").val());
var data_text = 'post_text='+ post_text;
if (post_text === "") return;
if(xhr) xhr.abort(); // abort current xhr if there is one
xhr = $.ajax({
type: "POST",
url: "comm_main_post.php",
data: data_text,
cache: false,
success: function (data){
//content
$("#posting_main").fadeIn();
$("#posting_main").load("pull_comm.php");
$("#main_text_area").attr("value", "");
$("#posting_main").animate({
marginTop: "+=130px",
}, 1000 );
}
});
});
});
I am not sure I fully understand your question, however:
xhr.abort() will kill the AJAX request. After calling abort(), you could modify and resend the request, if desired.
$("#posting_main").stop() will stop the fadeIn animation. (And I think you might need to follow that with $("#posting_main").hide() to be sure it isn't left partially visible.)
I have a form.submit that fires multiple times. The first time, it's fine. After I get the response back, if I click the submit button again, it fires twice. Then thrice. Seems like each time the response comes back, the submit fires an extra time the next time the button is clicked.
RetrievePassword = function () {
var $popup = $("#fancybox-outer");
var form = $popup.find("form");
form.submit(function (e) {
var data = form.serialize();
var url = form.attr('action');
$.ajax({
type: "POST",
url: url,
data: data,
dataType: "json",
success: function (response) {
if (response.Success) {
$.fancybox.close();
}
alert(response.Message);
},
error: function (xhr, status, error) {
alert(xhr.statusText);
}
});
e.cancelBubble = true;
if (e.stopPropagation) e.stopPropagation();
return false;
});
};
I'm not even sure how to debug this. Any advice is appreciated...
I assume you are calling RetrievePassword() multiple times. Everytime you call it another onsubmit handler will be registered.
The solution is to register the handler only once.