I have a code :
var index = 100;
var arr =[];
arr[index.toString()] = "Hello"
The result : index still known as integer not a string. Anyone can explain what's wrong with my code?
You have to declare associative arrays using {}, which creates a new object, because in JavaScript, arrays always use numbered indexes.
You need to declare an object: var arr={};
arrays use numbered indexes.
objects use named indexes.
var index = 100;
var arr ={};
arr[index.toString()] = "Hello";
console.log(arr);
How to make associative array with number as string in Javascript
JavaScript doesn't have associative arrays in the sense that term is frequently used. It has objects, and as of ES2015 (aka "ES6"), it has Maps.
The result : index still known as integer not a string. Anyone can explain what's wrong with my code?
The index variable's value is still a number, yes, because you haven't done anything to change it. But the index in the array is a string (and would be even if you didn't use .toString()), because standard arrays aren't really arrays at all1, they're objects with special handling of a class of properties (ones whose names are strings that fit the spec's definition of an array index), a special length property, and that use Array.prototype as their prototype.
Here's proof that array indexes are strings:
var a = [];
a[0] = "zero";
for (var name in a) {
console.log("name == " + name + ", typeof name == " + typeof name);
}
That said, you don't want to use an array when you want a generic object or map.
Here's using a generic object for name/value mappings:
var o = Object.create(null);
var name = "answer";
o[name] = 42;
console.log(o[name]); // 42
The property names in objects are strings or (as of ES2015) Symbols. I used Object.create(null) to create the object so it wouldn't have Object.prototype as its prototype, since that gives us properties (toString, valueOf, etc.) that we don't want if we're using the object as a map.
Here's using a Map:
var m = new Map();
var name = "answer";
m.set(name, 42);
console.log(m.get(name)); // 42
The main advantages Maps have over objects are:
Their keys can be anything, not just strings or Symbols
They're iterable, so you can use for-of to loop through the mappings they contain
Maps have a size property telling you how many entries they have
Maps guarantee that iteration of their entries is performed in the order the entries were added to the map
With ES6, you could use a Map, which holds any type as key.
var map = new Map;
map.set(100, "Hello");
map.set('100', "Foo");
console.log(map.get(100)); // 'Hello'
console.log(map.get('100')); // 'Foo'
console.log([...map]);
JavaScript does not support arrays with named indexes, in JavaScript, arrays always use numbered indexes.
If you use a named index, JavaScript will redefine the array to a standard object.
After that, all array methods and properties will produce incorrect results.
As you can see in the following example:
var person = [];
person["firstName"] = "John";
person["lastName"] = "Doe";
person["age"] = 46;
var x = person.length; // person.length will return 0
console.log(x);
var y = person[0]; // person[0] will return undefined
console.log(y);
Related
In the example below, the array2.length is only 10, while in my mind, it should be 13.
Why does the "string keyed" indexes not increase the length of the array?
I can store things and still access it, and the VS debugger shows that those arrays are being stored properly. So why is the length not increased?
var array2 = new Array();
array2["a"] = new Array();
array2["b"] = new Array();
array2["c"] = new Array();
for (var i = 0; i < 10; ++i)
array2[i] = new Array();
var nothing = "";
for (var i = 0; i < array2.length; ++i)
nothing = "";
Javascript arrays cannot have "string indexes". A Javascript Array is exclusively numerically indexed. When you set a "string index", you're setting a property of the object. These are equivalent:
array.a = 'foo';
array['a'] = 'foo';
Those properties are not part of the "data storage" of the array.
If you want "associative arrays", you need to use an object:
var obj = {};
obj['a'] = 'foo';
Maybe the simplest visualization is using the literal notation instead of new Array:
// numerically indexed Array
var array = ['foo', 'bar', 'baz'];
// associative Object
var dict = { foo : 42, bar : 'baz' };
Because the length is defined to be one plus the largest numeric index in the array.
var xs = [];
xs[10] = 17;
console.log( xs.length ); //11
For this reason, you should only use arrays for storing things indexed by numbers, using plain objects instead if you want to use strings as keys. Also, as a sidenote, it is a better practice to use literals like [] or {} instead of new Array and new Object.
You're not adding items to the array; you're adding properties to the Array object.
As said above, use object for associative arrays.
If you don't you won't necessarily notice you're doing it wrong, until you innocently use "length" as an array index :
var myArray = [];
myArray["foo"] = "bar"; //works
console.log(myArray["foo"]) //print "bar"
myArray["length"] = "baz" //crash with a "RangeError: Invalid array length"
That is because you are replacing the length attribute of an array with a String, which is invalid.
"string keyed" indexes are not indexes at all, but properties. array2["a"] is the same as saying array2.a. Remember that you can set properties on any kind of variable in javascript, which is exactly what you're doing here.
You can push object to array, it will automatically get indexed (integer). If you want to add index as you want then you want to make it as object
If you want to use an object's properties as if they were like instances of a string indexed array, the work around for the length is:
var myArray = new Array();
myArray["a"] = 'foo';
myArray["b"] = 'bar';
myArray["c"] = 'baz';
let theLength = Object.keys(myArray).length
I have placed my frustrations into a jsfiddle to observe here: http://jsfiddle.net/8ShFr/1/
var brand_new_array = new Array();
brand_new_array[10] = "random array value";
alert('why does this array have a length of ' + brand_new_array.length + '???');
I am doing some calculations client side that require me to set javascript array keys of 1M+ in number.
Not knowing exactly what that number is demands that I iterate through the first 1M+ empty array values before getting to an array key that holds data.
I simply want to set a single large key value for a javascript array without creating a bunch of empty keys before it?
I am using jQuery.each to iterate over the array, and it keeps going through array[0], array[1], array[2], etc... when I only set array[123125] for example.
Just filter out the undefineds.
brand_new_array = brand_new_array.filter(function(n){return n !== undefined});
The reason for the length being 10 is that an array's length is set to the largest index number in the array. However, this does not mean there are 9 other values in there because in javascript an array is at its base an object.
The length is just a property in the object. Arrays in javascript are at their core objects (Array Object 1). They merely act like arrays through an api.
"Whenever a property is added whose name is an array index, the length property is changed, if necessary, to be one more than the numeric value of that array index" 1
1. ECMAScript Language Specification 15.4 Array Objects
You probably want to just use an object with strings for keys (the keys can be the toString() of Numbers, which will happen automatically if you try to use numbers).
var sparse_array_obj = {};
sparse_array_obj[10003210234] = 4; // Fair dice roll
sparse_array_obj[5] = 17; // Truly random number
sparse_array_obj[900] = Math.random(); // Pseudorandom number
for(var i in sparse_array_obj)
console.log(sparse_array_obj[i]);
The downside is that Javascript provides no guarantees about the iteration order through an object (since its keys are unordered by definition). There are however ways around this, such as:
// Sort the keys in numeric order
var sorted_keys = Object.keys(sparse_array_obj).sort(function(a, b){ return a - b; });
for(var i = 0; i < sorted_keys.length; i++)
console.log(sparse_array_obj[sorted_keys[i]]);
Object.keys needs to be shimmed in older browsers.
var brand_new_array = new Array();
brand_new_array[10] = "random array value";
var result = brand_new_array.filter(function(e) { return e != undefined;})[0];
alert(brand_new_array.indexOf(result));
Travis J is right. The array in your example only contains one entry, but your use of jQuery.each() is making you think there are 10 entries because it iterates from 0 up to the highest index number of the array (defines the length). This is from the jQuery.each() API documentation.
A generic iterator function, which can be used to seamlessly iterate over both objects and arrays. Arrays and array-like objects with a length property (such as a function's arguments object) are iterated by numeric index, from 0 to length-1. Other objects are iterated via their named properties.
Going back to your example:
var brand_new_array = new Array();
brand_new_array[10] = "random array value";
This will result in only one console.log output:
for(var i in brand_new_array)
console.log(brand_new_array[i]);
This will result in 10 console.log outputs:
$(brand_new_array).each( function(i,e) { console.log(e) })
Similarly, this will result in 10 console.log outputs:
for (var i=0;i<brand_new_array.length;i++)
console.log(brand_new_array[i]);
If you really want to stick with using .each() then you can skip the undefined indices like so:
$(brand_new_array).each( function(i,e) {
if (this.hasOwnProperty(i)){ console.log(e) }
})
Filter the falsy items - including undifined:
var a=[1,2,"b",0,{},"",NaN,3,undefined,null,5];
var b=a.filter(Boolean); // [1,2,"b",{},3,5]
The length is 11 because the index starts at 0.
x[0] = undefined
x[1] = undefined
x[2] = undefined
x[3] = undefined
x[4] = undefined
x[5] = undefined
x[6] = undefined
x[7] = undefined
x[8] = undefined
x[9] = undefined
x[10] = "random array value"
I am creating javascript two dimensional array
code is :
var field_arr=[];
$(".dr").each(function(index){
Id=$(this).attr("id");
alert(dragId);
topPos=$("#"+ dragId).position().top;
left=$("#"+ dragId).position().left;
parentDiv=$("#"+dragId).parent().attr("id");
parentDiv= parentDiv.split('-');
paId=parentDiv[1];
field_arr[Id]=new Array();
field_arr[Id]['paId']=paId;
field_arr[Id]['top']=topPos;
field_arr[Id]['left']=left;
});
console.log(field_arr);
Output Is:
[undefined, [] left 140 paId "1" top 10
What is problem in It Any help Should be appreciated.
The problem is in the display method of your arrays. The information is there, but both alert and console.log will not show it to you because it is expected that the only interesting properties of arrays are the ones with numeric indexes.
In JavaScript, unlike PHP, objects are used as maps/associative arrays.
First to check that your information is actually there:
$(".dr").each(function(index){
var Id=$(this).attr("id");
console.log(Id, field_arr[Id]['paId'], field_arr[Id]['top'], field_arr[Id]['left']);
});
Now to make make the display methods work you can go about multiple ways, but the best one is to use objects instead:
var field_arr = Object.create(null); // replace with {} if you want to support IE8-
$(".dr").each(function(index){
var id = $(this).attr("id"); // added var to keep variable local
var drag = $("#"+dragId);
field_arr[id] = Object.create(null); // {}
field_arr[id]['paId'] = drag.parent().attr("id").split('-')[1];
field_arr[id]['top'] = drag.position().top;
field_arr[id]['left'] = drag.position().left;
});
console.log(field_arr);
Iterating over properties of objects is quite easy:
for (var id in field_arr) {
console.log(field_arr[id], field_arr[id]['paId'], 'etc');
}
Add a hasOwnProperty check if your object doesn't inherit from null (var obj = {} needs it, unlike var obj = Object.create(null))
you're storing values with a key string and its wrong because you declared your field_arr as a numerical array (well there's no such thing as associative array in javascript i think).
field_arr[Id] = new Array();
field_arr[Id]['paId']=paId; //this is wrong
You need to create an object to store in values as if they are associated with string keys. But literally they are object properties
redeclare it like this
field_arr[Id] = {}; //you create an object
field_arr[Id]['paId'] = paId; //create an object property named paId and store a value
field_arr[Id].paId = paId; //you can also access property paId like this
EDIT:
but to conform to you current code you can access your indexes using strings by accessing it like a property of an object. (Thanks to Tibos)
var field_arr=[];
...
...
field_arr[Id].paId = paId;
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
What is the difference between an array and an object?
The item exists in the array but it says that the array is 0 length?
I m a bit confused in object and associative array in javascript. I read this :question but this question says that there is not much of a difference in both. I wrote this in the console:
var a = [];
a["A"] = 1;
var b = {};
b["B"] = 2;
var c = new Object();
c["C"] = 3;
output for above are as:
a gives {A : 1}
b gives {B : 2}
c gives {C : 3}
All above three cases gives same reault as in they all gives an object. Question is how all above 3 cases are treated in javascript.
An array is also an object, that's why you can use non-numeric indices also. Those will be added as properties to the array object, not part of the array data.
The difference between an array and an object, is that the array counts properties with a numeric index as being part of the array data, and updates the length property accordingly. (Also the Array object has some specific methods to work with the array data.)
var a = [];
a[42] = 1337;
Now the length has changed to include the item:
alert(a.length); // shows 43
Using strings or numbers as index doesn't matter, a numeric index counts even if it's a string:
alert(a[42]); // shows 1337
alert(a["42"]); // shows 1337
Reducing the length removes the properties outside it:
a.length = 10;
alert(a[42]); // shows undefined
In your example, b and c are essentially the same thing, because {} is the equivalent of new Object().
Coming back to a, it's defined as an Array which is a special kind of Object in the sense that numeric properties (based on uint32) are treated differently. Its length property gets updated when those properties are added and removed.
When you use 'A' as an index, it gets treated as a regular property, defined by how Object works with properties, so you can access it as a.A or a['A'] whereas an index of [5] can only be accessed using a[5].
Normally, the debug output of an array is always [] unless the length property is non-zero, so the output you've shown is somewhat irregular.
Trivia
According to the ECMAScript documentation, a particular value p can only be an array index if and only if:
(p >>> 0 === p) && (p >>> 0 !== Math.pow(2, 32) - 1)
See also:
The item exists in the array but it says that the array is 0 length?
Let's start by clarifying something:
new Object() is the same as {}
new Array() is the same as []
The latter are just shortened forms of the former.
Behind the scenes, everything in javascript is basically an object (this is an exaggeration but fairly accurate). Arrays are simply derived from objects. Here's a fairly rudimentary example of what an Array REALLY looks like:
var myArray = {};
myArray[0] = 'value1';
myArray[1] = 'value2';
myArray[2] = 'value3';
myArray[length] = 3;
The prototype of an array contains all the methods. For example:
// myArray#push
myArray.prototype.push = function(val){
myArray[this.length] = val;
this.length++;
}
Another way to illustrate this is to take an array and add keys that are not numeric:
var example = [];
example.push(0);
example.push(1);
example.push(2);
example['a'] = 'a';
example['b'] = 'b';
example['c'] = 'c';
example.log = function(){
for(var i = 0, l = this.length; i < l; i++){
console.log( example[i] );
}
console.log(this['a']);
console.log(this['b']);
console.log(this['c']);
}
// example[0] is 0
// example[1] is 1
// example[2] is 2
// example.log is my custom function
example.log(); // results in
// 0
// 1
// 2
// a
// b
// c
Also, don't always believe everything the console tells you. For example, if you do this:
var console_confusion = {};
console_confusion.length = 100;
console_confusion.splice = function(){ /* do absolutely nothing */ };
console.log( console_confusion );//results in
//
// in Chrome:
// [undefined × 100]
//
Chrome will interprut anything with a numeric length property and a splice function as an Array. This is why jQuery objects look like Arrays in the console.
Please read the following article – http://www.2ality.com/2012/12/arrays.html
In short, “regular arrays”, denoted as [] in JavaScript, are also objects, just like {}, but they have length property and “numeric” keys (“indicies”), plus their internal __proto__ property points at Array.prototype object, which holds all Array methods, such as push or forEach etc.
first is an array
second is an object array
third is an array object
In the example below, the array2.length is only 10, while in my mind, it should be 13.
Why does the "string keyed" indexes not increase the length of the array?
I can store things and still access it, and the VS debugger shows that those arrays are being stored properly. So why is the length not increased?
var array2 = new Array();
array2["a"] = new Array();
array2["b"] = new Array();
array2["c"] = new Array();
for (var i = 0; i < 10; ++i)
array2[i] = new Array();
var nothing = "";
for (var i = 0; i < array2.length; ++i)
nothing = "";
Javascript arrays cannot have "string indexes". A Javascript Array is exclusively numerically indexed. When you set a "string index", you're setting a property of the object. These are equivalent:
array.a = 'foo';
array['a'] = 'foo';
Those properties are not part of the "data storage" of the array.
If you want "associative arrays", you need to use an object:
var obj = {};
obj['a'] = 'foo';
Maybe the simplest visualization is using the literal notation instead of new Array:
// numerically indexed Array
var array = ['foo', 'bar', 'baz'];
// associative Object
var dict = { foo : 42, bar : 'baz' };
Because the length is defined to be one plus the largest numeric index in the array.
var xs = [];
xs[10] = 17;
console.log( xs.length ); //11
For this reason, you should only use arrays for storing things indexed by numbers, using plain objects instead if you want to use strings as keys. Also, as a sidenote, it is a better practice to use literals like [] or {} instead of new Array and new Object.
You're not adding items to the array; you're adding properties to the Array object.
As said above, use object for associative arrays.
If you don't you won't necessarily notice you're doing it wrong, until you innocently use "length" as an array index :
var myArray = [];
myArray["foo"] = "bar"; //works
console.log(myArray["foo"]) //print "bar"
myArray["length"] = "baz" //crash with a "RangeError: Invalid array length"
That is because you are replacing the length attribute of an array with a String, which is invalid.
"string keyed" indexes are not indexes at all, but properties. array2["a"] is the same as saying array2.a. Remember that you can set properties on any kind of variable in javascript, which is exactly what you're doing here.
You can push object to array, it will automatically get indexed (integer). If you want to add index as you want then you want to make it as object
If you want to use an object's properties as if they were like instances of a string indexed array, the work around for the length is:
var myArray = new Array();
myArray["a"] = 'foo';
myArray["b"] = 'bar';
myArray["c"] = 'baz';
let theLength = Object.keys(myArray).length