First of all i know there are multiple topics about this on stackoverflow, i read most of them but i still cant figure out why the following is not working.
So i have a form like this:
echo "<td> <form action=\"admin.php\" method=\"GET\" onsubmit=\" modifyPassword();\">
this is the modifyPassword function:
function modifyPassword(){
var newpw=prompt("Enter a new password");
if(newpw !== null){
$.ajax({
type: "GET",
url: "admin.php",
data: newpw,
success: function(data)
{
console.log(data);
}
});
}}
And when the form is actually submitted i want to get the value from what is typed in like this:
echo $_GET['data'];
This is all in the same file.
The output of $_GET['data'] does not show anything.
Can someone tell me what i am doing wrong?
//edit, more code:
I am using multiple forms, so here is the code that handles the form:
}elseif (isset($_GET['Modify'])){
echo $_GET['data'];
Form itself:
echo "<td> <form action=\"admin.php\" method=\"GET\" onsubmit=\" modifyPassword();\">
<input type='hidden' name='counter' value=\"$count\"/>
<input type=\"submit\" value=\"Modify\" name=\"Modify\"/>
Function that is provided:
<script type="text/javascript">
function modifyPassword(){
var newpw=prompt("Enter a new password");
if(newpw !== null){
$.ajax({
type: "GET",
url: "admin.php",
data: {data: newpw}, // passing a key/value pair
success: function(data)
{
console.log(data);
}
});
}}
</script>
data: newpw, should be data: {data: newpw}, This will result in $_GET['data'] being populated. In this case 'data' becomes the key, while 'newpw' is the value.
function modifyPassword(){
var newpw=prompt("Enter a new password");
if(newpw !== null){
$.ajax({
type: "GET",
url: "admin.php",
data: {data: newpw}, // passing a key/value pair
success: function(data)
{
console.log(data);
}
});
}}
I will argue that you should not use so many variables with the same name - just to make things less confusing during bug hunting.
Related
I use typeahead.js to put tags for my multiple input. The tags input function correctly except the fact that its autocomplete suggestion does not come out. Is there any way to correct this problem?
I've tried most solution related to my problem that are already on this site but currently still not be able to display the autocomplete suggestion. I am always stuck at the successful ajax response and that's it.
my jquery:
<script>
$("#s_to").tagsinput({
tagClass: 'uk-badge',
typeaheadjs: {
source: function(query) {
console.log(query);
url = "<?php echo base_url(); ?>index.php/<?php echo $loc_pts; ?>/ajax_email";
var s_to = extractLast(query);
ajax_status = "fail";
$.ajax({
url: url,
method: "POST",
data: {
s_to: s_to
},
async: false,
dataType: "json",
success: function(json){
return json.s_to;
}
});
}
}
});
</script>
my input :
<input required type="text" name="s_to" id="s_to" class="controls uk-autocomplete-results" value="<?php echo $s_client_email; ?>" autocomplete="on" data-provide="typeaheadjs" />
my related script:
<script src="<?php echo base_url(); ?>assets/bower_components/typeahead.js/typeahead.jquery.min.js"></script>
console log output screen shot
Supposedly the input able to receive multiple input and each input seleccted will be displayed inside a tag. What make it harder is that no error message displayed. Thus, I know that my ajax is done correctly.
The main issue is that you do not return the array in correct scope. Your return json.s_to; is inside the ajax success function, but you need to return the value in parent scope. So, the code should be like this:
$("#s_to").tagsinput({
tagClass: 'uk-badge',
typeaheadjs: {
source: function(query) {
console.log(query);
url = "<?php echo base_url(); ?>index.php/<?php echo $loc_pts; ?>/ajax_email";
var s_to = extractLast(query);
ajax_status = "fail";
var toReturn = [];
$.ajax({
url: url,
method: "POST",
data: {
s_to: s_to
},
async: false,
dataType: "json",
success: function(json) {
toReturn = json.s_to;
}
});
/* This is the correct scope to return the array */
return toReturn;
}
}
});
I am trying to send values to other page Using Ajax
But i am unable to receive those values , i don't know where i am wrong
here is my code
<script type="text/javascript">
function get_more_info() { // Call to ajax function
var fval = document.getElementById('get_usecompny').value;
var dataString1 = "fval="+fval;
alert(fval);
var sval = document.getElementById('country').value;
var dataString2 = "sval="+sval;
alert(sval);
$.ajax({
type: "POST",
url: "getmoreinfo.php", // Name of the php files
data: "{'data1':'" + dataString1+ "', 'data2':'" + dataString2+ "'}",
success: function(html)
{
$("#get_more_info_dt").html(html);
}
});
}
</script>
in alert i am getting those value but in page 'getmoreinfo.php' i am not receiving any values
here is my 'getmoreinfo.php' page code
if ($_POST) {
$country = $_POST['fval'];
$country1 = $_POST['sval'];
echo $country1;
echo "<br>";
echo $country;
}
Please let me know where i am wrong .! sorry for bad English
You are passing the parameters with different names than you are attempting to read them with.
Your data: parameter could be done much more simply as below
<script type="text/javascript">
function get_more_info() { // Call to ajax function
var fval = document.getElementById('get_usecompny').value;
var sval = document.getElementById('country').value;
$.ajax({
type: "POST",
url: "getmoreinfo.php", // Name of the php files
data: {fval: fval, sval: sval},
success: function(html)
{
$("#get_more_info_dt").html(html);
}
});
}
</script>
Or cut out the intermediary variables as well and use the jquery method of getting data from an element with an id like this.
<script type="text/javascript">
function get_more_info() { // Call to ajax function
$.ajax({
type: "POST",
url: "getmoreinfo.php", // Name of the php files
data: { fval: $("#get_usecompny").val(),
sval: $("#country").val()
},
success: function(html)
{
$("#get_more_info_dt").html(html);
}
});
}
</script>
No need to create 'dataString' variables. You can present data as an object:
$.ajax({
...
data: {
'fval': fval,
'sval': sval
},
...
});
In your PHP, you can then access the data like this:
$country = $_POST['fval'];
$country1 = $_POST['sval'];
The property "data" from JQuery ajax object need to be a simple object data. JQuery will automatically parse object as parameters on request:
$.ajax({
type: "POST",
url: "getmoreinfo.php",
data: {
fval: document.getElementById('get_usecompny').value,
sval: document.getElementById('country').value
},
success: function(html) {
$("#get_more_info_dt").html(html);
}
});
I'm trying to send a input value to php via ajax but I can't seem to get this right. I'm trying to create a datatable based on the user input.
This is my code:
<input class="form-control" id="id1" type="text" name="id1">
My javascript code:
<script type="text/javascript">
$(document).ready(function() {
var oTable = $('#jsontable').dataTable(); //Initialize the datatable
$('#load').on('click',function(){
var user = $(this).attr('id');
if(user != '')
{
$.ajax({
url: 'response.php?method=fetchdata',
data: {url: $('#id1').val()},
dataType: 'json',
success: function(s){
console.log(s);
oTable.fnClearTable();
for(var i = 0; i < s.length; i++) {
oTable.fnAddData([
s[i][0],
s[i][1],
s[i][2],
s[i][3],
s[i][4],
s[i][5],
s[i][6],
s[i][7]
]);
} // End For
},
error: function(e){
console.log(e.responseText);
}
});
}
});
});
</script>
My php script:
<?php
$conn = pg_connect(...);
$id1 = $_POST["id1"];
$result = pg_query_params($conn, 'SELECT * FROM t WHERE id1 = $1 LIMIT 20', array($id1));
while($fetch = pg_fetch_row($result)) {
$output[] = array ($fetch[0],$fetch[1],$fetch[2],$fetch[3],$fetch[4],$fetch[5],$fetch[6],$fetch[7]);
}
echo json_encode($output);
?>
I don't know a lot of js but my php is correct i test it. So i guess the problem is in the javascript code.
The problem is, my datatable is not being created based on the user input.
Thank you!
change
data: {url: $('#id1').val()},
to:
type: 'POST',
data: {id1: $('#id1').val()},
However the problem might be bigger. You might not be getting the correct data from PHP. You can debug by adding the error option to your ajax() call, like this:
$.ajax({
url: 'response.php?method=fetchdata',
type: 'POST',
data: {id1: $('#id1').val()},
dataType: 'json',
success: function(s){
},
error: function (xhr, status, errorThrown) {
console.log(xhr.status);
console.log(xhr.responseText);
}
});
Then check your browser's Console for the output, this should give you some type of error message coming from PHP.
My assumption is that since you are using dataType: 'json', the ajax request expects JSON headers back, but PHP is sending HTML/Text. To fix, add the correct headers before echoing your JSON:
header('Content-Type: application/json');
echo json_encode($output);
I have this button
<button id="<?php echo $u['id']?>" name="activation" onclick="handleButton(this);" type="submit" class="btn btn-success"></button>
And this button related to this
<td id="<?php echo $u['id']?>"><?php echo $u['id']?></td>
I'm using this script to send value of button to my php controller
function handleButton(obj) {
var javascriptVariable = obj.id;
// alert (javascriptVariable);
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/admin/active_users",
dataType: 'text',
data: 'myname='+javascriptVariable,
success: function (data){
}
});
}
When I use alert, the result of javascriptVariable is correct and I want it in my controller so I'm trying in my controller to do this:
if(isset($_POST['activation']))
{
$name = $this->input->post('myname');
var_dump($name);
}
But I get null value, what is the wrong?
When you pass data from the browser via AJAX only the data you pass in the data: parameter is sent to the PHP script.
So if you want to test for activation in the PHP script you must actually send that parameter
Also see the amendment to the data: parameter creation below. Its easier to read and a lot easier to code correctly when passing more than one parameter as you dont have to remember &'s and + concatenation.
function handleButton(obj) {
obj.preventDefault();
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/admin/active_users",
dataType: 'text',
data: {activation: 1, myname: obj.id}, // add parameter
success: function (data){
alert(data);
}
});
}
Now the PHP will see 2 parameters in the $_POST array activation and myname
if(isset($_POST['activation']))
{
$name = $_POST['myname'];
var_dumb($name);
}
Or if you are using a framework which I assume you are
if(isset($this->input->post('activation')) {
$name = $this->input->post('myname');
var_dumb($name);
}
EDIT:
Spotted another issue your button has an attribute type="submit" this will cause the javascript to run AS WELL AS the form being submitted in the normal way.
Remove the type="submit" attribute and to be doubly sure that the form will not be submitted as well as the AJAX add a call to preventDefault(); as well before the AJAX call
Since the php script is conditioned by a second POST variable [if(isset($_POST['activation']))], you should post that as well.
function handleButton(obj) {
var javascriptVariable = obj.id;
// alert (javascriptVariable);
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/admin/active_users",
dataType: 'text',
data: 'myname='+javascriptVariable+'&activation=1',// <-- RIGHT HERE
success: function (data){
alert(data);
}
});
}
SIDE NOTE: you could also echo instead of dump the variable:
if(isset($_POST['activation']))
{
echo $this->input->post('myname');
}
Try this in your ajax function :
function handleButton(obj) {
var javascriptVariable = obj.id;
//alert (javascriptVariable);
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/admin/active_users",
dataType: 'text',
data: {myname: javascriptVariable},
success: function (data) {}
});
}
And in your PHP script, you can do $_POST['myname'] to get it (maybe $this->input->post('myname') can work, you can test it)
Look two id
<button id="<?php echo $u['id']?>" name="activation" onclick="handleButton(this);" type="submit" class="btn btn-success"></button>
AND
<td id="<?php echo $u['id']?>"><?php echo $u['id']?></td>
For both html elements id is same.It can not be used with in the same page.This may cause a problem for you...
I've search for many solution but without success.
I have a html form;
<form id="objectsForm" method="POST">
<input type="submit" name="objectsButton" id="objectsButton">
</form>
This is used for a menu button.
I'm using jquery to prevent the site from refreshing;
$('#objectsForm').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: '/php/objects.php',
data: $('#objectsForm').serialize(),
success: function () {
alert('success');
}
});
});
In my php file I try to echo text to the body of my site;
<?php
if (isset($_POST["objectsButton"])){
echo '<div id="success"><p>objects</p></div>';
} else {
echo '<div id="fail"><p>nope</p></div>';
}
?>
I know the path to my php file is correct, but it doesn't show anything? Not even the "fail div".
Does anyone has a solution for me?
Thanks in advance!
The success function takes two parameters. The first parameter is what is returned from the php file. Try changing it to:
success: function (xhr){ alert(xhr);}
Based in your php source..
$.ajax({
type: 'post',
dataType: "html", // Receive html content
url: '/php/objects.php',
data: $('#objectsForm').serialize(),
success: function (result) {
$('#divResult').html(result);
}
});
PHP scripts run on the server, that means any echo you do won't appear at the user's end.
Instead of echoing the html just echo a json encoded success/ failure flag e.g. 0 or 1.
You'll be able to get that value in your success function and use jQuery to place divs on the web page.
PHP:
<?php
if (isset($_POST["objectsButton"])){
echo json_encode(1); // for success
} else {
echo json_encode(0); // for failure
}
?>
jQuery:
var formData = $('#objectsForm').serializeArray();
formData.push({name:this.name, value:this.value });
$.ajax({
type: 'post',
url: '/php/objects.php',
dataType: 'json',
data: formData,
success: function (response) {
if (response == 1) {
alert('success');
} else {
alert('fail');
}
}
});
EDIT:
To include the button, try using the following (just before the $.ajax block, see above):
formData.push({name:this.name, value:this.value });
Also, have the value attribute for your button:
<input type="submit" name="objectsButton" value="objectsButton" id="objectsButton">