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Why i can't compare two objects in javascript? [duplicate]

This question already has answers here:
How to determine equality for two JavaScript objects?
(82 answers)
Closed 6 years ago.
What is the best way to compare objects in JavaScript?
Example:
var user1 = {name : "nerd", org: "dev"};
var user2 = {name : "nerd", org: "dev"};
var eq = user1 == user2;
alert(eq); // gives false
I know that two objects are equal if they refer to the exact same object, but is there a way to check if they have the same attributes' values?
The following way works for me, but is it the only possibility?
var eq = Object.toJSON(user1) == Object.toJSON(user2);
alert(eq); // gives true

Unfortunately there is no perfect way, unless you use _proto_ recursively and access all non-enumerable properties, but this works in Firefox only.
So the best I can do is to guess usage scenarios.
1) Fast and limited.
Works when you have simple JSON-style objects without methods and DOM nodes inside:
JSON.stringify(obj1) === JSON.stringify(obj2)
The ORDER of the properties IS IMPORTANT, so this method will return false for following objects:
x = {a: 1, b: 2};
y = {b: 2, a: 1};
2) Slow and more generic.
Compares objects without digging into prototypes, then compares properties' projections recursively, and also compares constructors.
This is almost correct algorithm:
function deepCompare () {
var i, l, leftChain, rightChain;
function compare2Objects (x, y) {
var p;
// remember that NaN === NaN returns false
// and isNaN(undefined) returns true
if (isNaN(x) && isNaN(y) && typeof x === 'number' && typeof y === 'number') {
return true;
}
// Compare primitives and functions.
// Check if both arguments link to the same object.
// Especially useful on the step where we compare prototypes
if (x === y) {
return true;
}
// Works in case when functions are created in constructor.
// Comparing dates is a common scenario. Another built-ins?
// We can even handle functions passed across iframes
if ((typeof x === 'function' && typeof y === 'function') ||
(x instanceof Date && y instanceof Date) ||
(x instanceof RegExp && y instanceof RegExp) ||
(x instanceof String && y instanceof String) ||
(x instanceof Number && y instanceof Number)) {
return x.toString() === y.toString();
}
// At last checking prototypes as good as we can
if (!(x instanceof Object && y instanceof Object)) {
return false;
}
if (x.isPrototypeOf(y) || y.isPrototypeOf(x)) {
return false;
}
if (x.constructor !== y.constructor) {
return false;
}
if (x.prototype !== y.prototype) {
return false;
}
// Check for infinitive linking loops
if (leftChain.indexOf(x) > -1 || rightChain.indexOf(y) > -1) {
return false;
}
// Quick checking of one object being a subset of another.
// todo: cache the structure of arguments[0] for performance
for (p in y) {
if (y.hasOwnProperty(p) !== x.hasOwnProperty(p)) {
return false;
}
else if (typeof y[p] !== typeof x[p]) {
return false;
}
}
for (p in x) {
if (y.hasOwnProperty(p) !== x.hasOwnProperty(p)) {
return false;
}
else if (typeof y[p] !== typeof x[p]) {
return false;
}
switch (typeof (x[p])) {
case 'object':
case 'function':
leftChain.push(x);
rightChain.push(y);
if (!compare2Objects (x[p], y[p])) {
return false;
}
leftChain.pop();
rightChain.pop();
break;
default:
if (x[p] !== y[p]) {
return false;
}
break;
}
}
return true;
}
if (arguments.length < 1) {
return true; //Die silently? Don't know how to handle such case, please help...
// throw "Need two or more arguments to compare";
}
for (i = 1, l = arguments.length; i < l; i++) {
leftChain = []; //Todo: this can be cached
rightChain = [];
if (!compare2Objects(arguments[0], arguments[i])) {
return false;
}
}
return true;
}
Known issues (well, they have very low priority, probably you'll never notice them):
objects with different prototype structure but same projection
functions may have identical text but refer to different closures
Tests: passes tests are from How to determine equality for two JavaScript objects?.

Here is my ES3 commented solution (gory details after the code):
function object_equals( x, y ) {
if ( x === y ) return true;
// if both x and y are null or undefined and exactly the same
if ( ! ( x instanceof Object ) || ! ( y instanceof Object ) ) return false;
// if they are not strictly equal, they both need to be Objects
if ( x.constructor !== y.constructor ) return false;
// they must have the exact same prototype chain, the closest we can do is
// test there constructor.
for ( var p in x ) {
if ( ! x.hasOwnProperty( p ) ) continue;
// other properties were tested using x.constructor === y.constructor
if ( ! y.hasOwnProperty( p ) ) return false;
// allows to compare x[ p ] and y[ p ] when set to undefined
if ( x[ p ] === y[ p ] ) continue;
// if they have the same strict value or identity then they are equal
if ( typeof( x[ p ] ) !== "object" ) return false;
// Numbers, Strings, Functions, Booleans must be strictly equal
if ( ! object_equals( x[ p ], y[ p ] ) ) return false;
// Objects and Arrays must be tested recursively
}
for ( p in y )
if ( y.hasOwnProperty( p ) && ! x.hasOwnProperty( p ) )
return false;
// allows x[ p ] to be set to undefined
return true;
}
In developing this solution, I took a particular look at corner cases, efficiency, yet trying to yield a simple solution that works, hopefully with some elegance. JavaScript allows both null and undefined properties and objects have prototypes chains that can lead to very different behaviors if not checked.
First I have chosen to not extend Object.prototype, mostly because null could not be one of the objects of the comparison and that I believe that null should be a valid object to compare with another. There are also other legitimate concerns noted by others regarding the extension of Object.prototype regarding possible side effects on other's code.
Special care must taken to deal the possibility that JavaScript allows object properties can be set to undefined, i.e. there exists properties which values are set to undefined. The above solution verifies that both objects have the same properties set to undefined to report equality. This can only be accomplished by checking the existence of properties using Object.hasOwnProperty( property_name ). Also note that JSON.stringify() removes properties that are set to undefined, and that therefore comparisons using this form will ignore properties set to the value undefined.
Functions should be considered equal only if they share the same reference, not just the same code, because this would not take into account these functions prototype. So comparing the code string does not work to guaranty that they have the same prototype object.
The two objects should have the same prototype chain, not just the same properties. This can only be tested cross-browser by comparing the constructor of both objects for strict equality. ECMAScript 5 would allow to test their actual prototype using Object.getPrototypeOf(). Some web browsers also offer a __proto__ property that does the same thing. A possible improvement of the above code would allow to use one of these methods whenever available.
The use of strict comparisons is paramount here because 2 should not be considered equal to "2.0000", nor false should be considered equal to null, undefined, or 0.
Efficiency considerations lead me to compare for equality of properties as soon as possible. Then, only if that failed, look for the typeof these properties. The speed boost could be significant on large objects with lots of scalar properties.
No more that two loops are required, the first to check properties from the left object, the second to check properties from the right and verify only existence (not value), to catch these properties which are defined with the undefined value.
Overall this code handles most corner cases in only 16 lines of code (without comments).
Update (8/13/2015). I have implemented a better version, as the function value_equals() that is faster, handles properly corner cases such as NaN and 0 different than -0, optionally enforcing objects' properties order and testing for cyclic references, backed by more than 100 automated tests as part of the Toubkal project test suite.

Utils.compareObjects = function(o1, o2){
for(var p in o1){
if(o1.hasOwnProperty(p)){
if(o1[p] !== o2[p]){
return false;
}
}
}
for(var p in o2){
if(o2.hasOwnProperty(p)){
if(o1[p] !== o2[p]){
return false;
}
}
}
return true;
};
Simple way to compare ONE-LEVEL only objects.

Certainly not the only way - you could prototype a method (against Object here but I certainly wouldn't suggest using Object for live code) to replicate C#/Java style comparison methods.
Edit, since a general example seems to be expected:
Object.prototype.equals = function(x)
{
for(p in this)
{
switch(typeof(this[p]))
{
case 'object':
if (!this[p].equals(x[p])) { return false }; break;
case 'function':
if (typeof(x[p])=='undefined' || (p != 'equals' && this[p].toString() != x[p].toString())) { return false; }; break;
default:
if (this[p] != x[p]) { return false; }
}
}
for(p in x)
{
if(typeof(this[p])=='undefined') {return false;}
}
return true;
}
Note that testing methods with toString() is absolutely not good enough but a method which would be acceptable is very hard because of the problem of whitespace having meaning or not, never mind synonym methods and methods producing the same result with different implementations. And the problems of prototyping against Object in general.

The following algorithm will deal with self-referential data structures, numbers, strings, dates, and of course plain nested javascript objects:
Objects are considered equivalent when
They are exactly equal per === (String and Number are unwrapped first to ensure 42 is equivalent to Number(42))
or they are both dates and have the same valueOf()
or they are both of the same type and not null and...
they are not objects and are equal per == (catches numbers/strings/booleans)
or, ignoring properties with undefined value they have the same properties all of which are considered recursively equivalent.
Functions are not considered identical by function text. This test is insufficient because functions may have differing closures. Functions are only considered equal if === says so (but you could easily extend that equivalent relation should you choose to do so).
Infinite loops, potentially caused by circular datastructures, are avoided. When areEquivalent attempts to disprove equality and recurses into an object's properties to do so, it keeps track of the objects for which this sub-comparison is needed. If equality can be disproved, then some reachable property path differs between the objects, and then there must be a shortest such reachable path, and that shortest reachable path cannot contain cycles present in both paths; i.e. it is OK to assume equality when recursively comparing objects. The assumption is stored in a property areEquivalent_Eq_91_2_34, which is deleted after use, but if the object graph already contains such a property, behavior is undefined. The use of such a marker property is necessary because javascript doesn't support dictionaries using arbitrary objects as keys.
function unwrapStringOrNumber(obj) {
return (obj instanceof Number || obj instanceof String
? obj.valueOf()
: obj);
}
function areEquivalent(a, b) {
a = unwrapStringOrNumber(a);
b = unwrapStringOrNumber(b);
if (a === b) return true; //e.g. a and b both null
if (a === null || b === null || typeof (a) !== typeof (b)) return false;
if (a instanceof Date)
return b instanceof Date && a.valueOf() === b.valueOf();
if (typeof (a) !== "object")
return a == b; //for boolean, number, string, xml
var newA = (a.areEquivalent_Eq_91_2_34 === undefined),
newB = (b.areEquivalent_Eq_91_2_34 === undefined);
try {
if (newA) a.areEquivalent_Eq_91_2_34 = [];
else if (a.areEquivalent_Eq_91_2_34.some(
function (other) { return other === b; })) return true;
if (newB) b.areEquivalent_Eq_91_2_34 = [];
else if (b.areEquivalent_Eq_91_2_34.some(
function (other) { return other === a; })) return true;
a.areEquivalent_Eq_91_2_34.push(b);
b.areEquivalent_Eq_91_2_34.push(a);
var tmp = {};
for (var prop in a)
if(prop != "areEquivalent_Eq_91_2_34")
tmp[prop] = null;
for (var prop in b)
if (prop != "areEquivalent_Eq_91_2_34")
tmp[prop] = null;
for (var prop in tmp)
if (!areEquivalent(a[prop], b[prop]))
return false;
return true;
} finally {
if (newA) delete a.areEquivalent_Eq_91_2_34;
if (newB) delete b.areEquivalent_Eq_91_2_34;
}
}

I wrote this piece of code for object comparison, and it seems to work. check the assertions:
function countProps(obj) {
var count = 0;
for (k in obj) {
if (obj.hasOwnProperty(k)) {
count++;
}
}
return count;
};
function objectEquals(v1, v2) {
if (typeof(v1) !== typeof(v2)) {
return false;
}
if (typeof(v1) === "function") {
return v1.toString() === v2.toString();
}
if (v1 instanceof Object && v2 instanceof Object) {
if (countProps(v1) !== countProps(v2)) {
return false;
}
var r = true;
for (k in v1) {
r = objectEquals(v1[k], v2[k]);
if (!r) {
return false;
}
}
return true;
} else {
return v1 === v2;
}
}
assert.isTrue(objectEquals(null,null));
assert.isFalse(objectEquals(null,undefined));
assert.isTrue(objectEquals("hi","hi"));
assert.isTrue(objectEquals(5,5));
assert.isFalse(objectEquals(5,10));
assert.isTrue(objectEquals([],[]));
assert.isTrue(objectEquals([1,2],[1,2]));
assert.isFalse(objectEquals([1,2],[2,1]));
assert.isFalse(objectEquals([1,2],[1,2,3]));
assert.isTrue(objectEquals({},{}));
assert.isTrue(objectEquals({a:1,b:2},{a:1,b:2}));
assert.isTrue(objectEquals({a:1,b:2},{b:2,a:1}));
assert.isFalse(objectEquals({a:1,b:2},{a:1,b:3}));
assert.isTrue(objectEquals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}},{1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}));
assert.isFalse(objectEquals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}},{1:{name:"mhc",age:28}, 2:{name:"arb",age:27}}));
assert.isTrue(objectEquals(function(x){return x;},function(x){return x;}));
assert.isFalse(objectEquals(function(x){return x;},function(y){return y+2;}));

I have modified a bit the code above. for me 0 !== false and null !== undefined. If you do not need such strict check remove one "=" sign in "this[p] !== x[p]" inside the code.
Object.prototype.equals = function(x){
for (var p in this) {
if(typeof(this[p]) !== typeof(x[p])) return false;
if((this[p]===null) !== (x[p]===null)) return false;
switch (typeof(this[p])) {
case 'undefined':
if (typeof(x[p]) != 'undefined') return false;
break;
case 'object':
if(this[p]!==null && x[p]!==null && (this[p].constructor.toString() !== x[p].constructor.toString() || !this[p].equals(x[p]))) return false;
break;
case 'function':
if (p != 'equals' && this[p].toString() != x[p].toString()) return false;
break;
default:
if (this[p] !== x[p]) return false;
}
}
return true;
}
Then I have tested it with next objects:
var a = {a: 'text', b:[0,1]};
var b = {a: 'text', b:[0,1]};
var c = {a: 'text', b: 0};
var d = {a: 'text', b: false};
var e = {a: 'text', b:[1,0]};
var f = {a: 'text', b:[1,0], f: function(){ this.f = this.b; }};
var g = {a: 'text', b:[1,0], f: function(){ this.f = this.b; }};
var h = {a: 'text', b:[1,0], f: function(){ this.a = this.b; }};
var i = {
a: 'text',
c: {
b: [1, 0],
f: function(){
this.a = this.b;
}
}
};
var j = {
a: 'text',
c: {
b: [1, 0],
f: function(){
this.a = this.b;
}
}
};
var k = {a: 'text', b: null};
var l = {a: 'text', b: undefined};
a==b expected true; returned true
a==c expected false; returned false
c==d expected false; returned false
a==e expected false; returned false
f==g expected true; returned true
h==g expected false; returned false
i==j expected true; returned true
d==k expected false; returned false
k==l expected false; returned false

Here is my version, pretty much stuff from this thread is integrated (same counts for the test cases):
Object.defineProperty(Object.prototype, "equals", {
enumerable: false,
value: function (obj) {
var p;
if (this === obj) {
return true;
}
// some checks for native types first
// function and sring
if (typeof(this) === "function" || typeof(this) === "string" || this instanceof String) {
return this.toString() === obj.toString();
}
// number
if (this instanceof Number || typeof(this) === "number") {
if (obj instanceof Number || typeof(obj) === "number") {
return this.valueOf() === obj.valueOf();
}
return false;
}
// null.equals(null) and undefined.equals(undefined) do not inherit from the
// Object.prototype so we can return false when they are passed as obj
if (typeof(this) !== typeof(obj) || obj === null || typeof(obj) === "undefined") {
return false;
}
function sort (o) {
var result = {};
if (typeof o !== "object") {
return o;
}
Object.keys(o).sort().forEach(function (key) {
result[key] = sort(o[key]);
});
return result;
}
if (typeof(this) === "object") {
if (Array.isArray(this)) { // check on arrays
return JSON.stringify(this) === JSON.stringify(obj);
} else { // anyway objects
for (p in this) {
if (typeof(this[p]) !== typeof(obj[p])) {
return false;
}
if ((this[p] === null) !== (obj[p] === null)) {
return false;
}
switch (typeof(this[p])) {
case 'undefined':
if (typeof(obj[p]) !== 'undefined') {
return false;
}
break;
case 'object':
if (this[p] !== null
&& obj[p] !== null
&& (this[p].constructor.toString() !== obj[p].constructor.toString()
|| !this[p].equals(obj[p]))) {
return false;
}
break;
case 'function':
if (this[p].toString() !== obj[p].toString()) {
return false;
}
break;
default:
if (this[p] !== obj[p]) {
return false;
}
}
};
}
}
// at least check them with JSON
return JSON.stringify(sort(this)) === JSON.stringify(sort(obj));
}
});
Here is my TestCase:
assertFalse({}.equals(null));
assertFalse({}.equals(undefined));
assertTrue("String", "hi".equals("hi"));
assertTrue("Number", new Number(5).equals(5));
assertFalse("Number", new Number(5).equals(10));
assertFalse("Number+String", new Number(1).equals("1"));
assertTrue([].equals([]));
assertTrue([1,2].equals([1,2]));
assertFalse([1,2].equals([2,1]));
assertFalse([1,2].equals([1,2,3]));
assertTrue(new Date("2011-03-31").equals(new Date("2011-03-31")));
assertFalse(new Date("2011-03-31").equals(new Date("1970-01-01")));
assertTrue({}.equals({}));
assertTrue({a:1,b:2}.equals({a:1,b:2}));
assertTrue({a:1,b:2}.equals({b:2,a:1}));
assertFalse({a:1,b:2}.equals({a:1,b:3}));
assertTrue({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}.equals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}));
assertFalse({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}.equals({1:{name:"mhc",age:28}, 2:{name:"arb",age:27}}));
assertTrue("Function", (function(x){return x;}).equals(function(x){return x;}));
assertFalse("Function", (function(x){return x;}).equals(function(y){return y+2;}));
var a = {a: 'text', b:[0,1]};
var b = {a: 'text', b:[0,1]};
var c = {a: 'text', b: 0};
var d = {a: 'text', b: false};
var e = {a: 'text', b:[1,0]};
var f = {a: 'text', b:[1,0], f: function(){ this.f = this.b; }};
var g = {a: 'text', b:[1,0], f: function(){ this.f = this.b; }};
var h = {a: 'text', b:[1,0], f: function(){ this.a = this.b; }};
var i = {
a: 'text',
c: {
b: [1, 0],
f: function(){
this.a = this.b;
}
}
};
var j = {
a: 'text',
c: {
b: [1, 0],
f: function(){
this.a = this.b;
}
}
};
var k = {a: 'text', b: null};
var l = {a: 'text', b: undefined};
assertTrue(a.equals(b));
assertFalse(a.equals(c));
assertFalse(c.equals(d));
assertFalse(a.equals(e));
assertTrue(f.equals(g));
assertFalse(h.equals(g));
assertTrue(i.equals(j));
assertFalse(d.equals(k));
assertFalse(k.equals(l));

If you work without the JSON library, maybe this will help you out:
Object.prototype.equals = function(b) {
var a = this;
for(i in a) {
if(typeof b[i] == 'undefined') {
return false;
}
if(typeof b[i] == 'object') {
if(!b[i].equals(a[i])) {
return false;
}
}
if(b[i] != a[i]) {
return false;
}
}
for(i in b) {
if(typeof a[i] == 'undefined') {
return false;
}
if(typeof a[i] == 'object') {
if(!a[i].equals(b[i])) {
return false;
}
}
if(a[i] != b[i]) {
return false;
}
}
return true;
}
var a = {foo:'bar', bar: {blub:'bla'}};
var b = {foo:'bar', bar: {blub:'blob'}};
alert(a.equals(b)); // alert's a false

if you want to check for methods explicitly you can use the method.toSource() or method.toString() methods.

React Native state equality comparison returning unexpected value [duplicate]

This question already has answers here:
How to determine equality for two JavaScript objects?
(82 answers)
Closed 6 years ago.
What is the best way to compare objects in JavaScript?
Example:
var user1 = {name : "nerd", org: "dev"};
var user2 = {name : "nerd", org: "dev"};
var eq = user1 == user2;
alert(eq); // gives false
I know that two objects are equal if they refer to the exact same object, but is there a way to check if they have the same attributes' values?
The following way works for me, but is it the only possibility?
var eq = Object.toJSON(user1) == Object.toJSON(user2);
alert(eq); // gives true

Unfortunately there is no perfect way, unless you use _proto_ recursively and access all non-enumerable properties, but this works in Firefox only.
So the best I can do is to guess usage scenarios.
1) Fast and limited.
Works when you have simple JSON-style objects without methods and DOM nodes inside:
JSON.stringify(obj1) === JSON.stringify(obj2)
The ORDER of the properties IS IMPORTANT, so this method will return false for following objects:
x = {a: 1, b: 2};
y = {b: 2, a: 1};
2) Slow and more generic.
Compares objects without digging into prototypes, then compares properties' projections recursively, and also compares constructors.
This is almost correct algorithm:
function deepCompare () {
var i, l, leftChain, rightChain;
function compare2Objects (x, y) {
var p;
// remember that NaN === NaN returns false
// and isNaN(undefined) returns true
if (isNaN(x) && isNaN(y) && typeof x === 'number' && typeof y === 'number') {
return true;
}
// Compare primitives and functions.
// Check if both arguments link to the same object.
// Especially useful on the step where we compare prototypes
if (x === y) {
return true;
}
// Works in case when functions are created in constructor.
// Comparing dates is a common scenario. Another built-ins?
// We can even handle functions passed across iframes
if ((typeof x === 'function' && typeof y === 'function') ||
(x instanceof Date && y instanceof Date) ||
(x instanceof RegExp && y instanceof RegExp) ||
(x instanceof String && y instanceof String) ||
(x instanceof Number && y instanceof Number)) {
return x.toString() === y.toString();
}
// At last checking prototypes as good as we can
if (!(x instanceof Object && y instanceof Object)) {
return false;
}
if (x.isPrototypeOf(y) || y.isPrototypeOf(x)) {
return false;
}
if (x.constructor !== y.constructor) {
return false;
}
if (x.prototype !== y.prototype) {
return false;
}
// Check for infinitive linking loops
if (leftChain.indexOf(x) > -1 || rightChain.indexOf(y) > -1) {
return false;
}
// Quick checking of one object being a subset of another.
// todo: cache the structure of arguments[0] for performance
for (p in y) {
if (y.hasOwnProperty(p) !== x.hasOwnProperty(p)) {
return false;
}
else if (typeof y[p] !== typeof x[p]) {
return false;
}
}
for (p in x) {
if (y.hasOwnProperty(p) !== x.hasOwnProperty(p)) {
return false;
}
else if (typeof y[p] !== typeof x[p]) {
return false;
}
switch (typeof (x[p])) {
case 'object':
case 'function':
leftChain.push(x);
rightChain.push(y);
if (!compare2Objects (x[p], y[p])) {
return false;
}
leftChain.pop();
rightChain.pop();
break;
default:
if (x[p] !== y[p]) {
return false;
}
break;
}
}
return true;
}
if (arguments.length < 1) {
return true; //Die silently? Don't know how to handle such case, please help...
// throw "Need two or more arguments to compare";
}
for (i = 1, l = arguments.length; i < l; i++) {
leftChain = []; //Todo: this can be cached
rightChain = [];
if (!compare2Objects(arguments[0], arguments[i])) {
return false;
}
}
return true;
}
Known issues (well, they have very low priority, probably you'll never notice them):
objects with different prototype structure but same projection
functions may have identical text but refer to different closures
Tests: passes tests are from How to determine equality for two JavaScript objects?.

Here is my ES3 commented solution (gory details after the code):
function object_equals( x, y ) {
if ( x === y ) return true;
// if both x and y are null or undefined and exactly the same
if ( ! ( x instanceof Object ) || ! ( y instanceof Object ) ) return false;
// if they are not strictly equal, they both need to be Objects
if ( x.constructor !== y.constructor ) return false;
// they must have the exact same prototype chain, the closest we can do is
// test there constructor.
for ( var p in x ) {
if ( ! x.hasOwnProperty( p ) ) continue;
// other properties were tested using x.constructor === y.constructor
if ( ! y.hasOwnProperty( p ) ) return false;
// allows to compare x[ p ] and y[ p ] when set to undefined
if ( x[ p ] === y[ p ] ) continue;
// if they have the same strict value or identity then they are equal
if ( typeof( x[ p ] ) !== "object" ) return false;
// Numbers, Strings, Functions, Booleans must be strictly equal
if ( ! object_equals( x[ p ], y[ p ] ) ) return false;
// Objects and Arrays must be tested recursively
}
for ( p in y )
if ( y.hasOwnProperty( p ) && ! x.hasOwnProperty( p ) )
return false;
// allows x[ p ] to be set to undefined
return true;
}
In developing this solution, I took a particular look at corner cases, efficiency, yet trying to yield a simple solution that works, hopefully with some elegance. JavaScript allows both null and undefined properties and objects have prototypes chains that can lead to very different behaviors if not checked.
First I have chosen to not extend Object.prototype, mostly because null could not be one of the objects of the comparison and that I believe that null should be a valid object to compare with another. There are also other legitimate concerns noted by others regarding the extension of Object.prototype regarding possible side effects on other's code.
Special care must taken to deal the possibility that JavaScript allows object properties can be set to undefined, i.e. there exists properties which values are set to undefined. The above solution verifies that both objects have the same properties set to undefined to report equality. This can only be accomplished by checking the existence of properties using Object.hasOwnProperty( property_name ). Also note that JSON.stringify() removes properties that are set to undefined, and that therefore comparisons using this form will ignore properties set to the value undefined.
Functions should be considered equal only if they share the same reference, not just the same code, because this would not take into account these functions prototype. So comparing the code string does not work to guaranty that they have the same prototype object.
The two objects should have the same prototype chain, not just the same properties. This can only be tested cross-browser by comparing the constructor of both objects for strict equality. ECMAScript 5 would allow to test their actual prototype using Object.getPrototypeOf(). Some web browsers also offer a __proto__ property that does the same thing. A possible improvement of the above code would allow to use one of these methods whenever available.
The use of strict comparisons is paramount here because 2 should not be considered equal to "2.0000", nor false should be considered equal to null, undefined, or 0.
Efficiency considerations lead me to compare for equality of properties as soon as possible. Then, only if that failed, look for the typeof these properties. The speed boost could be significant on large objects with lots of scalar properties.
No more that two loops are required, the first to check properties from the left object, the second to check properties from the right and verify only existence (not value), to catch these properties which are defined with the undefined value.
Overall this code handles most corner cases in only 16 lines of code (without comments).
Update (8/13/2015). I have implemented a better version, as the function value_equals() that is faster, handles properly corner cases such as NaN and 0 different than -0, optionally enforcing objects' properties order and testing for cyclic references, backed by more than 100 automated tests as part of the Toubkal project test suite.

Utils.compareObjects = function(o1, o2){
for(var p in o1){
if(o1.hasOwnProperty(p)){
if(o1[p] !== o2[p]){
return false;
}
}
}
for(var p in o2){
if(o2.hasOwnProperty(p)){
if(o1[p] !== o2[p]){
return false;
}
}
}
return true;
};
Simple way to compare ONE-LEVEL only objects.

Certainly not the only way - you could prototype a method (against Object here but I certainly wouldn't suggest using Object for live code) to replicate C#/Java style comparison methods.
Edit, since a general example seems to be expected:
Object.prototype.equals = function(x)
{
for(p in this)
{
switch(typeof(this[p]))
{
case 'object':
if (!this[p].equals(x[p])) { return false }; break;
case 'function':
if (typeof(x[p])=='undefined' || (p != 'equals' && this[p].toString() != x[p].toString())) { return false; }; break;
default:
if (this[p] != x[p]) { return false; }
}
}
for(p in x)
{
if(typeof(this[p])=='undefined') {return false;}
}
return true;
}
Note that testing methods with toString() is absolutely not good enough but a method which would be acceptable is very hard because of the problem of whitespace having meaning or not, never mind synonym methods and methods producing the same result with different implementations. And the problems of prototyping against Object in general.

The following algorithm will deal with self-referential data structures, numbers, strings, dates, and of course plain nested javascript objects:
Objects are considered equivalent when
They are exactly equal per === (String and Number are unwrapped first to ensure 42 is equivalent to Number(42))
or they are both dates and have the same valueOf()
or they are both of the same type and not null and...
they are not objects and are equal per == (catches numbers/strings/booleans)
or, ignoring properties with undefined value they have the same properties all of which are considered recursively equivalent.
Functions are not considered identical by function text. This test is insufficient because functions may have differing closures. Functions are only considered equal if === says so (but you could easily extend that equivalent relation should you choose to do so).
Infinite loops, potentially caused by circular datastructures, are avoided. When areEquivalent attempts to disprove equality and recurses into an object's properties to do so, it keeps track of the objects for which this sub-comparison is needed. If equality can be disproved, then some reachable property path differs between the objects, and then there must be a shortest such reachable path, and that shortest reachable path cannot contain cycles present in both paths; i.e. it is OK to assume equality when recursively comparing objects. The assumption is stored in a property areEquivalent_Eq_91_2_34, which is deleted after use, but if the object graph already contains such a property, behavior is undefined. The use of such a marker property is necessary because javascript doesn't support dictionaries using arbitrary objects as keys.
function unwrapStringOrNumber(obj) {
return (obj instanceof Number || obj instanceof String
? obj.valueOf()
: obj);
}
function areEquivalent(a, b) {
a = unwrapStringOrNumber(a);
b = unwrapStringOrNumber(b);
if (a === b) return true; //e.g. a and b both null
if (a === null || b === null || typeof (a) !== typeof (b)) return false;
if (a instanceof Date)
return b instanceof Date && a.valueOf() === b.valueOf();
if (typeof (a) !== "object")
return a == b; //for boolean, number, string, xml
var newA = (a.areEquivalent_Eq_91_2_34 === undefined),
newB = (b.areEquivalent_Eq_91_2_34 === undefined);
try {
if (newA) a.areEquivalent_Eq_91_2_34 = [];
else if (a.areEquivalent_Eq_91_2_34.some(
function (other) { return other === b; })) return true;
if (newB) b.areEquivalent_Eq_91_2_34 = [];
else if (b.areEquivalent_Eq_91_2_34.some(
function (other) { return other === a; })) return true;
a.areEquivalent_Eq_91_2_34.push(b);
b.areEquivalent_Eq_91_2_34.push(a);
var tmp = {};
for (var prop in a)
if(prop != "areEquivalent_Eq_91_2_34")
tmp[prop] = null;
for (var prop in b)
if (prop != "areEquivalent_Eq_91_2_34")
tmp[prop] = null;
for (var prop in tmp)
if (!areEquivalent(a[prop], b[prop]))
return false;
return true;
} finally {
if (newA) delete a.areEquivalent_Eq_91_2_34;
if (newB) delete b.areEquivalent_Eq_91_2_34;
}
}

I wrote this piece of code for object comparison, and it seems to work. check the assertions:
function countProps(obj) {
var count = 0;
for (k in obj) {
if (obj.hasOwnProperty(k)) {
count++;
}
}
return count;
};
function objectEquals(v1, v2) {
if (typeof(v1) !== typeof(v2)) {
return false;
}
if (typeof(v1) === "function") {
return v1.toString() === v2.toString();
}
if (v1 instanceof Object && v2 instanceof Object) {
if (countProps(v1) !== countProps(v2)) {
return false;
}
var r = true;
for (k in v1) {
r = objectEquals(v1[k], v2[k]);
if (!r) {
return false;
}
}
return true;
} else {
return v1 === v2;
}
}
assert.isTrue(objectEquals(null,null));
assert.isFalse(objectEquals(null,undefined));
assert.isTrue(objectEquals("hi","hi"));
assert.isTrue(objectEquals(5,5));
assert.isFalse(objectEquals(5,10));
assert.isTrue(objectEquals([],[]));
assert.isTrue(objectEquals([1,2],[1,2]));
assert.isFalse(objectEquals([1,2],[2,1]));
assert.isFalse(objectEquals([1,2],[1,2,3]));
assert.isTrue(objectEquals({},{}));
assert.isTrue(objectEquals({a:1,b:2},{a:1,b:2}));
assert.isTrue(objectEquals({a:1,b:2},{b:2,a:1}));
assert.isFalse(objectEquals({a:1,b:2},{a:1,b:3}));
assert.isTrue(objectEquals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}},{1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}));
assert.isFalse(objectEquals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}},{1:{name:"mhc",age:28}, 2:{name:"arb",age:27}}));
assert.isTrue(objectEquals(function(x){return x;},function(x){return x;}));
assert.isFalse(objectEquals(function(x){return x;},function(y){return y+2;}));

I have modified a bit the code above. for me 0 !== false and null !== undefined. If you do not need such strict check remove one "=" sign in "this[p] !== x[p]" inside the code.
Object.prototype.equals = function(x){
for (var p in this) {
if(typeof(this[p]) !== typeof(x[p])) return false;
if((this[p]===null) !== (x[p]===null)) return false;
switch (typeof(this[p])) {
case 'undefined':
if (typeof(x[p]) != 'undefined') return false;
break;
case 'object':
if(this[p]!==null && x[p]!==null && (this[p].constructor.toString() !== x[p].constructor.toString() || !this[p].equals(x[p]))) return false;
break;
case 'function':
if (p != 'equals' && this[p].toString() != x[p].toString()) return false;
break;
default:
if (this[p] !== x[p]) return false;
}
}
return true;
}
Then I have tested it with next objects:
var a = {a: 'text', b:[0,1]};
var b = {a: 'text', b:[0,1]};
var c = {a: 'text', b: 0};
var d = {a: 'text', b: false};
var e = {a: 'text', b:[1,0]};
var f = {a: 'text', b:[1,0], f: function(){ this.f = this.b; }};
var g = {a: 'text', b:[1,0], f: function(){ this.f = this.b; }};
var h = {a: 'text', b:[1,0], f: function(){ this.a = this.b; }};
var i = {
a: 'text',
c: {
b: [1, 0],
f: function(){
this.a = this.b;
}
}
};
var j = {
a: 'text',
c: {
b: [1, 0],
f: function(){
this.a = this.b;
}
}
};
var k = {a: 'text', b: null};
var l = {a: 'text', b: undefined};
a==b expected true; returned true
a==c expected false; returned false
c==d expected false; returned false
a==e expected false; returned false
f==g expected true; returned true
h==g expected false; returned false
i==j expected true; returned true
d==k expected false; returned false
k==l expected false; returned false

Here is my version, pretty much stuff from this thread is integrated (same counts for the test cases):
Object.defineProperty(Object.prototype, "equals", {
enumerable: false,
value: function (obj) {
var p;
if (this === obj) {
return true;
}
// some checks for native types first
// function and sring
if (typeof(this) === "function" || typeof(this) === "string" || this instanceof String) {
return this.toString() === obj.toString();
}
// number
if (this instanceof Number || typeof(this) === "number") {
if (obj instanceof Number || typeof(obj) === "number") {
return this.valueOf() === obj.valueOf();
}
return false;
}
// null.equals(null) and undefined.equals(undefined) do not inherit from the
// Object.prototype so we can return false when they are passed as obj
if (typeof(this) !== typeof(obj) || obj === null || typeof(obj) === "undefined") {
return false;
}
function sort (o) {
var result = {};
if (typeof o !== "object") {
return o;
}
Object.keys(o).sort().forEach(function (key) {
result[key] = sort(o[key]);
});
return result;
}
if (typeof(this) === "object") {
if (Array.isArray(this)) { // check on arrays
return JSON.stringify(this) === JSON.stringify(obj);
} else { // anyway objects
for (p in this) {
if (typeof(this[p]) !== typeof(obj[p])) {
return false;
}
if ((this[p] === null) !== (obj[p] === null)) {
return false;
}
switch (typeof(this[p])) {
case 'undefined':
if (typeof(obj[p]) !== 'undefined') {
return false;
}
break;
case 'object':
if (this[p] !== null
&& obj[p] !== null
&& (this[p].constructor.toString() !== obj[p].constructor.toString()
|| !this[p].equals(obj[p]))) {
return false;
}
break;
case 'function':
if (this[p].toString() !== obj[p].toString()) {
return false;
}
break;
default:
if (this[p] !== obj[p]) {
return false;
}
}
};
}
}
// at least check them with JSON
return JSON.stringify(sort(this)) === JSON.stringify(sort(obj));
}
});
Here is my TestCase:
assertFalse({}.equals(null));
assertFalse({}.equals(undefined));
assertTrue("String", "hi".equals("hi"));
assertTrue("Number", new Number(5).equals(5));
assertFalse("Number", new Number(5).equals(10));
assertFalse("Number+String", new Number(1).equals("1"));
assertTrue([].equals([]));
assertTrue([1,2].equals([1,2]));
assertFalse([1,2].equals([2,1]));
assertFalse([1,2].equals([1,2,3]));
assertTrue(new Date("2011-03-31").equals(new Date("2011-03-31")));
assertFalse(new Date("2011-03-31").equals(new Date("1970-01-01")));
assertTrue({}.equals({}));
assertTrue({a:1,b:2}.equals({a:1,b:2}));
assertTrue({a:1,b:2}.equals({b:2,a:1}));
assertFalse({a:1,b:2}.equals({a:1,b:3}));
assertTrue({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}.equals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}));
assertFalse({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}.equals({1:{name:"mhc",age:28}, 2:{name:"arb",age:27}}));
assertTrue("Function", (function(x){return x;}).equals(function(x){return x;}));
assertFalse("Function", (function(x){return x;}).equals(function(y){return y+2;}));
var a = {a: 'text', b:[0,1]};
var b = {a: 'text', b:[0,1]};
var c = {a: 'text', b: 0};
var d = {a: 'text', b: false};
var e = {a: 'text', b:[1,0]};
var f = {a: 'text', b:[1,0], f: function(){ this.f = this.b; }};
var g = {a: 'text', b:[1,0], f: function(){ this.f = this.b; }};
var h = {a: 'text', b:[1,0], f: function(){ this.a = this.b; }};
var i = {
a: 'text',
c: {
b: [1, 0],
f: function(){
this.a = this.b;
}
}
};
var j = {
a: 'text',
c: {
b: [1, 0],
f: function(){
this.a = this.b;
}
}
};
var k = {a: 'text', b: null};
var l = {a: 'text', b: undefined};
assertTrue(a.equals(b));
assertFalse(a.equals(c));
assertFalse(c.equals(d));
assertFalse(a.equals(e));
assertTrue(f.equals(g));
assertFalse(h.equals(g));
assertTrue(i.equals(j));
assertFalse(d.equals(k));
assertFalse(k.equals(l));

If you work without the JSON library, maybe this will help you out:
Object.prototype.equals = function(b) {
var a = this;
for(i in a) {
if(typeof b[i] == 'undefined') {
return false;
}
if(typeof b[i] == 'object') {
if(!b[i].equals(a[i])) {
return false;
}
}
if(b[i] != a[i]) {
return false;
}
}
for(i in b) {
if(typeof a[i] == 'undefined') {
return false;
}
if(typeof a[i] == 'object') {
if(!a[i].equals(b[i])) {
return false;
}
}
if(a[i] != b[i]) {
return false;
}
}
return true;
}
var a = {foo:'bar', bar: {blub:'bla'}};
var b = {foo:'bar', bar: {blub:'blob'}};
alert(a.equals(b)); // alert's a false

if you want to check for methods explicitly you can use the method.toSource() or method.toString() methods.

How to compare two JSON have the same properties without order?

I have tried to compare those two JSON objects:
<input type="hidden" id="remoteJSON" name="remoteJSON" value='{"allowExternalMembers": "false", "whoCanJoin": "CAN_REQUEST_TO_JOIN"}' /><br />
<input type="hidden" id="localJSON" name="localJSON" value='{"whoCanJoin": "CAN_REQUEST_TO_JOIN", "allowExternalMembers": "false"}' /><br />
I got values with javascript and I tried to compare with : JSON.stringify(remoteJSON) == JSON.stringify(localJSON) but this return false: it seems that the order of the properties is important.
And I even tried deep compare with this solution and always got a false return.
Is there a fast way to do the issue with jQuery (i.e. libraries for comparing JSON) ?

Lodash _.isEqual allows you to do that:
var
remoteJSON = {"allowExternalMembers": "false", "whoCanJoin": "CAN_REQUEST_TO_JOIN"},
localJSON = {"whoCanJoin": "CAN_REQUEST_TO_JOIN", "allowExternalMembers": "false"};
console.log( _.isEqual(remoteJSON, localJSON) );
<script src="https://cdn.jsdelivr.net/npm/lodash#4.17.10/lodash.min.js"></script>

Lodash isEqual() method is the best way to compare two JSON object.
This will not consider the order of the keys in object and check for the equality of object. Example
const object1 = {
name: 'ABC',
address: 'India'
};
const object2 = {
address: 'India',
name: 'ABC'
};
JSON.stringify(object1) === JSON.stringify(object2)
// false
_.isEqual(object1, object2)
// true
Reference - https://lodash.com/docs/#isEqual
If sequence is not going to change than JSON.stringify() will be fast as compared to Lodash's isEqual() method.
Reference - https://www.measurethat.net/Benchmarks/Show/1854/0/lodash-isequal-test

DeepCompare method to compare two json objects..
deepCompare = (arg1, arg2) => {
if (Object.prototype.toString.call(arg1) === Object.prototype.toString.call(arg2)){
if (Object.prototype.toString.call(arg1) === '[object Object]' || Object.prototype.toString.call(arg1) === '[object Array]' ){
if (Object.keys(arg1).length !== Object.keys(arg2).length ){
return false;
}
return (Object.keys(arg1).every(function(key){
return deepCompare(arg1[key],arg2[key]);
}));
}
return (arg1===arg2);
}
return false;
}
console.log(deepCompare({a:1},{a:'1'})) // false
console.log(deepCompare({a:1},{a:1})) // true

This code will verify the json independently of param object order.
var isEqualsJson = (obj1,obj2)=>{
keys1 = Object.keys(obj1);
keys2 = Object.keys(obj2);
//return true when the two json has same length and all the properties has same value key by key
return keys1.length === keys2.length && Object.keys(obj1).every(key=>obj1[key]==obj2[key]);
}
var obj1 = {a:1,b:2,c:3};
var obj2 = {a:1,b:2,c:3};
console.log("json is equals: "+ isEqualsJson(obj1,obj2));
alert("json is equals: "+ isEqualsJson(obj1,obj2));

Easy way to compare two json string in javascript
var obj1 = {"name":"Sam","class":"MCA"};
var obj2 = {"class":"MCA","name":"Sam"};
var flag=true;
if(Object.keys(obj1).length==Object.keys(obj2).length){
for(key in obj1) {
if(obj1[key] == obj2[key]) {
continue;
}
else {
flag=false;
break;
}
}
}
else {
flag=false;
}
console.log("is object equal"+flag);

I adapted and modified the code from this tutorial to write a function that does a deep comparison of two JS objects.
const isEqual = function(obj1, obj2) {
const obj1Keys = Object.keys(obj1);
const obj2Keys = Object.keys(obj2);
if(obj1Keys.length !== obj2Keys.length) {
return false;
}
for (let objKey of obj1Keys) {
if (obj1[objKey] !== obj2[objKey]) {
if(typeof obj1[objKey] == "object" && typeof obj2[objKey] == "object") {
if(!isEqual(obj1[objKey], obj2[objKey])) {
return false;
}
}
else {
return false;
}
}
}
return true;
};
The function compares the respective values of the same keys for the two objects. Further, if the two values are objects, it uses recursion to execute deep comparison on them as well.
Hope this helps.

lodash will work, tested even for angular 5, http://jsfiddle.net/L5qrfx3x/
var remoteJSON = {"allowExternalMembers": "false", "whoCanJoin":
"CAN_REQUEST_TO_JOIN"};
var localJSON = {"whoCanJoin": "CAN_REQUEST_TO_JOIN",
"allowExternalMembers": "false"};
if(_.isEqual(remoteJSON, localJSON)){
//TODO
}
it works, for installation in angular, follow this

This function works for objects with simple primitives:
function compareObjects(o1, o2) {
const normalizedObj1 = Object.fromEntries(Object.entries(o1).sort(([k1], [k2]) => k1. localeCompare(k2)));
const normalizedObj2 = Object.fromEntries(Object.entries(o2).sort(([k1], [k2]) => k1. localeCompare(k2)));
return JSON.stringify(normalizedObj1) === JSON.stringify(normalizedObj2);
}
compareObjects({a: 1, b: 2}, {b: 2, a: 1}); // true
If the objects contain nested objects, it won't work because we need to normalize them recursively

This question reminds of how to determine equality for two JavaScript objects.
So, I would choose this general function
Compares JS objects:
function objectEquals(x, y) {
// if both are function
if (x instanceof Function) {
if (y instanceof Function) {
return x.toString() === y.toString();
}
return false;
}
if (x === null || x === undefined || y === null || y === undefined) { return x === y; }
if (x === y || x.valueOf() === y.valueOf()) { return true; }
// if one of them is date, they must had equal valueOf
if (x instanceof Date) { return false; }
if (y instanceof Date) { return false; }
// if they are not function or strictly equal, they both need to be Objects
if (!(x instanceof Object)) { return false; }
if (!(y instanceof Object)) { return false; }
var p = Object.keys(x);
return Object.keys(y).every(function (i) { return p.indexOf(i) !== -1; }) ?
p.every(function (i) { return objectEquals(x[i], y[i]); }) : false;
}

In VueJs function you can use this as well... A working solution using recursion. Base credits Samadhan Sakhale
check_objects(obj1, obj2) {
try {
var flag = true;
if (Object.keys(obj1).length == Object.keys(obj2).length) {
for (let key in obj1) {
if(typeof (obj1[key]) != typeof (obj2[key]))
{
return false;
}
if (obj1[key] == obj2[key]) {
continue;
}
else if(typeof (obj1[key]) == typeof (new Object()))
{
if(!this.check_objects(obj1[key], obj2[key])) {
return false;
}
}
else {
return false;
}
}
}
else {
return false
}
}
catch {
return false;
}
return flag;
},

We use the node-deep-equal project which implements the same deep-equal comparison as nodejs
A google serach for deep-equal on npm will show you many alternatives

If you are trying to compare those two objects with the same goal as mine: which is to deserialize just an valid object, in that case, I would recommend you to use the following method:
using Newtonsoft.Json;
try
{
var myObj = JsonConvert.DeserializeObject<**YourTargetObjectType**>(jsonString, new JsonSerializerSettings
{
MetadataPropertyHandling = MetadataPropertyHandling.Ignore,
MissingMemberHandling = MissingMemberHandling.Error
});
}catch (MissingMemberException mme)
{
throw;
}
If an error get caught, so your object does not belong to YourTargetObjectType. Otherwise it is good to go, and you can do the same for the second object.
The JsonSerializerSetings with the MissingMemberHandling do the trick. And in the mme exception object you can check which property property failed. This validates extra properties, missing ones and/or misspelled properties.
So in your case, you should have a Object which will be used as reference to compare both objects.

There is Intellij Idea plugin for this purpose: https://plugins.jetbrains.com/plugin/20169-json-comparator?preview=true
It sorts all fields and objects in arrays recursively

with JSONata simply use = operator
async function compare() {
const jsonEQObj = {
object1: {
name: 'ABC',
address: 'India'
},
object2: {
address: 'India',
name: 'ABC'
}
};
let isEqual = await jsonata('object1=object2').evaluate(jsonEQObj)
console.log(isEqual)
jsonEQObj.object1.name = 'X';
isEqual = await jsonata('object1=object2').evaluate(jsonEQObj)
console.log(isEqual)
}
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>JSONata test</title>
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<body onload=compare()>
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Due to #zerkems comment:
i should convert my strings to JSON object and then call the equal method:
var x = eval("(" + remoteJSON + ')');
var y = eval("(" + localJSON + ')');
function jsonequals(x, y) {
// If both x and y are null or undefined and exactly the same
if ( x === y ) {
return true;
}
// If they are not strictly equal, they both need to be Objects
if ( ! ( x instanceof Object ) || ! ( y instanceof Object ) ) {
return false;
}
// They must have the exact same prototype chain, the closest we can do is
// test the constructor.
if ( x.constructor !== y.constructor ) {
return false;
}
for ( var p in x ) {
// Inherited properties were tested using x.constructor === y.constructor
if ( x.hasOwnProperty( p ) ) {
// Allows comparing x[ p ] and y[ p ] when set to undefined
if ( ! y.hasOwnProperty( p ) ) {
return false;
}
// If they have the same strict value or identity then they are equal
if ( x[ p ] === y[ p ] ) {
continue;
}
// Numbers, Strings, Functions, Booleans must be strictly equal
if ( typeof( x[ p ] ) !== "object" ) {
return false;
}
// Objects and Arrays must be tested recursively
if ( !equals( x[ p ], y[ p ] ) ) {
return false;
}
}
}
for ( p in y ) {
// allows x[ p ] to be set to undefined
if ( y.hasOwnProperty( p ) && ! x.hasOwnProperty( p ) ) {
return false;
}
}
return true;
}

Implementing contains, which checks where the specified elements exists in the array or not is not working

I have tried this code to find if some object already exists in Array, but, it is not working:
function lote(pnIdLote,psNmLote, pnIdQuadro){
this.idlote = pnIdLote;
this.nmlote = psNmLote;
this.idquadro = pnIdQuadro;
}
Array.prototype.contains = function(obj){
var i = this.length;
while(i--){
console.log(i);
if (this[i] == obj) return true;
}
return false;
};
My code:
$(data).each(function(index){
if(this.idlote!=""){
loLote = new lote(this.idlote, this.nmlote, this.quadro);
if(!laLote.contains(loLote)){
laLote.push(loLote);
}
}
});
console.log(laLote);
The array appears this way:
[
lote
idlote: "2"
idquadro: "1"
nmlote: "Lote 1"
__proto__: lote
,
lote
idlote: "2"
idquadro: "1"
nmlote: "Lote 1"
__proto__: lote
,
lote
idlote: "2"
idquadro: "1"
nmlote: "Lote 1"
__proto__: lote
]
And I'd like an array with only one element, like this:
[
lote
idlote: "2"
idquadro: "1"
nmlote: "Lote 1"
__proto__: lote
]
Where do I fix my code?
Thanks,
Luciano

When a and b are objects in JavaScript, a == b or a === b is only true if a and b point to the same instance.
Example:
var a = [], b = [], c = a;
alert(a == b); // False
alert(a == c); // True
For your specific comparison method, I recommend creating a custom array constructor, to not pollute the Array object:
function lote() {} // Your lote constructor
var customArray = function() {
return Array.apply(this, arguments);
}
customArray.prototype = new Array;
customArray.prototype.contains = function(obj) {
var i = this.length;
// Not designed for non-"lote" instances, return null
if (!(obj instanceof lote)) return null;
while (i--) {
var current = this[i];
if (current.idlote === obj.idlote &&
current.nmlote === obj.nmlote &&
current.idquadro === obj.idquadrio) return true;
}
return false;
}
Instead of hard-coding the property names, you can also loop through the Object's properties, using Object.keys():
customArray.prototype.contains = function(obj) {
var i = this.length;
// Not designed for non-"lote" instances, return null
if (!(obj instanceof lote)) return null;
var keys = Object.keys(obj), keysLen = keys.length;
// Labeled loop
loop: while (i--) {
var current = this[i];
var len = keysLen, key;
for (len--) {
key = keys[len];
if (current[key] !== current[key]) {
len = -1;
continue loop; //Not equal, go to the next item in the outer loop
}
}
return true; // At this point, every property was equal.
}
return false;
}
Note that the shown method depends is based on the properties of the given obj. If it's not a valid lote object, the function returns null. Object.keys retrieves all properties of the given obj.

I think you should change the "contains" method to use Object.equals function, and you could use the code of
Array.prototype.contains = function(obj){
var i = this.length;
while(i--){
console.log(i);
if(this[i].equals(obj)) return true;
}
return false;
};
Object.prototype.equals = function(x){
var p;
for(p in this) {
if(typeof(x[p])=='undefined') {return false;}
}
for(p in this) {
if (this[p]) {
switch(typeof(this[p])) {
case 'object':
if (!this[p].equals(x[p])) { return false; } break;
case 'function':
if (typeof(x[p])=='undefined' ||
(p != 'equals' && this[p].toString() != x[p].toString()))
return false;
break;
default:
if (this[p] != x[p]) { return false; }
}
} else {
if (x[p])
return false;
}
}
for(p in x) {
if(typeof(this[p])=='undefined') {return false;}
}
return true;
}
Code of object comparison extracted from Object comparison in JavaScript

Is object empty? [duplicate]

This question already has answers here:
How do I test for an empty JavaScript object?
(48 answers)
Closed 5 years ago.
What is the fastest way to check if an object is empty or not?
Is there a faster and better way than this:
function count_obj(obj){
var i = 0;
for(var key in obj){
++i;
}
return i;
}

For ECMAScript5 (not supported in all browsers yet though), you can use:
Object.keys(obj).length === 0

I'm assuming that by empty you mean "has no properties of its own".
// Speed up calls to hasOwnProperty
var hasOwnProperty = Object.prototype.hasOwnProperty;
function isEmpty(obj) {
// null and undefined are "empty"
if (obj == null) return true;
// Assume if it has a length property with a non-zero value
// that that property is correct.
if (obj.length > 0) return false;
if (obj.length === 0) return true;
// If it isn't an object at this point
// it is empty, but it can't be anything *but* empty
// Is it empty? Depends on your application.
if (typeof obj !== "object") return true;
// Otherwise, does it have any properties of its own?
// Note that this doesn't handle
// toString and valueOf enumeration bugs in IE < 9
for (var key in obj) {
if (hasOwnProperty.call(obj, key)) return false;
}
return true;
}
Examples:
isEmpty(""), // true
isEmpty(33), // true (arguably could be a TypeError)
isEmpty([]), // true
isEmpty({}), // true
isEmpty({length: 0, custom_property: []}), // true
isEmpty("Hello"), // false
isEmpty([1,2,3]), // false
isEmpty({test: 1}), // false
isEmpty({length: 3, custom_property: [1,2,3]}) // false
If you only need to handle ECMAScript5 browsers, you can use Object.getOwnPropertyNames instead of the hasOwnProperty loop:
if (Object.getOwnPropertyNames(obj).length > 0) return false;
This will ensure that even if the object only has non-enumerable properties isEmpty will still give you the correct results.

EDIT: Note that you should probably use ES5 solution instead of this since ES5 support is widespread these days. It still works for jQuery though.
Easy and cross-browser way is by using jQuery.isEmptyObject:
if ($.isEmptyObject(obj))
{
// do something
}
More: http://api.jquery.com/jQuery.isEmptyObject/
You need jquery though.

Underscore and lodash each have a convenient isEmpty() function, if you don't mind adding an extra library.
_.isEmpty({});

Lets put this baby to bed; tested under Node, Chrome, Firefox and IE 9, it becomes evident that for most use cases:
(for...in...) is the fastest option to use!
Object.keys(obj).length is 10 times slower for empty objects
JSON.stringify(obj).length is always the slowest (not surprising)
Object.getOwnPropertyNames(obj).length takes longer than Object.keys(obj).length can be much longer on some systems.
Bottom line performance wise, use:
function isEmpty(obj) {
for (var x in obj) { return false; }
return true;
}
or
function isEmpty(obj) {
for (var x in obj) { if (obj.hasOwnProperty(x)) return false; }
return true;
}
Results under Node:
first result: return (Object.keys(obj).length === 0)
second result: for (var x in obj) { return false; }...
third result: for (var x in obj) { if (obj.hasOwnProperty(x)) return false; }...
forth result: return ('{}' === JSON.stringify(obj))
Testing for Object with 0 keys
0.00018
0.000015
0.000015
0.000324
Testing for Object with 1 keys
0.000346
0.000458
0.000577
0.000657
Testing for Object with 2 keys
0.000375
0.00046
0.000565
0.000773
Testing for Object with 3 keys
0.000406
0.000476
0.000577
0.000904
Testing for Object with 4 keys
0.000435
0.000487
0.000589
0.001031
Testing for Object with 5 keys
0.000465
0.000501
0.000604
0.001148
Testing for Object with 6 keys
0.000492
0.000511
0.000618
0.001269
Testing for Object with 7 keys
0.000528
0.000527
0.000637
0.00138
Testing for Object with 8 keys
0.000565
0.000538
0.000647
0.00159
Testing for Object with 100 keys
0.003718
0.00243
0.002535
0.01381
Testing for Object with 1000 keys
0.0337
0.0193
0.0194
0.1337
Note that if your typical use case tests a non empty object with few keys, and rarely do you get to test empty objects or objects with 10 or more keys, consider the Object.keys(obj).length option. - otherwise go with the more generic (for... in...) implementation.
Note that Firefox seem to have a faster support for Object.keys(obj).length and Object.getOwnPropertyNames(obj).length, making it a better choice for any non empty Object, but still when it comes to empty objects, the (for...in...) is simply 10 times faster.
My 2 cents is that Object.keys(obj).length is a poor idea since it creates an object of keys just to count how many keys are inside, than destroys it! In order to create that object he needs to loop overt the keys... so why use it and not the (for... in...) option :)
var a = {};
function timeit(func,count) {
if (!count) count = 100000;
var start = Date.now();
for (i=0;i<count;i++) func();
var end = Date.now();
var duration = end - start;
console.log(duration/count)
}
function isEmpty1() {
return (Object.keys(a).length === 0)
}
function isEmpty2() {
for (x in a) { return false; }
return true;
}
function isEmpty3() {
for (x in a) { if (a.hasOwnProperty(x)) return false; }
return true;
}
function isEmpty4() {
return ('{}' === JSON.stringify(a))
}
for (var j=0;j<10;j++) {
a = {}
for (var i=0;i<j;i++) a[i] = i;
console.log('Testing for Object with '+Object.keys(a).length+' keys')
timeit(isEmpty1);
timeit(isEmpty2);
timeit(isEmpty3);
timeit(isEmpty4);
}
a = {}
for (var i=0;i<100;i++) a[i] = i;
console.log('Testing for Object with '+Object.keys(a).length+' keys')
timeit(isEmpty1);
timeit(isEmpty2);
timeit(isEmpty3);
timeit(isEmpty4, 10000);
a = {}
for (var i=0;i<1000;i++) a[i] = i;
console.log('Testing for Object with '+Object.keys(a).length+' keys')
timeit(isEmpty1,10000);
timeit(isEmpty2,10000);
timeit(isEmpty3,10000);
timeit(isEmpty4,10000);

Elegant way - use keys
var myEmptyObj = {};
var myFullObj = {"key":"value"};
console.log(Object.keys(myEmptyObj).length); //0
console.log(Object.keys(myFullObj).length); //1
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/keys

function isEmpty( o ) {
for ( var p in o ) {
if ( o.hasOwnProperty( p ) ) { return false; }
}
return true;
}

var x= {}
var y= {x:'hi'}
console.log(Object.keys(x).length===0)
console.log(Object.keys(y).length===0)
true
false
http://jsfiddle.net/j7ona6hz/1/

Surprised to see so many weak answers on such a basic JS question... The top answer is no good too for these reasons:
it generates a global variable
returns true on undefined
uses for...in which is extremely slow by itself
function inside for...in is useless - return false without hasOwnProperty magic will work fine
In fact there's a simpler solution:
function isEmpty(value) {
return Boolean(value && typeof value === 'object') && !Object.keys(value).length;
}

https://lodash.com/docs#isEmpty comes in pretty handy:
_.isEmpty({}) // true
_.isEmpty() // true
_.isEmpty(null) // true
_.isEmpty("") // true

How bad is this?
function(obj){
for(var key in obj){
return false; // not empty
}
return true; // empty
}

No need for a library.
function(){ //must be within a function
var obj = {}; //the object to test
for(var isNotEmpty in obj) //will loop through once if there is a property of some sort, then
return alert('not empty')//what ever you are trying to do once
return alert('empty'); //nope obj was empty do this instead;
}

It might be a bit hacky. You can try this.
if (JSON.stringify(data).length === 2) {
// Do something
}
Not sure if there is any disadvantage of this method.

fast onliner for 'dictionary'-objects:
function isEmptyDict(d){for (var k in d) return false; return true}

You can write a fallback if Array.isArray and Object.getOwnPropertyNames is not available
XX.isEmpty = function(a){
if(Array.isArray(a)){
return (a.length==0);
}
if(!a){
return true;
}
if(a instanceof Object){
if(a instanceof Date){
return false;
}
if(Object.getOwnPropertyNames(a).length == 0){
return true;
}
}
return false;
}

Imagine you have the objects below:
var obj1= {};
var obj2= {test: "test"};
Don't forget we can NOT use === sign for testing an object equality as they get inheritance, so If you using ECMA 5 and upper version of javascript, the answer is easy, you can use the function below:
function isEmpty(obj) {
//check if it's an Obj first
var isObj = obj !== null
&& typeof obj === 'object'
&& Object.prototype.toString.call(obj) === '[object Object]';
if (isObj) {
for (var o in obj) {
if (obj.hasOwnProperty(o)) {
return false;
break;
}
}
return true;
} else {
console.error("isEmpty function only accept an Object");
}
}
so the result as below:
isEmpty(obj1); //this returns true
isEmpty(obj2); //this returns false
isEmpty([]); // log in console: isEmpty function only accept an Object

funtion isEmpty(o,i)
{
for(i in o)
{
return!1
}
return!0
}

here's a good way to do it
function isEmpty(obj) {
if (Array.isArray(obj)) {
return obj.length === 0;
} else if (typeof obj === 'object') {
for (var i in obj) {
return false;
}
return true;
} else {
return !obj;
}
}

var hasOwnProperty = Object.prototype.hasOwnProperty;
function isArray(a) {
return Object.prototype.toString.call(a) === '[object Array]'
}
function isObject(a) {
return Object.prototype.toString.call(a) === '[object Object]'
}
function isEmpty(a) {
if (null == a || "" == a)return!0;
if ("number" == typeof a || "string" == typeof a)return!1;
var b = !0;
if (isArray(a)) {
if (!a.length)return!0;
for (var c = 0; c < a.length; c++)isEmpty(a[c]) || (b = !1);
return b
}
if (isObject(a)) {
for (var d in a)hasOwnProperty.call(a, d) && (isEmpty(a[d]) || (b = !1));
return b
}
return!0
}

May be you can use this decision:
var isEmpty = function(obj) {
for (var key in obj)
if(obj.hasOwnProperty(key))
return false;
return true;
}

I modified Sean Vieira's code to suit my needs. null and undefined don't count as object at all, and numbers, boolean values and empty strings return false.
'use strict';
// Speed up calls to hasOwnProperty
var hasOwnProperty = Object.prototype.hasOwnProperty;
var isObjectEmpty = function(obj) {
// null and undefined are not empty
if (obj == null) return false;
if(obj === false) return false;
if(obj === true) return false;
if(obj === "") return false;
if(typeof obj === "number") {
return false;
}
// Assume if it has a length property with a non-zero value
// that that property is correct.
if (obj.length > 0) return false;
if (obj.length === 0) return true;
// Otherwise, does it have any properties of its own?
// Note that this doesn't handle
// toString and valueOf enumeration bugs in IE < 9
for (var key in obj) {
if (hasOwnProperty.call(obj, key)) return false;
}
return true;
};
exports.isObjectEmpty = isObjectEmpty;

here my solution
function isEmpty(value) {
if(Object.prototype.toString.call(value) === '[object Array]') {
return value.length == 0;
} else if(value != null && typeof value === 'object') {
return Object.getOwnPropertyNames(value).length == 0;
} else {
return !(value || (value === 0));
}
}
Chears

if (Object.getOwnPropertyNames(obj1).length > 0)
{
alert('obj1 is empty!');
}