I'm constructing a javascript indicator for my client and they gave me below C++ code from their old system. I have never done C++ program before. Below is the part of the C++ code. What I want to know is in the line
if (it3 != d1Swing.end() && it3->x == h[i].x) --(it1 = it2 = it3); what is the meaning of --(it1 = it2 = it3)? What will it looks like in javascript?
vector<PTPoint::PTIndexPoint> dnSwing;
list<PTPoint::PTIndexPoint> hq, lq;
vector<PTPoint::PTIndexPoint>::iterator it1 = d1Swing.begin(), it2 = d1Swing.begin(), it3 = ++d1Swing.begin();
//
// more code here
//
for (int i = 0; i < period; ++i)
{
while (!hq.empty() && hq.back().y < h[i].y) hq.pop_back();
hq.push_back(h[i]);
while (!lq.empty() && lq.back().y > l[i].y) lq.pop_back();
lq.push_back(l[i]);
if (it3 != d1Swing.end() && it3->x == h[i].x) --(it1 = it2 = it3);
//
// more code here
//
}
//
// more code here
//
p->swap(dnSwing);
Thanks in advance.
tslin
It means that their previous programmer loved being "clever".
The value of an assignment is a reference to the object that was assigned to, and assignment associates to the right.
--(it1 = it2 = it3)
is
--(it1 = (it2 = it3))
and it's intended to assign the value of it3 to it2 and it1, then decrement it1.
(I have a hunch that this may be undefined, which is a thing that happens frequently when you're being clever in C++.)
it1 is apparently intended to be "one step behind" it2.
A more reasonable way to write that is
it2 = it3;
it1 = it2 - 1;
(In JavaScript, I suspect that you need to work with array indices rather than iterators to accomplish the same thing.)
Related
A little new to JS so be gentle :)
I'm trying to create a program that holds 5000+ boolean values that dynamically change based on other vars.
const chars = "abcdefghijklmnopqrstuvwxyz0";
const charsC = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0"
const maxNum = 48;
const maxTile = 6;
var tile1, tile2, tile3, tile4, tile5, tile6
// test vars
var tile4 = "A27"
var t4a27 = false
// this snippet will be in an interval loop
for (let i = 1; i <= maxTile; ++i) {
for (let n = 0; n < chars.length; ++n) {
for (let j = 1; j <= maxNum; ++j) {
// this obviously doesnt work
var t[i][`${chars[n]}`][j];
// ^ ^ ^
if (tile[i] == `${charsC[n]}${j}`) {
t[i][h][j] = true;
console.log(t4a27)
} else {
t[i][h][j] = false;
}
}
}
}
For clarification a better word than "tile" for the vars could be "sprite" rather because its a point on the sprite.
The basic concept is the tile vars are designed to output their current position as a string value e.g. "A27". Then this loop will take that information and scan each tile subset to be true/false. So if the sprite lower right quadrant is inside "A27" the output would be t4a27 = true
In practice I can do this with just a lot of code (over 20,000 lines) but I figured their has to be an easier way that requires far less code.
This is probably not the right approach for your problem.
If you really need to store this amount of variables, it is probably best to put them in an object like so:
var tiles = {}
var tileName = 'abc'
// Dynamic setting:
tile[tileName] = true
// Dynamic reading:
console.log(tile[tileName])
I am wondering if you really want to store 5000 variables or if there is another way to calculate them at the time you need time, but that requires a bit more knowledge of the problem.
Javascript doesn't have this kind of ability to reflect local variables.
What you can do is attach all those variables to a global object, and proceed with: Object.keys(your_object) and your_object[key_name_here] = ...
I think you should use a 2-dim array for this. Or use a regular array of booleans with the appropriate size and do the index-magic yourself.
As you said, you are running on coordinates. A-27 is the same as row(1)+field(27) -- considering A is 1
If your field is 500x100, you create an Array as such: let gamefield = Array(500*100);
Warning: I have not tested this for syntax errors, but you should get the idea.
let gamefield = Array(500*100);
// optional gamefield.fill(true);
let row = idx => idx * 500;
let posIdx = (r, c) => row(r) + c;
// there is a sprite with a tiles property that returns
// 4 index positions for the sprite's quadrants as [r,c]
let quadrants = sprite.tiles.reportPositions()
// filter the quadrants where the gamefield at r,c is true
// this might also be a good case for some() instead of filter()
let collisions = quadrants.filter(pos => return gamefield[posIdx(...pos)]);
// if there is any of these, you can kill the sprite.
if(collisions.length > 0) sprite.kill();
Hey guys I am trying trying to right this javascript code into c++. I am doing quick sort and everything is straight forward minus the last step.
function quickSort(arr)
{
//base case if the arr is 1 or 0 then return the array
if(arr.length === 1 || arr.length === 0)
{
return arr;
}
var pivotIndex = Math.floor(arr.length/2);
var pivotValue = arr[pivotIndex];
var before = [];
var after = [];
for(var counter = 0; counter < arr.length; counter++)
{
if(counter === pivotIndex)
continue;
if(pivotValue <= arr[counter])
{
before.push(arr[counter])
}
else
{
after.push(arr[counter])
}
}
//this step I am having trouble rewriting in c++
return quickSort(after).concat(pivotValue).concat(quickSort(before));
}
I am having a hard time rewriting the recursive step in c++. I am not sure how concat 2 vector. I tried using the insert method but I keep getting an error about invalid use of void expression.
vector<int> quickSort(vector<int> arr)
{
if(arr.size() == 1 || arr.size() == 0)
{
return arr;
}
int pivotIndex = arr.size()/2;
int pivotValue = arr[pivotIndex];
vector<int> before;
vector<int> after;
//put values in before or after the piv
for(size_t counter = 0; counter < arr.size(); counter++)
{
if(counter == pivotIndex)
continue;
if(pivotValue <= arr[counter])
before.push_back( arr[counter]);
else
after.push_back( arr[counter]);
}
return //????? not sure how to do this
}
So, you realized that your core question was "how to concatenate two vectors", and you found a right answer: using insert. Now your question is about why you were getting "an error about invalid use of void expression." (That's the assumption my answer is for, at least.)
That's because you were likely trying to do something like the following:
return quickSort(after).insert( /* stuff */ );
which is wrong. In JavaScript, array.concat returns the concatenated array. It's return type is effectively Array, and so doing return arr.concat(arr2) returns an Array because arr.concat would return an Array. Further, in JavaScript, array.concat doesn't modify the array it was called on, but rather returns a new array.
In C++, however, vector.insert (#4 in the reference) returns void. That means it returns nothing. So when you try to return the result of insert, you get that error about invalid use of a void expression. Further, in C++, vector.insert does modify the vector it was called on.
So how do you use insert in this case?
vector<int> quickSort(vector<int> arr)
{
// ...
// Sort `before` and `after`
before = quickSort(before);
after = quickSort(after);
// Modify `after` and return it.
after.push_back(pivotValue);
after.insert(after.end(), before.begin(), before.end());
return after;
}
Note: My code isn't optimal and the idea of rewriting JS in C++ is also oddly specific. My answer is to simply outline the problem asked in the question, not to give a good C++ implementation of quick sort.
To concat two vector , you can use std::merge
like:std::merge(v1.begin(), v1.end(), v2.begin(), v2.end(), std::back_inserter(dst));
I'm new to JavaScript and are trying to solve a problem. I shall only write in JavaScript and the instructions are telling me to use readline(), for example like this: while (line = readline())
But I cant get how this works and I cant find any information about this in JavaScript. I want to get a users input and then put that in a variable. But when I try "while (line = readline())" I can's se anything happen (like with propt, which is the only way I know)...
Thankful for your help!
Here is my code (which works if I use alert and prompt istead of print and readline):
var usersNumber;
while (usersNumber = readline()) {
if (1 <= usersNumber && usersNumber <= 1000000000)
{
var inputBinary = usersNumber.toString(2);
var binaryArray = [];
for (i = 0; i < inputBinary.length; i++) {
binaryArray[i] = inputBinary.charAt(i);
};
binaryArray.reverse();
var stringBinaryFromArray = "";
for (i = 0; i < binaryArray.length; i++) {
stringBinaryFromArray = stringBinaryFromArray + binaryArray[i];
}
var digit = parseInt(stringBinaryFromArray, 2);
print(digit);
}
}
readline() is not a standard Javascipt function. You can use prompt() instead
while (usersNumber = prompt())
You might need to change the input from a string to a number.
while (usersNumber = Number(prompt()))
On another note, there are built-in functions you can use instead of the loops you have. split() and join(). You can even do it all in 1 line.
var stringBinaryFromArray = inputBinary.split('').reverse().join('');
(line = readline()) both assign line AND returns the value returned by readline()
if readline() returns null, line is null and the loop stops
I have a big question.
I have many Strings in my Programm and want to check these Strings on there values.
I wrote a Loop for it, but insted of the Definition of an String he is creating a new value. It's basicly really difficult to discribe, also because i am basicly German.
But i can give you my current code, so maybee you will see what I mean:
{
var Loch1G = $('#m1-Rundenanalyse-Datum').val(); //In the strings just the number is changing
var Loch2G = $('#m1-Rundenanalyse-Turnier').val();
x=1
while (x <= 2) {
if ("Loch" + x + "G" == ""){ //Next String is genrated (x=x+1)
alert("Eingabe war leer");
}
x=x+1
}
}
How can I solve this?
I'd suggest using an array to store the values you want to check:
var lochs = [];
lochs.push($('#m1-Rundenanalyse-Datum').val());
lochs.push($('#m1-Rundenanalyse-Turnier').val());
for (var i = 0, len = lochs.length; i < len; i++){
if (lochs[i] == ''){
alert("Eingabe war leer");
}
}
JS Fiddle demos: passes (no alert), fails (alert)
This suggestion is based on my presumption that you're trying to create the names of the vars you want to check, which won't work, whereas this approach lets you store all values (however many) in the same array and then iterate over that array to find any values that are equal to an empty string.
If you really want to stick with your current approach, you could do the following:
{
window.Loch1G = $('#m1-Rundenanalyse-Datum').val(); //In the strings just the number is changing
window.Loch2G = $('#m1-Rundenanalyse-Turnier').val();
var x=1;
while (x <= 2) {
if (window["Loch" + x + "G"] == ""){ //Next String is genrated (x=x+1)
alert("Eingabe war leer");
}
x=x+1;
}
}
But I can't think why you'd want to; plus the use of global variables is poor practice as it explicitly makes those variables available to every closure within the document, which allows them to be easily, and accidentally, overwritten.
In a reasonably up-to-date browser, that implements Array.prototype.every, you could dispense with the explicit iteration:
var lochs = [];
lochs.push($('#m1-Rundenanalyse-Datum').val());
lochs.push($('#m1-Rundenanalyse-Turnier').val());
if (!lochs.every(function(a){ return a !== ''; })) {
alert("Eingabe war leer");
}
JS Fiddle demos: passes (no alert), fails (alerts).
I have a script setup like this (http://jsfiddle.net/YD66s/):
var countFull = new Array(0,1,2,3,4,5,6);
var countActive = new Array(0,1,2,3,4,5,6);
function pickRandom(a) {
if(arguments[1].length == 0) {
arguments[1] = arguments[0];
}
var m = Math.floor(Math.random()*arguments[1].length);
chosen = arguments[1].splice(m,1);
return chosen;
}
setInterval(function() {
pickRandom(countFull,countActive);
}, 1000);
When I run this I want the variable to be set for that function only. Instead it is affecting countFull towards the end because I make arguments[1] = arguments[0]. How in javascript can I just reference a variable but not consume it and ultimately arguments[1] becomes arguments[0].
Hope this makes sense. This is driving me nuts how different javascript variables are compared to other languages like PHP.
Javascript arrays are just pointers so when you do arguments[1] = arguments[0] you actually just set the pointer but the underlying arrays are the same. As a result, every time you modify arguments[1] you also modify arguments[0]. To do what you want, you need to copy the array. You could do it this way:
if (arguments[1].length == 0) {
for(var i = 0; i < arguments[0].length; i++) {
arguments[1][i] = arguments[0][i];
}
}
To copy an array, instead of referencing it, use copy = original.slice(0).