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How to use select values for form action

I am trying to pass the select values for form action URL for wordpress,
$args_shortcode = shortcode_atts(array(
'category_name' => ''
), $attr);
$condition = "";
if(isset($_POST['Collateral_services'])){
$condition = "/?Collateral_services=".$_POST['Collateral_services'];
}
$action_url = site_url() . "/category/" . $args_shortcode['category_name'] . $condition;
As you can see, the action url will redirect user to a different page which is getting fetched from shortcode attribute, so $_POST['Collateral_services'] is not fetching any data because it needs to be on search result page,
But the action URL needs to be based on selected option of the form, so I am not getting how can I change values in url after "/category/" using javascript or jQuery ?
form:
<form method="POST" action="<?php echo $action_url; ?>">
<div class="form-group">
<div class="col-xs-12 col-sm-12">
<select name="Collateral_services" class="custom-select-input">
<option value="" disabled selected>All Services</option>
<?php
foreach ($terms_ser as $term_ser) {
?>
<option value="<?php echo $term_ser->slug; ?>"><?php echo $term_ser->name; ?></option>
<?php } ?>
</select>
</div>
</div>
<div class="custom-search-button-align">
<input type="submit" value="Filter" class="custom-search">
</div>
</form>

How to get value of select-option tag from database

i made this form of adding data in the database. I have exam table that contains exam_code(PK), exam_title and subject_code(FK). Here is the design
<div style="width:800px;height:auto;margin-left:auto;margin-right:auto;margin-top:50px;">
<form action="" method="POST" class="form-horizontal" role="form">
<div class="form-group">
<div class="col-xs-6 col-sm-3 ">
<input name="code" type="text" class="form-control" id="excode" placeholder="Enter Exam Code">
</div>
<div class="col-xs-6 col-sm-3 ">
<input name="title" type="text" class="form-control" id="extitle" placeholder="Enter Exam Title">
</div>
<div class="col-xs-6 col-sm-3 ">
<select name="subjcode" class="form-control">
<option selected="selected">Choose subject</option>
<option disabled="disabled">---------------------------------</option>
<?php
include('db.php');
$subj = $connect->query("SELECT subject_code FROM subject");
while($row1 = mysqli_fetch_array($subj)){
echo "<option value = $row1[subject_code]>$row1[subject_code]</option>";
}
?>
</select>
</div>
<div class="col-xs-6 col-sm-3 ">
<input type="submit" name="add" class="btn btn-default" value="Add" />
</div>
</div>
</form>
</div>
Is my query here correct? I can't think of anyway to insert the data. Here..
<?php
include('db.php');
if(isset($_POST['add'])){
$excode = $_POST['code'];
$extitle = $_POST['title'];
$subcode = $_POST['subjcode'];
$examinsert = $connect->query("INSERT INTO exam (exam_code, exam_title, subject_code) VALUES ('$excode', '$extitle', '$subcode')");
if(!$examinsert){
die("<script>
alert('Error encountered, Reloading page');
window.location.href='teacher.php';
</script>");
}else{
die("<script>
alert('Your exam title has been added. You will see your titles in the Examination title section below!');
window.location.href='teacher.php';
</script>");
}
}
?>

Change Your PHP CODE
FROM This
<?php
include('db.php');
$subj = $connect->query("SELECT subject_code FROM subject");
while($row1 = mysqli_fetch_array($subj)){
echo "<option value = $row1[subject_code]>$row1[subject_code]</option>";
}
?>
To This
<?php
include('db.php');
$subj = $connect->query("SELECT subject_code FROM subject");
while($row1 = mysqli_fetch_array($subj)){
echo "<option value = ".$row1[subject_code].">".$row1[subject_code]."</option>";
}
?>

store value in Variable and than put it.
<?php
include('db.php');
$subj = $connect->query("SELECT subject_code FROM subject");
while($row1 = mysqli_fetch_array($subj)){
$subjectCode = $row1[subject_code];
echo "<option value = $subjectCode>$subjectCode</option>";
}
?>
Its Works.

I fixed it by adding a query that disables the foreign keys.
$set = $connect->query('SET foreign_key_checks = 0');
/*insert query*/
$set1 = $connect->query('SET foreign_key_checks = 1');

Codeigniter update form does not submit

Codeigniter offers you a tutorial to get to know it and how to use it. This tutorial teaches you to create elements in a table in a database, but doesn't teach you how to update this elements. I am trying to make an update query using the codeigniter libraries, but the form from de update view doesn't submit.
AT NEWS_MODEL:
public function update_news($slug)
{
$this->load->helper('url');
$data = array(
'title' => $this->input->post('title'),
'slug' => $slug,
'text' => $this->input->post('text')
);
$this->db->where('slug', $slug);
$this->db->update('news', $data);
}
AT NEWS CONTROLLER:
public function update($slug)
{
$this->load->helper('form');
$this->load->library('form_validation');
$data['title'] = 'Update a news item';
$this->form_validation->set_rules('title', 'Title', 'required');
$this->form_validation->set_rules('text', 'Text', 'required');
if ($this->form_validation->run() === FALSE)
{
// The form was NOT posted
// So we load the view
$data['news_item'] = $this->news_model->get_news($slug);
$this->load->view('templates/header', $data);
$this->load->view('news/update', $data);
$this->load->view('templates/footer');
}
else
{
// The form was submitted
$data = array(
'title' => $this->input->post('title'), //-->post variable
'slug' => $this->input->post('slug'),
'text' => $this->input->post('text')
);
$this->news_model->update_news($slug, $data);
$this->load->view('news/success');
}
}
AT UPDATE VIEW:
<h2><?php echo $title; ?></h2>
<?php echo validation_errors(); ?>
<?php echo form_open('news/update') ;?>
<label for="title">Title</label>
<input type="input" name="title" /><br />
<label for="text">Text</label>
<textarea name="text"></textarea><br />
<input type="submit" name="submit" value="Update news item" />
</form>
I've tested the code with "console.log()" and the problem seems to be that the form of the update view doesn't submit, but I cannot figure why, because the form is similar to the create form, which does work perfectly:
<h2><?php echo $title; ?></h2>
<?php echo validation_errors(); ?>
<?php echo form_open('news/create'); ?>
<label for="title">Title</label>
<input type="input" name="title" /><br />
<label for="text">Text</label>
<textarea name="text"></textarea><br />
<input type="submit" name="submit" value="Create news item" />
</form>

your problem is :
you use === instead of == in this line:
if ($this->form_validation->run() === FALSE)

Based on a forms input value, how 2 generate selections 4 a drop down menu w row/record data from a database that will prefill a form when selected?

I'm trying to figure out a way to pre fill a form with data with past form information submitted in the past.
I have a form and a database. In my form I have a input named email that holds the pre-loaded default value of logged in member's email address that is read-only.
PIC
http://oi57.tinypic.com/2iubb4j.jpg
How can I generate a selection under a drop down menu that when selected will pre-fill the form with row/record data from my database?
and how can I generate only the records that match the forms input value 'email' to the records with the same value under the 'email' column in the database?
I've been at it for weeks now and can not seem to find any sense of direction on how to achieve this. Can't really find any tutorials site, video, sample code or anything close on how to make this possible. Any help would be great...thanks for your help in advance.
FORM
</header>
<body>
<form action="/demoform/contact_form.php" class="well" id="contactForm" method="post" name="sendMsg" novalidate="">
<big>LOAD PAST ORDERS:</big>
<select id="extrafield1" name="extrafield1">
<option value="">Please select...</option>
<option value="xxx">SAMPLE SELECTION</option>
</select>
</br>
<input type="text" required id="mile" name="mile" placeholder="Miles"/>
</br>
<input id="email" name="email" placeholder="Email" required="" type="text" value="demo#gmail.com" readonly="readonly"/>
</br>
<input id="name" name="itemname" placeholder="ITEM NAME 1" required="" type="text" />
</br>
<input type="reset" value="Reset" />
<button type="submit" value="Submit">Submit</button>
</form>
</body>
</html>
PHP FILE
<?php
define('DB_NAME', 'xxx');
define('DB_USER', 'xxx');
define('DB_PASSWORD', 'xxx');
define('DB_HOST', 'xxx');
$connection = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!$connection){
die('Database connection failed: ' . mysqli_connect_error());
}
$db_selected = mysqli_select_db($connection, DB_NAME);
if(!$db_selected){
die('Can\'t use ' .DB_NAME . ' : ' . mysqli_connect_error());
}
echo 'Connected successfully';
if (isset($_POST['itemname'])){
$itm = $_POST['itemname'];
}
else {
$itm = '';
}
if($_POST['mile']){
$mi = $_POST['mile'];
}else{
echo "Miles not received";
exit;
}
if($_POST['email']){
$email = $_POST['email'];
}else{
echo "email not received";
exit;
}
$sql = "INSERT INTO seguin_orders (itemname, mile, email)
VALUES ('$itm', '$mi', '$email')";
if (!mysqli_query($connection, $sql)){
die('Error: ' . mysqli_connect_error($connection));
}
UPDATE: closest thing below so far...but wont work...not sure it covers the matching the email values portion...thanks anyways 'edcoder'
<select id="extrafield1" name="extrafield1">
<option value="">Please select...</option>
<?php
$query='select * from tablename';
$res=mysql_query($query);
while($row=mysql_fetch_array($res))
{
?>
<option value="<?php echo $row['feildname']; ?>"><?php echo $row['feildname']; ?></option>
<?php
}
?>
</select>

It seems that you're almost there.
Try this.
<select id="extrafield1" name="extrafield1">
<option value="">Please select...</option>
<?php
$email = $_POST['email'];
$query="select * from tablename WHERE email={$_POST['email']}";
$res=mysqli_query($connection,$query);
while($row = mysqli_fetch_assoc($res))
{
?>
<option value="<?php echo $row['fieldname']; ?>"><?php echo $row['fieldname']; ?></option>
<?php
}
?>
</select>

Using Ajax with Codeigniter

I saw few pages but tried all and none worked for me.
This is what i want:
on my html:
<form class="form-horizontal" role="form" method="POST" action="">
<select name="customer_id" id="customer_id" class="form-control">
<option>Select customer</option>
<?php foreach($customers AS $customer): ?>
<option value="<?php echo $customer->id;?>"><?php echo $customer->name; ?></option>
<?php endforeach; ?>
</select>
</div>
</div>
<div class="form-group">
<label for="category" class="col-xs-4 control-label">Category</label>
<div class="col-sm-4 col-xs-8">
<input type="text" class="form-control" name="category" id="category" placeholder="Category" disabled="disabled">
</div>
</div>
Then i have a script to auto fill the category field depending on the customer selected, ass on the database each customers fall into different categories.
<script type="text/javascript">
$(document).ready(function() {
$('#customer_id').change(function() {
var customer_id = $("#customer_id").val();
$.ajax({
type: "POST",
url: <?php echo base_url(). 'customer/getCustomerCat' ; ?>,
data: form_data,
success: function(cat)
{
$("#category").val(cat);
}
});
});
});
</script>
Then on my controller i have:
public function getCustomerCat(){
$id = $this->input->post('customer_id');
$category = $this->customer_model->getCustomerCat($id)[0]->category;
echo $category;
}
On my Model i have:
public function getCustomerCat($id){
$query ="SELECT category FROM customers WHERE id=$id";
$query = $this->db->query($query);
return $query->result();
}
I am not so good with ajax but expected the categoory field to be populated after selecting a customer without reloading the page.