I am implementing search result view to my app.
I figured out that mongoose internally provide full text search function with $text.
I put the code below to Post.js
PostSchema.index({desc: 'text'}); //for example
Here's the code I put in my routing file route/posts.js
Post.find({$text: {$search : 'please work!'}}).exec(function (err, posts) {...})
The error message I come up with is below
Index with pattern: { _fts: "text", _ftsx: 1 } already exists with different options
Would there any body who know how to deal with this error and figure out?
Thanks you.
check on which field you have your text index defined. Right now mongodb allows only one text index per collection. so if you have defined a text index on desc column and try to use that index on some other column you are bound to get this error.
can you try to query your index and see on which column you created it. To get indexes you can do
db.collection.getIndexes()
and it will return something like this
[
{
"v" : 1,
"key" : {
"_id" : 1
},
"name" : "_id_",
"ns" : "some.ns"
},
{
"v" : 1,
"key" : {
"_fts" : "text",
"_ftsx" : 1
},
"name" : "desc_text",
"ns" : "some.ns",
"weights" : {
"title" : 1
},
"default_language" : "english",
"language_override" : "language",
"textIndexVersion" : 2
}
]
now if you want to scope in other columns also to use this index simply drop this index
db.collection.dropIndex('desc_text');
and then recreate it by including all columns you want to be covered by text index,
db.collection.createIndex({
title:'text;,
body: 'text;,
desc: 'text',
...... and so on
});
Related
I have this collection:
[{ "_id" : 7,
"category" : "Festival",
"comments" : [
{
"_id" : ObjectId("4da4e7d1590295d4eb81c0c7"),
"usr" : "Mila",
"txt" : "This is a comment",
"date" : "4/12/11"
}
]
}]
All I want is to push insert a new field inside comments like this:
[{ "_id" : 7,
"category" : "Festival",
"comments" : [
{
"_id" : ObjectId("4da4e7d1590295d4eb81c0c7"),
"usr" : "Mila",
"txt" : "This is a comment",
"date" : "4/12/11",
"type": "abc" // find the parent doc with id=7 & insert this inside comments
}
]
}]
How can I insert inside the comments subdocument?
You need to use the $ positional operator
For example:
update({
_id: 7,
"comments._id": ObjectId("4da4e7d1590295d4eb81c0c7")
},{
$set: {"comments.$.type": abc}
}, false, true
);
I didn't test it but i hope that it will be helpful for you.
If you want to change the structure of document you need to use
db.collection.update( criteria,
objNew, upsert, multi )
Arguments:
criteria - query which selects the record to update;
objNew - updated object or $ operators (e.g., $inc) which manipulate the object
upsert - if this should be an "upsert"; that is, if the record does not exist, nsert it
multi - if all documents matching criteria should be updated
and insert new objNew with new structure. check this for more details
The $ positional operator is only going to work as expected if the 'comments' field is NOT an array. The OP's json is malformed, but it looks like it could be an array.
The issue is that mongodb right now will only update the first element of an array which matches the query. Though there is an RFE open to add support for updating all matching array elements: https://jira.mongodb.org/browse/SERVER-1243
To work around this issue with arrays you just have to do a regular find then update the elements in the array individually.
I am trying to update a document in Mongo if it has a certain value within a field.
{
"_id" : ObjectId("myObject"),
"source" : "BW",
"sourceTableName" : "myTable",
"tableName" : "tier",
"type" : "main",
"fieldMappings" : [
{
"sourceField" : "tier_id", <~~~~ If this is "tier_id", I want to change it to "trmls_id"
"reportingField" : "bw_id",
"type" : "integer",
"defaultMap" : {
"shouldErrorOnConvert" : false
}
}
]
}
I tried something like
db.getCollection('entityMap').update({"sourceTableName":"myTable"}, {"fieldMappings.0.sourceField":"trmls_id":{$exists : true}}, { $set: { "fieldMappings.0.sourceField": "tier_id" } })
and I think it is failing on the $exists parameter I am setting.
Is there a more cleaner/dynamic way to do this?
The whole query I am trying to formulate is
In the table myTable
I want to check if there is a sourceField that has the value tier_id
If there is tier_id, then change it to trmls_id
Otherwise do nothing
If there is a similar StackOverflow question that answers this, I am happy to explore it! Thanks!
There is a syntax mistake and you can use positional operator $ in update part because you have already selector field in query part,
db.getCollection('entityMap').update(
{
"sourceTableName": "myTable",
"fieldMappings.sourceField": "tier_id" // if this field found then it will go to update part
},
{
$set: {
"fieldMappings.$.sourceField": "trmls_id"
}
}
)
I am trying to remove the duplicate values from a deeply nested array. I've put the structure of the database down below. I want to compare the location of the steps with eachother and check for duplicates. I was thinking about using db.collection.aggregate, but it becomes a problem when trying to search through all steps since { $unwind: '$mapbox.routes.legs.0.steps' } requires a specific index for the steps as far as i know.
"mapboxRoute" : {
"routes" : [
{
"distance" : 105375,
"duration" : 8261.3,
"weight" : 11365.5,
"weight_name" : "routability",
"geometry" : 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"legs" : [
{
"distance" : 105336.1,
"duration" : 8259.5,
"steps" : [
{
"distance" : 132.5,
"duration" : 50,
"geometry" : "iv||H_{f^w#b#??AFDZ??H`#?#DT??BL???B#LN`A??Lx#??BP",
"name" : "Mariaplaats",
"ref" : null,
"destinations" : null,
"exits" : null,
"driving_side" : "right",
"mode" : "driving",
"maneuver" : {
"location" : [
5.117934,
52.089493
]
Does someone know how I can compare the locations of the steps?
At the end I stopped making a seperate file for connecting with mongodb and cleaning the database and started using the already existing API to create a call. In this call I looped through the steps in the database and mapped the location to a key. After that I check if that key already existed and pushed that index to a duplicate array.
Then I proceeded to loop through the duplicate list and spliced the duplicate entries from the list with steps. After that I ran the following function to update the entry: await routeSchema.updateOne({ _id: route._id }, { $set: route });
I'm doing an opensource Yelp with Firebase + Angular.
My database:
{
"reviews" : {
"-L0f3Bdjk9aVFtVZYteC" : {
"comment" : "my comment",
"ownerID" : "Kug2pR1z3LMcZbusqfyNPCqlyHI2",
"ownerName" : "MyName",
"rating" : 2,
"storeID" : "-L0e8Ua03XFG9k0zPmz-"
},
"-L0f7eUGqenqAPC1liYj" : {
"comment" : "me second comment",
"ownerID" : "Kug2pR1z3LMcZbusqfyNPCqlyHI2",
"ownerName" : "MyName",
"rating" : 3,
"storeID" : "-L0e8Ua03XFG9k0zPmz-"
},
},
"stores" : {
"-L0e8Ua03XFG9k0zPmz-" : {
"description" : "My good Store",
"name" : "GoodStore",
"ownerID" : "39UApyo0HIXmKPrTOi8D0nWLi6n2",
"tags" : [ "good", "health", "cheap" ],
}
},
"users" : {
"39UApyo0HIXmKPrTOi8D0nWLi6n2" : {
"name" : "First User"
},
"Kug2pR1z3LMcZbusqfyNPCqlyHI2" : {
"name" : "MyName",
"reviews" : {
"-L0f3Bdjk9aVFtVZYteC" : true,
"-L0f7eUGqenqAPC1liYj" : true
}
}
}
}
I use this code below to get all store's reviews (using AngularFire2)
getReviews(storeID: string){
return this.db.list('/reviews', ref => {
return ref.orderByChild('storeID').equalTo(storeID);
});
}
Now, I want to make a server-side review pagination, but I think I cannot do it with this database structure. Am I right? Tried:
getReviews(storeID: string){
return this.db.list('/reviews', ref => {
return ref.orderByChild('storeID').equalTo(storeID).limitToLast(10) //How to make pagination without retrive all data?
});
}
I thought that I could put all reviews inside stores, but (i) I don't want to retrieve all reviews at once when someone ask for a store and (ii) my review has a username, so I want to make it easy to change it (that why I have a denormalized table)
For the second page you need to know two things:
the store ID that you want to filter on
the key of the review you want to start at
You already have the store ID, so that's easy. As the key to start at, well use the key of the last item on the previous page, and then just request one item extra. Then finally, you'll need to use start() (and possibly endAt() for this:
return this.db.list('/reviews', ref => {
return ref.orderByChild('storeID')
.startAt(storeID, lastKeyOnPreviousPage)
.limitToLast(11)
});
Refer this and this documentation.
For the first page:
snapshot = await ref.orderByChild('storeID')
.equalTo(store_id) //store_id is the variable name.
.limitToLast(10)
.once("value")
Store the firstKey (NOT the lastKey) from the above query. (Since you are using limitToLast())
firstKey = null
snapshot.forEach(snap => {
if (!firstKey)
firstKey = snap.key
// code
})
For the next page:
snapshot = await ref.orderByChild('storeID') //storeID is the field name in the database
.startAt(store_id) //store_id is the variable name which has the desired store ID
.endAt(store_id, firstKey)
.limitToLast(10 + 1) //1 is added because you will also get value for the firstKey
.once("value")
The above query will fetch 11 list data which will contain one redundant data from the first page's query.
How it works:
startAt ( value : number | string | boolean | null , key ? : string ) : Query
The starting point is inclusive, so children with exactly the specified value will be included in the query. The optional key argument can be used to further limit the range of the query. If it is specified, then children that have exactly the specified value must also have a key name greater than or equal to the specified key.
endAt ( value : number | string | boolean | null , key ? : string ) : Query
The ending point is inclusive, so children with exactly the specified value will be included in the query. The optional key argument can be used to further limit the range of the query. If it is specified, then children that have exactly the specified value must also have a key name less than or equal to the specified key.
So the query will try to fetch:
storeID >= store_id && storeID <= store_id (lexicographically)
which will equal to
storeID == store_id
I have the following documents in my mongodb collection:
{
"current" :
{
"aksd" : "5555",
"BullevardBoh" : "123"
},
"history" :
{ "1" : {
"deleted" : false,
"added" : false,
"date" : "21-08-2014"
}
},
{ "2" : {
"deleted" : false,
"added" : false,
"date" : "01-01-2013"
}
},
"_id" : ObjectId("53f74dad2cbfdc136a07bf16"),
"__v" : 0
}
I have multiple of these documents. Now I want to achieve two things with my Mongoose/Express API.
Query for all nested "current" in each document and retrieve them as JSON objects like such: {"aksd":"5555","BullevardBoh":"123"},{..},{..}.
Retrieve all history revisions (1,2...) where "date" is smaller than a given date.
As you can clearly see this is a kind of versioning I am trying to implement. I would also be interested if this kind of data structure will get indexed by MongoDB and if there is possibly a better way. (e.g. with arrays inside objects?)
This isn't working in MongoDB:
db.ips.findOne({current.aksd: {$exists:true}});
I think the quotes around the field are missing here:
db.ips.findOne({current.aksd: {$exists:true}});
This should work instead:
db.ips.findOne({"current.aksd": {$exists:true}});
While Ritesh's reply was a step in the right direction, I rather wanted to fetch the current object literal and its members inside the document not the whole document.
1.) Query for all nested "current" in each document
db.ips.find({"current":{$exists:true}}, {"current":1});
This is giving back all nested documents where the aksd literal is present:
{ "current" : { "aksd" : "5555", "BullevardBoh" : "123" }, "_id" : ObjectId("53f74dad2cb3dc136a07bf16") }
...
2.) Retrieving history revisions where date is smaller then a given date:
db.ips.find({"history.date": {$lt: "01-01-2014"}},{history:{$elemMatch:{date: {$lt:"01-01-2014"}}}});
Giving back the wanted nested date literal(s):
{ "historie" : [ { "date" : "01-01-2013", "added" : false, "deleted" : false } ], "_id" : ObjectId("53faf20f399a954b2b7736b6") }