I tried to implement AJAX live search with AJAX and I did it quite well. Then I tried to add the _.debounce function so it will not overloads the server but it didn't work well..
this is the code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>PHP Live MySQL Database Search</title>
<script src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('.search-box input[type="text"]').on("keyup input", _.debounce(function(){
/* Get input value on change */
var term = $(this).val();
var resultDropdown = $(this).siblings(".result");
if(term.length){
$.get("backend-search.php", {query: term}).done(function(data){
// Display the returned data in browser
resultDropdown.html(data);
});
} else{
resultDropdown.empty();
}
}),250);
// Set search input value on click of result item
$(document).on("click", ".result p", function(){
$(this).parents(".search-box").find('input[type="text"]').val($(this).text());
$(this).parent(".result").empty();
});
});
</script>
</head>
<body>
<div class="search-box">
<input type="text" autocomplete="off" placeholder="Search country..." />
<div class="result"></div>
</div>
</body>
</html>
and this is the php file:
<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
$link = mysqli_connect("localhost", "root", "", "demo");
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Escape user inputs for security
$query = mysqli_real_escape_string($link, $_REQUEST['query']);
if(isset($query)){
// Attempt select query execution
$sql = "SELECT * FROM countries WHERE name LIKE '" . $query . "%'";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
echo "<p>" . $row['name'] . "</p>";
}
// Close result set
mysqli_free_result($result);
} else{
echo "<p>No matches found for <b>$query</b></p>";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
}
// close connection
mysqli_close($link);
?>
Thanks!
Your code doesn't include the Underscore library, so _.debounce() won't be available to use. That said, you can achieve what that method does quite easily by using a setTimeout() call:
var timeout;
$('.search-box input[type="text"]').on("keyup input", function() {
var term = $(this).val();
var $resultDropdown = $(this).siblings(".result");
clearTimeout(timeout);
timeout = setTimeout(function() {
if (term.trim().length) {
$.get("backend-search.php", { query: term }).done(function(data) {
$resultDropdown.html(data);
});
} else {
$resultDropdown.empty();
}
}, 250);
});
you can do this by setting a setTimeout to make an ajax call on every change that occurs on input after passing a specific time but don't forget to kill the previous calls. you can use the code below to any function needs denounce.
var debounce;
$('#input').on('input', function (e) {
clearTimeout(debounce);
debounce = setTimeout(
function () {
searchText(e.target.value)
}, 1000
);
});
Related
I have a form where you can add orders with different details to the database. In this form there is a field called Client where you can create a new client or select an existing one.
To make this last part I found some snippets of a live bar with Ajax. It works fine and you get the results, but I want the selected result to be passed to a PHP variable to update the client field in the database.
Here is my HTML code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Search bar</title>
<script src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('.search-box input[type="text"]').on("keyup input", function(){
var inputVal = $(this).val();
var resultDropdown = $(this).siblings(".result");
if(inputVal.length){
$.get("backend-search.php", {term: inputVal}).done(function(data){
resultDropdown.html(data);
});
} else{
resultDropdown.empty();
}
});
$(document).on("click", ".result p", function(){
$(this).parents(".search-box").find('input[type="text"]').val($(this).text());
$(this).parent(".result").empty();
});
});
</script>
</head>
<body>
<div class="search-box">
<input type="text" autocomplete="off" placeholder="Search client..." />
<div class="result"></div>
</div>
<p> Selected result: </p>
</body>
</html>
And this is my PHP code:
<?php
$link = mysqli_connect("localhost", "root", "", "test");
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
if(isset($_REQUEST["term"])){
$sql = "SELECT * FROM clientes WHERE nombre LIKE ?";
if($stmt = mysqli_prepare($link, $sql)){
mysqli_stmt_bind_param($stmt, "s", $param_term);
$param_term = $_REQUEST["term"] . '%';
if(mysqli_stmt_execute($stmt)){
$result = mysqli_stmt_get_result($stmt);
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
echo "<p>" . $row["nombre"] . " | (ID:" . $row["id"] . ")</p>";
}
} else{
echo "<p>No matches found</p>";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
}
mysqli_stmt_close($stmt);
}
mysqli_close($link);
?>
Here are a few pics if it helps to see what I mean:
Search bar after typing something
Search bar after selecting one of the results
Actually, if I get it right, you should not pass it to a variable on php. You need to use ajax once more but instead of getting something from the database using get, you should add/update somthing to the database using post.
$.post(...)
And then you need to control the route you set in your ajax and voilà.
I actually solved it placing the code inside the form, thanks for your time!
enter image description hereI am new to php and JavaScript/jQuery. Before starting to Learn php I somehow know a little bit of htmL and css.
I have been editing a template I just downloaded and tumbled to this problem that I have been trying to figure out to look for a workaround
My problem is I can't make the result from my searchbox redirect to my update.php page on click of the result and clear the search when no match is found, and that is the output I am trying to accomplish.
I just can't make the same action from the anchor of my table when the user clicks the name do the same with my search bar.
I hope someone can help me.
(by the way, I am a magnifier and screen reader user due to some visual disability.)
Thanks in advance :-)
<?php
$link = mysqli_connect("localhost", "root", "", "ajax_crud");
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
if(isset($_REQUEST['term'])){
$search_string = "SELECT * FROM name WHERE name LIKE ?";
if($stmt = mysqli_prepare($link, $sql)){
mysqli_stmt_bind_param($stmt, "s", $param_term);
$param_term = $_REQUEST['term'] . '%';
if(mysqli_stmt_execute($stmt)){
$result = mysqli_stmt_get_result($stmt);
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
echo "<p>" . $row["name"] . "</p>";
}
} else{
echo "<p>No matches found!</p>";
}
} else{
echo "ERROR: Could not able to execute $sql. " .
mysqli_error($link);
}
}
mysqli_stmt_close($stmt);
}
mysqli_close($link);
?>
/* and the script
<script type="text/javascript">
$(document).ready(function(){
$('.search-box input[type="text"]').on("keyup input", function(){
var inputVal = $(this).val();
var resultDropdown = $(this).siblings(".result");
if(inputVal.length){
$.get("backend-search.php", {term: inputVal}).done(function(data){
resultDropdown.html(data);
});
} else{
resultDropdown.empty();
}enter image description here
});
$(document).on("click", ".result p", function(){
$(this).parents(".search-
box").find('input[type="text"]').val($(this).text());
$(this).parent(".result").empty();
});
});
</script>
/* the part of the table where I can redirect the user to the update.php
fiLe
echo sprintf('<td>%s</td>', $row['id'],
$row['name']);
this is how my index page Looks Like
this is an exampLe of a search in action
i cLicked on a resuLt from the search
the resuLt is pLaced in the searchbox on cLick
this is the update.php wherein the user shouLd be redirected upon cLicking the resuLt
i am sorry i wasn't abLe to add these Line of codes earLier.
i hope this couLd cLear things and make myseLf more understandabLe.
<script type="text/javascript">
$(document).ready(function(){
$('.search-box input[type="text"]').on("keyup input", function(){
var inputVal = $(this).val();
var resultDropdown = $(this).siblings(".result");
if(inputVal.length){
$.get("backend-search.php", {term: inputVal}).done(function(data){
resultDropdown.html(data);
});
} else{
resultDropdown.empty();
}
});
$(document).on("click", ".result p", function(){
$(this).parents(".search-box").find('input[type="text"]').val($(this).text());
$(this).parent(".result").empty();
});
});
</script>
So you have an auto complete searchbox, and the results should not auto-complete the searchbox, but instead redirect to some other page?
If so, then you have a problem, the default jquery auto complete won't help you here, so your function to add contents to result should be custom and then insert html to an object you provide styling to yourself.
something like this:
$('input[type="text"]').on("keyup input", function(){
var inputVal = $(this).val();
var resultDropdown = document.getElementById("result");
if(inputVal.length){
//$.get("backend-search.php", {term: inputVal}).done(function(data){
// exmaple data response
var data = 'name1<br>name2';
resultDropdown.innerHTML = data;
} else{
resultDropdown.innerHTML = "";
}
});
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
</head>
<body>
<input type="text">
<div id="result"></div>
</body>
I have a simple ajax live search script using PHP jQuery and ajax. It all works great but the input box does not clear completely so the results box doesn't disappear unless I manually clear it..
JS -
<script type="text/javascript">
$(document).ready(function(){
$('.search-box input[type="text"]').on("keyup input", function(){
/* Get input value on change */
var inputVal = $(this).val();
var resultDropdown = $(this).siblings(".result");
if(inputVal.length){
$.get("backend-search.php", {term: inputVal}).done(function(data){
// Display the returned data in browser
resultDropdown.html(data);
});
} else{
resultDropdown.empty();
}
});
// Set search input value on click of result item
$(document).on("click", ".result", function(){
$(this).parents(".search-box").find('input[type="text"]').val($(this).text());
$(this).parent(".result").empty();
});
});
</script>
PHP -
$user = $_GET['user'];
$term = mysqli_real_escape_string($conn, $_REQUEST['term']);
if(isset($term)){
// Attempt select query execution
$sql = "SELECT * FROM prospects WHERE dealer_name LIKE '" . $term . "%'";
if($result = mysqli_query($conn, $sql)){
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
$dealer_name = $row['dealer_name'];
echo "<form method='post' class='editForm'>
<input type='hidden' name='dealer' value='$dealer_name'/>
<input type='submit' id='subDealer' value='$dealer_name'/>
</form>";
}
// Close result set
} else{
echo "<p>No matches found</p>";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($conn);
}
}
HTML -
<div class="search-box">
<input type="text" id="searchBox" autocomplete="off" placeholder="Search dealer..." />
<div class="result"></div>
</div>
Like it said it all works but there is blank whitespace in the input field (#searchBox) which will not allow the .result to clear..
Thanks!
Try the below snippet
// Set search input value on click of result item
$(document).on("click", ".result", function(){
$(this).parents(".search-box").find('input[type="text"]').val($(this).text().trim());
});
$(document).on('click', 'input[type=submit]', function() {
// This is NOT the best practice. But it works. Try to change your implementation to a better one!
setTimeout(function() {
$('.result').empty();
}, 1000);
return true;
}
Use jQuery trim() function
<script type="text/javascript">
$(document).ready(function(){
$('.search-box input[type="text"]').on("keyup input", function(){
/* Get input value on change */
var inputVal1 = $(this).val();
var inputVal = $.trim(inputVal1);
var resultDropdown = $(this).siblings(".result");
if(inputVal.length){
$.get("backend-search.php", {term: inputVal}).done(function(data){
// Display the returned data in browser
resultDropdown.html(data);
});
} else{
resultDropdown.empty();
}
});
// Set search input value on click of result item
$(document).on("click", ".result", function(){
$(this).parents(".search-box").find('input[type="text"]').val($(this).text());
$(this).parent(".result").empty();
});
});
</script>
Hi guys its my first time trying out a live ajax search for my site. I am new to php so any help on this matter would be great. I was following some tutorials here and there and trying to make it work, but every time i press search no results come up at all. Any help on this matter would be great.
Code:
<?php
mysql_connect("localhost","root","") or die ("could not connect");
mysql_select_db("reg") or die ("could not find db");
if (isset($_POST['search_term']) == true && empty($_POST['search_term']) == false) {
$search_term = mysql_real_escape_string($_POST['search_term']);
$query = mysql_query("SELECT `ingName` FROM `ing` WHERE `ingName` LIKE '$search_term%'");
while(($row = mysql_fetch_assoc($query)) !== false) {
echo '<li>',$row['ingName'],'</li>';
}
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
</head>
<body>
<div class="container">
<input type="text" class="searchFunction"> <input type = "submit" value ="Search">
<div class = "dropdown">
<ul class = "result">
</ul>
</div>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('.searchFunction').keyup(function() {
var search_term = $(this) .attr('value');
$.post('build.php', {search_term:search_term}, function(data) {
$('.result').html(data);
$('.result li').click(function() {
var result_value = $(this).text();
$('.searchFunction').attr('value', result_value);
$('.result').html('');
});
});
});
});
</script>
</body>
</html>
Again i am so new to this, so i am just trying to build my knowledge around this area. Any help in solving this big problem out would be great
P.S i know about the sql injections :) but one step at a time for now x
As has been pointed out - the method used so far is at risk of sql injection so before getting committed to using the now deprecated mysql suite of functions you would be wise to read up on and implement mysqli which, when you employ prepared statements will offer significant protection from malevolent sql injection attacks.
As your ajax query is being sent to the same page ( by the looks of code posted ) one important thing to do is exit from the phpafter sending the response - otherwise you end up sending the entire page ( which would also be badly formed as there would be content outside the html tags ) and I suspect this is not your desired goal.
The ajax function looks, to my untrained eye, ok but as I don't use jQuery I might well be wrong and have missed something important.
<?php
/*
as the rest of the page doesn't use a db connection,
only load the db conn if the page is requested via post
*/
if( $_SERVER['REQUEST_METHOD']=='POST' ){
/* assign db connection to a variable */
$conn=mysql_connect("localhost","root","") or die ("could not connect");
mysql_select_db("reg") or die ("could not find db");
/* empty() does an implied `isset` */
if ( !empty( $_POST['search_term'] ) ) {
$search_term = mysql_real_escape_string( $_POST['search_term'] );
/*
You ought to look at using mysqli ( prepared statements )
rather than the now deprecated `mysql_*` functions
*/
$query = mysql_query( "SELECT `ingName` FROM `ing` WHERE `ingName` LIKE '$search_term%'", $conn );
if( $query ){/* only send response if the query succeeds */
while( $row = mysql_fetch_assoc( $query ) ) {
echo '<li>',$row['ingName'],'</li>';
}
}
}
mysql_close( $conn );
/* make sure that the rest of the page is not sent back with the response data */
exit();
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<title>Gotta have a title!</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script type="text/javascript">
$( document ).ready( function() {
$('.searchFunction').keyup( function( event ) {
/* I could not get this to work - I don't know what this is doing as I don't use jQuery */
/*var search_term = $(this).attr('value');*/
/* this however does work */
var el=event.target || event.srcElement;
var search_term=el.value;
/* maybe better to search after a few letters have been added? */
if( search_term.length < 2 )return;
/* it appears you are posting to the same page */
$.post( document.location.href, { search_term:search_term }, function( data ) {
$('.result').html( data );
$('.result li').click( function( event ) {
var result_value = $(this).text();
$('.searchFunction').attr('value', result_value );
$('.result').html('');
});
});
});
});
</script>
</head>
<body>
<div class="container">
<input type="text" name='search_term' class="searchFunction">
<input type="submit" value="Search">
<div class="dropdown">
<ul class="result"></ul>
</div>
</div>
</body>
</html>
Full, working example
<?php
if( $_SERVER['REQUEST_METHOD']=='POST' ){
if ( !empty( $_POST['search_term'] ) ) {
$dbhost = 'localhost';
$dbuser = 'root';
$dbpwd = 'xxx';
$dbname = 'xxx';
$db = new mysqli( $dbhost, $dbuser, $dbpwd, $dbname );
/* using lower() helped account for vagueries in spelling */
$sql='select * from `maps` where
lower( `location_name` ) like lower( "%'.$_POST['search_term'].'%" );';
$res=$db->query( $sql );
if( $res ){
while( $rs=$res->fetch_object() ){
echo "<li>".$rs->location_name."</li>";
}
}
}
exit();
}
?>
<!doctype html>
<html lang='en'>
<head>
<title>Gotta have a title!</title>
<script src='https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js'></script>
<script type='text/javascript'>
$( document ).ready( function() {
$('.searchFunction').keyup( function( event ) {
var search_term=this.value;
/* maybe better to search after a few letters have been added? */
if( search_term.length < 5 )return;
/* it appears you are posting to the same page */
$.post( document.location.href, { search_term:search_term }, function( data ) {
$('.result').html( data );
$('.result li').click( function( event ) {
var result_value = $(this).text();
$('.searchFunction').attr( 'value', result_value );
$('.result').html('');
});
});
});
});
</script>
</head>
<body>
<div class='container'>
<input type='text' name='search_term' class='searchFunction'>
<input type='submit' value='Search'>
<div class='dropdown'>
<ul class='result'></ul>
</div>
</div>
</body>
</html>
You can try writing your query without the quotations ie:
$query = mysql_query("SELECT ingName FROM ing WHERE ingName LIKE '$search_term%'");
and you can also loosen your search by using '%$search_term%' instead of '$search_term'.
Another possible issue is the mysql_connect(). I was using that function and it did not work for me so I resolved to the mysqli_connect() function which worked for me.
Some more advise, you do not need the ==true and you can also you can use
!empty($_POST['search_term']).
Once you are through learning that you can also try the PDO function which is far much better than initiating your own connection.
You initiate a PDO connection like this.
$dbh1 = new PDO('mysql:dbname=dbname;host=127.0.0.1', 'username', 'dbpass');
Then you can search like this. - using the initialized connection.
$query = "SELECT ingName from ing WHERE ingName LIKE %$search_term%";
$stmt = $dbh1->prepare($query);
$stmt->execute();
$allRows = count($stmt);
$row = $stmt->fetch(PDO::fetch_assoc);
foreach($row as $one){
echo "<li>".$one['ingName']."</li><br>";
}
Cheers!
Im trying to get my PHP script called from AJAX (that is in my main php file).
Here's an example of what it is supposed to do: http://jsfiddle.net/xfuddzen/
The HTML source code shows only desk_box DIV being created (which is in my main.php). station_info DIV (being created in the display_station.php) is not there. How can I fix this? thanks in advance
Problem: DIVs from my display_stationinfo.php are not being created by using the AJAX call.
main.php with JQuery/AJAX part:
<div id="map_size" align="center">
<?php
//didsplay Desk stations in the map
while($row = mysqli_fetch_assoc($desk_coord_result)){
//naming X,Y values
$id = $row['coordinate_id'];
$x_pos = $row['x_coord'];
$y_pos = $row['y_coord'];
//draw a box with a DIV at its X,Y coord
echo "<div class='desk_box' data='".$id."' style='position:absolute;left:".$x_pos."px;top:".$y_pos."px;'>id:".$id."</div>";
} //end while loop for desk_coord_result
?>
<script type="text/javascript">
//Display station information in a hidden DIV that is toggled
//And call the php script that queries and returns the results LIVE
$(document).ready(function() {
$('.desk_box').each((function(){(this).click(function() {
var id = $(this).attr("data")
$("#station_info_"+id).toggle();
$.ajax({
url: 'station_info.php',
data: { 'id': id },
type: 'POST',
dataType: 'json',
success: function(json) {
$("#station_info_"+id).css({'left':json.x_pos ,'top': json.y_pos}).append('<p>Hello the id is:'+ json.id +'</br>Section:'+ json.sec_name +'</p>');
}//end success
});//end ajax
});//end click
});//end ready
</script>
</div> <!-- end map_size -->
display_station.php (script that I want to call):
<?php
include 'db_conn.php';
//query to show workstation/desks information from DB for the DESKS
$station_sql = "SELECT coordinate_id, x_coord, y_coord, section_name FROM coordinates";
$station_result = mysqli_query($conn,$station_sql);
//see if query is good
if ($station_result === false) {
die(mysqli_error());
}
//Display workstations information in a hidden DIV that is toggled
$html = '';
if($station_result->num_rows > 0){
while($row = $station_result->fetch_object()) {
$id = $row->coordinate_id;
$html .= "<div class='station_info_' id='station_info_$id' style='position:absolute;left:{$row->x_coord}px;top:{$row->y_coord}px;'>Hello the id is:$id</br>Section:{$row->section_name}</br></div>";
}
}
else{
// no results - may want to do something with $html
$html = "no result given";
}
$station_result->free();
$conn->close();
echo $html;
?>
Why dont you filter the coordinate in the query? Like this:
$station_sql = "SELECT coordinate_id, x_coord, y_coord, section_name FROM coordinates WHERE coordinate_id = " . $_GET['coordinate_id'];
And in jquery code:
url: 'display_stationinfo.php?coordinate_id=' + id,
Let's start with your database connection, which should be on a separate secure page.
connect.php:
<?php
function db(){
return new mysqli('host', 'username', 'password', 'database');
}
?>
Obviously, your host will not be 'host'.
Now main.php:
<?php
// only use for PHP on this page for initial page load - target other pages with AJAX
?>
<!DOCTYPE html>
<html xmlns='http://www.w3.org/1999/xhtml' xml:lang='en' lang='en'>
<head>
<meta http-equiv='content-type' content='text/html;charset=utf-8' />
<title>This is Where Your Title Goes</title>
<script type='text/javascript' src='//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js'></script>
<script type='text/javascript' src='main.js'></script>
<link rel='stylesheet' type='text/css' href='main.css' />
</head>
<body>
<div id='map_container'>
<div id='map_size'>
</div>
</div>
</body>
</html>
Now for main.js:
//<![CDATA[
$(function(){
var ms = $('#map_size');
$.post('main_init.php', {init:'1'}, function(d){
for(var i in d){
var di = d[i], x = di.x, y = di.y;
var sti = $("<div class='station_info_' id='station_info_"+i+"'></div>").css({
left:x,
top:y
});
// HTML id, class, and name attributes cannot start with a number
$("<div class='desk_box' data='"+i+"'>id:"+i+'</div>').css({
left:x,
top:y
}).appendTo(ms).append(sti).click(function(){
var info = $(this).next();
$.post('live_info.php', {station_id:info.attr('id').replace(/^station_info_/, '')}, function(r){
// do stuff with r
info.html('love:'+r.love+'<br />hate:'+r.hate).toggle();
}, 'json');
});
}
}, 'json');
});
// use CSS to do `.desk_box,.station_info_{position:absolute;}`
//]]>
Now for main_init.php:
<?php
if(isset($_POST['init']) && $_POST['init'] === '1'){
include_once 'connect.php'; $db = db(); $json = array();
$q = $db->query("SELECT * FROM table WHERE"); // example only
if($q->num_rows > 0){
while($r = $q->fetch_object()){
$json[strval($r->coordinate_id)] = array('x' => $r->x_coord, 'y' => $r->y_coord);
}
}
else{
// no results
}
$q->free(); $db->close();
echo json_encode($json);
}
else{
// could be a hack
}
?>
Here's what live_info.php might look like:
<?php
if(isset($_POST['station_id'])){
include_once 'connect.php'; $db = db(); $json = array();
// example only - you will only get one `$row` if query is done specific, so while loop is not needed
$q = $db->query("SELECT love,hate FROM some_table WHERE id='{$_POST['station_id']}'");
if($q->num_rows > 0){
$row = $q->fetch_object();
// it's okay to overwrite array in this case
$json = array('love' => $row->love, 'hate' => $row->hate);
}
else{
// no results
}
$q->free(); $db->close();
echo json_encode($json);
}
else{
// may be a hack
}
?>