I'm using jquery UI autocomplete for a search on my site. It's working properly without any problems while is on localhost. But on the live server it doesn't get any results. I have reviewed many posts on this topic, but I am still stymied as to why this doesn't work. I don't know if I can tell you the name of web hosting I use or not.
HTML code: index.php
<input type="text" placeholder="" name="ser" class="form-control" id="hotels" value="" required />
javascript code
<script type="text/javascript">
$(function() {
$( "#hotels" ).autocomplete({
source: 'scripts/chresults.php'
});
});
</script>
chresults.php
<?php
$dbHost = '';
$dbUsername = '';
$dbPassword = '';
$dbName = '';
//connect with the database
$db = new mysqli($dbHost,$dbUsername,$dbPassword,$dbName);
//get search term
$searchTerm = $_GET['term'];
//get matched data from skills table
$query = $db->query("SELECT * FROM hotels WHERE hotel LIKE '%".$searchTerm."%' or hotelen LIKE '%".$searchTerm."%' or city LIKE '%".$searchTerm."%'limit 5") or die ('mysql_error');
while ($row = $query->fetch_assoc())
{
$results['city'] = $row['city'];
$results[] = $row['hotel'].' , '.$row['city'];
}
//return json data
$json_string = json_encode($results, JSON_PRETTY_PRINT);
echo $json_string;
?>
Related
My aim is to fetch location from the database once user start entering in the input tetc field
i have done all the coding properly but the also am not able to fetch the data from the database.
<!--My java script code-->
$(function() {
$( "#LocationName" ).autocomplete({
source: 'search.php'
});
});
<!--My Search.php code-->
<?php
include('dbConnect.php');
$searchTerm = $_GET['term'];
$sql = mysql_query ("SELECT LocationName,From arealistmain WHERE LocationName LIKE ?");
$array = array();
while ($row = mysql_fetch_array($sql)) {
$array[] = array (
'value' => $row['LocationName'].'',
);
}
//RETURN JSON ARRAY
echo json_encode ($array);
?>
First of all don't use mysql_* functions as they were deprecated in PHP 5.5 and removed in PHP 7 instead use mysqli_* functions.
Second thing you should always sanitize user input don't just do $searchTerm = $_GET['term']; read more about this
Then your SQL query should read
$query = "SELECT LocationName From arealistmain WHERE LocationName LIKE '%$searchTerm%';";
The comma before FROM removed and the $searchTerm is enclosed in two percentage signs to match all
Update your query to below code
$sql = mysql_query ("SELECT LocationName From arealistmain WHERE LocationName LIKE '%".$searchTerm."%'");
$array = array();
while ($row = mysql_fetch_array($sql)) {
$array[] = $row['LocationName'];
}
I have a small problem that I'm not quite sure what the solution would be.
I'm doing an autoComplete using Jquery, I have a php file that takes the data from the database and leaves it in a format that I need like this in the image below.
http://prntscr.com/hgxjsc
in my html I have the following code
<input type="text" id="input_produto" value="" name="input_produto" placeholder="Produto" class="span4 m-wrap">
for better visualization by identation issue
http://prntscr.com/hgxo8z
Anyone who can help in any way, I'll be grateful, I'm new to this area. If you have an example of how to do it, better yet ... Thank you in advance
Excuse me, my English is not very good either.
I would recommend following these steps in order.
For php code;
<?php
//database configuration
$dbHost = 'localhost';
$dbUsername = 'root';
$dbPassword = '';
$dbName = 'codexworld';
//connect with the database
$db = new mysqli($dbHost,$dbUsername,$dbPassword,$dbName);
//get search term
$searchTerm = $_GET['term'];
//get matched data from skills table
$query = $db->query("SELECT * FROM skills WHERE skill LIKE '%".$searchTerm."%' ORDER BY skill ASC");
while ($row = $query->fetch_assoc()) {
$data[] = $row['skill'];
}
//return json data
echo json_encode($data);
?>
For Jquery code;
<script>
$(function() {
$( "#skills" ).autocomplete({
source: 'search.php'
});
});
</script>
For example Html code;
<div class="ui-widget">
<label for="skills">Skills: </label>
<input id="skills">
</div>
Good luck.
I have a form that currently is able to auto complete base on user input, it queries the MySQL database and successfully lists all possible matches in the table and give suggestions. Now I want to handle rows that do not exist. I am having trouble to get my PHP file to echo the error. Here is what I have so far:
I'm guessing in my auto search function in my javascript in main.php I need to return the error message to the page?
search.php
<?php
//database configuration
$host = 'user';
$username = 'user';
$password = 'pwd';
$name = 'name';
//connect with the database
$dbConnection = new mysqli($host,$username,$password,$name);
if(isset($_GET['term'])){
//get search term
$searchTerm = '%'.$_GET['term'].'%';
//get matched data from skills table
if($query = $dbConnection->prepare("SELECT * FROM nametbl WHERE name LIKE ? ORDER BY name ASC")) {
$query->bind_param("s", $searchTerm);
$query->execute();
$result = $query->get_result();
//$row_cnt = $result->num_rows;
//echo $row_cnt;
if($result -> num_rows){
while ($row = $result->fetch_assoc()) {
$data[] = $row['name'];
}
//return json data
echo json_encode($data);
mysqli_close($dbConnection);
}
else { echo '<pre>' . "there are no rows." . '</pre>'; }
}
else {
echo '<pre>' . "something went wrong when trying to connect to the database." . '</pre>';
}
}
?>
main.php
<div id="gatewayInput">
<form method="post">
<input type="text" id="name" name="name" placeholder="Name..."><br><br>
<?php
include("search.php");
?>
</div>
...
...
...
<script src ="../../../jqueryDir/jquery-3.2.1.min.js"></script>
<script src ="../../../jqueryDir/jquery-ui.min.js"></script>
<script type="text/javascript">
//auto search function
$(function() {
$( "#name" ).autocomplete({
source: 'search.php'
});
});
1.your method type is post in the form
in main.php
and in the search.php, you have used "if(isset($_GET['term'])){"
this needs to be fixed I guess. either both needs to be POST or GET.
Again you are using include method which the whole code in search.php will be made in-line and treated as a one file main.php. so you need not use GET or Post method.
How does get and Post methods work is
3.1) you have a html or PHP which submits the data from browser(main.php), and this request is being served by an action class(search.php)
example :- in main.php
3.2) now in search.php you can use something like if(isset($_POST['term'])){
You can use num_rows (e.g. if ($result -> num_rows)) to see if the query returned anything.
I have the following php script which works fine, it uses the search term and compares it with a few different fields, then prints out the each record that matches:
<?php
mysql_connect ("localhost", "root","") or die (mysql_error());
mysql_select_db ("table");
$search = isset($_POST['search']) ? $_POST['search'] : '';
$sql = mysql_query("select * from asset where
name like '%$search%' or
barcode like '%$search%' or
serial like '%$search%' ");
while ($row = mysql_fetch_array($sql)){
echo '<br/> Name: '.$row['name'];
echo '<br/> Barcode: '.$row['barcode'];
echo '<br/> Serial: '.$row['serial'];
}
?>
And this is the form that links to it:
<form action="http://localhost/test/search.php" method="post">
Search: <input type="text" name="search" /><br />
<input type="submit" name="submit" value="Submit" />
</form>
I need to some how encode the results of the search so I can use them in a javascript function, then I can display them on the same html page below the form.
For that you have to use AJAX. You can send data back to the same page using JSON.
Advice - Don't use mysql_* functions since they are deprecated. Learn mysqli_* and try using that.
<script>
$(function(ev){
ev.preventDefault();
$("form").on('submit', function(){
var form = $(this);
var url = form.attr('action');
var data = form.serialize();
$.post(url, data)
.done(function(response){
if(response.success == TRUE)
{
// Search result found from json
// You have to loop through response.data to display it in your page
// Your single loop will have something like below -
var name = response.data.name;
var barcode = response.data.barcode;
var serial = response.data.serial;
$("#name").html(name);
$("#barcode").html(barcode);
$("#serial").html(serial);
}
else
{
// search result not found
}
});
});
});
</script>
On search.php
<?php
mysql_connect ("localhost", "root","") or die (mysql_error());
mysql_select_db ("table");
$search = isset($_POST['search']) ? $_POST['search'] : '';
$sql = mysql_query("select * from asset where
name like '%$search%' or
barcode like '%$search%' or
serial like '%$search%' ");
$num = mysql_rows_nums($sql);
$json = array();
if($num > 0)
{
$json['success'] = TRUE;
while ($row = mysql_fetch_array($sql)){
$json['data']['name'] = $row['name'];
$json['data']['barcode'] = $row['barcode'];
$json['data']['serial'] = $row['serial'];
}
}
else
{
$json['success'] = FALSE;
}
return json_encode($json);
?>
Overview
I am attempting to encrypt data, send it to a database, then decrypt the data using the Stanford Javascript Crypto Library (SJCL).
Problem
Whenever I attempt to call the data from the database, I get a "CORRUPT: ccm: tag doesn't match" error. I have looked this up and it seems as if my content or password is corrupted, and because the password is being straight from a textbox, I have narrowed it down to the content.
Code Snippet
(PHP)
$paste = $_GET['url'];
$query = "SELECT * FROM posts WHERE url='$paste'";
$result = mysqli_query($db, $query);
$row = mysqli_fetch_array($result);
$t = $row['title'];
$c = $row['content'];
$con = json_encode($c);
$e = $row['encode'];
$ca = $row['Catagory'];
$en = $row['encrypted'];
(Javascript) -Invokes SJCL-
<script type="text/javascript">
var content = <?php echo $con; ?>;
function decryptPaste() {
try {
sjcl.decrypt(document.getElementById("decrypt-pass").value, content)
} catch (e) {
alert("Can't decrypt: " + e);
}}
Any and all help appreciated, thanks in advance!