I am trying to get key(primary key) for selected value in my form, so I can add key into joining table. I change my form to autocomplete from drop down list. but do not how to do map with jquery.
This is my php for autocomplete
<?php
if (isset($_POST['type']) && $_POST['type'] == 'faculty_id') {
$type = $_POST['type'];
$name = $_POST['name_startsWith'];
$nameID = $_POST['nameID'];
$query = "SELECT FirstName, LastName, FacultyId FROM Test.Faculty where UPPER(FirstName) LIKE '" . strtoupper($name) . "%'";
$result = mysqli_query($con, $query);
$data = array();
while ($row = mysqli_fetch_assoc($result)) {
$name = $row['FirstName'] . ' ' . $row['LastName'];
$nameID = $row['FacultyId'];
array_push($data, $name);
}
mysqli_close($con);
echo json_encode($data);
exit;
}
?>
this is form and jQuery page
<form action="Form.php" method="post">
<input type='text' id="faculty_id" placeholder="Instructor" name="faculty_id" value='' />
<input type="submit" value="submit" name="submit" />
</form>
<script type="text/javascript">
$('#faculty_id').autocomplete({
source: function (request, response) {
$.ajax({
url: 'Form.php',
dataType: "json",
method: 'post',
data: {
name_startsWith: request.term,
nameID: request.term,
type: 'faculty_id'
},
success: function (data) {
response($.map(data, function (item) {
console.log(item);
//var code = item.split("|");
return {
label: item,
value: item,
data: item
}
}));
}
});
},
autoFocus: true,
minLength: 1,
});
</script>
and php insert query
<?php
if (isset($_POST)) {
$faculty_id = $_POST['faculty_id'];
try {
$stat = $db->prepare("Insert into ATCTest.Schedule
(Faculty )
VALUE (':faculty_id' )");
$stat->bindParam(":faculty_id", $faculty_id);
if ($stat->execute()) {
echo "<h5>Faculty-js: " . $faculty_id . "</h5>";
} else {
echo "Problem!!!";
}
} catch (PDOException $e) {
echo $e->getMessage();
}
}
Stay consistent. Choose either PDO or MySQLi. Not both. Your autocomplete script uses MySQLi, but then in your insert script, you use PDO. Pick one and stick with it.
I'll use PDO as I find it much easier to use than MySQLi.
Use the appropriate request methods. If you are getting something, use GET not POST. If you are adding or updating, use POST.
Let's rewrite your autocomplete script to use PDO:
if (isset($_GET['type']) && $_GET['type'] == 'faculty_id') {
// this will hold your response that gets sent back
$data = null;
$name = trim($_GET['name']);
try {
// because you are passed untrusted data, use prepared statement
$sth = $db->prepare("
SELECT FirstName, LastName, FacultyId
FROM Test.Faculty
WHERE UPPER(FirstName) LIKE UPPER(?)
");
$sth->execute(array($name . '%'));
// set the results (array of objects) as your JSON response
$data['faculties'] = $sth->fetchAll(PDO::FETCH_OBJ);
} catch(PDOException $e){
echo $e->getMessage();
}
// send the results i.e. response
header('Content-Type: application/json');
echo json_encode($data);
exit;
}
I've never used the autocomplete plugin before but I'll take a crack at it based on other answers I've seen.
$('#faculty_id').autocomplete({
source: function (request, response) {
// short syntax for .ajax() using GET method that expects a JSON response
$.getJSON('Form.php', { type: 'faculty_id', name: request.term }, function (data) {
// data.faculties (your AJAX script's response) should now be an array of objects
console.log(data.faculties);
response($.map(data.faculties, function (faculty) {
console.log(faculty);
return {
label: faculty.FirstName + ' ' + faculty.LastName,
value: faculty.FacultyId
}
}));
});
},
autoFocus: true,
minLength: 1,
});
Lastly, when you insert
// check if form was POSTed
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
$faculty_id = $_POST['faculty_id'];
try {
// VALUES not VALUE
// don't wrap your placeholders with quotes in your prepared statement
// simplified
$sth = $db->prepare("INSERT INTO ATCTest.Schedule(Faculty) VALUES(?)");
// simplified way to bind parameters
$sth->execute(array($faculty_id));
// use rowCount() not execute() to determine if the operation was successful or not
if ($sth->rowCount()){
echo "<h5>Faculty-js: $faculty_id</h5>";
} else {
echo "Problem!!!";
}
} catch (PDOException $e) {
echo $e->getMessage();
}
}
Related
How to display the data title, image and content?
Here's the code:
view.php
$id = $_REQUEST['edit_literature_id'];
$literature = $_REQUEST['literatureID'];
$module = $_REQUEST['edit_moduleId'];
if (isset($id)) {
$dataArr = array();
$responseArr = array();
$sql = "SELECT * FROM $literature WHERE `id`='".$id."'";
if ($result = mysqli_query($conn, $sql)) {
if (mysqli_num_rows($result) > 0) {
while ($row = mysqli_fetch_array($result)) {
$data['title'] = $row['title'];
$data['name'] = 'data:image/jpeg;base64,' . base64_encode($row['name']);
$data['content'] = $row['content'];
array_push($dataArr, $data);
}
echo json_encode($dataArr);
}
mysqli_free_result($result);
} else {
echo "No Record";
}
}
index.php
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
rowId = $(this).attr('data-id');
moduleData = $(this).attr('data-module');
literatureData = $(this).attr('data-literature');
$('#edit_id').val(rowId);
$('#edit_module').val(moduleData);
$('#edit_literature').val(literatureData);
$('#edit_imageId').val(rowId);
$('#update').val('update');
$.ajax({
type: 'POST',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (data) {
alert(data)
}
});
});
});
What I'm trying to do is to get the title, image and content.
How to get the value of title, image and content?
How to call the "title", "name" and "content" from the php?
console.log('DATA: ' + data);
No need to use while loop for result. Also remove extra $dataArr and $responseArr
Update your code to:
in view.php
$id = $_REQUEST['edit_literature_id'];
$literature = $_REQUEST['literatureID'];
$module = $_REQUEST['edit_moduleId'];
if (isset($id)) {
$sql = "SELECT * FROM $literature WHERE `id`='".$id."'";
if ($result = mysqli_query($conn, $sql)) {
if (mysqli_num_rows($result) > 0) {
$row = mysqli_fetch_array($result);
$data['title'] = $row['title'];
$data['name'] = 'data:image/jpeg;base64,' . base64_encode($row['name']);
$data['content'] = $row['content'];
echo json_encode($data); exit;
}
mysqli_free_result($result);
}
}
$data['error'] = "No Record";
echo json_encode($data); exit;
Index.php
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
rowId = $(this).attr('data-id');
moduleData = $(this).attr('data-module');
literatureData = $(this).attr('data-literature');
$('#edit_id').val(rowId);
$('#edit_module').val(moduleData);
$('#edit_literature').val(literatureData);
$('#edit_imageId').val(rowId);
$('#update').val('update');
$.ajax({
type: 'POST',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (data) {
var response = jQuery.parseJSON(data);
var title = response.title;
var name = response.name;
var content = response.content;
alert(title);
alert(name);
alert(content);
}
});
});
});
After taking data from jQuery side, you can set value in html side using id or class attribute in jQuery.
How your ajax receiving .php file should look:
$validLiteratureIds = ['yourTable1', 'yourTable2'];
if (!isset($_GET['edit_literature_id'], $_GET['literatureID']) || !in_array($_GET['literatureID'], $validLiteratureIds)) {
$response = ['error' => 'Missing/Invalid Data Submitted'];
} else {
$conn = new mysqli('localhost', 'root', '', 'dbname');
$sql = "SELECT title, name, content
FROM `{$_GET['literatureID']}`
WHERE `id` = ?";
$stmt = $conn->prepare($sql);
$stmt->bind_param("s", $_GET['edit_literature_id']);
$stmt->execute();
$stmt->bind_result($title, $name, $content);
if (!$stmt->fetch()) {
$response = ['error' => 'No Record'];
} else {
$response = [
'title'=> $title,
'name' => 'data:image/jpeg;base64,' . base64_encode($name),
'content' => $content
];
}
}
echo json_encode($response);
Important practices:
Validate the user input so that only qualifying submissions have the privilege of accessing your database.
Write the failure outcomes before success outcomes consistently throughout your project, this will make your scripts easier to read/follow.
Always use prepared statements and bind user-supplied data to placeholders into your query for stability/security.
The tablename cannot be bound like the id value; it must be written directly into your sql string -- this is why it is critical that you validate the value against a whitelist array of literature ids.
There is no need to declare new variables to receive the $_GET values; just access the values directly from the superglobal array.
I am going to assume that your id is a primary/unique key in your table(s), so you don't need to loop over your result set. Attempt to fetch one row -- it will either contain data or the result set was empty.
Call json_encode() only once and at the end of your script.
It is not worth clearing any results or closing a prepared statement or a connection, because those tasks are automatically done when the script execution is finished anyhow -- avoid the script bloat.
As for your jquery script:
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
$.ajax({
type: 'GET',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (response) {
if (response.hasOwnProperty('error')) {
console.log(response.error);
} else {
console.log(response.title, response.name, response.content);
}
}
});
});
});
I've trim away all of the irrelevant lines
changed POST to GET -- because you are merely reading data from the database, not writing
parseJSON() is not necessary -- response is a ready-to-use object.
I am checking for an error property in the response object so that the appropriate data is accessed.
Both scripts above are untested (and completely written from my phone). If I have made any typos, please leave me a comment and I'll fix it up.
I've seen that there has been a lot of questions about this but I did not find any specifics that could apply to my case so if I'm creating a duplicate, sorry for that.
I am trying to retrieve data from SQL database with php file that passes the data to ajax call. Everything seems to be working fine, just when I try to output data into console I get "undefined" variable, even when I tried accessing a precise part of the array with data.story for example. I have also tried data[0].story but that gave me an error that 'story' field of undefined cannot be accessed.
The code is below:
Thanks for your help guys.
my php file:
<?php
$con = mysqli_connect('localhost','root','password','db');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
$array = array();
$sqlFetch = "SELECT s.storyTitle, s.story, s.lattitude, s.longitude,
u.nickname, u.platformUsed, u.sexuality, u.gender, u.age, s.category,
s.dateRecorded FROM stories AS s INNER JOIN users AS u ON u.email = s.email
WHERE s.postStatus != 'published'";
$result = mysqli_query($con,$sqlFetch);
if(!is_null($result->num_rows)){
$encode = array();
while($row = mysqli_fetch_assoc($result)) {
$encode[] = $row;
}
echo json_encode($encode);
}
?>
and ajax code:
$.ajax({
type: 'post',
url: "http://localhost/wordpress/wp-content/themes/TinDA/js/loadData.php",
dataType: 'json',
data: "",
}).done(function(data){
console.log(data);
//tried also: console.log(data.story); and data[0].story;
});
It seems that you are mixing the mysqli connection for
Procedural Style with Object Oriented Style
Procedural:
$con = mysqli_connect('localhost','root','password','db');
$result = mysqli_query($con, "SOME SELECT STATEMENT");
while ($row = mysqli_fetch_assoc($result)){
$data[] = $row;
}
$rows = mysqli_num_rows($result);
if($rows){
json_encode(array('data' => $data, 'msg'=> 'successs'));
} else {
json_encode(array('data' => $data, 'msg'=> 'error or no records...'));
}
OOP:
$con = new mysqli('localhost','root','password','db');
if($con->connect_errno){
echo "WTF didn't work!!" . $con->connect_error;
}
$res = $con->query('SOME SELECT STMNT');
while ($row = $res->fetch_assoc()){
$data[] = $row;
}
$rows = $con->num_rows;
if($rows){
json_encode(array('data' => $data, 'msg'=> 'successs'));
}else {
json_encode(array('data' => $data, 'msg'=> 'error or no records...'));
}
I also like to use this version of ajax (different with 3.0 may not work).
You can then see the data errors. Note, you can have a successful ajax call and return but still have an error.
$.ajax( '/http://localhost/...', {
type: 'POST',
dataType: 'json',
success: function( json ) {
console.log( json );
},
error: function( req, status, err ) {
console.log( 'WTF!!', status, err );
}
});
I am searching this and other sites for hours now, so I'm getting pretty desperate. No code from many questions with the same topic here works.
I need to insert data into the database and display a message after it is done. Also, I am using AJAX with jQuery so it would be asynchronous. It works just fine, the data gets inserted, but no response message shows.
I am a beginner at PHP and can't understend why this won't work. Relevant code below.
PHP function call:
if(isset($_POST["function"]) && !empty($_POST["function"]) && $_POST["function"] == "cl-add") {
$dbb->addMember("MyUsername", $_POST["name"]);
//$dbb is a DataBaseBroker instance
}
PHP function from the Broker:
function addMember($username, $ime) {
$query = "INSERT INTO clan";
$query.=" (username, ime) ";
$query.="VALUES ('".$username."','".$ime."');";
$result = $this->mysqli->query($query);
if ($result) {
echo("You added a member: ".$ime);
} else {
$response = "An error occured. Please try again.";
$response .= "<br>";
$response .= "Error: ".mysqli_error($connection);
echo $response;
}
}
JQuery function declarations:
var addMember = function(name, responseFn) {
if (name === "") {
alert("Please enter a name");
return;
}
$.ajax({
type : 'POST',
url: '../includes/layout/cl.php',
dataType : 'json',
data : {
'name' : name,
'function' : 'cl-add'
},
success : function(data) {
responseFn(data); //not working, should alert
}
});
}
var responseCallback = function(data) {
alert(data);
}
And inside $(document).ready():
$(document).on('click', '#cl-add', function(evt) {
var name = $("#cl_frm input").val();
addMember(name, responseCallback);
});
On your code:
dataType : 'json',
The Ajax request is waiting for a JSON response but you are giving a text response.
You should change the dataType: to text or html depending on your needs.
dataType : 'html',
or
dataType : 'text',
PHP changes:
<?php
function addMember($username, $ime)
{
$query = "INSERT INTO clan";
$query .= " (username, ime) ";
$query .= "VALUES ('" . $username . "','" . $ime . "');";
$result = $this->mysqli->query($query);
$response = null;
if ($result) {
$response = "You added a member: " . $ime;
} else {
$response = "An error occured. Please try again.";
$response .= "<br>";
$response .= "Error: " . mysqli_error($connection);
}
echo $response;
exit;
}
Change dataType parameter to 'text'. Also you can alert an object in JavaScript, actually you are not trying to alert an object but i just wanted to mention it.
I have some problem with the returned value of ajax.
this is the ajax code:
$(document).ready(function() {
var request;
$("#flog").submit(function(event) {
if(request)
request.abort();
event.preventDefault();
var form = $(this);
var serializedData = form.serialize();
var btnname = $('#log').attr('name');
var btnval = $('#log').val();
var btn = '&'+btnname+'='+btnval;
serializedData += btn;
request = $.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: serializedData,
});
request.done(function(data, status, jdXHR) {
alert(data);
});
request.fail(function(jdXHR, status, error) {
});
});
});
it takes data from a form and send it to another page.
this is the second page:
<?php include 'head.php'; ?>
<?php
if($_POST['login']) {
session_regenerate_id(true);
$con = mysqli_connect("localhost", "Alessandro", "ciao", "freetime")
or die('Could not connect: ' . mysqli_error($con));
$query = 'SELECT * FROM users WHERE username="' . $_POST['user'] . '"';
$result = mysqli_query($con, $query) or die('Query failed: ' . mysqli_error($con));
if(mysqli_num_rows($result) == 0) {
mysqli_close($con);
session_unset();
session_destroy();
$res = false;
return $res;
}
$query = 'SELECT password FROM users WHERE username="' . $_POST['user'] . '"';
$result = mysqli_query($con, $query) or die('Query failed: ' . mysqli_error($con));
$line = mysqli_fetch_array($result, MYSQL_ASSOC);
if(md5($_POST['password']) != $line['password']) {
mysqli_close($con);
session_unset();
session_destroy();
return false;
}
?>
<?php include 'foot.php'; ?>
and in .done the returned data is all the html page.
How can I retrieve only a data, like $res? I tried with json_encode() but with no results.
If in the second page I delete the lines include 'head.php' and include 'foot.php' it works. But I need that the secon page is html, too.
Somenone can help me?
Dont use the Data attribute from AJAX.
Replace
request.done(function(data, status, jdXHR) {
alert(data);
});
with
request.done(function(data, status, jdXHR) {
alert(jdXHR.responseText);
});
You could do it in a much simpler way.
In PHP store the result of the attempted login into a variable, for instance $result =0; to start with
If the login is valid change it to 1 and return it to ajax by doing an echo at the end of your PHP file. If you need other value returned such as the name you could add it to the variable with a separator such as || for instance.
in javascript collect your return and go data = data.split('||');
if (data[0] == 0){alert("Welcome back " + data[1]);}else{alert("wrong login...")}
Previous use is correct, you need to escape the user collected in your PHP script.
Hope this helps.
PHP PAGE:
<?php
include "linkpassword.inc";
function showVotes()
{
$showresult = mysql_query("SELECT * from mms") or die("Invalid query: " . mysql_error());
$row = mysql_fetch_assoc($showresult);
}
function addVote()
{
$sql= "UPDATE mms SET votes = votes+1 WHERE color = '".$_POST['color']."'";
$result= mysql_query($sql) or die(mysql_error());
return $result;
}
addVote();
showVotes();
?>
I am trying to get the output of the array to load into a JavaScript page where I can break up the array into seperate divs that have IDs assigned to them. Here is what I tried
<script>
$(document).ready(function () {
$('.answer').click(function (e) {
var color = $(this).attr("data-color");
$.ajax({
type: 'POST',
url: 'mm.php',
data: { color: color},
dataType: 'json',
cache: false,
success: function(showVotes) {
$('#rvotes').html(showVotes[0]);
},
error: function (jqXHR) {
}
})
})
});
</script>
Where am I going wrong??
From what you've posted in comments, what you have is an array of objects.. not html, as your function seems to indicate. Depending on what you want done, the answer would be either of the following, to access that object's properties:
showVotes[0].votes
Or
showVotes[0]['votes']
Eg:
$('#rvotes').html(showVotes[0].votes);
Or etc.
Second attempt:
Firstly, change your current 'showVotes' function to this:
function showVotes()
{
$showresult = mysql_query("SELECT * from mms") or die("Invalid query: " . mysql_error());
while ($row = mysql_fetch_assoc($showresult)) {
$response[] = $row;
}
return json_encode($response);
}
Secondly, remove your 'connected successfully' text from the page, as well as any other text generated by anything else(aka, the other function which returns a result pointer). I may be wrong, but it would seem to me that the generation of this other text is causing the returned json to be interpreted as malformed.
Quick explanation on PDO:
try {
$dbh = new PDO("mysql:host=localhost;dbname=dbname", "user", "password");
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch (\PDOException $e) {
echo "Error! Could not connect to database: " . $e->getMessage() . "<br/>";
die();
}
Connecting to the database.. This is how I've learned to do it, though I've been warned(and downvoted) to not check for errors this way, though it was never explained why.
Database interaction:
$stmt = $dbh->prepare("UPDATE mms SET votes = votes+1 WHERE color = :color");
$stmt->bindParam(":color",$_POST['color']);
$stmt->execute();
Result use:
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
$response[] = $row;
}
And so on and so forth. PDO escapes the values for you, so you don't have to worry about injection attacks.