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How to remove the alphabet in my case using JQuery?

I wants to remove alphabet from string. In my string variable it will have the numbers with alphabet
For example
var myString = '1122D'
// I want remove the last alphabet only from the above variable
var myString = '1122Z3'
// I want remove the `Z3` from above string
var myString = '112DD2'
// I want remove the `DD2` from above string
I know how to replace specific character using .replace('',''). But in my case it is different

If the strings are always made up starting with numbers and you want to get the number up until the first alphabetical character, I'd recommend the use of parseInt() since its behaviour is exactly that it parses numeric characters in a string to a number until it encounters the first non-numeric character where it stops parsing.
var myNumber = parseInt(myString);

use this code:
myString.substr(0,myString.search('[a-zA-Z]'));

You may also do like
myString.replace(/[^\d].*/,"");

You can use regex /([\d]+).+$/g as well:
var regex = /([\d]+).+$/g;
console.log(regex.exec("1122D")[1]);
regex.lastIndex = 0;
console.log(regex.exec("1122Z3")[1]);
regex.lastIndex = 0;
console.log(regex.exec("112DD2")[1]);

Best way -
myString.slice(0, myString.indexOf(myString.match(/[a-zA-Z]/)));

JavaScript - strip everything before and including a character

I am relatively new to RegEx and am trying to achieve something which I think may be quite simple for someone more experienced than I.
I would like to construct a snippet in JavaScript which will take an input and strip anything before and including a specific character - in this case, an underscore.
Thus 0_test, 1_anotherTest, 2_someOtherTest would become test, anotherTest and someOtherTest, respectively.
Thanks in advance!

You can use the following regex (which can only be great if your special character is not known, see Alex's solution for just _):
^[^_]*_
Explanation:
^ - Beginning of a string
[^_]* - Any number of characters other than _
_ - Underscore
And replace with empty string.
var re = /^[^_]*_/;
var str = '1_anotherTest';
var subst = '';
document.getElementById("res").innerHTML = result = str.replace(re, subst);
<div id="res"/>
If you have to match before a digit, and you do not know which digit it can be, then the regex way is better (with the /^[^0-9]*[0-9]/ or /^\D*\d/ regex).

Simply read from its position to the end:
var str = "2_someOtherTest";
var res = str.substr(str.indexOf('_') + 1);

Regex trying to match characters before and after symbol

I'm trying to match characters before and after a symbol, in a string.
string: budgets-closed
To match the characters before the sign -, I do: ^[a-z]+
And to match the other characters, I try: \-(\w+) but, the problem is that my result is: -closed instead of closed.
Any ideas, how to fix it?
Update
This is the piece of code, where I was trying to apply the regex http://jsfiddle.net/trDFh/1/
I repeat: It's not that I don't want to use split; it's just I was really curious, and wanted to see, how can it be done the regex way. Hacking into things spirit
Update2
Well, using substring is a solution as well: http://jsfiddle.net/trDFh/2/ and is the one I chosed to use, since the if in question, is actually an else if in a more complex if syntax, and the chosen solutions seems to be the most fitted for now.

Use exec():
var result=/([^-]+)-([^-]+)/.exec(string);
result is an array, with result[1] being the first captured string and result[2] being the second captured string.
Live demo: http://jsfiddle.net/Pqntk/

I think you'll have to match that. You can use grouping to get what you need, though.
var str = 'budgets-closed';
var matches = str.match( /([a-z]+)-([a-z]+)/ );
var before = matches[1];
var after = matches[2];
For that specific string, you could also use
var str = 'budgets-closed';
var before = str.match( /^\b[a-z]+/ )[0];
var after = str.match( /\b[a-z]+$/ )[0];
I'm sure there are better ways, but the above methods do work.

If the symbol is specifically -, then this should work:
\b([^-]+)-([^-]+)\b
You match a boundry, any "not -" characters, a - and then more "not -" characters until the next word boundry.
Also, there is no need to escape a hyphen, it only holds special properties when between two other characters inside a character class.
edit: And here is a jsfiddle that demonstrates it does work.

Filter out second set of digits with regex

In my HTML markup, there will be a series of elements with the following naming scheme:
name="[].timeEntries[].Time"
Between both sets of brackets, there will be numbers with at least one possibly two digits. I need to filter out the second set of digits.
Disclaimer: This is my first time getting to know regex.
This is my pattern so far:
var re = /\[\d{1,2}\].timeEntries\[(\d{1,2})\]\.Time/;
I am not sure if I should use the * or + character to indicate two possible digits.
Is replace() the right method for this?
Do I need to escape the period '.' ?
Any other tips you can offer are appreciated.
For example, if I come across an element with
name="[10].timeEntries[9].Time"
I would like to put just the 9 into a variable.

I am not sure if I should use the * or + character to indicate two possible digits.
Neither, use {1,2}
\[\d{1,2}\]\.timeEntries\[(\d{1,2})\]\.Time
Example
This indicates explicitly 1 or 2 digits.
Also, yes, you should escape the .'s
You can use it like this:
var re = /\[\d{1,2}\]\.timeEntries\[(\d{1,2})\]\.Time/;
var myNumber = "[0].timeEntries[47].Time".match(re)[1];
Now myNumber will contain 47.
One final word of warning, myNumber contains the string "47". If your intention is to use it as a number you'll need to either use parseInt or use +:
var myNumber = +"[0].timeEntries[47].Time".match(re)[1];

You're pretty close.
There are a lot of ways you could do this - especially depending on how solid the format of that text will be.
You could use replace:
var re = /\[\d+\]\.timeEntries\[([\d]+)\]\.Time/;
var digits = element_name.replace(re, '$1');
If you know it will always be the second set of digits, you could use match
You could also use indexOf and/or split and some other string functions... In some cases that can be faster (but I think in your case, the regex is fine and probably easier to follow)

Javascript regex expression to replace multiple strings?

I've a string done like this: "http://something.org/dom/My_happy_dog_%28is%29cool!"
How can I remove all the initial domain, the multiple underscore and the percentage stuff?
For now I'm just doing some multiple replace, like
str = str.replace("http://something.org/dom/","");
str = str.replace("_%28"," ");
and go on, but it's really ugly.. any help?
Thanks!
EDIT:
the exact input would be "My happy dog is cool!" so I would like to get rid of the initial address and remove the underscores and percentage and put the spaces in the right place!
The problem is that trying to put a regex on Chrome "something goes wrong". Is it a problem of Chrome or my regex?

I'd suggest:
var str = "http://something.org/dom/My_happy_dog_%28is%29cool!";
str.substring(str.lastIndexOf('/')+1).replace(/(_)|(%\d{2,})/g,' ');
JS Fiddle demo.
The reason I took this approach is that RegEx is fairly expensive, and is often tricky to fine tune to the point where edge-cases become less troublesome; so I opted to use simple string manipulation to reduce the RegEx work.
Effectively the above creates a substring of the given str variable, from the index point of the lastIndexOf('/') (which does exactly what you'd expect) and adding 1 to that so the substring is from the point after the / not before it.
The regex: (_) matches the underscores, the | just serves as an or operator and the (%\d{2,}) serves to match digit characters that occur twice in succession and follow a % sign.
The parentheses surrounding each part of the regex around the |, serve to identify matching groups, which are used to identify what parts should be replaced by the ' ' (single-space) string in the second of the arguments passed to replace().
References:
lastIndexOf().
replace().
substring().

You can use unescape to decode the percentages:
str = unescape("http://something.org/dom/My_happy_dog_%28is%29cool!")
str = str.replace("http://something.org/dom/","");

Maybe you could use a regular expression to pull out what you need, rather than getting rid of what you don't want. What is it you are trying to keep?
You can also chain them together as in:
str.replace("http://something.org/dom/", "").replace("something else", "");

You haven't defined the problem very exactly. To get rid of all stretches of characters ending in %<digit><digit> you'd say
var re = /.*%\d\d/g;
var str = str.replace(re, "");

ok, if you want to replace all that stuff I think that you would need something like this:
/(http:\/\/.*\.[a-z]{3}\/.*\/)|(\%[a-z0-9][a-z0-9])|_/g
test
var string = "http://something.org/dom/My_happy_dog_%28is%29cool!";
string = string.replace(/(http:\/\/.*\.[a-z]{3}\/.*\/)|(\%[a-z0-9][a-z0-9])|_/g,"");