I'd like to search a string for multiple strings, and return true if it finds any of them in there, false otherwise, something like this:
var s = "thing1 thing2"
s.contains(["thing1","thing44444"]) // true
s.contains("1") // true
s.contains("x") // false
Here's what I have so far, but it's getting messier and doesn't really work:
String.prototype.contains = function(xv) {
var t = this
if(xv.isString()){ // isString/isArray are functions I made elsewhere in my code, they work.
if(t.indexOf(xv) > -1)
return true;
} else if(xv.isArray()) {
if(xv.contains(t)){
return true
}
for(v in xv){
if(t.indexOf(xv[v]) > -1){
return true
}
}
} else {
return false
}
}
As of now, it will return undefined if it makes it through the for loop without finding anything. I had return false after the for loop, but it would run before the for finished.
I feel like there's gotta be an easier way to do this.
I've already tried How do you search multiple strings with the .search() Method? but I couldn't send an array to .search().
Frameworks I'm using: angular 1.5.8, jquery 1.11.1
You can use Array.some and String.indexOf or String.includes
var s1 = "thing1 thing2";
var s2 = "Hello Kitty";
var r1 = ["thing1","thing44444"].some( x => s1.includes(x));
var r2 = ["Travis","Heeeeeeter"].some( x => s2.includes(x));
console.log(r1, r2); // true, false
Related
I have a Javascript array with multiple values:
var filterClasses = ['col-sm-12', 'hidden-xs', 'hidden-sm', 'hidden-lg', 'hidden-md', 'active', 'btn-'];
I have a function that gets all css classes in the DOM. But i want to check if this class should be added to a new array or not. So i can use indexOf for this:
return filterClasses.indexOf('col-sm-12');
This returns a true, so this class should be ignored.
But now i have a class that is btn-primary. As you see in my array i have the btn- added in it. I want to exclude all classes that contains the word btn-. How can i achieve this?
Current function:
function setupShouldAddClass( cssClass, filterClasses )
{
// If the cssClass exists in the filterClasses then false
if ( filterClasses.indexOf(cssClass) > 0 )
{
return true;
}
filterClasses.forEach(function ( item )
{
if ( stringContains(item, cssClass) )
{
return true;
}
});
return false;
}
function stringContains( needle, haystack )
{
return (haystack.indexOf(needle) !== -1);
}
Maybe you can solve your issue using regular expressions instead of using imperative code:
var classBlackListRegExp = /(col-sm-12|hidden-xs|hidden-sm|hidden-lg|hidden-md|active|^btn-.+)/i;
var result = classBlackListRegExp.test("btn-whatever");
console.log(result);
Check the ^btn-.+ part. This matches anything starting with "btn-".
I believe that your scenario is the ideal use case of regular expressions!
OP concerns if class black list is very large
OP said:
what im wondering is, that if i add more then 100 classes, how does
this handle the line breaks?
You can join the whole array of black-listed strings and create a RegExp object with it as follows:
// I use a templated string and String.prototype.join
// to create a regular expression from a given array:
var classBlackListRegExp = new RegExp(`(${[
'col-sm-12',
'hidden-xs',
'hidden-sm',
'hidden-lg',
'hidden-md',
'active',
'^btn-.+'
].join("|")})`, "i");
var result = classBlackListRegExp.test("btn-whatever");
console.log(result);
You need to use Array#some and check against each value and return true if found.
function setupShouldAddClass(cssClass, filterClasses) {
return filterClasses.indexOf(cssClass) !== -1 || filterClasses.some(function (item) {
return stringContains(item, cssClass);
});
}
I would loop over them like this.
function setupShouldAddClass( cssClass, filterClasses )
{
// If the cssClass exists in the filterClasses then false
var ret = true;
filterClasses.forEach(function(el) {
if (cssClass.indexOf(el) >= 0) {
ret = false;
}
});
return ret;
}
How about bringing the cssClass to what you needed to be compared to:
var transformedToMyNeedsCSS = "btn-primary".replace(/^(btn[-])(?:.*)/,"$1");
// --> Output "bnt-"
And then you compare as you are doing it now:
if ( filterClasses.indexOf(transformedToMyNeedsCSS) > 0 )
{
return true;
}
There's a whole host going wrong here. Let's deal with it step by step:
First
if ( filterClasses.indexOf(cssClass) > 0 )
That is incorrect because indexOf returns -1 if the search term is not found. It returns 0 if it is the first item in the array. So you want >= 0.
Second, the forEach loop:
filterClasses.forEach(function ( item )
{
if ( stringContains(item, cssClass) )
{
return true;
}
});
This achieves nothing. As in, genuinely nothing. Because you are inside a new function (the callback to forEach) return only returns from the inner function. And the return value is then discarded. What this code actually does is loop all the way through the array and do nothing. What you actually want is a clever function called Array.prototype.some. This loops through the array and tests each element. If you return true on any of the elements, some returns true. Otherwise it returns false.
So your code could look like this:
return filterClasses.some(function(element) {
return stringContains(item, cssClass);
}
Now we want to ignore all classes where they begin with btn-. I presume this means that you want to return false if the class begins with btn-.
if (cssClass.indexOf('btn-') === 0) {
return false;
}
So your function now looks like:
function setupShouldAddClass( cssClass, filterClasses )
{
if (cssClass.indexOf('btn-') === 0) {
return false;
}
// If the cssClass exists in the filterClasses then false
if ( filterClasses.indexOf(cssClass) >= 0 )
{
return true;
}
return filterClasses.some(function(element) {
return stringContains(item, cssClass);
});
}
Return true if the string in the first element of the array contains all of the letters of the string in the second element of the array. No case-sensitivity and order doesn't matter only the letters matter. For ex - ["Hello","hello"] returns true and so does ["Alien","lien"] and also ["Mary", "Aarmy"]. I think you get it. If not return false.
I could solve it with Array.indexOf() === -1 (in the first for loop) but can it work with this code, it's the opposite. I just can't make it return false. Ultimately, I wanna know, can you make it return false without changing the method.
function mutation(arr) {
var split = arr[1].toLowerCase().split("");
var splitSecond = arr[0].toLowerCase().split("");
for(k=0;k<=arr[0].length;k++){
for(i=0;i<=arr[1].length;i++){
if(split[i]===splitSecond[k]) {
return true
}
}
} return false
}
mutation(["hello", "hney"], "");
If using any other method, explain :)
The problem with your code is that you return true; as soon as one letter matches.
What you need to do is check if all letters match, which is easier achieved by checking if any letter doesn't match.
mainloop:
for(k=0;k<=arr[0].length;k++){
for(i=0;i<=arr[1].length;i++){
if(split[i]===splitSecond[k]) {
continue mainloop; // found the letter, move on to next search
}
}
return false; // failed to find letter, fail here
}
return true; // haven't failed yet and end of input reached. Success!
Another alternative would be:
for(k=0;k<arr[0].length;k++) {
if( arr[1].indexOf(split[k]) < 0) {
// letter not found
return false;
}
}
// not failed yet? Excellent!
return true;
function mutation(arr) {
var test = arr[0].toLowerCase(),
chars = arr[1].toLowerCase(),
len=chars.length;
for(var i=0;i<len;i++)
if(test.indexOf(chars[i])==-1) //this char not exist in test string
return false;
return true;//all chars already checked
}
mutation(["hello", "he"]);
https://jsfiddle.net/hb2rsm2x/115/
Here is an interesting way using regular expressions. escapeRegExp was taken from here.
function mutation(arr){
var matcher = new RegExp('[^'+escapeRegExp(arr[1])+']', "i");
return arr[0].match(matcher) === null;
}
function escapeRegExp(s) {
return s.replace(/[-/\\^$*+?.()|[\]{}]/g, '\\$&')
}
What it is supposed to do -
Example
url1(pages,"ALT") returns "www.xyz.ac.uk"
url1(pages,"xyz") returns ""
The error - TypeError: Cannot call method 'toUpperCase' of undefined
This is just for some coursework, Im stuck with these errors. Any help would be much appreciated
function index(string,pattern,caseSensitive) {
if(caseSensitive == false) {
var v = string.toUpperCase();
} else {
var v = string;
}
return indexNumber = v.indexOf(pattern);
}
var pages = [ "|www.lboro.ac.uk|Loughborough University offers degree programmes and world class research.", "!www.xyz.ac.uk!An alternative University" , "%www%Yet another University"];
alert(url1(pages, "ALT"));
function url1(pages,pattern) {
var siteContent = [];
for(i=0;i<pages.length;i++) {
var seperator = pages[i].charAt(0);
if(pages[i].indexOf(seperator)>0){
siteContent = pages[i].split(pages[i].indexOf(seperator));
}
if( index(siteContent[2],pattern,false)>=0){
return siteContent[1];
}else{
return "";
}
}
}
if(pages[i].indexOf(seperator)>0){
siteContent = pages[i].split(pages[i].indexOf(seperator));
}
if( index(siteContent[2],pattern,false)>=0){
return siteContent[1];
}else{
return "";
}
If pages[i].indexOf(seperator)<=0, siteContent is still whatever it was from the last iteration. If that happens on the first iteration, siteContent is still [], and siteContent[2] is undefined.
Another problem: the expression pages[i].indexOf(seperator) returns a number, and pages[i].split expects a delimiting string as an argument. Since the number doesn't appear in your input, you'll always get a single-element array, and siteContent[2] will always be undefined. Get rid of .indexOf(seperator), change it to siteContent = pages[i].split(seperator).
One more: get rid of the else { return ""; }. Add a return ""; after the for loop.
Finally, in the first if statement condition, change .indexOf(seperator) > 0 to .indexOf(seperator, 1) !== -1. Since you're getting seperator from the first character of the string, it will be found at 0. You want the second occurrence, so start the search at 1. In addition, .indexOf returns -1 if it doesn't find the substring. You'll need to account for this in both if conditions.
Side note, as this is not causing your problem: never use == false. JS will coerce stuff like 0 and "" to == false. If that's what you want, just use the ! operator, because the expression has nothing to do with the value false.
My final answer is http://jsfiddle.net/QF237/
Right here:
alert(url1(pages, ALT)); // ALT ISN'T DEFINED
I believe you forgot to quote it:
alert(url1(pages, "ALT"));
You should split the string passing the separator character itself. Your function then will look like:
function url1(pages,pattern) {
var siteContent = [];
for(i=0;i<pages.length;i++) {
var seperator = pages[i].charAt(0);
console.log(seperator);
if(pages[i].indexOf(seperator)>=0){
siteContent = pages[i].split(seperator); //fixed here
}
console.log(siteContent);
if( index(siteContent[2],pattern,false)>=0){
return siteContent[1];
}else{
return "";
}
}
}
Tell us if it worked, please.
EDIT: It seeems your index() also has a little problem. Please try the function below.
function index(string,pattern,caseSensitive) {
var v;
if(caseSensitive == false) {
v = string.toUpperCase();
pattern = pattern.toUpperCase(); //to clarify: pattern should be uppercased also if caseSensitiveness is false
} else {
v = string;
}
return v.indexOf(pattern);
}
EDIT 2:
And url1() is finally like this:
function url1(pages,pattern) {
var siteContent = [];
for(i=0;i<pages.length;i++) {
var seperator = pages[i].charAt(0);
if(pages[i].indexOf(seperator)>=0){
siteContent = pages[i].split(seperator);
}
if( index(siteContent[2],pattern,false)>=0){
return siteContent[1];
}
}
return "";
}
In this case, the first occurrence of pattern in all pages will be returned.
I am using jstree library to display a tree.
In the code below, I am looping through the selected nodes in the tree and based on some conditions, I am assigning a variable 'allow_edit' a boolean value.
I would like to break the main loop if 'allow_edit = false'.
I tried using label and breaking the loop but this does not seem to work. I am getting undefined label.
loop1:
$j.each($j("#demo2").jstree("get_selected"), function(index, element) {
var selected_node_depth = parseInt($j(element).attr('node_depth'));
var allow_edit = false;
var array_first_filter = $j.grep(array_first, function(v) { return v[1] != "not detected";})
var array_second_filter = $j.grep(array_first_filter, function(v) { return v[3] > selected_node_depth;})
if (array_second_filter.length === 0 || array_second_filter.length == null)
{
allow_edit = true;
}
else{
alert("Confliction exists in your selected terms.");
allow_edit = false;
//break loop1; /** not working, getting undefined label **/
}
}
Any suggestions on how to break the main loop if 'allow_edit = false'? Thanks a lot
If the function you pass to .each() returns false, the iteration will stop.
else {
allow_edit = false; // pointless since you're about to return ...
return false;
}
Also, as a programming style note, any construction of the form:
if (something) {
flag = true;
}
else {
flag = false;
}
can be better written as simply:
flag = something;
In JavaScript, to force flag to be boolean (true or false), you can do this:
flag = !!(something);
The two ! (logical "not") operators force the expression ("something") to be evaluated as a boolean by the same rules as are used when that expression is the test clause of an if statement.
If I have a JavaScript object such as:
var x = {foo: 42, bar: {fubar: true}}
then I can get the value true with var flag = x.bar.fubar. I'd like to be able to separate out and store the path "bar.fubar", then evaluate it dynamically. Something like:
var paths = ["bar.fubar", ...];
...
var flag = evalPath( x, paths[0] );
Obviously I could write a simple parser and evaluator for a basic path expression grammar. But under DRY principles I wonder if there's already an existing way to do something like evalPath built-in to JavaScript, or a small library that would do the job? I also anticipate needing array indexes in the path expression in future.
Update Just to be clear, I'm not asking for code samples - my question is whether there's existing code (built-in or library) I can re-use. Thanks to the contributors below for suggestions of code samples anyway! Note that none of them handle the array index requirement.
Doing a quick search, I came across JSONPath. Haven't used it at all, but it looks like it might do what you want it to.
Example usage:
var x = {foo: 42, bar: {fubar: true}}
var res1 = jsonPath(x, "$.bar.fubar"); // Array containing fubar's value
Why not try something like
function evalPath(obj, path)
{
var rtnValue = obj;
// Split our path into an array we can iterate over
var path = path.split(".");
for (var i = 0, max=path.length; i < max; i++)
{
// If setting current path to return value fails, set to null and break
if (typeof (rtnValue = rtnValue[path[i]]) == "undefined")
{
rtnValue = null;
break;
}
}
// Return the final path value, or null if it failed
return rtnValue;
}
Not tested, but it should work fairly well. Like XPath, it will return null if it can't find what it's looking for.
JavaScript provides eval, but I don't recommend it.
like
function locate(obj, path) {
var p = path.split("."), a = p.shift();
if(a in obj)
return p.length ? locate(obj[a], p.join(".")) : obj[a];
return undefined;
}
locate(x, "bar.fubar")
this works on the right only, of course
You could try something like this. I can't really think of a situation where it would be appropriate to store paths this way though.
function evalPath(obj, path) {
var pathLevels = path.split('.');
var result = obj;
for (var i = 0; i < pathLevels.length; i++) {
try {
result = result[pathLevels[i]];
}
catch (e) {
alert('Property not found:' + pathLevels[i]);
}
}
return result;
}
The alert is really only there for debugging purposes. You may want to return null or something.
How about:
evalPath = function(obj, path) {
if (path[0] === "[") {
return eval("obj" + path);
} else {
return eval("obj." + path);
}
};
This has the advantage that it works for arbitrary strings:
evalPath([1,2,3], "[0]"); => 1
evalPath({a:{b:7}}, "a.b"); => 7
This, of course, only works if you really trust your input.