My problem is as follows: I am trying to take data as formatted in the 'names' variable in the snippet below, convert the string to array, then reorganize the array so the text is in the correct order. I am able to get the pieces I have put together to properly sort the first or last instance of a first & last name, but am seeking guidance on how to go about processing multiple names. The snippet below will return the last instance of the first & last name in the correct order. At this point, I am only looking to have the data returned as a properly sorted array, e.g.
if the input string is
names = "Bond, James & Banner, Bruce";
once processed should return: ['James', 'Bond,', '&', 'Bruce', 'Banner,']
As always I appreciate all the help I can get, thanks in advance!
Array.prototype.move = function(from,to){
this.splice(to,0,this.splice(from,1)[0]);
return this;
};
var names ="Bond, James & Banner, Bruce";
var namesArr = names.split(' ');
var idx;
// search for a comma (only last names have commas with them)
for(var i = 0; i < namesArr.length; i++) {
if(namesArr[i].indexOf(',') != -1) {
idx = i;
}
}
namesArr.move(idx, idx+1);
console.log(namesArr);
You were close but this solution should work for you. Basically you need to update in the loop and increment the index i to account for the switch. Otherwise you will end up revisiting the first last name you switch.
Array.prototype.move = function(from,to){
this.splice(to,0,this.splice(from,1)[0]);
return this;
};
var names ="Bond, James & Banner, Bruce & Guy, Other";
var namesArr = names.split(' ');
var idx;
// search for a comma (only last names have commas with them)
for(var i = 0; i < namesArr.length; i++) {
if(namesArr[i].indexOf(',') != -1) {
namesArr.move(i, i+1);
i++;
}
}
console.log(namesArr);
Another solution could be by using String.prototype.match() and a regular expression \w+ to match the names:
var names = "Bond, James & Banner, Bruce & Licoln, Anna"; // ...
var arr_names = names.match(/\w+/g); // Match names
var res = [];
for (var i = 0; i < arr_names.length; i += 2) { // Step by 2
res.push(arr_names[i + 1]); // Push the name before
res.push(arr_names[i]); // Push the current name
res.push("&"); // Add "&"
}
res.splice((res.length - 1), 1); // Remove last "&"
console.log(res);
Related
I'm looking to extract the values 'adult' and '2ndclass' from this custom javascript array in separate javascript variables for each value. Anyone has any ideas on how to do this?
In the following case, there are 2 products added to cart but I would like to have the flexibility to always grab any existing values for each product that is added to cart regardless of the amount added. Is that possible?
[
'pass/DE-NO-RS-BE-FI-PT-BG-DK-LT-LU-HR-LV-FR-HU-SE-SI-ME-SK-GB-IE-MK-EE-CH-GR-IT-ES-AT-CZ-PL-RO-NL-TR-BA/**adult/2ndclass**',
'pass/DE-NO-RS-BE-FI-PT-BG-DK-LT-LU-HR-LV-FR-HU-SE-SI-ME-SK-GB-IE-MK-EE-CH-GR-IT-ES-AT-CZ-PL-RO-NL-TR-BA/**youth/2ndclass**'
]
Thank you in advance for your help
You can also use RegExp to get those values out.
var arr = [
"pass/DE-NO-RS-BE-FI-PT-BG-DK-LT-LU-HR-LV-FR-HU-SE-SI-ME-SK-GB-IE-MK-EE-CH-GR-IT-ES-AT-CZ-PL-RO-NL-TR-BA/**adult/2ndclass**",
"pass/DE-NO-RS-BE-FI-PT-BG-DK-LT-LU-HR-LV-FR-HU-SE-SI-ME-SK-GB-IE-MK-EE-CH-GR-IT-ES-AT-CZ-PL-RO-NL-TR-BA/**youth/2ndclass**"
];
var results = [];
for (var i=0; i < arr.length; i++) {
var matches = arr[i].match(/\*\*(.+)\/(.+)\*\*/);
if(matches && matches.length >= 3)
results.push([matches[1], matches[2]]);
}
console.log(results);
You can try the code here https://jsfiddle.net/p84eftL7/1/
First of all i didn't get your question completely. But as far as i can understand you want those 2 values at the end of the strings from an array. You can try something like this
var a, b;
for(s in YOUR_ARRAY){
[...other, a, b] = YOUR_ARRAY[s].split("/");
console.log(a, b);
//Do whatever you want to do with a,b
}
Let me explain myself, Firstly you would require to iterate over your array thats why we have a 'for' loop here. Then for each string which is given by 'YOUR_ARRAY[s]' you are splitting the string with '/' as a delimiter. Rest of the thing is pretty simple.
For your reference go through these links
https://www.w3schools.com/js/js_loop_for.asp
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Destructuring_assignment
UPDATE:
As mentioned in the comments. If you want to have a function for this then
function processValues(arr){
var a, b;
for(s in arr){
[...other, a, b] = arr[s].split("/");
console.log(a, b);
//Do whatever you want to do with a,b
}
}
processValues(YOUR_ARRAY);
In the end what I did was the following
As I had to reference back to the name of the variable I used the following to slice up the array so I could reference that using index numbers for the values I needed to retrieve:
function() {
var myStringArray = {{MY_ARRAY}};
var arrayLength = myStringArray.length;
var output = []
for (var i = 0; i < arrayLength; i++) {
var string = myStringArray[i].split("/",4)
/*pull index 2 and 3 from string and convert to string*/
output.push(string)
}
return output
}
After that I had to loop the new array that was being pushed out of the info as mentioned above
Since I only needed to split up particular indices from that NEW_ARRAY_2, I used the following to do that
function() {
var products = {{NEW_ARRAY_2}};
var arr = []
for (var i=0; i < products.length; i++) {
var prod = products[i];
var matches = prod[2];
arr.push(matches);
}
var list = arr.join(', ')
return list
}
SAMPLE RETURN for 2 products: 'adult, youth'
Thank you for your support
I want to retrieve inside an array all the elements who match multiple strings (all of them & not necessary words): like a search engine returning all results matching term_searched#1 && term_searched#2.
It's not a question about duplicates in the array (there's none), but about searching for a conjunction of elements: traditionally, the search is for one element, by himself or in disjunction with others (a|b|c). Just want to search (a && b && c).
I tried:
indexOf() : I can work only with one element to locate in the array.
match() : there is no AND operator in a regex expression (only | - sadly, it would be so simple). So I tried to inject these regex expressions
/(?=element1).*(?=element2)/gim
/(?=element1)(?=element2)/gim see here
The first regex expression works, but not at every time: seems very fragile...
So I don't know if I'm in the good direction (match) or if I can't figure what is the right regex expression... Need your advices.
// filter grid by searching on 'input' event
'input #search': (e)=> {
var keypressed = e.currentTarget.value;
// create array on 'space' input
var keyarr = keypressed.toLowerCase().split(" ");
// format each array's element into regex expression
var keyarrReg = [];
for(i = 0; i < keyarr.length; i++) {
var reg = '(?=' + keyarr[i] + ')';
keyarrReg.push(reg);
}
// array to regex string into '/(?=element1).*(?=element2)/gim' format
var searching = new RegExp(keyarrReg.join(".*"), 'mgi');
// set grid
var grid = new Muuri('#gridre', {
layout: {
fillGaps: true,
}
});
if (keypressed) {
// filter all grid's items (grid of items is an array)
grid.filter(function (item) {
var searchoperator = item.getElement().textContent.toLowerCase().match(searching);
// get items + only their text + lower case their text + return true (not false) in the value ('keypressed') is found in them
//var searchoperator = item.getElement().textContent.toLowerCase().indexOf(keypressed.toLowerCase()) != -1;
return searchoperator;
}
[....]
}
}
Edit with Gawil's answer adapted to my initial code (to help if needed)
// filter grid by searching on 'input' event
'input #search': (e)=> {
var keypressed = e.currentTarget.value;
// create array on 'space' input
var keyarr = keypressed.toLowerCase().split(" ");
// convert the array to a regex string, in a '^(?=.*word1)(?=.*word2).*$' format
// here is Gawil's answer, formatted by Teemu
var searching = new RegExp('^(?=.*' + keyarr.join(')(?=.*') + ').*$', 'm');
// set grid
var grid = new Muuri('#gridre', {
layout: {
fillGaps: true,
}
});
if (keypressed) {
// filter all grid's items (grid of items is an array)
grid.filter(function (item) {
// get items + only their text + lower case their text + delete space between paragraphs
var searchraw = item.getElement().textContent.toLowerCase().replace(/\r\n|\n|\r/gm,' ');
var searchoperator = searchraw.match(searching);
return searchoperator;
}
[....]
}
}
The code bellow will log each element of the array containing words cats and dogs.
It uses the regex ^(?=.*word1)(?=.*word2).*$To handle new lines, use this one instead :
^(?=(?:.|\n)*word1)(?=(?:.|\n)*word2).*$
You can add as many words as you want following the same logic, and it does not take order of the words in count.
It is very similar to what you tried, except that you have to do all (?=) checks before matching the string. Indeed, your first regex works only when the words are in the right order (element1 and then element2). Your second regex almost works, but you wrote only lookaheads, so it checks the presence of each word, but won't match anything.
var words = ["cats", "dog"]
var array = [
"this is a string",
"a string with the word cats",
"a string with the word dogs",
"a string with both words cats and dogs",
"cats rule everything",
"dogs rule cats",
"this line is for dog\nbut cats prefer this one"
]
var regexString = "^";
words.forEach(function(word) { regexString += ("(?=(?:.|\n)*"+word+")"); });
var regex = new RegExp(regexString);
array.forEach(function(str) { // Loop through the array
if(str.match(regex)) {
console.log(str); // Display if words have been found
}
});
If I've correctly understood your question, you've an array of strings, and some keywords, which have to be found from every index in the array to be accepted in the search results.
You can use a "whitelist", i.e. a regExp where the keywords are separated with |. Then iterate through the array, and on every member create an array of matches against the whitelist. Remove the duplicates from the matches array, and check, that all the keywords are in the list simply by comparing the length of the matches array to the count of the keywords. Like so:
function searchAll (arr, keywords) {
var txt = keywords.split(' '),
len = txt.length,
regex = new RegExp(txt.join('|'), 'gi'), // A pipe separated whitelist
hits; // The final results to return, an array containing the contents of the matched members
// Create an array of the rows matching all the keywords
hits = arr.filter(function (row) {
var res = row.match(regex), // An array of matched keywords
final, temp;
if (!res) {return false;}
// Remove the dups from the matches array
temp = {}; // Temporary store for the found keywords
final = res.filter(function (match) {
if (!temp[match]) {
// Add the found keyword to store, and accept the keyword to the final array
return temp[match] = true;
}
return false;
});
// Return matches count compared to keywords count to make sure all the keywords were found
return final.length === len;
});
return hits;
}
var txt = "Some text including a couple of numbers like 8 and 9. More text to retrieve, also containing some numbers 7, 8, 8, 8 and 9",
arr = txt.split('.'),
searchBut = document.getElementById('search');
searchBut.addEventListener('change', function (e) {
var hits = searchAll(arr, e.target.value);
console.log(hits);
});
<input id="search">
The advantage of the whitelist is, that you don't have to know the exact order of the keywords in the text, and the text can contain any characters.
What I’m trying to do is select an option based on the url. So what I have done so far is get the url and match it to the options. Then stored the matches in an array, next I removed a few terms like ‘http’,’org’, etc.. I was able to narrow it down to two keywords.
Now what I have to is select an option that match one of the keywords in the array.
I tried to use ‘filter’, contains: and map but it only work if I’m using one term and the array, I have an array of terms. So what I need to know how to do is select and option based on the first match. From the text of the option to the term in the array.
//this is my arr
var arr = ["Pro_life", "Inactive"]
//this is the text from the options
FB_Ext_Pro_life_Specific_Inactive
FB_register_now
i need to find a way to select 'FB_Ext_Pro_life_Specific_Inactive' with a term from my array.
Anyone have any ideas?
I didn't get your question completely, but i managed to make this
var arr = ["Pro_life", "Inactive"]
var options = ["FB_Ext_Pro_life_Specific_Inactive", "FB_register_now", "sample_Inactive__"]
for (var x = 0; x < arr.length; x++) {
for (var y = 0; y < options.length; y++) {
if (options[y].indexOf(arr[x]) != -1) {
console.log("Option " + options[y] + " matches with " + arr[x]);
}
}
}
It uses indexOf() for checking if the keyword matches with the option
May be you can do like this;
var arr = ["Pro_life", "Inactive"],
str = "FB_Ext_Pro_life_Specific_Inactive\nFB_register_now",
result = str.split("\n")
.filter(s => arr.some(k => s.indexOf(k) !== -1));
console.log(result);
I have a given word, that I want to match against a given list of words, mainList, and establish which words of that given list are anagrams of the given word, and add them to another list, subList.
I feel like my method to do this is fine, but it returns an unexpected result.
For example...
var word = 'master';
var mainList = ['stream', 'pidgeon', 'maters'];
var subList = [];
Then I take the word, split to an array of letters, alphabetise, and join back into a string. With this string I should be able match against any possible anagrams (which I will covert in the same way).
var mainSorted = [];
for (i = 0; i < word.length; i++) {
mainSorted = word.split('').sort().join();
}
This is where it goes wrong. I loop through the mainList array trying to establish if a given item, when converted, matches the original. If so, I want to push the word to the subList array.
for (var i = 0; i < mainList.length; i++) {
var subSorted = mainList[i].split('').sort().join;
if (mainSorted === subSorted) {
subList.push(mainList[i])
}
}
return subList;
...and the value I expect to see for subList is: ['stream', 'maters']
Yet I am returned an empty array instead.
I've gone through this so many times and I cannot see what's going wrong, would really appreciate some help!
Also, I'm aware there's probably more eloquent methods to do this (and I welcome any suggestions) but primarily I want to see where this is going wrong.
Thanks in advance.
You forgot () at the end of join
var subSorted = mainList[i].split('').sort().join;
should be
var subSorted = mainList[i].split('').sort().join();
One non-issue is
for (i = 0; i < word.length; i++) {
mainSorted = word.split('').sort().join();
}
doesnt need to be in a loop
mainSorted = word.split('').sort().join();
alone suffices
as a bonus, here's a tidier way of doing what you are doing
var word = 'master';
var mainList = ['stream', 'pidgeon', 'maters'];
var mainSorted = word.split('').sort().join();
return mainList.filter(function(sub) {
return sub.split('').sort().join() == mainSorted;
});
I'm trying to break up a string like this one:
fname=bill&mname=&lname=jones&addr1=This%20House&...
I want to end up with an array indexed like this
myarray[0][0] = fname
myarray[0][1] = bill
myarray[1][0] = mname
myarray[1][1] =
myarray[2][0] = lname
myarray[2][1] = jones
myarray[3][0] = addr
myarray[3][1] = This House
The url is quite a bit longer than the example. This is what I've tried:
var
fArray = [],
nv = [],
myarray = [];
fArray = fields.split('&');
// split it into fArray[i]['name']="value"
for (i=0; i < fArray.length; i++) {
nv = fArray[i].split('=');
myarray.push(nv[0],nv[1]);
nv.length = 0;
}
The final product is intended to be in 'myarray' and it is, except that I'm getting a one dimensional array instead of a 2 dimensional one.
The next process is intended to search for (for example) 'lname' and returning the index of it, so that if it returned '3' I can then access the actual last name with myarray[3][1].
Does this make sense or am I over complicating things?
Your line myarray.push(nv[0],nv[1]); pushes two elements to the array myarray, not a single cell with two elements as you expect (ref: array.push). What you want is myarray.push( [nv[0],nv[1]] ) (note the brackets), or myarray.push(nv.slice(0, 2)) (ref: array.slice).
To simplify your code, may I suggest using Array.map:
var q = "foo=bar&baz=quux&lorem=ipsum";
// PS. If you're parsing from a-tag nodes, they have a property
// node.search which contains the query string, but note that
// it has a leading ? so you want node.search.substr(1)
var vars = q.split("&").map(function (kv) {
return kv.split("=", 2);
});
For searching, I would suggest using array.filter:
var srchkey = "foo";
var matches = vars.filter(function (v) { return v[0] === srchkey; });
NB. array.filter will always return an array. If you always want just a single value, you could use array.some or a bespoke searching algorithm.
for (var i = 0; i < fArray.length; i++) {
nv = fArray[i].split('=');
myarray.push([nv[0],nv[1]]);
}
nv.length = 0; is not required, since you're setting nv in each iteration of the for loop.
Also, use var i in the for-loop, otherwise, you're using / assigning a global variable i, that's asking for interference.